Hi Guys,
Can anyone please let me know How to find the first day of the week, if I know the weekno and the year.
For ex: If I know the week no is 22 and Year is 2003 then I should find a way to output the date. which is the first day (monday) of that week
for the above query the date will be eg:26/06/2003
I really appreciate your Help
Thanks:confused: Find the Date if I know the week and year
Hi,
I have a Serial No which has a length as 14.For eg IL010730123456. IL01 is The Default Code. 07 is the current year and 30 is the week of the year. 123456 is Serial. How shoud I find The Year and week with the help of this serial no ie The First day of the 30th week of 2007.Is it Possible?
Plz Help me with an appropriate solution.
Thanks.....
i have this SQL table with a year, week and day-of-week field, but no field containing the actual date
is there a way (e.g. in a view of the SQL table) to transform the year/week/day combination into a date string (e.g. format dd/mm/yyyy) ?
Can I get a date from a week number in a certain year, like I know it's week 7 in 2014 (I may know the month.)
View 7 Replies View RelatedIn my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedFunction F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
I've written sql code which takes a date and finds the Last Day of the Month one year ago. For example, it takes the date '2015-04-17' and returns the date '2014-04-30'. The code works fine in a query. Now I'm trying to turn this into a function. However, when I try to create the function I get the error:
Operand type clash: date is incompatible with int
Why is this error being returned?
Here is my function:
CREATE FUNCTION dbo.zEOM_LY_D(@Input Date)
RETURNS date
AS
BEGIN;
DECLARE @Result date;
SET @Result = convert(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,dateadd(m, -11, @Input)+1),0)),101)
RETURN @Result;
END;
Hi every one,
I have a database table and currently users may retrieve records for a specified date range by providing the start and end dates and then records between those dates provided are retrieved. For example if users wanted to view all records entered in april, they would have to select 04/01/2007 as the start date and then 04/30/2007 as the end date. The records for april would then be displayed in a gridview.
How can configure my sql query such that instead the user selectes a month from a dropdownlist of 12 months. I would love a user to just select the desired month from a list instead of selecting start and end dates. Eg if they are intrested in a report for june, then they should just select june from the list instead of specifying the start and stop dates. HOW can i achieve this.
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
We have customers who are new to this year (2014) and there same customers in last year (2013). also there are customers we have not received business this year but only last year. so there are 4 conditions.
1) New customer (2014) - Customer(B)
2) Old Regular customer (2013 and 2014) - Customer(A)
3) Last Year (Lost) customer (2013) - Customer(C), no business received in year(2014)
For example we have a transaction table:
TransactionId, ReceivedDate, Customer
1, 2-Dec-2013, A
2, 3-Jan-2014, A
3, 2-Mar-2014, B
4, 25-Nov-2013, C
I want results like
Customer, Business (this year activity/last year activity)
A, 1/1
B, 1/0
C, 0/1
How can i show this for each year? I used to separate it month wise as below but it does not return applying year with each customer anyhow...
select t.customerId, YEAR(Receiveddate),
sum(case month(ReceivedDate) when 1 then 1 else 0 end )as Jan,
sum(case month(ReceivedDate) when 2 then 1 else 0 end )as Feb,
sum(case month(ReceivedDate) when 3 then 1 else 0 end )as Mar,
sum(case month(ReceivedDate) when 4 then 1 else 0 end )as Apr,
[Code] ....
How to define week of the year in sql? e.g. i want to search all the transcations in week 2, how can i do it?
View 2 Replies View RelatedThis function returns the ISO 8601 week of the year for the date passed. The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day of each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_WEEK_OF_YEAR
go
create function dbo.F_ISO_WEEK_OF_YEAR
(
@Datedatetime
)
returnsint
as
/*
Function F_ISO_WEEK_OF_YEAR returns the
ISO 8601 week of the year for the date passed.
