Duplicate Counts Per Column

I'm have a problem with trying to generate a view that has a count of duplicates values per column in a table.

example I have a table with the following structure:

CREATE TABLE [dbo].[TestDpln](
[CountryCode] [smallint] NOT NULL DEFAULT ((0)),
[NPA] [smallint] NOT NULL DEFAULT ((0)),
[NXX] [smallint] NOT NULL DEFAULT ((0)),
[XXXX] [smallint] NOT NULL DEFAULT ((0)),
[3-Digit] [nvarchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[4-Digit] [nvarchar](4) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[SiteIdx] [int] NULL DEFAULT ((0)),
CONSTRAINT [TestDpln$PrimaryKey] PRIMARY KEY NONCLUSTERED
(
[CountryCode] ASC,
[NPA] ASC,
[NXX] ASC,
[XXXX] ASC
)WITH (PAD_INDEX = OFF, IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON [PRIMARY]

the data loaded looks like this

INSERT INTO dbo.TestDpln VALUES('1','312','555','1212','212','1212','1')
INSERT INTO dbo.TestDpln VALUES('1','312','555','1213','213','1213','1')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2212','212','2212','2')
INSERT INTO dbo.TestDpln VALUES('1','525','555','2213','213','2213','2')

the results I need are

SiteIdx 3 Digit Count 4 Digit Count
------- ------------- -------------
1 2 0
2 2 0

I've tried various queries the closest being:

SELECT DISTINCT SiteIdx, COUNT(*) as "3-Digit Count"
FROM dbo.TestDpln
GROUP BY SiteIdx, "3-Digit"
HAVING COUNT(*) > 1

but it only shows one column and one site I'm not sure how to get the '4 Digit Count' column to show up and the rest of the sites. below are the results I get so far.

SiteIdx 3 Digit Count
------- -------------
1 2

any help would be great.
Thanks
Mike