Get Dicision Tree Attribute Name Using VB.net
Jul 10, 2007
Hello All,
I am going through the Data Mining Web Control sample and have that working beautifully. I now want to add in some more functionality by allowing the end user to select the: database, model and tree to view in the web viewer (similar to the parameters in SSRS). I am trying to figure out a way to get all this data programatically. So far this is what I have:
Code Snippet
For Each newDB As Microsoft.AnalysisServices.Database In myserver.Databases
dbName = newDB.Name.ToString
myLog.AppendText("DATABASE NAME - " + dbName + vbCrLf)
For Each newStructure As Microsoft.AnalysisServices.MiningStructure In newDB.MiningStructures
structureName = newStructure.Name.ToString
myLog.AppendText(" STRUCTURE NAME [ " + structureName + " ]" + vbCrLf)
For Each newModel As Microsoft.AnalysisServices.MiningModel In newStructure.MiningModels
modelName = newModel.ToString
modelAlgorithm = newModel.Algorithm.ToString
myLog.AppendText(" MODEL NAME -" + modelName + " " + modelAlgorithm + vbCrLf)
This works beautifully but I am having a problem getting the tree name which i believe its called the "attribute_name".
I can run the following SQL against Analysis Services and get the attribute name but I would like to get all this programatically and insert into a table.
Code Snippet
SELECT attribute_name
FROM [model].content
WHERE node_type=2
I plan to run this daily and update a table. This will ultimately let me pull the structure into my data mining viewer page. This way, I will only have to have one viewer page for all models, instead of a new page for each.
Thanks,
Cam
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Sep 22, 2006
Hi,
is there a way to import a decision tree-model from pmml where a node contains two or more states of an attribute as the split-rule?
Example:
...
<Node recordCount="600">
<CompoundPredicate booleanOperator="or">
<SimplePredicate field="color" operator="equal" value="red" />
<SimplePredicate field="color" operator="equal" value="green" />
</CompoundPredicate>
<ScoreDistribution value="true" recordCount="200"/>
<ScoreDistribution value="false" recordCount="400"/>
</Node>
...
This node shoud contain all cases, whose color is red or green (The Microsoft DecisionTree-Algorithm would build a model with two steps like red/ not red and then green / not green). According to the DMG, this is valid PMML 2.1, but when trying to import the server complains about an unexpected value in the SimplePredicate-tag.
How can i import such a node in SqlServer 2005?
Thank you in advance for any help
Chris
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Aug 10, 2015
I want to insert attibute att1 in field F1 . Value for this attribute is content of another field in this table (F2).
My query :
update MyTable
set F1.modify
('insert attribute att1 {sql:column("F2")} into (/ROOT/Node1)[1]')
Where F1 Is not null
But I get this error :
XML well-formedness check: Duplicate attribute 'att1'. Rewrite your XQuery so it returns well-formed XML.
How do I check the douplicate attribute ?
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May 16, 2008
HI,
I had to change the key columns of a dimension attribute to fix an error. I did this in BIDS. The change was from a single key column to a composite key column. Now I am getting these error when I process the cube:
Measure group attribute key column x does not match source attribute ..
I looked at the cube XMLA definition under mesaure groups and it still shows a single key column with inherited binding. However, the BIDS does not give me an option correct this in any way. I have had to do this once before and the only option seems to be removing the dimension from the cube and add it back in. But that is very error prone since I lose any specific settings at the cube dimension level not to mention aggregations no longer include the dimension, etc.
Not seeing an alternative, I went through each measure group (I have 7) and changed the key columns manually in the XMLA and saved the cube. This worked, but I don't understand why BIDS automatically doesn't do it.
Is this a flaw in the BIDS or I should be missing something.
thanks
MJ
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Apr 6, 2015
I got assignment, how to make it appear in the right order .
/* DROP TABLE EMP
SELECT * INTO Emp FROM (
SELECT 'A' EmpID, NULL ManID, 'Name' EmpName UNION ALL
SELECT 'MAC' EmpID, 'A' ManID, 'Name__' EmpName UNION ALL
SELECT '1ABA' EmpID, 'MAC' ManID, 'Name____' EmpName UNION ALL
SELECT 'ABB' EmpID, '1ABA' ManID, 'Name______' EmpName UNION ALL
SELECT 'XB' EmpID, 'A' ManID, 'Name__' EmpName UNION ALL
SELECT 'BAC' EmpID, 'XB' ManID, 'Name____' EmpName ) b
*/
[code]....
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May 20, 2004
Dear all,
I would like to know how to create a single level hierachy structure in SQL.
Example, I have a single parent record in table A that may later on spawn one or child record in table B that relates back to the parent. It only needs a single level.
that means, one to many.
thanks and rgds.