*/
begin
declare @WeekOfYearint
select
-- Compute week of year as (days since start of year/7)+1
-- Division by 7 gives whole weeks since start of year.
-- Adding 1 starts week number at 1, instead of zero.
@WeekOfYear =
(datediff(dd,
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end,@date)/7)+1
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aa
) a
return @WeekOfYear
end
go
-- Execute function on first day of first week of year from 1990 to 2030
select
DT,
ISO_WEEK_OF_YEAR =
dbo.F_ISO_WEEK_OF_YEAR(a.DT)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
CODO ERGO SUM
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
My boss would like to see one report with parameter promts. I tried doing this, but I keep getting an error. Can someone help me out here?
Thanks.
WHERE
(@YEAR(CLM_Dout) = YEAR(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND MONTH(CLM_DOUT) = MONTH(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND DATEPART(wk, CLM_DOUT) = DATEPART(wk, GETDATE()))
I am trying to group counts by week,month,quarter, year for a particular activity type and I'm having issues.Here's my code so far:
SELECT
distinct
EmailAddressID,
emailaddress,
SUM(CASE WHEN [ActivityDate] >= DATEADD(WEEK, DATEDIFF(WEEK, 0, @DT), 0)
THEN
SUM(CASE WHEN EmailActivityType = 'OPEN' THEN 1 ELSE 0 END) END AS WeekTotalOpens
FROM EmailActivity
WHERE DATEPART(YEAR, [ActivityDate]) = DATEPART(YEAR, @DT)
GROUP BY EmailAddressID,emailaddress
Desired Output:
EmailAddressId EmailAddress WeekTotalOpens MonthTotalOpens etc. then WeekTotalClicks and so on....
SQL doesn't seem to like the sub-aggregate. What is the best way to approach?
I have to insert YEAR WEEKNUMBER STARTDATE ENDDATE values to a datatable (sayweekrange), if I pass 2011 as year.
Week range starts at 2011-03-28 to 2011-04-03 (because in my database 2010 last week range ends with 2011-03-27) like this I have to generate for 52 weeks.
I want to write a stored procedure, that takes only year as parameter. with this year I have to generate week ranges and insert into my table as shown above.
How can I do this ?
I have three web form controls, a ddl that contains the day, another ddl that contains the month and a textbox that contains the current year. To send the date chosen by the user to the database, I join the three web form control values so that the resultant string is ‘day/month/year’ thus:
CmdInsert.Parameters("@Date").Value = day.SelectedItem.Value + "/" + month.SelectedItem.Value + "/" + year.Text()
And the resultant string is: dd/mm/yyyy, for example 30/08/2004.
But the problem is if the user does not select any day or any day and month, then the resultant string is for example; 00/08/2004 or 00/00/2004, but the problem is the database does not accept this format as datetime. How can I do it?
I want the user has the possibility to chose as well only the month and year, and as well only the year. Is it possible to send to the database the datetime format with only the month and year, or only the year?
Thank you,
Cesar
seriously now
View 1 Replies View RelatedI need developing a query to get the average count by the following:
Day - use daily info for the last ??? days
Weekly - average
- Add all days and divide by 7
- As of Saturday midnight
Monthly - average
- Add all days and divide by days in the month
- As of last save on last day of month
Quarter - average
- Add all days and divide by number of days in the quarter
- As of last day of quarter
Year - average
I don't have requirements for year as of yet.
How can I get the avery count per these timeframes?
I need to build a report that compares a count on a certain day of the week by month by year by stacks. That is,for first Monday in October 2012 against first Monday in October 2013 for stack DM1 against first Monday in October 2014 stack DM1, same for second Monday, first Tuesday, second Tuesday, ect. Attached is a sample dataset and what I want to achieve.
View 9 Replies View RelatedSQL express 2012. I am trying to case in the where part and having a syntax errors - This is what i am trying to do:
select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ....
