GROUP BY Vs. DISTINCT
Jan 22, 2008
I am looking for a document or article that explains when it would be best to use a GROUP BY, or DISTINCT.
Cheers,
Casey
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DISTINCT Or GROUP BY Does Not Work. Help
Oct 17, 2002I have have a column where there would be some duplicate records, but I have tried using the IN list, DISTINCT, and GROUP BY, and it does not give me distinct record set.
However DISTINCT and GROUP BY will work as long as my columns to display remain only one, but the minute I add more columns to my SELECT statement it does not make them distinct anymore.
Example 1 works, but Example 2 does NOT. In Example 2, I have added more columns otherwise it identical to Example 1. In Example 3, I was using the IN list, but the results of Example 3 is identical to Example 2 !!
EXAMPLE 1:
SELECT DISTINCT email_address AS Email
FROM email_address
WHERE Send = 'y' and (DATEDIFF(DAY, Sent, getdate()) > 30)
EXAMPLE 2:
SELECT distinct email_address AS Email, email_address_ID AS ID, Sent
FROM email_address
WHERE Send = 'y' and (DATEDIFF(DAY, Sent, getdate()) > 30)
EXAMPLE 3:
SELECT email_address_ID AS ID, email_address AS Email, Sent
FROM email_address
WHERE email_address IN (SELECT DISTINCT email_address FROM email_address
WHERE Send = 'y' and (DATEDIFF(DAY, Sent, getdate()) > 30))
Group By Or Distinct - But Several Fields
Feb 11, 2014How can I use a Distinct or Group by statement on 1 field when calling All or at least several ones.
Example:
SELECT id_product, description_fr, DiffMAtrice, id_mark, id_type, NbDiffMatrice, nom_fr, nouveaute
From C_Product_Tempo
And I want Distinct or Group By nom_fr
Selecting Distinct Data Using Group By
Aug 4, 2013I have an action log table which records when a registrant record was viewed by a compnay employee. I have an sql query like this:
SELECT [ID]
,[RegistrantID]
,[EmployeeID]
,[UserID]
,[CompanyID]
[Code] ....
and data is like this:
IDRegistrantID EmployeeIDUserID CompanyID VacancyID Action ActionDate
17931629515163213NULL 42013-08-04 16:45:40.457
17921629215163213NULL 42013-08-04 16:45:33.003
1791NULL15163213NULL 32013-08-04 16:45:23.660
1790162959162893NULL 42013-08-04 16:45:09.543
[Code] ....
I want to select distinct views to a registrantid record ( the first ones) in one year. if a registrant was viewed 10 tmes a year then it will show only first time it was viewed. If it was viewed 10 times by an employeed in 2 years then it will show first time it was viewed. if it was viewed by 2 employees of same company 10 times in one year then it first time viewed record will be shown. if it was seen 10 times by 2 employees of two different companies in one year then first record of two companies will be shown. do i need to use group by or what ?
Distinct, Unique, Group By, 'Footing'?
Jun 13, 2007I created an ouput text file that was perfect until specs were revised today to add quarterly tax and deduction summations for each employee. (Expected turnaround time for new spec: today!)
So my employee record now has 8 records (which I expected) because I had to join it to the pay_summary table. Like this:
SELECT
COALESCE(CONVERT(char(1),e.record_status),'')
+ COALESCE(CONVERT(char(4),'97 '),'')
and many more fields
from employees as e
JOIN emp_taxes as t on e.employee_no = t.employee_no
LEFT OUTER JOIN pay_summary AS p ON e.employee_no = p.employee_no
Where
dateadd(d, 0, datediff(d, 0, p.dated)) BETWEEN '20061231' AND '20070401'
and e.record_status not like 'D'
and t.tax_authority_type = 'F'
and e.company_no = '2' and e.employee_no = t.employee_no
order by e.employee_no
There are 6 or so fields I intend to sum as records to go into the
file. In another language, in order to get one record per employee_no, the syntax would be like this:
sort on employee_no
footing at employee_no
report field_a field_b field_c subtotal field_e field_f subtotal
in which case fields c and f are numeric and summed from the multiple pay_summary records.
What is the (most efficient) SQL command to give only one record per
employee while summing all the detail records?
I can't thank you guys enough for this forum.