Loke HC
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Jan 2, 2008
I have two tables.
table1 has 3 fields a , b and c. field "a" is a primary key.
table2 has 2 fields x and y. Fields x and y are nothing but the value of "a". Also, y is the child of x.
Therefore, x and y can never have same value. It means value of "a" either be child or parent.
But there is possibility that parent has no child.
Now, i wanted to write Select/Insert query for parent, b , c and child.
This tree is no a binary tree but N-Ary Tree.
Thanks,
sha
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May 18, 2007
Hi,
I'm having a major brain-failure moment here.
Using T-SQL I want to be able to get all of the leaf nodes (e.g. nodes at the furthest end of a tree from the root) in a hierarchical relationship where the table structure is such NodeID|ParentID|NodeName.
Basically if I had the following tree structure:
Root
Child1
Grandchild1
Child2
Grandchild2
I want to get all of the Grandchild nodes. Number of levels will vary and I haven't got any kind of HasChilds column.
I know this is possible because I remember having done it on a course years ago but I can't for the life of me figure it out on this sunny Friday afternoon. I know it's going to involve either recursion, a while loop or cursors but my mind is currently jelly. Can anyone help?
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Sep 10, 2007
hi. I am working on Multiline Marketing Project.I have to calculate all the childens and display the whole tree..I have save records in tree format...But not able to calculate the all childrens.
SELECT count(*) FROM dfTree WHERE id in (SELECT id FROM dfTree WHERE lineage like '16%')
This query works properly.Problem is that it is not working in the project because in the like I have to pass a variable.
SELECT count(*) FROM dfTree WHERE id in (SELECT id FROM dfTree WHERE lineage like '@idl%')
Please Suggest me...
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Jun 2, 2008
HI,
I am working on a Family tree portal which need tree functionality to display family members in tree structure. on click on any node the adding option should be displayed
for this i need a table and procedure to complete family tree
Thanks
@mbi
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Jan 3, 2006
Consider the following SQL query:
SELECT ENAME,SAL
FROM EMP,ASG,PAY,PROJ
WHERE EMP.ENO=ASG.ENO
AND PAY.TITLE=EMP.TITLE
AND ASG.PNO=PROJ.PNO
AND ASG.DUR=48 AND BUDGET>200000
Give the possible operator trees:right-deep,left-deep and bush
Tank you very much!
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Jun 11, 2006
Hi,
i'm writing a app in c# and have to store Trees in a Database.
I'm working with Datasets for the exchange between the DB and the App.
The trees have the same options like the windows folders. If u delete a node, all subnodes should be deleted too.
But something a Foreign Key from ParentID references (Id) with the delete-Rule on cascade seems not to be possible, because of multiple cascade Paths or cycles. Do i have to add some xtra constarins:
Not Possible:
create Table tree (
Id varchar Not null,
ParentId varchar Not null,
Constraint pk1 Primary Key (Id),
Constraint fk1 Foreign Key (ParentId) references tree(Id)
On Update Cascade
On delete CAscade
)
Do i have to write triggers, which delete The subnodes too and set the Update-/deleterulr on NO Action
Greetz
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Oct 24, 2006
Does anyone know any good links for SQL tree structures and example queries and stuff... I cant really find anything part from the standard example of emplyee, boss, salary which explains how to create the tree table...(dun dis bit) I did notice a book but I live in a little village so cant go get it till wekend?
I'm desperate, reli need to work out how too do this.....
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Jun 13, 2008
SELECT a.Network_ID, b.Last_Name + ', ' + b.Preferred_FirstName AS full_name, c.Security_Class_Description,
d.Security_Type_Description, a.Security_Value
FROM Company_Hierarchy_Security a
JOIN V_Entity_Employee_Active b on a.Network_ID= b.Network_ID
JOIN Company_Security_Class c on a.Security_Class_Code=c.Security_Class_Code
JOIN Company_Security_Type d on a.Security_Type = d.Security_Type
inner join (select e.Budget_Center_ID + ' - ' + e.Budget_Center_Description As Budget_Center_Description,
f.Company_Name, g.Enterprise_Description, h.Business_Segment_Description,
i.Team_Description
from Company_Hierarchy_Security a.
Inner JOIN Budget_Center e on a.Security_Value = e.Budget_Center_ID
Inner JOIN Company f on a.Security_Value = f.Company_ID
Inner JOIN Enterprise g ON a.Security_Value = Cast(g.Enterprise_Number As Varchar(5))
Inner JOIN Business_Segment h on a.Security_Value = h.Business_Segment_ID
Inner JOIN Team i on a.Security_Value = i.Team_ID
Ok. I have the Security Value located in Company_Hierarchy_Security table. All those values are divided into 5 other tables that I need to join together. I found all of them separate but I have not been able to figue it out how to put it together with the rest of the querie.
