Formula For Computed Column
Jan 17, 2007
I have downloaded the SQL Server Books online and found the section on Computed columns. In my small banking program I have columns named Deposit/Withdrawel and Balance. If I am reading this right I need to set the Computed Column Specification of my Balance Column in order to perform the calculation. My problem now is that I have no idea how to word the formula and other than telling me what a formula is the SQL Server Books online is no help whatsoever, so any help would be awesome.
If i've misunderstood what I am meant to do somebody please please tell me. Thanks
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Aug 1, 2006
Is it possible to retrieve the formula associated with a computed column using t-SQL? I can use COLUMNPROPERTY( id, column, 'IsComputed') to find the computed columns, but how do I get the formula itself?
Thanks,
Mable
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May 25, 2011
I'm trying to write a query that will display the formula for a computed column in SQL Server 2008R2.
I have looked here: [URL] ....
and it say (at least I think) that I can look at the Formula property of COLUMNPROPERTY like this:
SELECT COLUMN_NAME ,
COLUMNPROPERTY(OBJECT_ID(TABLE_NAME),COLUMN_NAME,'IsComputed'),
COLUMNPROPERTY(OBJECT_ID(TABLE_NAME),COLUMN_NAME,'Formula'),
COLUMNPROPERTY(OBJECT_ID(TABLE_NAME),COLUMN_NAME,'IsDeterministic')
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = 'Event' AND COLUMN_NAME = 'CurrentAttendance'
I know the column is computed and I can see the formula in SSMS. I wanted to do this in T-SQL. How to get this value?
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Sep 13, 2007
I want to create a computed column with this formula:
ISNULL(NULLIF (tot_mnc, 0) / NULLIF (repl_value, 0), 0)
It works in a straight select query, but when I put it in the formula of the table design window, I get an error "Error validating the formula for column 'test_fci'"
I don't know if it's relevant but repl_value is itself a computed column with the formula:
(repl_value_e_g + repl_value_aux)
Is it possible to use the system functions in a computed column? If not, how would I pass those values into a udf and use it for the formula?
Thanks.
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Jun 16, 2015
I'm trying to replicate client data from multiple databases into a single table. So database A, B and C replicate client data to a table in database Z. There is a settings table on A, B and C that holds the businessID and I use a function in a computed column to add this to the client table. At the moment I have just database A and Z as a test and what happens is the computed column gets replicated as a computed column with the formula.
Can I change this so that I can replicate the computed value (at db A,B,C) of this column?
I don't really want to add a businessID to the table if possible as I'm going to need to add a number of other tables to this replication which will each need to have the businessID, a computed column would be much easier and save updating a load of scripts.
If the above is not possible is there some other solution available so I can identify which database the records came from in the table on database Z?
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Sep 5, 2007
Hi all,
I have a table with 3 computed columns, the first two reference a function for there value. The last computed column should be total of the other computed columns, however when trying to write the formula for this column SQL Server rejects it.
Am i correct in thinking it is not possible to reference other computed columns in a computed column's forumla.
My current work around is to call the functions again that the other computed columns use to generate the total, though this seems to me like a performance issue.
Could anyone offer some advise on my situation.
Any input apreciated.
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Nov 17, 2015
I have a Table Having Date,Opening,Addition,Sale values where opening value comes in the very first row other times it is zero.
In ssrs how can i have a report showing closing value = Opening+Addition-Sale in current row (it is simple for 1st row ). this closing be the opening value in next row and same formula to be continued...
Date Opening AdditionTotalTank saleClosing Stock
01-11-15 14435 0 14435 8243 20627
02-11-15 0 15000 15000 9433
03-11-15 0 9000 9000 9436
04-11-15 0 12000 12000 8392
05-11-15 0 6000 6000 8157
06-11-15 0 12000 12000 8456
07-11-15 0 15000 15000 10903
08-11-15 0 6000 6000 8485
09-11-15 0 6000 6000 9413
10-11-15 0 21000 21000 6413
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Mar 29, 2001
I have a table called test with 4 fields namley studentname, Mark1, Mark2, total (formula column).
Created table test in the following structure,
create table test (studentname varchar(50), Mark1 numeric, Mark2 numeric, total as ([Mark1]+[Mark2]))
Now I need to drop formula nature of this column total and assign default value '0'. I like to know how to do it using T-Sql script.
Thanks for your help in advance.
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Aug 3, 2004
Maybe I am missing something very obvious, but I couldn't do it: begin trangocreate table foo (f1 int not null,f2 int not null,f3 as (f1 + f2) not null primary key clustered)gorollback trango This returns:Server: Msg 8183, Level 16, State 1, Line 8Only UNIQUE or PRIMARY KEY constraints are allowed on computed columns.