Lisa
Error In Group By And Distinct Clauses
May 2, 2008
hai,
i'm using a table in sql.the name of register. the table datas are
FirstName LastName UserName Pwd dob
krishna murthy ckm0006 asdfg 1985-04-01 00:00:00.000
krishna dfgd ckm0006 cxbcv 1985-05-01 00:00:00.000
raja fdd ddd ddd 1985-01-01 00:00:00.000
raja hgff fgrgf fgf 1985-02-01 00:00:00.000
i want the result as:[group by or distinct by FirstName && order by dob]
FirstName LastName UserName Pwd dob
krishna dfgd ckm0006 cxbcv 1985-05-01 00:00:00.000
raja hgff fgrgf fgf 1985-02-01 00:00:00.000
i tried many queries i'm getting error Like this
Column 'register.LastName' is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.
can anyone resolve my problem...
COUNT (Distinct Column) = 0 With GROUP BY
Mar 20, 2008I have a table of users and date when they logged on to a system. I am trying to count how many distinct users logged on for each day of the week. The SQL below works when there's at least a user for each day. But when there is no user for a particular day such as Sunday, I still want it to return "SUN
0 "
I learned that you can use GROUP BY ALL and it works but the "ALL" is deprecated beyond SQL 2005.
------------------------------------
SELECT UPPER(LEFT(DATENAME(dw, StartTime), 3)) AS DayOfWeek,
COUNT(DISTINCT UserID) AS NumberOfUser
FROM testUserLoginDuration
WHERE Archived = 0
GROUP BY UPPER(LEFT(DATENAME(dw, StartTime), 3))
ORDER BY
CASE WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'MON' THEN 1
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'TUE' THEN 2
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'WED' THEN 3
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'THU' THEN 4
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'FRI' THEN 5
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'SAT' THEN 6
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'SUN' THEN 7
END
--------------
returns
MON 6
TUE 3
WED 5
THU 3
FRI 2
SAT 1
How To Get Group Wise Distinct Count
May 9, 2008Hi,
I need to get the groupwise distinct count .
For eg. Lets assume we have group as Category and under this there are two childs Category1 and Category2.
I need the distinct count under Category1 and Category2 separately with the count resetting after Category1 and Category2.
Any help will be greatly appreciated.
Regards,
Ravi
QUERY HELP: Selecting Distinct For Two Columns Group By One
Jul 23, 2005Greetings.I'm having a little trouble with a query. The idea is simple I need todisplay a list of recently unique visited URLs and the last time Ivisited.I have 2 table one stores the user and time/date and another has theURL.So all I need is the URL (no duplicates) and the last visit.Below is the SQL to create the tables and data to help with the query.Thank you for your help.CREATE TABLE [stat_hits] ([hit_id] [int] (1, 1) NOT NULL ,[hit_date] [datetime] NOT NULL CONSTRAINT [DF_stat_hits_hit_date]DEFAULT (getdate()),[user_id] [varchar] (12) NOT NULL ,[hit_ip] [varchar] (15) NOT NULL ,[shp_id] [int] NOT NULL ,CONSTRAINT [PK_stat_hits] PRIMARY KEY CLUSTERED([hit_id]) ON [PRIMARY]) ON [PRIMARY]GOCREATE TABLE [stat_hit_pages] ([shp_id] [int] (1, 1) NOT NULL ,[shp_url] [varchar] (1000) NULL ,[shp_count] [int] NULL ,CONSTRAINT [PK_stat_hit_pages] PRIMARY KEY CLUSTERED([shp_id]) ON [PRIMARY]) ON [PRIMARY]GOINSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37878,'2005-06-01 16:07:35','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37877,'2005-06-01 16:07:13','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37876,'2005-06-01 15:41:17','ADMIN','0.0.0.0',7339)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37875,'2005-06-01 15:41:03','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37874,'2005-06-01 15:20:31','ADMIN','0.0.0.0',7330)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37873,'2005-06-01 15:20:28','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37872,'2005-06-01 14:45:46','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37871,'2005-06-01 14:35:51','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37870,'2005-06-01 14:30:25','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37869,'2005-06-01 14:28:28','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37868,'2005-06-01 14:28:23','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37867,'2005-06-01 14:28:17','ADMIN','0.0.0.0',7322)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37866,'2005-06-01 14:28:15','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37861,'2005-06-01 14:27:09','ADMIN','0.0.0.0',7339)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37860,'2005-06-01 14:27:05','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37859,'2005-06-01 14:26:59','ADMIN','0.0.0.0',7322)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37858,'2005-06-01 14:26:58','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37853,'2005-06-01 14:25:59','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37852,'2005-06-01 14:23:51','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37851,'2005-06-01 