Find Data Within 10m Distance Of Coordinates?
Nov 22, 2013
I am trying to write a piece of SQL which gives me a list of enquiries within 10 metre distance of a enquiry.
The idea is to identify possible duplicates.
Table: enquiry
Primary key: enquiry_number
Co-ordinates data fields: enquiry.enquiry_easting and enquiry.enquiry_northing.
I will need to self-search on the same table to find possible enquiries within 10m distance.
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Sep 20, 2006
I am working on a program in VB 2005 in which i want to store and retrieve GPS coordinates. I am not sure which data type is the best to use to enter Latitude & Longitude numbers and maintain their proper integrity.
Like LAT ( N38 28.025' ) and LONG (W105 52.098' )
The numbers will be entered by the user and that format can be maintained, but how to re-enter & or insert them into the database using the same format is my real question.
I hope I have explained this right. The numbers in BOLD are what I need to maintain.
Thanks for any help in advance.
Steve
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Apr 29, 2015
I have the two following locations.
They're both towns in Australia , State of Victoria
Fitzroy,-37.798701, 144.978687
Footscray,-37.799736, 144.899734
After running geography::Point(Latitude, Longitude , 4326) on the latitude and longitude provided for each location, my Geography column for each row is populated with the following:
Fitzroy, 0xE6100000010C292499D53BE642C0A7406667511F6240
Footscray, 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240
In my SQL Query, I have the following which works out the distance between both towns. Geo being my Geography column
DECLARE @s geography = 0xE6100000010C292499D53BE642C0A7406667511F6240 -- Fitzroy
DECLARE @t geography = 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240 -- Footscray
SELECT @s.STDistance(@t)
The result I get is
6954.44911927616
I then looked at formatting this as in Australia we go by KM so after some searching I found two solutions one for Miles and the other KM
So I changed Select statement to look like this
select @s.STDistance(@t)/1000 -- format to KM
My result is then
6.95444911927616
When I go to google maps and do a direction request between the locations provided above it says 10.2km (depending on traffic)
Now I'm new to this spatial data within SQL, why would I get a different result from google maps?
Also I would like to round this number so its easier to use within my where statement so I'm using Ceiling as shown here:
SELECT CEILING(@s.STDistance(@t)/1000)
Is ceiling the correct way to go?
Reason I need to round this is because we are allowing the end user to search by radius so if they pass in 50km I will then say
Where CEILING(@s.STDistance(@t)/1000) < 50
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Jul 20, 2005
Hi All,I've been struggling with how best to define a query to get a list of uniquecoordinates from a database table and my SQL skills are not good enough towork out a good solution. The basic table structure is as follows:CREATE TABLE [Readings Data Table] (CY DOUBLE,PY DOUBLE,C1X DOUBLE, C2X DOUBLE,P1X DOUBLE, P2X DOUBLE)Each record in the table represents a geophysical measurement for a sensorsat the four locations (P1X,PY), (P2X,PY), (C1X,CY) and (C2X,CY). There canbe many repeat readings (ie with the same locations) and many overlappedreadings (ie which share at least one sensor location) and an example set ofdata is:CY PY C1X C2X P1X P2X0 0 0 100 200 3000 0 0 100 200 3000 0 0 100 300 4000 0 0 100 400 5000 0 100 200 300 4000 0 100 200 500 600100 0 0 100 200 300The distinct locations for this set are:(0,0), (100,0), (200,0), (300,0), (400,0) (500,0), (600,0), (0,100),(100,100), (200,100) and (300,100) ie there are 11 unique locations out ofthe 28 (=7*4) sensor measurement locations.My problem is to create a table with a list of just the distinct sensorlocations. I have implemented a brute-force method where I build a table bylooping through each of the four coordinate combinations to create allpossible locations and then getting just the distinct locations, but this isquite slow with even just a moderate number of readings. Can anyone suggesta more efficient way to get the distinct sensor locations using SQL?Many thanksJohn Paine
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Jan 21, 2004
Hi
How do I get a nearest distance of a point? For example, I have two tables A and B and I want to find the nearest distance between the records of the two tables. In addition, one of the tables should also give me the distance. The data I have geo spatial data. Can this be done in SQL
Help will be appreciated
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Mar 1, 2007
Is there a recommended practice for mirroring in regards to distance? Is it best practice to mirror with both nodes at the same physical location and use another method for failing over to a remote location or can one just put the other node in the mirror a few thousand miles away? I'm suspecting not.
Any comments??
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Mar 18, 2008
Hi,
please, it is possible to know the edit distance used in the fuzzy lookup/grouping.