SQL express 2012
I am trying to case in the where part and having a syntax errors - this is what i am trying to do:
Select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ...
Does anyone have an example of an SQL query which returns rows for theyear-to-date, but where the "year" commences on August 1st?e.g. select * from mytable where datefield > last august 1stTIA for any helpIsabel
View 2 Replies View RelatedI have a table where hours are being loaded in a weekly basis. The YearWeek is populated when the data is loaded. The value format of the Year Week is 2015-39, 2015-41, etc. I need to calculate the total hours per Fiscal Year.For example, week '2015-39' will be return FY15 and week '2015-41' will return FY16, and so on. By extracting the year, I can do a group by and have total hours for each year.
Currently, I have it working by splitting the value into year and week and then looping through each year and week, so I can assign the totals to the corresponding FY.select sum(hours) as total, yearweek from tablename group by yearweek...Then I loop through using C#.I can return the FY using an actual date,how to do it for year-week format for any given year.
select CASE
WHEN CAST(GETDATE() AS DATE) >
SMALLDATETIMEFROMPARTS(DATEPART(YEAR,GETDATE()),09,30,00,000)
THEN
DATEPART(YEAR,GETDATE()) + 1 ELSE DATEPART(YEAR,GETDATE())
END AS FY
Greetings All,
I have a SQL question that maybe someone out there can help me with. Our fiscal year starts on 01/27. I want to write a query that I can pass a date to and it will return the week number (DATEPART("ww", someDate)) of the year using the Fiscal Year Start Date as the base. Datepart works great except it figures the first day of the year as 1/1. Does anyone know how I can make it work with a first day of the year equal to the fiscal year date 01/27. Any help would be appreciated.
TIA,
~ck
Please provide a function or logic to find week of month..
View 1 Replies View RelatedHello All,
i have three textboxes in a page and i want fill those textboxes with the date, month,year respectively.....
i have a datecreated column in discount table in a mm/dd/yy format ...how to extract the date, month, year from this format and put the value in textboxes..?
Any help..
Thanks..
Anne
I have a list of students who have taken a test on different dates.
I need a function to calculate year ago date from the date of test.
eg Sam took the test on feb 23 2015
I need to get a feb 23 2014 to see what subjects he studied from feb 23 2014 to feb 23 2015.
How can I do that.
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
I'm wanting to see if there is a simpler way to accomplish the retrival of the first day of the week Date. What I currently have is:
CASE
WHEN DATEPART(DW, GETDATE()) = 1 THEN DATEADD([D], - 7, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 2 THEN DATEADD([D], - 8, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 3 THEN DATEADD([D], - 9, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 4 THEN DATEADD([D], - 10, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 5 THEN DATEADD([D], - 11, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 6 THEN DATEADD([D], - 12, GETDATE())
WHEN DATEPART(DW, GETDATE()) = 7 THEN DATEADD([D], - 13, GETDATE()) END AS StartWeek1
I'm trying to figure if there might be an easier way to code this. Thanks.
Hi,
How would it be possible to calculate the next date of a given week day.
So if today is 6th April 2008 find the date of the next wednesday (i.e. the up and coming wednesday) of the next saturday etc.
You help is appreciated.
Cheers
--find day,month,year
--for day select datediff(d,'01 may 2008',getdate())
-- --for month select datediff(m,'01 jun 2006',getdate())
-- --for year select datediff(year,'01 jun 2006',getdate())
above working fine but suppose difference is 1 year 4 month and 2 month 15 days then It's giving 1 year and 2 month respectively.
but I want completely so I can use this in case of expired user in my project.
User can be expired in 1 month,3 month and 1 year. So I'm not able to recognize.
thanks
Hey, Im pretty sure this is possible, but let me know if it isnt.I have a table of dates in the format "DD/MM/YYYY", is there a way of converting it to output the day of the week? for example 16/11/2007 would display Friday insted.Thanks in advance John
View 3 Replies View Related