13:58:49','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37850,'2005-06-01 13:44:06','ADMIN','0.0.0.0',7330)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37849,'2005-06-01 13:44:04','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37848,'2005-06-01 13:44:04','ADMIN','0.0.0.0',7340)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37847,'2005-06-01 13:43:58','ADMIN','0.0.0.0',7330)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37846,'2005-06-01 13:43:53','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37845,'2005-06-01 13:26:29','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37844,'2005-06-01 13:22:34','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37843,'2005-06-01 13:22:29','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37842,'2005-06-01 13:21:15','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37841,'2005-06-01 13:19:17','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37840,'2005-06-01 13:17:20','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37839,'2005-06-01 13:17:20','ADMIN','0.0.0.0',7320)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37838,'2005-06-01 11:55:15','ADMIN','0.0.0.0',7339)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37837,'2005-06-01 11:55:09','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37836,'2005-06-01 11:53:08','ADMIN','0.0.0.0',7338)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37835,'2005-06-01 11:53:01','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37834,'2005-06-01 11:34:34','ADMIN','0.0.0.0',7337)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37833,'2005-06-01 11:34:24','ADMIN','0.0.0.0',7336)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37832,'2005-06-01 11:02:59','ADMIN','0.0.0.0',7335)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37831,'2005-06-01 11:02:53','ADMIN','0.0.0.0',7334)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37830,'2005-06-01 11:02:46','ADMIN','0.0.0.0',7324)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37829,'2005-06-01 11:02:40','ADMIN','0.0.0.0',7333)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37828,'2005-06-01 11:02:31','ADMIN','0.0.0.0',7332)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37827,'2005-06-01 11:02:25','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37826,'2005-06-01 11:02:21','ADMIN','0.0.0.0',7331)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37825,'2005-06-01 11:02:12','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37824,'2005-06-01 11:01:23','ADMIN','0.0.0.0',7330)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37823,'2005-06-01 11:01:21','ADMIN','0.0.0.0',7328)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37822,'2005-06-01 11:01:20','ADMIN','0.0.0.0',7327)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37821,'2005-06-01 10:58:23','ADMIN','0.0.0.0',7330)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37820,'2005-06-01 10:58:10','ADMIN','0.0.0.0',7328)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37819,'2005-06-01 10:58:09','ADMIN','0.0.0.0',7327)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37818,'2005-06-01 10:55:27','ADMIN','0.0.0.0',7326)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37817,'2005-06-01 10:55:23','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37816,'2005-06-01 10:55:17','ADMIN','0.0.0.0',7322)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37815,'2005-06-01 10:55:16','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37810,'2005-06-01 10:54:20','ADMIN','0.0.0.0',7330)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37809,'2005-06-01 10:54:12','ADMIN','0.0.0.0',7329)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37808,'2005-06-01 10:51:30','ADMIN','0.0.0.0',7328)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37807,'2005-06-01 10:51:29','ADMIN','0.0.0.0',7327)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37806,'2005-06-01 10:51:10','ADMIN','0.0.0.0',7328)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37805,'2005-06-01 10:51:09','ADMIN','0.0.0.0',7327)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37804,'2005-06-01 10:35:46','ADMIN','0.0.0.0',7326)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37803,'2005-06-01 10:35:41','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37802,'2005-06-01 10:35:29','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37801,'2005-06-01 10:35:21','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37800,'2005-06-01 10:35:20','ADMIN','0.0.0.0',7320)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37799,'2005-06-01 10:33:58','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37798,'2005-06-01 10:33:50','ADMIN','0.0.0.0',7328)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37797,'2005-06-01 10:33:50','ADMIN','0.0.0.0',7327)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37796,'2005-06-01 10:33:09','ADMIN','0.0.0.0',7326)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37795,'2005-06-01 10:33:05','ADMIN','0.0.0.0',7325)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37794,'2005-06-01 