On this forum I read fuzzy lookup use 4-gram with fix size.
Does exist any document explaining how fuzzy lookup calculate the similarity? In other word, what kind of edit distance, algorithm is used by fuzzy lookup/grouping?
I hope I was enough clear with my poor english.
Thanks All
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Mar 28, 2007
I'm trying to run a dyncamic query that returns all records within a specific distance of a certain point. The longitude and latitude of each record is stored in the database. The query is constructed from two dynamic variables $StartLatitude and $StartLongitude with represent the starting point.
SELECT UserID, ACOS(SIN($StartLatitude * PI() / 180) * SIN(Latitude * PI() / 180) + COS($StartLatitude * PI() / 180) * COS(Latitude * PI() / 180) * COS(($StartLongitude - Longitude) * PI() / 180)) * 180 / PI() * 60 * 1.1515 AS Distance
FROM HPN_Painters
HAVING (Distance <= 150)
It runs fine until I add the 'HAVING (Distance <= 150)' clause, in which I recieve the error: Invalid column name 'Distance' It seems that Distance cannot be referenced in the HAVING clause.
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Jul 23, 2005
I'm looking to find out how I'd go about setting up a database where avisitor to my site could punch in their postal code, and find out how farthey are from another postal code. For example, AutoTrader has this featureI believe to tell you how far the vehicle is from you. Dating sites havethem so you can do proximity searches.Anyone have any ideas where I could start? I'm thinking the post office,but if anyone else has suggestions, I'm open to hear them.Thanks!
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Mar 20, 2007
Various posts have noted that mirroring over distance is not advisable or that either async connections should be used.
Are there any limits/recommendations i.e. if two datacenters are a couple of files part with 10GBs fibre links and <50ms response times would this be acceptable for high-availability mirroring?
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Mar 27, 2007
I am new to data mining so please excuse my ignorance. Lets assume
- i have created a cluser model
- identified 3 clusters ( a, b, c)
- each record consists of 15 columns
- collecting new records( 15 variables) real time
what i would like to do is plot these new records programmatically as i collect them realtime. I assume this new record will belong to one of these three clusters. I believe we can find the cluster this new record belongs to by ' SELECT Cluster()....' and distance from the center of the cluster by ClusterDistance(). To plot this on a 2-dimentional space i need (x, y).
ClusterDistance() could be Y but what will be X.
thanks.
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Jan 12, 2008
I have a user defined function, I want to determine the distance between the 2 points. I have it working but i'm having a problem getting to print.
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Code Snippetcreate function dbo.Distance( @lat1 float , @long1 float , @lat2 float , @long2 float)
returns float
as
begin
declare @DegToRad as float
declare @Ans as float
declare @Miles as float
set @DegToRad = 57.29577951
set @Ans = 0
set @Miles = 0
if @lat1 is null or @lat1 = 0 or @long1 is null or @long1 = 0 or @lat2 is
null or @lat2 = 0 or @long2 is null or @long2 = 0
begin
return ( @Miles )
end
set @Ans = SIN(@lat1 / @DegToRad) * SIN(@lat2 / @DegToRad) + COS(@lat1 / @DegToRad ) * COS( @lat2 / @DegToRad ) * COS(ABS(@long2 - @long1 )/@DegToRad)
set @Miles = 3959 * ATAN(SQRT(1 - SQUARE(@Ans)) / @Ans)
set @Miles = CEILING(@Miles)
return ( @Miles )
end
DECLARE @RC float
EXEC Distance '39.943762', '-78.122265', '32.334709', '-96.633546'
PRINT @RC /* in miles */
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Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
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Oct 15, 2015
DECLARE @Latitude NUMERIC(9, 6), @Longitude NUMERIC(9, 6)
DECLARE @MyLatitude NUMERIC(9, 6), @MyLongitude NUMERIC(9, 6)
Set @Latitude = 42.329596;
Set @Longitude = -83.709286;
Set @MyLatitude = 42.430883;
Set @MyLongitude = -82.923642;
Question: How do we calculate the distance in miles between the 2 points.
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Jun 24, 2005
See here www.merriampark.com/ld.htm for information about the algorithm. This page has a link (http://www.merriampark.com/ldtsql.htm) to a T-SQL implementation by Joseph Gama: unfortunately, that function doesn't work. There is a debugged version in the also-referenced package of TSQL functions (http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=502&lngWId=5), but this still has the fundamental problem that it only works on pairs of strings up to 49 characters.