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Apr 5, 2008
i have a table that contains 2 columns
A B (B values are only 1 and 2)
-- --
x 1
y 2
z 1
x 2
z 1
j 1
k 2
i want to make a query that will check for dinstinct x what B values it has Ex. It will show result like this
result
A B
-- --
X 1 and 2
Y 2
z 1
K 2
how to make please help
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Feb 16, 2007
I want to create computed column in table.
Suppose I have three physical column A,B and C
I want to create compute column with computed column.
A+B= X
X+C=Z
Is it possible.
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Jul 20, 2005
I created a index on a computed column. I did not see any improvementin performance with a join to this column and also my inserts andupdates to this table are failing. Any ideas?Chender
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May 22, 2008
Hi,
i have to use a datetime field in all the tables in a database as a updated timestamp.
i.e. : whenever an update happens to a row in a table, this column called LASTUPDATED has to be updated with current date time.Is there any way to implement this without using the trigger ?
can i use COMPUTED column to acheive this ?
Please help me..thnks in advance..
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Jul 20, 2005
HI,I have a problem in formula column.I have 8 1 bit varibles in a tablefor ex: Flag1, falg2, flag3 ...Flag8Now I want to create another variable as a small integer and copy allthe flgas to that field.For ex:(flag1 << 0x80) | (flag2 << 0x40) | ..... | flag8I tried all possible ways?Let me know how to write the formula for this column.Thanks,Venkat.
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Jul 20, 2005
Hi,I would like to create a calculated column using the formulasection for a table. I am having some trouble doing this.The table's name is ReportParameter. The calculated column's name istbcalculatedcolumn and tb1 and tb2 are boolean columns in the table.I would like to use an If then statement such as the following (inpsuedo code):If tb1 = 1 then tbcalculatedcolumn = 1Elseif tb2 = 1 then tbcalculatedcolumn = 2EndifThanks for the help,Bill
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Jun 25, 2007
I have a SQL table that maintains a field on the status of a report being completed.
I have in the record the date the report is due (DateDue)
I also have a field called DaysLate which I have set to be a calculated field with formula:
DATEDIFF(dd, DateDue, GETDATE())
Thsi works but when the report is *not* late I'd like this to be null is there I way I can do this conditional calculation in a calculated field?
Regards
Cvive
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Jun 11, 2003
I have a view that has 2 columns. The first column is associated with a function for the Units. The second column calculates the Market Value:
View
====
Col1: Unit = get_number_of_units()
Col2: MV = get_number_of_units() * get_unit_value()
I need to call get_number_of_units() twice in the view. Is it possible to changes Col2 to something like: MV = Col1 * get_unit_value()?
Is get_unit_value() being called if I do Select Col1 from View?
Thanks.
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Feb 27, 2008
somehow I am not able to figure this out.
How do I change a computed column using the ALTER TABLE ALTER COLUMN... command?
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May 19, 2008
Hi,
I'm having a problem with a computed field in a table. I have a stored procedure that inserts a row into a table and returns the id and the computed value.
The computed colmn is returned as a decimal (29,6) but for some reason the value is returned with no decimals (confirmed by the Profiler).
The value is calculated and displayed in the database properly with decimals. Also, Is Persisted is OFF.
Below is the stored procedure, computed column foruma (both give same result), and the profiler trace.
Thanks
Stored Procedure
================================================== ==============
ALTER PROCEDURE [Purchasing].[ntp_PurchaseOrderDetail_Insert]
(
@PurchaseOrderDetailId int OUTPUT,
@PurchaseOrderId int ,
@OrderQty decimal (11, 4) ,
@VendorProductId int ,
@Description nvarchar (255) ,
@UnitPrice decimal (18, 6) ,
@PackingQty decimal (14, 4) ,
@DueDateValue nvarchar (50) ,
@ModifiedDate datetime ,
@IsUnitPriceManual bit ,
@LineTotal decimal (29, 6) OUTPUT
)
AS
INSERT INTO [Purchasing].[PurchaseOrderDetail]
(
[PurchaseOrderID]
,[OrderQty]
,[VendorVendorProductID]
,[Description]
,[UnitPrice]
,[PackingMethod]
,[PackingQty]
,[DueDateValue]
,[ModifiedDate]
,[IsUnitPriceManual]
)
VALUES
(
@PurchaseOrderId
,@OrderQty
,@VendorVendorProductId
,@Description
,@UnitPrice
,@PackingMethod
,@PackingQty
,@DueDateValue
,@ModifiedDate
,@IsUnitPriceManual
)
-- Get the identity value
SET @PurchaseOrderDetailId = SCOPE_IDENTITY()
-- Select computed columns into output parameters
SELECT
@LineTotal = [LineTotal]
FROM
[Purchasing].[PurchaseOrderDetail]
WHERE
[PurchaseOrderDetailID] = @PurchaseOrderDetailId
Computed Column Formula
================================================== ==============
isnull(CONVERT(DECIMAL (29,6),[OrderQty]*([UnitPrice]*[PackingQty])),0.000000)
or
isnull([OrderQty]*([UnitPrice]*[PackingQty]),0.000000)
Profiler Trace
================================================== ==============
declare @p1 int
set @p1=115
declare @p16 numeric(29,0) <- should be numeric(29,6)
set @p16=5 <- value should be 5.259200
exec Purchasing.PurchaseOrderDetail_Insert @PurchaseOrderDetailId=@p1 output,@PurchaseOrderId=68,@OrderQty=4,@VendorProd uctId=28,@Description=N'93678975 - GL-2222',@UnitPrice=0.657400,@PackingMethod=N'Bags (2)',@PackingQty=2.0000,@DueDateValue=NULL,@Modifi edDate=''2008-05-19 15:06:37:610'',@LineTotal=@p16 output
select @p1, @p16
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Dec 13, 2012
I have a question about Computed Column Specification which you can specify as a formula for each column inside a table.
