Displaying Difference Between Two Dates In The HH:mm:ss Format

Feb 28, 2007

I have a need to display the difference between two dates, a start date and a end date in the format HH:mm where the hours could be greater than 60.

For example:

Start Date - 30/01/2007 09:00:01
End Date - 01/02/2007 20:40:04

When i use the following code (=Fields!dateend.Value - Fields!DateStart.Value) i get 2.11:40:03 which i can easily understand, but the customer wants it as above!

I would like to be able to get it to be 59:40:03.

Any help would be much appreciated.

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Not Displaying Same Dates On PHP Driven Site

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I'm trying to create a simple attendance website where a user logs in and a time and user name (with unique ID) is stored into a table, and then the user is able to click "Check Attendance" and the site will display only the times they logged in (which wasn't too bad). I want a button we can click to "clean up the database" and delete duplicate dates.

If I have a user sign in 10 times in one day - I don't need all 10 times logged into the database, only one. So how do I create a query (needs to be a query so I can tack it onto a button in PHP) that will delete 'where date = the same as a previous date'?

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ID (int)
RESULT (float)
TS (datetime)

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----------------------------
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Oct 23, 2007

I have 2 datatime columns....i want to get the difference in the dates...

EXample

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10/10/2007 20/10/2007
11/10/2007 21/10/2007
12/10/2007 22/10/2007
13/10/2007 23/10/2007
14/10/2007 25/10/2007


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pavan

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Mar 15, 2007



By using DateDiff we can do.Could you please send me the expression

Thanks

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advance thanks to all...can anybody helpme soon...........
i am using sql server 2005........i want to find out time difference between two dates in HH,MM,SS format
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19/Apr/07 11:52:31 AM 
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I was thinking something like


Code:

Update #ClaimMaster
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Does that make any sense?

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Nov 27, 2007

This is tricky so please read it through


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The result set is







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Activity ID

Activity Date/Time

Activity Type




100819

4521404

11/4/07 2:06 PM

INIT




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4521405

11/4/07 2:07 PM

LOG




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4521406

11/4/07 2:07 PM

LOG




100819

4521473

11/4/07 2:28 PM

TR




100819

4521501

11/4/07 2:33 PM

WIP




100819

4521839

11/4/07 3:25 PM

RE




100819

4521844

11/4/07 3:27 PM

RE_Method




100819

4522575

11/4/07 8:53 PM

CL




100820

4521412

11/4/07 2:10 PM

INIT




100820

4521419

11/4/07 2:13 PM

ATTACHTDOC




100820

4525856

11/5/07 2:49 PM

ATTACHTDOC




100820

4525859

11/5/07 2:49 PM

LOG




100820

4525869

11/5/07 2:49 PM

CL




100821

4521423

11/4/07 2:14 PM

INIT




100821

4521425

11/4/07 2:14 PM

LOG




100821

4521429

11/4/07 2:14 PM

TR




100821

4521432

11/4/07 2:14 PM

ACK




100821

4522219

11/4/07 4:58 PM

RE




100821

4522221

11/4/07 4:58 PM

RE_Method




100821

4522447

11/4/07 6:51 PM

CL




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e.g. Time difference between 4521404 and 4521405, 4521405 and 4521406, 4521406 and 4521473 etc. Please note that the difference between 4521412 and 4522575 will NOT be calculated since they are from different Reference Numbers.

Thanks,

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Sep 26, 2006

Hi all,

I have a table named Orders and this table has two relevant fields: CustomerId and OrderDate. I am trying to construct a query that will give me the difference, in days, between each customer's order so that the results would be something like: (using Northwind as the example)

...
ALFKI 25/08/1997 03/10/1997 39
ALFKI 03/10/1997 13/10/1997 10
ALFKI 13/10/1997 15/01/1998 94
ALFKI 15/01/1998 16/03/1998 60
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...

At the moment, I have the following query that I think is on the right track:
€¦
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€¦

However, this gives me too much data:
€¦
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ALFKI 25/08/1997 13/10/1997 49
ALFKI 25/08/1997 15/01/1998 143
ALFKI 25/08/1997 16/03/1998 203
ALFKI 25/08/1997 09/04/1998 227
ALFKI 03/10/1997 13/10/1997 10
ALFKI 03/10/1997 15/01/1998 104
ALFKI 03/10/1997 16/03/1998 164
ALFKI 03/10/1997 09/04/1998 188
ALFKI 13/10/1997 15/01/1998 94
ALFKI 13/10/1997 16/03/1998 154
ALFKI 13/10/1997 09/04/1998 178
ALFKI 15/01/1998 16/03/1998 60
ALFKI 15/01/1998 09/04/1998 84
€¦

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Thanks for any help you have to offer,

Regards,

Stephen.

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SQL
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