10:32:45','ADMIN','0.0.0.0',7324)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37793,'2005-06-01 10:32:18','ADMIN','0.0.0.0',7323)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37792,'2005-06-01 10:31:47','ADMIN','0.0.0.0',7322)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37791,'2005-06-01 10:31:31','ADMIN','0.0.0.0',7321)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37790,'2005-06-01 10:31:31','ADMIN','0.0.0.0',7320)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37789,'2005-06-01 10:30:04','ADMIN','0.0.0.0',7320)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37788,'2005-05-31 20:49:56','ADMIN','0.0.0.0',7311)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37787,'2005-05-31 20:49:54','ADMIN','0.0.0.0',5942)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37786,'2005-05-31 20:49:54','ADMIN','0.0.0.0',31)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37785,'2005-05-31 20:49:02','ADMIN','0.0.0.0',5942)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37784,'2005-05-31 20:48:54','ADMIN','0.0.0.0',7311)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37783,'2005-05-31 20:48:53','ADMIN','0.0.0.0',5942)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37782,'2005-05-31 20:48:52','ADMIN','0.0.0.0',31)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37781,'2005-05-31 20:48:41','ADMIN','0.0.0.0',5941)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37780,'2005-05-31 20:48:37','ADMIN','0.0.0.0',215)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37779,'2005-05-31 20:48:30','ADMIN','0.0.0.0',4)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37775,'2005-05-31 20:46:44','ADMIN','0.0.0.0',7311)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37774,'2005-05-31 20:46:40','ADMIN','0.0.0.0',7319)INSERT INTO [stat_hits]([hit_id],[hit_date],[user_id],[hit_ip],[shp_id]) VALUES(37773,'2005-05-31 20:46:39','ADMIN','0.0.0.0',31)INSERT INTO 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VALUES(7325,'/scripts/objects/list.asp?_XID=70000030&_Ref=1398186089&_reset=true&_table=3001062&|MenuID=40000000',6)INSERT INTO [stat_hit_pages] ([shp_id],[shp_url],[shp_count]) VALUES(7326,'/scripts/objects/edit.asp?_XID=70000030&_Ref=1398186089&_table=3001062&_item=12',2)INSERT INTO [stat_hit_pages] ([shp_id],[shp_url],[shp_count]) VALUES(7327,'/scripts/objects/save.asp?',4)INSERT INTO [stat_hit_pages] ([shp_id],[shp_url],[shp_count]) VALUES(7328,'/scripts/objects/edit.asp?_XID=70000030&_Ref=1398186089&_table=3001062&_item=12&_formtab=&process=&step=&elem=',4)
View 2 Replies View RelatedTSQL - Avoid Duplicated Rows - Using Distinct / Group By
Sep 3, 2007Hi guys,
need some help here please...
The code below shows 4 rows.
The first two rows are almost identical, but the two of them exists in the same table as different rows.
Row number 1 is also related to Row number 3 and Row number 2 is also related to Row number 4
The problem is that I have to use only one of then (Rows number 1 or 2) togheter with row 3 & 4.
I thought using GROUP BY RECEIPTJURNALMATCH.JURNALTRANSID, but getting error.
Thanks in advance,
Aldo.
Code Snippet
SELECT
RECEIPTJURNALMATCH.JURNALTRANSID AS 'R.JURNALTRANSID',
RECEIPTJURNALMATCH.MATCHNUM AS 'R.MATCHNUM',
JURNALTRANSMOVES.ACCOUNTKEY AS 'J.ACCOUNTKEY',
JURNALTRANSMOVES.SUF AS 'J.TOTAL',
STOCK.REMARKS AS 'S.REMARKS'
FROM
RECEIPTJURNALMATCH
INNER JOIN JURNALTRANSMOVES ON RECEIPTJURNALMATCH.JURNALTRANSID = JURNALTRANSMOVES.ID
LEFT OUTER JOIN STOCK ON RECEIPTJURNALMATCH.STOCKID = STOCK.ID
WHERE
JURNALTRANSMOVES.ACCOUNTKEY IN ('123456')
Below the results:
R.JURNALTRANSID R.MATCHNUM J.ACCOUNTKEY J.TOTAL S.REMARKS
89634 16702 123456 1155 עח: ;5752
89634 16703 123456 1155 עח: ;5752
89637 16702 123456 400 NULL
89639 16703 123456 155 NULL
Reporting Services :: Subtotal By Group That Is Not Distinct In Data
May 14, 2015Table here shows partial data extract in order I want to see the report. I need to report:
part-a full, 8 layer, 7 layer, 6 layer....
Part-b full, 8 layer, 7 layer, 6 layer....
part-a full, 8 layer, 7 layer, 6 layer....
Part_Number
Pal_num
MFGDate
Shifttime
WorkCen
[Code] ....
if I group by part number, I get a total. I need a 'sub-total' by part as each group is produced.
Report should be:
Part FULL 8layer 7layer 6layer 5layer
4layer.....
604-04043 6 1
604-02057 14
604-04043 7
GROUP By Clause Or DISTINCT Clause
Jul 23, 2005Hi, can anyone shed some light on this issue?SELECT Status from lupStatuswith a normal query it returns the correct recordcountSELECT Status from lupStatus GROUP BY Statusbut with a GROUP By clause or DISTINCT clause it return the recordcount= -1
View 3 Replies View RelatedSelect DISTINCT On Multiple Columns Is Not Returning Distinct Rows?
Jul 6, 2007Hi, I have the following script segment which is failing:
CREATE TABLE #LatLong (Latitude DECIMAL, Longitude DECIMAL, PRIMARY KEY (Latitude, Longitude))
INSERT INTO #LatLong SELECT DISTINCT Latitude, Longitude FROM RGCcache
When I run it I get the following error: "Violation of PRIMARY KEY constraint 'PK__#LatLong__________7CE3D9D4'. Cannot insert duplicate key in object 'dbo.#LatLong'."