Thanks for the help!!!!!
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Jun 16, 2008
Thank You visakh16 --- The following section of my querie works but doesn't give the exact information that I need. This is what is giving me:
NetworkId Full Name Sec Class Desc Sec Type Desc SecValue
tte Test Scenario Accounting Budget Center 142- ?
SELECT a.Network_ID, b.Last_Name + ', ' + b.Preferred_FirstName AS full_name, c.Security_Class_Description,
d.Security_Type_Description, a.Security_Value
FROM Company_Hierarchy_Security a
JOIN V_Entity_Employee_Active b on a.Network_ID= b.Network_ID
JOIN Company_Security_Class c on a.Security_Class_Code=c.Security_Class_Code
JOIN Company_Security_Type d on a.Security_Type = d.Security_Type
------------------
inner join (select e.Budget_Center_ID + ' - ' + e.Budget_Center_Description As Budget_Center_Description,
f.Company_Name, g.Enterprise_Description, h.Business_Segment_Description,
i.Team_Description
from Company_Hierarchy_Security a.
Inner JOIN Budget_Center e on a.Security_Value = e.Budget_Center_ID
Inner JOIN Company f on a.Security_Value = f.Company_ID
Inner JOIN Enterprise g ON a.Security_Value = Cast(g.Enterprise_Number As Varchar(5))
Inner JOIN Business_Segment h on a.Security_Value = h.Business_Segment_ID
Inner JOIN Team i on a.Security_Value = i.Team_ID
_____________________________________________________________________
What I need is the Description that are located in 4 other different tables that matches the Security Value from my first querie.
The result should look like this...
Network Id full Name Sec Class Desc Sec Type Desc Security Value
tst , Test Example , Accounting ,Budget Center , 142-Accountig dept
Thank you very much,
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Oct 14, 2005
Any recomendations on how to store organization trees on a database withlots of paths and branches? Any white papers out there that explain this?Thanks
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Sep 12, 2006
Hello,I have a "tree" table:Id - primary keyParrentId - (foreign key) related to IdTitle.....when I delete some record I want to delete it with all childs (cascadedeleting). I can't set cascade deleting on the same table :(. Is thereany easy way in the MSSQL 2005 to do this ? There is one idea - usingcursors + recursive functions but I think this solution is not easyand elegant.Thakns for any help and sugestions.Regards.Andy
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Mar 5, 2008
Hi:
Is there a resource or an object in Reporting Services that I could make a tree view in a report file .rdl and see the result on it?
If not, is there a software of MS that a could make a component for it, and connect this component in the report file .rdl ?
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Apr 16, 2007
I'm having this problem.....
I wanted to use the Decision Tree to show a result..... after i configure the Mining Structures..... and set all the input.... my decision tree shows only until level 2..... i have 3 input and one PredictOnly column.....where is the other input?
Say.... i have House Owner, Marital Status, Num Cars Owned and Number Of Children(PredictOnly)
my Tree only shows All ---- > Marital Status when i input all 3 together...... the other 2 doesn't seems to show.
wat should i do?? my database in SQL Server and the other keys are all correct and deploying finely.....why is this happening.....?
i'm a newbie in this software.......so any pro here can plz help me if there's actually something that i might have missed out along the way.......
Thank you again.........
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Feb 28, 2008
Alright what im trying to do is build a classic tree, i have id's like this set up in my table referencing itself in sql 2000
cmponent_prt_no parent_part_no
--------------- --------------
112837A2A L115100-1
114379A1A L115100-1
115623A1A L115100-1
203604A L115100-1
203790A L115100-1
203791A L115100-1
115623A 115623A1A
M010137 115623A1A
115623A 115623A1A
20766CR 115623A1A
DRAWINGS 20766CR
M010137 20766CR
i have tried 3 different solutions all coming to a crash at some point, if ANYONE can help me out i would appreciate it, i know the logic will be recursive, i just dont know how to implement
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Jun 25, 2004
Does someone could explain me the NOCASE attribute in the order by line?
I cant find that anywhere.
Thanks a lot,
venusgirrl
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Jun 3, 2007
Hello !
Can somebody help me with the following error while deploying my cube:
The attribute key cannot be found : dbo_fact_table, Column: datetime Value 25/10/1901 4:18:00 pm...
The year 1901 is included in the time period of the time dimension.
The calendar includes the following dates :
1/1/1753 - 31/12/2007 (Time binding)
Why this referential integrity error occurs ??
Please help me because it is urgent and I cannot find a solution..
Thanks
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Sep 10, 2007
What happens if a column which has been defined so that it should not be Nullable is passed a value which is null?
i.e. IDNumber - Primary Key and Nullable = No.
