Displaying Xml With Xslt In RS
Sep 10, 2007
Hi,
I've got an xml and an xslt - I want to get that into reporting services. Right now I have a link to the xml file in a 'report', which will open it correctly and format with the xslt. I'd like it to display without going to an external link.
I know how to use an xml datasource, but I need the xslt applied, since it has some nice formatting in it - so i don't think that will work.
I'm trying to report on the results of a scripted ms baseline security analyzer of several servers - the style sheet lets you drill down and has links to the base reports.
Thanks for your help.
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Jun 14, 1999
I want to delete and recreate the master Database Device for purpose of shrinking the size of the device .
I dont want to loose the Master db.
I thought of transfering the Master db to a different device,
Delete and recreate the master device and then tranfer back the master db .
and this is all done through the MS SQL enterprise Manager (SQL 6.5 )
Is this the safest eay to proceed with this task?
Any thoughts are greatly appreciated.
Thank you
Guss Hasb
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Feb 23, 2007
Can I use the XML task in SSIS to create an excel document? If so which operation type is best to do it with, XSLT?
I'm trying create excel files dynamically with nothing more than a SQL statement that I'm passing as a variable which generates XML. I would then like to take that variable and combine it with a template and create an excel document. Any help would be appreciated. I do not want to use the data flow because it requires all transformations ahead of time.
Thanks,
Phil
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Mar 3, 2008
Hi,
I've got a problem with my ssis package.
I have a webservice, which from i am downloading xml file which looks like this:
Code Snippet
<?xml version="1.0" encoding="utf-16"?>
<DataSet>
<xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="NewDataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="Table">
<xs:complexType>
<xs:sequence>
<xs:element name="lukas_id_nagrody" type="xs:string" minOccurs="0" />
<xs:element name="ilosc" type="xs:int" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<diffgr:diffgram xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" xmlns:diffgr="urn:schemas-microsoft-com:xml-diffgram-v1">
<NewDataSet>
<Table diffgr:id="Table1" msdata:rowOrder="0">
<lukas_id_nagrody>10</lukas_id_nagrody>
<ilosc>4</ilosc>
</Table>
<Table diffgr:id="Table2" msdata:rowOrder="1">
<lukas_id_nagrody>12</lukas_id_nagrody>
<ilosc>10</ilosc>
</Table>
<Table diffgr:id="Table3" msdata:rowOrder="2">
<lukas_id_nagrody>21</lukas_id_nagrody>
<ilosc>32</ilosc>
</Table>
<Table diffgr:id="Table4" msdata:rowOrder="3">
<lukas_id_nagrody>32</lukas_id_nagrody>
<ilosc>13</ilosc>
</Table>
<Table diffgr:id="Table5" msdata:rowOrder="4">
<lukas_id_nagrody>33</lukas_id_nagrody>
<ilosc>15</ilosc>
</Table>
<Table diffgr:id="Table6" msdata:rowOrder="5">
<lukas_id_nagrody>34</lukas_id_nagrody>
<ilosc>2</ilosc>
</Table>
</NewDataSet>
</diffgr:diffgram>
</DataSet>
And i want it to looks like this:
Code Snippet
<?xml version="1.0" encoding="utf-16"?>
<DataSet>
<xs:schema id="NewDataSet" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="DataSet" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="Table">
<xs:complexType>
<xs:sequence>
<xs:element name="lukas_id_nagrody" type="xs:string" minOccurs="0" />
<xs:element name="ilosc" type="xs:int" minOccurs="0" />
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
<Table id="Table1" rowOrder="0">
<lukas_id_nagrody>J07Z0</lukas_id_nagrody>
<ilosc>1</ilosc>
</Table>
<Table id="Table2" rowOrder="1">
<lukas_id_nagrody>J08Z0</lukas_id_nagrody>
<ilosc>1</ilosc>
</Table>
<Table id="Table3" rowOrder="2">
<lukas_id_nagrody>J09Z0</lukas_id_nagrody>
<ilosc>1</ilosc>
</Table>
</DataSet>
Can You help me?
Thanks in advance
ps. sorry for my english
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Sep 10, 2007
Hi,
I've a xml file and I want to substitute some of the values from database in this xml using XSLT transformation making use of XML task. How can this be achieved?
Thanks
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Mar 14, 2006
I'm writing some code to generate RDL based on a set of existing tables that define reports. (Headings, columns etc.)
The options I'm exploring so far for doing this are as follows:
Use XMLTextWriter class
Use XMLDocument class
Use XMLSerialiser to serialse a set of classes made with XSD.EXE and
Use XMLSerialiser to serialse a set of classes made with XSDObjectGen
Use XSLT to convert MyReportDefinitionDataset.GetXML into RDL
Has anybody else out there seen other code that does anything like this or in general has any suggestions to help me narrow these options down?
Note:
I am hoping to allow users supplying RDL their own files as templates enabling them to define things like report header and footer etc.