I have now columns named Age and Class.
Classes are "Kids" (ID #1) , "Junior" (ID #2) and "Senior" (ID #3)
Kids, which is for age of 6 till 12
Junior, which is for 12 till 16
Senior, 16 and above.
I have already searched for hours (I really did) on the internet for a solution, but ended with more questions because of the complicated solutions.
Now the Age is shown as a result of a formule of DOB (Date of Birth column), now I want the exact same thing, but the age must specify which Class the user is in.
Example, when I add a user with the birthdate 25/03/1988 (DD/MM/YYYY) he/she gets 24 as age.
With this formula : (datediff(year,[age],getdate()))
Now I want that the user gets "Senior" as Class (same table).
Senior is ID 3 in this case.
Now I do know how Case, When and Then works, but the validation fails. After reading some forums I understood that I should use a create function method. I am not really experienced with creating functions. Also the coding looks more different as I am used to. How to link the Computed Column to a created formula.
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Apr 14, 2004
need help ,
i have a table called "Loans" where i need to compute a column i.e. NoofDays based on which other calculation like interest calculation needs to be done.
my query goes like this
"select datediff(dd,VDate, MDate) as NoOfDays ,NoOfDays * Principal * Rate /100 * 365 from Loans".
if i run the above query it says
"Invalid column name 'NoOfDays'".
this executes fine if i use Access but not in SQL Server.
can anybody say what might be the problem and how i can solve it.
regards
Rajesh :)
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May 19, 2008
hi
i want to create a table that has a computed column like this :
create table resources(
id int identity(0,1) primary key,
currentDate int not null,
currentMonth int default 0,
monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))
as u can see, monthBefore is computed column, and i want get currentMonth value of previous month, for this work, i define a column as currentDate that hold only year+month (like 971,082,083,...) and by this expression, i want to get currentMonth of previous record (previous month), but the following error has shown me :
Subqueries are not allowed in this context. Only scalar expressions are allowed.
how to solve this problem to get currentMonth of previous record ?
thanks
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Oct 1, 2007
how do you change the allow null on a column to be 0,
so instead of having null when empty, it would be 0,
I tried default value or binding to 0 to -1, and to 1
and in 0 or -1, it stays null, in 1 it puts the 1
for example if is quantity, it puts as if I would have 1 quantity,
so it's either null, or whathever number I put visides -1 or 0
how can I make it be 0 as defult?
I'm using it to add and substract with computed column, formula;
and the problem is that if it's the first time it's used it does not add or substract, becsause it does not add null with a number, if it has 0 than it works,
whata I had to do is add it manually, but of course it doesn't suppoesed to be that way
any suggestions will be appriciated:
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Jul 23, 2005
If i want to split a computed column into two or more columns based onthe the length (its a varchar) of the computed column, how often willsql server determine what the computed column is? roughly along thelines ofselect comp_col,'comp_col 2'=case when datalength(comp_col)<=100 then comp_colelse left(comp_col,99) + '~' end,datalength(comp_col)from aTableAs you can see, in this scenario we use the computed coulumn,comp_col, in a few places, so does SQL server need to calculate thiseach time? I'm playing with this on the basis that it does and thustrying to shift the computed column out to a variable and thenmanipulte and return from their, but that has its own problems whenyou throw in additional parameters (trying to join table udf's) so ifSQL server is smart enough to not calculate the column each time Iwould save a lot of hassle?Cheers Dave
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Jul 28, 2006
Can I create an index on a variation of a column that isn't actually inthe table?I have a ParcelNumber column, with values like123 AB-67012345ABC 000-00-04012-345-67AP34567890The blanks and non-alphanumeric characters cause problems with users,because sometimes they're there, and sometimes they aren't. So I wouldlike to create an index based on this column, with the non-alphanumericcharacters squeezed out. Of course I can add such a column to thetable and index it, but I'm wondering if it can be done withoutactually adding the column.Thanks,Jim
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Sep 10, 2006
Hello,I want to assign a column a computed value, which is the multiplicationof a value from the table within and a value from another table.How can I do that?Say the current table is A, column1; and the other table is B, column3.What should I write as formula?I tried someting like;column1 * (SELECT column3 FROM B WHERE A.ID = B.ID)but it didn't work.