Thanks
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Dec 11, 2007
can someone please tell me if you can implement a drop down list within a table attribute.
If anyone could show me an example please do.
Kind Regards
Rob
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Aug 10, 2005
Hi:I need to store MAC Addresses. What is the standard way of storing thistype of attribute? Datatype? I can't find any discussions about thisanywhere.Thx for any pointers.
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Jul 20, 2005
Hi!I have a following problem: I need to select some attributes fromtable, i.e.first, third, fifth...Can anyone give me the hint how to do it. Is there some method to saysomthing like this:SELECT $1, $3, $5 which will refer to the 1st, 3rd and 5th attribute?Thanks!Mario.
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Jan 10, 2008
I have the following as part of a stored procedure that generates an HTML report based on the data inserted into the table variable "@tblTemp":
SET @html =
N'<table border="1" width="0" style="font-family: Verdana, sans-serif;">' +
N'<tr><th>Name></th><th>ID</th></tr>' +
N'<col align="left"></col><col align="right"></col>' +
CAST ( ( SELECT td = [Name], '',
td = IDNumber
FROM @tblTemp
ORDER BY ID
FOR XML PATH('tr'), TYPE
) AS NVARCHAR(MAX) ) +
N'</table>' ;
SET @html = @html + N'<br /><br /><img src="muuscreenshot.jpg" width="452" height="507" alt="sample.aspx" />'
This generates a 2 column table that later in the stored procedure is sent out via sp_send_dbmail. The problem I'm having is that I want the right (2nd) column of the table to be right-aligned. For some reason, the line "
N'<col align="left"></col><col align="right"></col>' +" doesn't right-align the 2nd column when the report is sent through email (althought it does work if I take the generated string a use it to manually create an HTML file). So I want to add something like:
SET @html = REPLACE(@html, '<td', '<td align="right"')
but I still want the left column to be left-aligned, and this right-aligns everything. Is it possible for me to use REPLACE (or some other string function) to replace every other (alternating) "<td", or should I be looking at parsing this string using some 2005 XML features (unfortunately, using a CLR function to do this is not an option, since I am not allowed to turn that on on the server I'm using)? Thanks in advance.
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Jan 9, 2008
I am trying to create a linear regression model. The model is skipping lot of columns for regression. But I want model to use all the columns even if they are not valid. I use Forced_Regressor attribute while creating the model.
add mining model Regressiontableinput2_Model
(
[id] ,
[Reading] PREDICT_ONLY,
[Const] regressor,
[HCDD] regressor,
[HHDD] regressor,
[Hr1] regressor,
[Hr2] regressor,
[Hr3] regressor,
) USING MICROSOFT_LINEAR_REGRESSION (FORCED_REGRESSOR=1)
I get the error
Error (Data mining): The 'FORCED_REGRESSOR' data mining parameter is not valid for the 'Regressiontableinput2_Model' model.
Can somedbody tell me what is the syntax for using FORCED_REGRESSOR
Thanks,
DMNovice
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Jun 30, 2015
I am trying to generate an output using Productname from below xml which will look like:
B/C/
B/D/E
demo xml:
DECLARE @myDoc xml
DECLARE @ProdID nvarchar(10)
SET @myDoc = '<Root>
<ProductDescription Productname="A" Productd="Road Bike">
[code]...
I have a query which works perfect but with nodes. similar way I am looking for the value column. I want a similar result from the function on "Value" column(value column is defined inside the below query) : B/D/E ....
with
CTE_xpath as (
select
T.C.value('local-name(.)', 'nvarchar(max)') as Name,
T.C.query('./*') as elements,
T.C.value('text()[1]', 'nvarchar(max)') as Value
[code]...
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Oct 11, 2007
i have a column in my table that will store the sum of 3 other column, e.g the data in total_book column will be equal to the sum of the number in the romance, fiction and thriller column. how do i do this?
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Mar 10, 2008
I am trying to retrive some values from and XML data colum , along with that i need other normal column data also . how can i do that ?
here is my problem
I have a table with 2 colum .
Column Data Type
ID Int
Data XML
The XML data looks like following
<A>
<B a = 'sun' b = 'Red' >
</B>
<A>
I want to get each id and the 'b' attribute of the B node of the xml data for each row ?
Please help me if there is any simple way to do this .
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Jan 21, 2008
Hi everyone,
I heard that it is possible to make more than one attribute(coloumn) primary key. Is this really possible, logical, productive and beneficial ?
Thanks
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Aug 21, 2007
Hi..I have a table register..in this fields are username,parent id,downline ; I have to determine all the child of a particular parent.
suppose table is like this. username parentid downline
B A left
C A right
D B left
E B right....
I have to also determine the level in the tree....please help...
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