My code will take the Table element from the template RDL and replace it with my generated XML (Headings and columns etc.)
Any suggestions/help/existing sample code appreciated.
Thanks,
Mike G
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Jun 15, 2006
I have an XSLT transform that works perfectly using the msxsl.exe utility.
When the same XSL file is run through an SSIS XML transform, the character spacing and carriage returns embedded in the XSL templates are mostly (but not completely) dropped.
Any comments on why SSIS is behaving differently than msxsl.exe? What to do?
Thanks in advance,
Richard
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Aug 10, 2006
In the XML Task if you set the OperationType to XSLT, how do you pass arguments to the Transform like you would in .Net by using the XsltArgumentList class? Thanks.
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Sep 11, 2006
Where does output from <xsl:message> stylesheet elements go? It's not in the Progress or Output window, and there doesn't seem to be a property that controls the destination for messages.
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Sep 4, 2007
I'm reading over this thread: http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=1884062&SiteID=1
and I'm kinda lost as to what to do to strip out the dtd from an XML file I am downloading. I do NOT know XSLT and for that reason, I can't follow his logic.
My SSIS package downloads my XML file just fine, now I need to do a strip of the DTD line in my XML Task.
The person who provided the solution in the above post said to do this...
Code Snippet
Operation Type: XSLT
Source Type: Variable
Source: Variable's name containing the xml text
Save Operation Result: True
DestinationType: Variable
OverwriteDestination: True
Destination: Variable's name which is to contain the original xml minus the DTD.
SecondOperandType: Variable
That stuff I understood. I'll replace variables with my files because they are stored that way, but from what I can tell, that's not my problem.
The stuff he says below this comment is going over my head like a ton of bricks. I can't figure out how to do it.
This is the kind of line of my XML that I want to strip out.
https://www.myaddy.com/pbdr.dtd"[]>
and then he said this...
Code Snippet
Since XSL doesn't know about DTDs, telling it to copy everything strips out DTDs. Then use the Variable specified in the Xml task's SecondOperand as the Source data for the xml source.
Code Snippet
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:copy-of select="." />
</< FONT>xsl:template>
</< FONT>xsl:stylesheet>
A note on how to paste a multi-line xml document into a Integration Services String variable:
Integration Services String variables textboxes are not multi-line, in the Windows sense of a line (CR+LF),
So, in order to paste multi-line text (which xml docs almost always are), save a temporary copy with a unix line ending.
That is, create an xml file in visual studio, and paste your sample original xml in there. Go to File/Advanced Save options, and save the xml with the the settings of Encoding: Unicode (utf-8 without signature) - CodePage 65001, and most importantly, set the Line endings dropdown to "Unix (LF)".
After selecting "OK", copy and paste the text from Visual Studio's xml file editor into the IS variable, and you'll note all the xml data appears.
So can anyone walk me through a dummies version of what he is suggesting to do?
Thanks,
Keith
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Nov 1, 2007
Hi guys,
I have a simple report created with rs2005. I want to get the output exported (using the export options of rs2005) in a specific xml format, so I am using xslt transformation to get it proper.
My problem is that, when I'm doing this using my own machine (SQL Server 2005 32bit installed) everything works OK. BUT when I want to try it on a server that we are supposed to use it gives me a real bad error. On the server, if I have the report without using xslt, it gets exported OK but not in the correct format. I have tested the report on a 32 and on a 64 bit server, I have used either SP1 and SP2 but still can't get through. The error message appearring while I try to export in xml is "Server Error in '/Reports' Application. The XSLT path is invalid. It refers to an external resource, uses invalid syntax, or the XSLT was not found in the catalog."
Has anyone seen something like this before ?
Your help would be much appreciated.
Thanx in advance
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Jun 27, 2007
Hi Does anyone have any information on how I can due a XSLT Transformation on XML Data Stored in SQL Server 2005?Thanks for the helpBones
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Sep 14, 2006
Hi All,
I'm using some xslt documents to transform the xml output of my Reports
but have come across two curiosities where the xslt filter seems to
behave unusually.
Firstly, I need the final saved file to have an xml declaration, which
I believe it should do by default. Even if I put
omit-xml-declaration="no" in the xsl:output tag I don't get an xml
declaration. At present we have a custom job that writes these
declarations back into the xml after SRS has saved it.
Secondly and more importantly, I need to have some of my output tags
wrapped in CDATA sections. I've tried using the cdata-section-elements
attribute, again with no luck.
my XSLT looks something like this (simplified for space)
<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" encoding="utf-8" media-type="text/xml" omit-xml-declaration="no" cdata-section-elements="description"/>
<xsl:template match="/">
<xsl:for-each select="Report/table1/Detail_Collection/Detail">
<item>
<description>
<xsl:value-of select="@Description"/>
</description>
</item>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
The output is something like:
<item>
<description>My first description text...</description>
</item>
<item>
<description>My seconddescription text...</description>
</item>
What I want is:
<?xml version="1.0" encoding="utf-8"?>
<item>
<description><![CDATA[My first description text...]]></description>
</item>
<item>
<description><![CDATA[My secondfirst description text...]]></description>
</item>
All help gratefully appreciated.