Im not sure how this is failing as when I try creating another table with 2 decimal columns and repeated values, select distinct only returns distinct pairs of values.
The failure may be related to the fact that RGCcache has about 10 million rows, but I can't see why.
Any ideas?
Trying To Add A NON-DISTINCT Field To A DISTINCT Record Set In A Query.
Mar 12, 2007I need to run a SELECT DISTINCT query acrossmultiple fields, but I need to add another field that is NON-DISTINCTto my record set.Here is my query:SELECT DISTINCT lastname, firstname, middleinitial, address1,address2, city, state, zip, age, genderFROM gpresultsWHERE age>='18' and serviceline not in ('4TH','4E','4W')and financialclass not in ('Z','X') and age not in('1','2','3','4','5','6','7','8','9','0')and (CAST (ADMITDATE AS DATETIME) >= DATEDIFF(day, 60, GETDATE()))ORDER BY zipThis query runs perfect. No problems whatsoever. However, I need toalso include another field called "admitdate" that should be treatedas NON-DISTINCT. How do I add this in to the query?I've tried this but doesn't work:SELECT admitdateFROM (SELECT DISTINCT lastname, firstname, middleinitial, address1,address2, city, state, zip, age, gender from gpresults)WHERE age>='18' and serviceline not in ('4TH','4E','4W')and financialclass not in ('Z','X') and age not in('1','2','3','4','5','6','7','8','9','0')and (CAST (ADMITDATE AS DATETIME) >= DATEDIFF(day, 60, GETDATE()))ORDER BY zipThis has to be simple but I do not know the syntax to accomplishthis.Thanks
View 2 Replies View RelatedReporting Services :: Display Group Name Value Of Each Group In Column Header Outside The Group?
Sep 29, 2015I have an SSRS 2012 table report with groups; each group is broken ie. one group for one page, and there are multiple groups in multiple pages.
'GroupName' column has multiple values - X,Y,Z,......
I need to group 'GroupName' with X,Y,Z,..... ie value X in page 1,value Y in page 2, value Z in page 3...
Now, I need to display another column (ABC) in this table report (outside the group column 'GroupName'); this outside column itself is another column header (not a group header) in the table (report) and it derives its name partly from the 'GroupName' values:
Example:
Value X for GroupName in page 1 will mean, in page 1, column Name of ABC column must be ABC-X Value Y for GroupName in page 2 will mean, in page 2, column Name of ABC column must be ABC-Y Value Z for GroupName in page 3 will mean, in page 3, column Name of
ABC column must be ABC-Z
ie the column name of ABC (Clm ABC) must be dynamic as per the GroupName values (X,Y,Z....)
Page1:
GroupName Clm ABC-X
X
Page2:
GroupName Clm ABC-Y
Y
Page3:
GroupName Clm ABC-Z
Z
I have been able to use First(ReportItems!GroupName.Value) in the Page Header to get GroupNames displayed in each page; I get X in page 1, Y in page 2, Z in page 3.....
However, when I use ReportItems (that refers to a group name) in the Report Body outside the group,
I get the following error:
Report item expressions can only refer to other report items within the same grouping scope or a containing grouping scope
I need to get the X, Y, Z ... in each page for the column ABC.
I have been able to use this - First(Fields!GroupName.Value); however, I get ABC-X, ABC-X, ABC-X in each of the pages for the ABC column, instead of ABC-X in page 1, ABC-Y in page 2, ABC-Z in page 3, ...
DISTINCT To ShortDateString, Not DISTINCT To The DateTime; How?
May 8, 2006Hello,
I have written a small asp.net application, which keeps record of the proposals coming from the branch offices of a bank in a tableCREATEd as a TABLE Proposals ( ID smallint identity(7,1), BranchID char(5), Proposal_Date datetime )
This app also calculates the total number of proposals coming from a specific branch in a given date bySELECTing COUNT(BranchID) FROM Proposals WHERE BranchID=@prmBranchID AND Proposal_Date=@prmDateand prints them in a table (my target table).
This target table has as many rows as the result of the "SELECT COUNT( DISTINCT Proposal_Date ) FROM Proposals"and excluding the first column which displays those DISTINCT Proposal_Dates, it also has as many columns as the result of the"SELECT DISTINCT BranchID FROM Proposals". This target table converts the DateTime values ToShortDateString so that we are able to see comfortably which branch office has sent how many proposals in a given day.
