Find Highest Marks In Student Table Query

Oct 9, 2007

Hi Everybody
I've one table named Student. Here is data

Name
Subject
Mraks

Prasad
English
80

Tushar
English
79

Sunil
English
78

Prasad
Geometry
80

Tushar
Geometry
81

Sunil
Geometry
79

Prasad
History
82

Tushar
History
81

Sunil
History
80

Now I want to write a query that displays student with subjects and marks who secured highest marks in each subject.
I want to output like this

Name
Subject
Mraks

Prasad
English
80

Tushar
Geometry
81

Prasad
History
82

So will anybody help me to write a sql query that acheive the same output

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T-SQL (SS2K8) :: Retrieve Subject Wise Highest Marks List In A Table?

Jul 18, 2011

I have a requirement like, we are having two tables in our database.

Table names: student, marklist

Student table values:

id studname
------------------
1x
2y
3z
4a
5b

Marklist table values:

id maths physics English
---------------------------------
1506070
2706040
3508070
45010070
5906070

But my requirement is, I need to display the data "subject wise" highest marks for each student.

for example:

id name highestmark
---------------------------------
1 x English

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Feb 12, 2013

I want to calculate average of grades of each student and get the highest one with SQL command.

I have 2 tables:

Students:
*StudentId
*StudentName
___________
Grades:
*StudentId
*Grade
___________

I need to calculate average of each student and then get the highest.

My try:

Code:
SELECT Students.StudentId,Students.StudentName,AVG(Grades.Grade) AS avg_grade FROM Students s JOIN Grades g ON Grades.StudentId =Students.StudentId
GROUP BY Students.StudentId, Students.StudentName

ORDER BY avg_grade
LIMIT 1 FROM Students;

I encounter problem with this code, maybe it's Completely wrong...

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Aug 4, 2013

I have created a table:

CREATE TABLE [dbo].[Student](
[StudentNumber] [varchar](50) NOT NULL,
[Name] [char](50) NOT NULL,
[Contact] [int] NOT NULL,
[Address] [char](50) NOT NULL,
[DateOfBirth] [datetime] NOT NULL,
[YearEnrolled] [int] NOT NULL,
[Year] [int] NOT NULL;

And insert the following data:

INSERT INTO Student VALUES('IT123456X', 'Ahmad Adam','05-18-1997', '33 Mangis Rod', 19970518, 2013, 1);
INSERT INTO Student VALUES('IT334455U', 'Mary Tan', '01-23-1996', '51 Koon Seng Road', 23-01-1996, 2012, 1);
INSERT INTO Student VALUES('BS123456X', 'Samuel Lee', '03-30-1997', '2 Joo Chiat Lane', 30-03-1997, 2013, 1);
INSERT INTO Student VALUES('BS234234Z', 'Nathaniel Koh', '12-08-1997', '5 Stll Road', 08-12-1997, 2013, 1);
INSERT INTO Student VALUES('BS987987F', 'Siti Faridah', '07-04-1995', '3 Duku Road', 04-07-1995, 2011, 3)

How do i calculate the age and how can i group by the StudentNumber like 'IT%'

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Nov 24, 2013

I have this table of Marks as shown below. All I need is to find the average Marks at various intervals of S.no. That is I need averages at every 3rd S.No. as shown.

S.No. Marks
1 ------ 5
2 ------ 5
3 ------ 6 1st Average Value here (16/3)
4 ------ 5
5 ------ 6
6 ------ 7 2nd Average Value here (18/3)
7 ------ 7
8 ------ 7
9 ------ 8 3rd Average Value here (22/3)
10 ----- 8
11 ----- 9
12 ----- 8 4th Average Value here (26/3)

So basically I need a new table which will have 4 average values for the table above. Of-course the table can be much bigger and the average values can be at any nth value of S.No.

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Sep 15, 2006

I am stumped on a set-based approach for this one.

A cursor approach is straightforward enough, but i want to avoid that.

Here's my table:

create table StudentScores
(
id int primary key identity(1,1),
student_id int not null,
score int not null
)

with some sample data:

insert into StudentScores (student_id, score)
select 1, 10 union all
select 1, 29 union all
select 1, 50 union all
select 1, 53 union all
select 1, 45 union all
select 1, 10 union all
select 1, 29 union all
select 1, 50 union all
select 1, 53 union all
select 1, 45 union all
select 1, 88 union all
select 2, 23 union all
select 2, 54 union all
select 2, 55 union all
select 2, 34 union all
select 2, 56 union all
select 2, 78 union all
select 2, 23 union all
select 2, 54 union all
select 2, 55 union all
select 2, 34 union all
select 2, 56 union all
select 2, 78 union all
select 2, 23 union all
select 2, 54 union all
select 2, 55 union all
select 2, 34 union all
select 2, 56 union all
select 2, 78 union all
select 2, 98

What I want is, for each student, what is their 90th percentile score?

For a given single student, one possibility would be:

declare @studentid int
set @studentid = 2
select top 1 @studentid as student_id, a.score as [90th percentile score]
from
(
select top 90 percent score from StudentScores
where student_id = @studentid order by score asc
) as a
order by a.score desc

But I want this for all students, and not use a cursor.

Any ideas?

Thanks!

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-- First Cursor

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DYNAMIC

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The above code seems totally inefficient but it gives the correct result. Now I want to pull some more value and join a third table (TABLE z) in the above CURSORS and not sure how to make it working using CURSORS.I would like to use the following in the CURSORS above.

SELECT x.publishdate, y.firstname, y.lastname, y.age, z.initialValue AS FirstValue, z.HighestValue AS Highest, z.LastValue AS Last
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Job B: Rate $15.00

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FROM OPENROWSET('MSDASQL',
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Im using SQL 2000

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