CREATE FUNCTION edit_distance(@s1 nvarchar(3999), @s2 nvarchar(3999))
RETURNS int
AS
BEGIN
DECLARE @s1_len int, @s2_len int, @i int, @j int, @s1_char nchar, @c int, @c_temp int,
@cv0 varbinary(8000), @cv1 varbinary(8000)
SELECT @s1_len = LEN(@s1), @s2_len = LEN(@s2), @cv1 = 0x0000, @j = 1, @i = 1, @c = 0
WHILE @j <= @s2_len
SELECT @cv1 = @cv1 + CAST(@j AS binary(2)), @j = @j + 1
WHILE @i <= @s1_len
BEGIN
SELECT @s1_char = SUBSTRING(@s1, @i, 1), @c = @i, @cv0 = CAST(@i AS binary(2)), @j = 1
WHILE @j <= @s2_len
BEGIN
SET @c = @c + 1
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j-1, 2) AS int) +
CASE WHEN @s1_char = SUBSTRING(@s2, @j, 1) THEN 0 ELSE 1 END
IF @c > @c_temp SET @c = @c_temp
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j+1, 2) AS int)+1
IF @c > @c_temp SET @c = @c_temp
SELECT @cv0 = @cv0 + CAST(@c AS binary(2)), @j = @j + 1
END
SELECT @cv1 = @cv0, @i = @i + 1
END
RETURN @c
END
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Jul 20, 2005
I am trying to use the haversine function to find the distance betweentwo points on a sphere, specifically two zip codes in my database. I'mneither horribly familiar with SQL syntax nor math equations :), so Iwas hoping I could get some help. Below is what I'm using and it is,as best as I can figure, the correct formula. It is not however,giving me correct results. Some are close, others don't seem right atall. Any ideas?SET @lat1 = RADIANS(@lat1)SET @log1 = RADIANS(@log1)SET @lat2 = RADIANS(@lat2)SET @log2 = RADIANS(@log2)SET @Dlat = ABS(@lat2 - @lat1)SET @Dlog = ABS(@log2 - @log1)SET @R = 3956 /*Approximate radius of earth in miles*/SET @A = SQUARE(SIN(@Dlat/2)) + COS(@lat1) * COS(@lat2) *SQUARE(SIN(@Dlog/2))SET @C = 2 * ATN2(SQRT(@A), SQRT(1 - @A))/*SET @C = 2 * ASIN(min(SQRT(@A))) Alternative calculation*/SET @distance = @R * @Cthnx,cjrsumner
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Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
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Feb 1, 2007
hi everyone:
the report show two tables two matrixs
how can i control the distance between them
I want to set the same distance between the table and matrix
or (table and table )
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Jan 2, 2008
Could I implement a failover cluster solution on the two DBs which are based in two different cities?
Possible?
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Jun 14, 2006
I need to be able to take the latitude and logitude of two locations and compare then to determine the number of miles between each point. It doesn't need to account for elevation, but assumes a flat plane with lat and long.
Does anyone have any algorithms in T-SQL to do this?
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Mar 11, 2014
Given the following example;
declare @CustIfno table (AccountNumber int, StoreID int, Distance decimal(14,10))
insert into @CustIfno values ('1','44','2.145223'),('1','45','4.567834'),
('1','46','8.4325654'),('2','44','7.8754345'),('2','45','1.54654323'),
('2','46','11.5436543'), ('3','44','9.145223'),('3','45','8.567834'),
('3','46','17.4325654'),('4','44','7.8754345'),('4','45','1.54654323'),
('4','46','11.5436543')
How can I show the shortest Distance by AccountID and StoreID. Results would look like this;
AccountNumberStoreID Distance
1 44 2.1452230000
2 45 1.5465432300
3 45 8.5678340000
4 45 1.5465432300
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Mar 28, 2007
This function computes the great circle distance in Kilometers using the Haversine formula distance calculation.
If you want it in miles, change the average radius of Earth to miles in the function.
create function dbo.F_GREAT_CIRCLE_DISTANCE
(
@Latitude1 float,
@Longitude1 float,
@Latitude2 float,
@Longitude2 float
)
returns float
as
/*
fUNCTION: F_GREAT_CIRCLE_DISTANCE
Computes the Great Circle distance in kilometers
between two points on the Earth using the
Haversine formula distance calculation.