So far so good, and everything works fine except one thing:
Certain DateTime values in the Proposals table which are of the same day but of different hours (for ex: 11.11.2005 08:30:45 and11.11.2005 10:45:30) cause some trouble in the target table, where "SELECT COUNT( DISTINCT Proposal_Date ) FROM Proposals" is executed, because (as you might already guess) it displays two identical dates in ShortDateString form, and this doesn't make much sense (i.e. it causes redundant rows)
What I need to do is to get a result like (in a neat fashion :)
"SELECT COUNT( DISTINCT Proposal_Date ) <<DISTINCT ONLY IN THE DAYS AND NOT IN HOURS OR MINUTES OR SECONDS>> FROM Proposals"
So, how to do it in a suitable way?
Thanks in advance.
What's Microsoft Doing About Providing Page Numbering Per Group And Total Pages Per Group?
Nov 27, 2007Hi!
I've posted a feedback with Microsoft to see if we can get them to fix the issue described below, but so far no one from Microsoft has commented to let us know what they're doing about this problem! I'm posting this here to see if maybe we can get more people to rate this feedback or chime in on what a pain it is! Please feel free to add your own comments or how you had to work around this issue and whether or not you think this is something Microsoft should be addressing NOW.
https://connect.microsoft.com/SQLServer/feedback/ViewFeedback.aspx?FeedbackID=311679
Provide Individual Page Numbering per Group and Total Pages per Group
Currently in a Reporting Services report, you can't readily reset the page number for each group in a table, nor can you display the total number of pages per group. For example, if I'm printing invoices and each invoice is a separate group, I'd like to be able to print "Page 1 of 5" , "Page 2 of 5" etc. for the first invoice, then "Page 1 of 3" when the next invoice begins, and so on. This was easy in Crystal Reports. I realize that Crystal Reports has a two-pass process that enables that kind of pagination. However, this is REALLY important functionality that's just missing from Reporting Services and I'm hoping you'll provide it REALLY SOON! Yeah, I know there are work-arounds if you can know exactly how many rows of information there are on each page. But gosh! That's not practical, especially if you have second level groups inside the main group or text blocks in rows that can 'grow' to more than one line. I've read a couple of work-arounds, but none of them works correctly and consistently when more than one user is running the same report or when you print the report while you're looking at it on the screen. I still may need access to the overall report page number and the overall total number of pages, so don't get rid of that. It's just that if you're doing this already for the entire report, I don't see why you can't do it per group! Lots of people have been asking for this for years, and I don't understand why it hasn't been implemented.
I've read a few articles on this topic, but no one has come up with a decent work around. My theory is that Microsoft should be addressing this immediately. This is major functionality that's just plain missing from SSRS and should have been there from the start. If anyone from Microsoft can let us know what's going on with this issue or if anyone would like for me to clarify this further, feel free to let me know.
Thanks!
Karen
Reporting Services :: RDL XML To Unmerge Cells In Group BUT Keep Group Drill-In In Excel
Nov 6, 2015I have an SSRS report with groups that when exported to excel contains drill-in's (plus marks on left side). The issue I have is that for all the groups in the drill-in, those cells become merged. I want to keep the group drill-in but have the cells UNMERGED. I have heard this can be done with the RDL XML but I don't know what to modify to accomplish this.
View 4 Replies View RelatedSQL Server 2012 :: Obtaining A Comma Delimited List For Each Group In The Output Of A Group By Query?
Jan 10, 2014I'd like to ask how you would get the OUTPUT below from the TABLE below:
TABLE:
id category
1 A
2 C
3 A
4 A
5 B
6 C
7 B
OUTPUT:
category count id's
A 3 1,3,4
B 2 5,7
C 2 2,6
The code would go something like:
Select category, count(*), .... as id's
from TABLE
group by category
I just need to find that .... part.
How To Show Distinct Rows Of The Column Of The Dataset And Number Of Distinct Rows Of That Column
Mar 29, 2007suppose i have aDataset with 11 rows. field1 with 5 rows of aaa, 6 rows of "bbb"
I want's some thing like
field1 rowcount
aaa 5
bbb 6
Error 15401: Windows NT Group Or Group Not Found
Sep 25, 2003I have a user in SQL Server with a NT login of Mike
I changed his NT account to Mikel in User Manager
Now when I try to add Mikel, Im getting error 15401.
Do I need to delete NT login in SQL Server 'Mike' account first ?..before adding 'Mikel' ?
Can I go into the Master database and just change Mike login to Mikel ?