Thanks - Andrew.
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Jan 30, 2014
I need to convert an xml file that has an attribute(name). This xml file has to be converted using xsl into the XSLT file such that the tag should have the same structure along with it and its the tag-content also should be the value of the attribute.
<?xml version="1.0" encoding="utf-8"?>
<PatientUpdateRequest xmlns="http://medseek.com/ecoEnablement/Schemas">
<General>
<SendingApplication>SendingApplication1</SendingApplication>
<SendingFacility>SendingFacility1</SendingFacility>
[code].....
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Sep 21, 2006
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This is what I'm trying to do:
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My select statement looks like this:
select 'AB'+(cast(substring(period,3,2) as int)-1) from table.
Result is AB6. But I want AB06 (ABzero6)
But when I do this, I'm getting AB6 instead of AB06. Can someone please tell me how to have '0' in front of 6? I guess when I cast it as integer, it is ignoring the leading 0.
Thanks.
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Oct 27, 2006
Hi
I am calculating percentage using expression. I want to display % at the end of the result.
If I use P1 or P0 somehow it multiplies the result with 100 I guess.
Here is what my calculated value is
15.384515
and I want to display 15.38%
Using P1 or P0 I am getting 1,538.5%
How can I get the desired result?
Any help would be appreciated.
Regards
Amit
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May 7, 2008
Hi there
I got the following returned simple dataset as follow:
Code Snippet
ReportViewType; Category; Name; Units; Price;
LIST_VIEW; FRUITS; Apple; 1; $10
LIST_VIEW; FRUITS; Banana; 2; $11
LIST_VIEW; CARS; Corolla; 8; $100
LIST_VIEW; CARS; BMW; 10; $200
I've managed to grouped by Category field nicely and added extra calculated column for handling to total plus as well as Total for each group plus added a new row for TOTAL in the TABLE and returned as follow:
Code Snippet
FRUITS
Apple; 1; $10; $10
Banana; 2; $11; $22
TOTAL FRUITS; $32
CARS
Corolla; 8; $100; $800
BMW; 10; $200; $2000
TOTAL CARS: $3000
TOTAL: $3032
Now I want to put another extra row underneath TOTAL for handling the calculated but the business rule is only for displaying from the first group for instance:
Code Snippet
TOTAL: $3032
Calculated Average per fruits: $1010.67 ($3032 / 3 UNITS).
3 UNITS is coming from Units for Apple and Banana.
I don't know if I can do this cause i did try to use
Code Snippet
=SUM(IIF(Fields!Category.value = "FRUITS", Fields!Units.Value, 0))
But it's successfully compiled but the report result error (#Error) on that field only. Any ideas?
I thought a simple like this can be handled quite easily instead of creating a new report view type in the the same dataset to handle this particular extra line.
Waiting your comment/feedback.
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Hi,
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Can any one give me directions to a solution, or send me a simple solution to this?
The best example of what I need is is a real estate listing, wherethe property for sale has 8 to 10 descriptive fields and 1 to 3 images that are displayed.
Any help would be appreciated.
Spacecaetrg.
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Function ..
Dim rs_get_defect_desc As New ADODB.Recordset, lot_n as integer
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Hello All,
I have a little problem. Here is the scenario:
I got two tables Asset and Personnel
Personnel has FirstName, LastName,and username which is unique.
Asset table stores all information related to an asset and the username to whom the asset is assigned and the POC username.
The tables look like this:
Personnel Table
FirstName, Last Name, UserName
John, Doe, jdoe
Bill, Smith, bsmith
Asset Table
POCUserName, AssigneeUserName
jdoe,bsmith
My problem arises when I want to display First Name and Last Name for both the POCusername and the AssigneeUserName since FirstName and LastName columns exists once in the Personnel table. How can I display the columns twice. Lets say POCFirstName, POCLastName, AssigneeFirstName, and AssigneeLastName. Or this is something that can't be done.
The query below only display the Assignee info. Of course, I need to something else to display the POC info as well...don't where to go from here...
select tblPersonnel.FirstName, tblPersonnel.LastName, tblAsset.AssigneeUserName, tblAsset.POCUserName
from tblVendor, tblAsset, tblPersonnel
where and tblPersonnel.UserName = tblAsset.AssigneeUserName
and tblAsset.POCUserName in(select tblPersonnel.UserName from tblAsset, tblPersonnel
where tblPersonnel.UserName= tblAsset.POCUserName)
Any help is greatly appreciated
~
N
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Hi
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[Ball, Frisbee, Kite]
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