Finding The Character Position Of Nth Occurence In A String.

Hi Friends:

I usually run this query in Oracle to find out the position of a character in a string from first position to the nth occurence.

For example, I run the following queries in oracle to get the desire result.

SQL> select instr('DADADAQQQA','A',1,1) FROM DUAL;

INSTR('DADADAQQQA','A',1,1) -- First occurence of 'A' from start.
---------------------------
2

SQL> select instr('DADADAQQQA','A',1,2) FROM DUAL;

INSTR('DADADAQQQA','A',1,2) -- Second occurence of 'A' from start.
---------------------------
4

SQL> select instr('DADADAQQQA','A',1,3) FROM DUAL;

INSTR('DADADAQQQA','A',1,3) -- Third occurence of 'A' from start.
---------------------------
6

SQL> select instr('DADADAQQQA','A',1,4) FROM DUAL;

INSTR('DADADAQQQA','A',1,4) -- Forth occurence of 'A' from start.
---------------------------
10


Is there ay equivelant way in Transact- SQL? If not, can anybody suggest the solution?


--Raj