Thank you
SQL 2012 :: SSRS Average Column Group Value For Row Group
Feb 28, 2014I'm having a fight with Reporting Services at the minute when trying to compute an average at the row group level for a value summed in a column group.I have the following column groups:
Year
Month
Date
And the following row groups:
Region
Product
SubType (hidden, data at the date level is summed to Product)
At the moment I'm computing the average for SubType for each Date at the Product level (giving a decimal value), so for each day I end up with a nice average, that works. However I am unable to average that average over the whole Year for a Product. The issue being that I'm trying to combine Row Groups (Product) and Column Groups (Date/Year)
SQL 2012 :: Fast Way To Do Group By Count On Items Within Group?
May 1, 2014select top 15 count(*) as cnt, state from table
group by state
order by cnt desc
[code[...
Can the above three queries be combined into one and still be fast, if so how?What i am trying to go is an item count, by group, similar to ones Inbox in Outlook.
Any Way To Show A Group Detail Header Row Once For Each Group In A Table?
Nov 21, 2007I have a need to show a row inside a table group to simulate a header row for the data rows inside the group. The table will not have a real header or footer. Thanks for the help.
View 1 Replies View RelatedLogin For Domain Local Group And Global Group
Jan 5, 2008I have one domoain in the forest. The domain level is set to Windows 2000 native mode and forest level is set to mixed mode. My SQL server 2005 server joined to this domain. I added a brand new domain local group and add a normal user account to this domain local group. I login to the SQL server 2005 server and make a query "SELECT * FROM sys.login_token". I cannot see my domain local group in sys.login_token. However, if I add my account to a global group, I can see it there.
Then, I setup another forest. This time, I have domain level set to Windows 2003 mode and forest level is set to Windows 2003 native mode. I do the same testing. This time, I can see my domain local group in sys.login_token.
Why does SQL server 2005 has this limitation? Is it a bug?
Adding A Group By Clause And Getting A Count Of A Group
Feb 6, 2008HiI am new to SQL and am having a problem. I need to fix my query to do the following...2) get a total of the number of rows returned.
DECLARE @StartDate varchar(12)DECLARE @EndDate varchar(12)DECLARE @Region varchar(20)
SET @StartDate = '01/01/2002'SET @EndDate = '12/31/2008'SET @Region = 'Central'
SELECTA.createdon,A.casetypecodename,A.subjectidname,A.title,A.accountid,A.customerid,A.customeridname,B.new_Region,B.new_RegionName
FROM dbo.FilteredIncident AINNER JOIN dbo.FilteredAccount B ON A.customerid = B.accountid
WHERE (A.createdon >=@StartDate AND A.createdon <= @EndDate)AND (B.new_RegionName = @Region)AND (A.casetypecode = 2)
How?: Group By Date And Count Rows In Group
Jan 29, 2007I'm new to MSSQL 2005 and want to get a summary of a log table. I want to count all the rows for each date based on a DATETIME field called 'post_date' that holds the date and time of each record's creation.
this is the best I can come up with:
Code:
SELECT
DISTINCT(LEFT(post_date,11)) AS post_date, COUNT(DISTINCT(LEFT(post_date,11))) AS total_posts
FROM log_directory_contacts
GROUP BY post_date
The results show each date but the count column ('total_posts') returns '1' for every row even when I know their are more than 1 record on that date.
What am I doing wrong? Thanks!
How To Use Group By (group Tasks Based On Projects)
May 28, 2007Hi folks,
I have a Projects , each project have many tasks now i want to display tasks replated to each project:
for example:
Project1-------------------->task1
task2
task3
task4
Project2----------------------->task4
task5
task6
.............................................projectN.....................
how to write query for this
i have 2 tables:
Project .......>columns are projectid
Task------------->columns are projectid, taskid
|
Repeat First Row Group Header For Second Row Group Items
Jun 6, 2007I have a matrix with two row groups and one column group with about 6 items in it. I have about 2100 rows at the lowewst row group level. This report was built solely for excel export. The first row group has about 20 items and controls the visibility of the other group. When I toggle the visibility of the second row group, how can I make the the header of the first row group copy down for each row of the other row group? The first row group is the Section and the second is Mnemonic.
Example:
Now:
Code Snippet
Column Column
Section1 -
Mnemonic
Mnemonic
Mnemonic
Mnemonic
Section2 -
Mnemonic
Mnemonic
Mnemonic
Mnemonic
Should be:
Code Snippet
Column Column
Section1 -
Section1 Mnemonic
Section1 Mnemonic
Section1 Mnemonic
Section2 -
Section2 Mnemonic
Section2 Mnemonic
Section2 Mnemonic
Distinct Values Among Distinct Column Values
Jan 9, 2015Okay, I've been working on this for a couple of hours with no success. I'm trying to find the number of telephone numbers that are associated with multiple students at different school sites. I've created a temp table that lists all phone numbers that are associated with more than one student. I'm now trying to query that table and count the number of telephone numbers that are associated with more than one site. Essentially, I'm looking for parent/guardians that have students at different sites.
