Formatting Numeric Value In Computed Column

Jan 12, 2008

Hi there --

I'm writing a SQL query that works something like this:

SELECT a, b, a/b AS col_name FROM TABLE

Dividing a by b can result in a value above or below 1, e.g. 1.234 or 0.123.

If the value is below 1, I don't want the preceding zero, e.g. .123.

I've been using a STR() function to format it to three decimal points, e.g.:

STR(a/b, 5, 3) AS col_name

.... but for values below 1 it'll look like 0.123.

Any suggestions for how I can make this look like .123?

Thanks in advance.

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scott writes "I am relatively new to SQL Server, but after a couple of hours searching help, I'm stuck.

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Is there a better way?

SELECT
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Hi,

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Thanks

Stored Procedure
================================================== ==============
ALTER PROCEDURE [Purchasing].[ntp_PurchaseOrderDetail_Insert]
(
@PurchaseOrderDetailId int OUTPUT,
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(
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,[UnitPrice]
,[PackingMethod]
,[PackingQty]
,[DueDateValue]
,[ModifiedDate]
,[IsUnitPriceManual]
)
VALUES
(
@PurchaseOrderId
,@OrderQty
,@VendorVendorProductId
,@Description
,@UnitPrice
,@PackingMethod
,@PackingQty
,@DueDateValue
,@ModifiedDate
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)

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SELECT
@LineTotal = [LineTotal]
FROM
[Purchasing].[PurchaseOrderDetail]
WHERE
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Computed Column Formula
================================================== ==============
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or
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Profiler Trace
================================================== ==============
declare @p1 int
set @p1=115
declare @p16 numeric(29,0) <- should be numeric(29,6)
set @p16=5 <- value should be 5.259200
exec Purchasing.PurchaseOrderDetail_Insert @PurchaseOrderDetailId=@p1 output,@PurchaseOrderId=68,@OrderQty=4,@VendorProd uctId=28,@Description=N'93678975 - GL-2222',@UnitPrice=0.657400,@PackingMethod=N'Bags (2)',@PackingQty=2.0000,@DueDateValue=NULL,@Modifi edDate=''2008-05-19 15:06:37:610'',@LineTotal=@p16 output
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hi
i want to create a table that has a computed column like this :
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hi
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Code Snippetcreate table resources(id int identity(0,1) primary key,currentDate int not null,currentMonth int default 0,monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))

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Code Block
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Sep 25, 2007



Hello everybody!

I have question about indexed and not indexed Persisted columns on sql server 2005. It's a bug?

First?, my version of SQL Server is
Microsoft SQL Server 2005 - 9.00.3186.00 (Intel X86) Aug 11 2007 03:13:58 Copyright (c) 1988-2005 Microsoft Corporation Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 2)


Now I create two tables and try four select queries:


Code Snippet
SET ANSI_NULLS ON
SET ANSI_PADDING ON
SET ANSI_WARNINGS ON
SET ARITHABORT ON
SET CONCAT_NULL_YIELDS_NULL ON
SET NUMERIC_ROUNDABORT OFF
SET QUOTED_IDENTIFIER ON
GO
create table t1 (id int primary key, id_bigint as cast(id as bigint))
GO
create table t2 (id int primary key, id_bigint as cast(id as bigint) persisted)
GO
select * from t1 -- (1)
-- Clustered index scan with two times Compute Scalar
GO
select * from t2 -- (2)
-- Clustered index scan with one times Compute Scalar
GO
create index IX_t2 on t2 (id_bigint)
GO
select * from t2 -- (3)
-- Index Scan with one times Compute Scalar
GO
select * from t2 where id_bigint = 0 -- (4)
-- Index Seek with one times Compute Scalar
GO
drop table t1
GO
drop table t2
GO
SET ANSI_PADDING OFF



1. I don't understand why access to computed column raise scalar computation wto times?
2. I don't understand why access to persisted computed column raise any scalar computation?
3. I don't understand why access to persisted computed column over index required any scalar computations?

Can anyone from Microsoft SQL Server Team told me about this mistake?
It's a BUG or I incorrect understand value of the "PERSISTED" word?


--
Thanks with avanced.
WBR, Roman S. Golubin
grominc[at]gmail.com

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ACCOUNT ¦(calculated column)

------------------------------

100 ¦alpha

100 ¦NULL



My concern is how should I remove record with NULL from final resultset ?

If I give some name to that calculated column say 'Name'

and tried to put in main query as

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Hi
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-----------
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|2 |def
|3 |erw
|4 |rwg
|5 |her


Table-2 "T2"
----------
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Result
----------
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|1 |abc |12
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|3 |erw |10

I tried:

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However following works:
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BUT IS IT OPTIMIZED?
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