Finding "missing" Records

Mar 7, 2001

Hi,

OK, here's a question for all you SQL Gurus.

I want to find all the records that are in t2 but are not in t1.
(NOTE: table print outs at bottom of post)

I could write this:
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~``
select t2.t from t2 where t not in (select t from t1)
t
-----------
6

(1 row(s) affected)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~``

BUT it takes to long.

So I thought of this:
select t2.t , t1.t from t2 left join t1 on t2.t = t1.t where t1.t = null

BUT it doesn't work.

WHY NOT?
Is there anything similar that i can write???

It should work, heres the output for the simple left join:

select t2.t , t1.t from t2 left join t1 on t2.t = t1.t
t t
----------- -----------
1 1
2 2
3 3
4 4
5 5
6 NULL
7 7

(7 row(s) affected)



Thanks,
Benny Hill

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~``
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ ~~~~~~``



select * from t1
t
-----------
1
2
3
4
5
7

(6 row(s) affected)



select * from t2
t
-----------
1
2
3
4
5
6
7

(7 row(s) affected)

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