Here's an example of what I'm hoping to accomplish:
*In this example, I'm just trying to get a count of the different/distinct school sites associated with each number. If I can, at the same time, limit it to a count of > 1 (essentially excluding parents with students at the same site), even better :)
===================================
Temp table
===================================
SCHOOL | STU_ID | STU_PHONE
101 | 12345 | 111-222-3333
101 | 23456 | 111-222-3333
102 | 34567 | 111-222-3333
101 | 45678 | 999-888-7777
101 | 56789 | 999-888-7777
101 | 67890 | 555-555-5555
102 | 78901 | 555-555-5555
103 | 89012 | 555-555-5555
==================================
Wanted query results
==================================
STU_PHONE | #Students | UNIQUE_SCHOOLS
111-222-3333 | 3 | 2
999-888-7777 | 2 | 1
555-555-5555 | 3 | 3
Not A Single-group Group Function
Feb 12, 2015I have a code like this:
SELECT Node_ID,Day,Operation, AA,BB
FROM
(SELECT
CASE
WHEN Operation LIKE 'NOTIFY' THEN SUM(Total_request) ELSE 0 END AS AA,
CASE WHEN OPERATION LIKE 'SEARCH' THEN SUM(Total_requests) ELSE 0 END AS BB,Node_ID,DAY,Operation
[code]....
So i want to make two columns by the name of operation. in the real code AA and BB are calculates with many counters. My code doesn't work, I have an error: "not a single-group group function" .....
T-SQL Problem...selecting TOP 1 Of Each GROUP In GROUP BY?
Jul 23, 2005Hi,I was hoping someone may be able to help me with a tricky T-SQLproblem.I need to come up with a SELECT statement that does basically thefollowing:Select RCRD_REFNO, MAX(MODIF_DTTM) as MODIF_DTTM from[StageDb].[dbo].tblPersonInfo group by RCRD_REFNOHowever, I need to select ONLY the TOP 1 of each group (i.e. only 1record for each unique RCRD_REFNO). The problem is of course that if Iadd 'top 1' after select, it only brings back 1 record full stop,rather than 1 for each group!Now, I have previously come up with a similar query that DOES do thissuccessfully, but it relies on a criteria (such as a unique identifier)-unfortunately, the nature of the table I'm using for this currentjob means that it actually doesn't have a primary key, as it'ssimply a staging area for raw data, and can even have completelyidentical records in it. I think the only way I'm going to be able todo it is to literally use the 'TOP' command somehow, but am notsure how to adapt the above to implement it...I'd be very gratefulfor any advice.Many thanks
View 6 Replies View RelatedAdding SubTotol Of A Group To Group
Sep 6, 2007Here is my Table Structure ( from Oracle database)
Team | Customer Code | Amount | Credit Limit
1 , a, 100, 1000
1 , a , 200, 1000
1 , b, 100, 100
1, b, 1000, 100
1, b, 2000, 100
2, a, 100, 2000
For the Report, I want to group the Team and Sum each customer total Amount and Show the Exceed limit amount.
Here I want to present
Team Customer Code Amount Credit Limit Exceed
1 a 300 1000 0
1 b 3100 100 3000
Team Total 3300 3000
2 a 100 2000 0
Team Total 100 0
Total 3400 3000
BUT it turn out..
Team Customer Code Amount Credit Limit Exceed
1 a 300 1000 0
1 b 3100 100 3000
Team Total 3300 2300 ( Problem here a )
2 a 100 2000 0
Team Total 100 0 ( Problem here a )
Total 3400 2400 ( Problem here b)
I Grouped the Custoer Code and Team I can preform the sum
however I can't Do the Exceed total
becoz the value should be
iif (Sum(amount)>(Creditlimt) , Sum(amount)-First(Creditlimt), 0)
but for the team total in team 1 the result is 2300 ( 3300 - customer a 's limit) not add from exceed amount
And the finial total it turns out 2400 (3400 - 1000)
I have tried use the coding to sum up the exceed
but I found that the group total is sumup first than the sum up the detail :
Team Customer Code Amount Credit Limit Exceed
1 a 300 1000 0
1 b 3100 100 3000
Team Total 3300 0
2 a 100 2000 0
Team Total 100 3000 ( The Total from Team 1 ! )
Total 3400 0 ( Problem here b)
this situration , I can't change the query statement
I can do the good result for CR report
but for reporting service 2005, I can't to the first report result
Any one can help me ??
thank you