Datepart (to Get 2 Digit Number For The Month)

I want to build a string that contains today's date (without the time).

For example, if select GETDATE() returns 2008-04-28 14:18:34.180, I want to end up with either

(1) 2008-04-28
or
(2) 20080428. (I always want the month to be represented by a 2 digit number)

Is there a datepart parameter that will give me (1) in one shot? I don't think so, since datepart returns an integer and (1) is not in the form of an integer.

So, I was trying to build (2) by using the yyyy, mm, and dd parameters to extract out the appropriate parts and casting them to a string and contatentating them. However, when I do the month portion, (using mm) it gives me the integer that represents the month, and this number can be 1 or 2 digits depending on the month. I always want it to be a 2 digit number. For example, if I'm in Apr, I want to end up with "04", not "4". This would also apply to the day portion. (although the date that I'm writing this post is on the 28th so I'm not certain what GETDATE() will return on dates that are 1 digit.)

The only way I can get the single digit month to write out as a 2 digit month is by doing a LEN() function on the string and if it is a length 1, then concatenate a "0" in front of it. I started doing this and the expression became too crazy, so I wanted to first check to see if someone can come up with something cleaner.

Thanks for looking.