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May 19, 2008
hi
i want to create a table that has a computed column like this :
Code Snippetcreate table resources(id int identity(0,1) primary key,currentDate int not null,currentMonth int default 0,monthBefore as (currentMonth - (select top 1 currentMonth from resources where (currentDate - resources.currentDate) = 1)))
as u can see, monthBefore is computed column, and i want get currentMonth value of previous month, for this work, i define a column as currentDate that hold only year+month (like 971,082,083,...) and by this expression, i want to get currentMonth of previous record (previous month), but the following error has shown me :
Code SnippetSubqueries are not allowed in this context. Only scalar expressions are allowed.
how to solve this problem to get currentMonth of previous record ?
thanks
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Dec 26, 2007
Is it possible to use a cursor in computed column?
I have two table (Table1 and Table2). Table 2 is child of Table 1.
Table 2 has more than one record for each record in table 1. What I want is, to concat records from table 2 and show it as a column value for Table1.
e.g.
Code Block
Table 1:
Col1 Col2
1 ABC
1 DEF
Table 2
T1Col1 Col2
1 A
1 -
1 B
1 1
1 -
1 C
I want to see the Results as
Table 1
Col1 Col2 Col3
1 ABC A-B1-C
Is it possible to add computed column for the table1 to get the result as shown in above block.
Thanks
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Sep 25, 2007
Hello everybody!
I have question about indexed and not indexed Persisted columns on sql server 2005. It's a bug?
First?, my version of SQL Server is
Microsoft SQL Server 2005 - 9.00.3186.00 (Intel X86) Aug 11 2007 03:13:58 Copyright (c) 1988-2005 Microsoft Corporation Developer Edition on Windows NT 5.1 (Build 2600: Service Pack 2)
Now I create two tables and try four select queries:
Code Snippet
SET ANSI_NULLS ON
SET ANSI_PADDING ON
SET ANSI_WARNINGS ON
SET ARITHABORT ON
SET CONCAT_NULL_YIELDS_NULL ON
SET NUMERIC_ROUNDABORT OFF
SET QUOTED_IDENTIFIER ON
GO
create table t1 (id int primary key, id_bigint as cast(id as bigint))
GO
create table t2 (id int primary key, id_bigint as cast(id as bigint) persisted)
GO
select * from t1 -- (1)
-- Clustered index scan with two times Compute Scalar
GO
select * from t2 -- (2)
-- Clustered index scan with one times Compute Scalar
GO
create index IX_t2 on t2 (id_bigint)
GO
select * from t2 -- (3)
-- Index Scan with one times Compute Scalar
GO
select * from t2 where id_bigint = 0 -- (4)
-- Index Seek with one times Compute Scalar
GO
drop table t1
GO
drop table t2
GO
SET ANSI_PADDING OFF
1. I don't understand why access to computed column raise scalar computation wto times?
2. I don't understand why access to persisted computed column raise any scalar computation?
3. I don't understand why access to persisted computed column over index required any scalar computations?
Can anyone from Microsoft SQL Server Team told me about this mistake?
It's a BUG or I incorrect understand value of the "PERSISTED" word?
--
Thanks with avanced.
WBR, Roman S. Golubin
grominc[at]gmail.com
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Apr 5, 2007
I've got two integer columns in the table, third one is computed by previous two ones division. That's fine, however sometimes can happen that divided by column is set to zero. How can i avoid division by zero exception, please? TIA
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Jun 17, 2008
I have 3 columns, all integers. [col1] [col2] [col3]
Is it possible to assing a formula to [col3] which always takes the sum of [col1] & [col2]?
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Sep 19, 2005
Hi,I'm struggling to get a calculated column to work in sql, the fields to be calculated are:[AdRevenue_a] money[Admissions_a] int[DoorPrice_a] smallmoney[DoorSplit_a] moneyAnd the calculation I require is:(AdRevenue_a / ( (Admissions_a * DoorPrice_a) - DoorSplit_a )) * 100This is what I think it should be but it doesn't work...convert(decimal(6,2), ((AdRevenue_a / ((Admissions_a * DoorPrice_a) - DoorSplit_a))*100) ))Any suggestions??
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Jul 29, 2004
Can anyone please explain what a valid column formula would look like please?
I am wondering if it would be applicable to a problem i have and cannot seem to enter any formula that will be accepted by SQLEM
tia
fatherjack
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