Input Parameters:
@Longitude1 - Longitude in degrees of point 1
@Latitude1 - Latitude in degrees of point 1
@Longitude2 - Longitude in degrees of point 2
@Latitude2 - Latitude in degrees of point 2
*/
begin
declare @radius float
declare @lon1 float
declare @lon2 float
declare @lat1 float
declare @lat2 float
declare @a float
declare @distance float
-- Sets average radius of Earth in Kilometers
set @radius = 6371.0E
-- Convert degrees to radians
set @lon1 = radians( @Longitude1 )
set @lon2 = radians( @Longitude2 )
set @lat1 = radians( @Latitude1 )
set @lat2 = radians( @Latitude2 )
set @a = sqrt(square(sin((@lat2-@lat1)/2.0E)) +
(cos(@lat1) * cos(@lat2) * square(sin((@lon2-@lon1)/2.0E))) )
set @distance =
@radius * ( 2.0E *asin(case when 1.0E < @a then 1.0E else @a end ))
return @distance
end
Edit: corrected spelling
CODO ERGO SUM
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Apr 28, 2008
Hi All,
Does anyone have a Stored Procedure that works perfectly to retrieve all zipcodes within a specified zipcode and distance radius - a zipcode and radius is passed and the Store Procedure result shows all zipcodes that falls within that range.
Thanks in advance
Ade
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Nov 19, 2014
I've got a working query which returns all leads within a supplied proximity to a city. I followed a tutorial I googled a couple months ago (can't find it now). It works, but would love others to look the query over (provided DDL and sample data) and tell me if it's as it should be.
Two things I don't like about query:
1. I have to do a UNION to another query that retrieves everything that is in the same city in order to have complete results.
2. very slow to retrieve results (> 1 minute)
Sample DDL: 2 tables
create table dim_lead
(
date_created datetime,
[contact_first_name] varchar(20),
[contact_last_name] varchar(20),
lead_id int,
[Code] .....
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Oct 4, 2007
Hi all,
It looks like these options are only available in the SQL Server Management Studio? I installed SQL Server Management Express Studio and I can't even find the DTSWizard.exe on my machine.
Can you please help how I can import data from excel or where can I download the SQL Server Management Studio?
Your prompt response is greatly appreciated.
Thanks!!
Tram
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Jun 18, 2007
Hi ALL
Just wondering is there an easy way to search every table and every column for a specific piece of data in sql 2000?
Any ideas would be appreciated
Cheers
Phil
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Sep 26, 2003
Hi,
I wanted to find the location in database objects(table/stored proc/view/function) for particular text.
For example a text 'BU1032' is located in tiles and titleathor table at PUBS databse.
I wanted get the result like
text_name filed_name table_name
--------- --------- ---------
BU1032 title_id titles
BU1032 title_id titleauthor
if we are using in stored proc/view for comparison that should be display
like
text_name storedproc_name
-------- ---------------
BU1032
Anybody has script for this kind of search?.
Thanks,
Ravi
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May 30, 2008
What I would like to do, is loop through a table, extract two fields from each record, and pass the values of those fields to a stored proc. I found some help on using cursors to do this, but can I use two cursors at the same time? Below is what I would like to do:
DECLARE @cursorPhone CURSOR, @cursorName cursor, @phone VARCHAR(30), @UserName varchar(50)
SET @cursorPhone = CURSOR
FOR
SELECT userPhone FROM dbo.RPM_Data
OPEN @cursorPhone
FETCH NEXT FROM @cursorPhone INTO @Phone
SET @cursorName = CURSOR
FOR
SELECT userName FROM dbo.RPM_Data
OPEN @cursorName
FETCH NEXT FROM @cursorName INTO @UserName
WHILE @@FETCH_STATUS = 0
BEGIN
EXEC sp_Subscription_Individual @phone, @UserName
FETCH NEXT FROM @cursorPhone INTO @phone
FETCH NEXT FROM @cursorName INTO @Username
END
DEALLOCATE @cursorPhone
DEALLOCATE @cursorName
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Apr 17, 2015
is it possible to find out all the data about the table so I need Table columns, type etc.
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Jun 7, 2007
how to find data mining 's example from sql2005
how to apply data mining in project
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Oct 15, 2007
Hi,
I use Visual Studio 2005 Pro.
I installed Microsoft SQL Server Compact Edition Developer Software Development Kit .
When i try to make a connection , i can't change the datasource to the compact version.(Not vissible)
What could be the problem.
Sorry for my bad english,
Thx
JoskeXP
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Nov 15, 2007
I got a table in sql server....
i don't know the field name where data is present.
i just want to search and find, where data is present in any field of that table.
How can i do?. I forgot that SQL.
Please help me.
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May 9, 2008
TableName: EmployeeCloumns: EmployeeID EmployeeName If I do "Select * From Employee", is there a way to do something like this...
Loop through each result IterateThroughControls.ID &= dbTable & dbColumnName & "<br />"EndSo that the end result would assign ID values...EmployeeEmployeeIDEmployeeEmployeeName
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