Get Date From Week Number In A Year
Feb 11, 2014Can I get a date from a week number in a certain year, like I know it's week 7 in 2014 (I may know the month.)
View 7 Replies
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SQL Server 2008 :: Get Week Ending Date Given Week Number
Apr 9, 2013How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
Transact SQL :: Select All Days In Week Number X Including Last Year If Necessary
May 24, 2015SQL express 2012. I am trying to case in the where part and having a syntax errors - This is what i am trying to do:
select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ....
Transact SQL :: Select All The Days In Week Number X Including Last Year If Necessary
May 24, 2015SQL express 2012
I am trying to case in the where part and having a syntax errors - this is what i am trying to do:
Select all the days in week number x including last year if necessary... so if the year start not at the beginning of the week then look in last year as well ( for the same week number of this year and last week nu of last year)
declare
@yyyy int = 2014,-- THE YEAR
@mm int = 1,-- THE MONTH
@week1No int = 1,-- THE WEEK NUMBER IN THE YEAR
@week2No int = 37-- THE last WEEK NUMBER IN last YEAR
select count(tblDay.start)-- tblDay.start IS smallDatetime
[Code] ...
Convert Week Number To Date Of 1st Day Of That Week...
Feb 2, 2008
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
Find The Date If I Know The Week And Year
Aug 5, 2004Hi Guys,
Can anyone please let me know How to find the first day of the week, if I know the weekno and the year.
For ex: If I know the week no is 22 and Year is 2003 then I should find a way to output the date. which is the first day (monday) of that week
for the above query the date will be eg:26/06/2003
I really appreciate your Help
Thanks:confused: Find the Date if I know the week and year
Converting Year/week/day To Date
Mar 19, 2007i have this SQL table with a year, week and day-of-week field, but no field containing the actual date
is there a way (e.g. in a view of the SQL table) to transform the year/week/day combination into a date string (e.g. format dd/mm/yyyy) ?
How Can I Get The Date From Week Number
Jan 17, 2008
I have week number and i want to get the date from that
for example Week=52 will be the first day of that day which is monday 12/24/2007
Thanks
Getting The Date From Week Number
Oct 7, 2007I have a column in my dataset that contains the week number.
I would like to use 'Expression' Or code function to do that
how can i get the date from week number? for example the week number is 38
so i wil get this output: 09/17/07 - 09/23/07 (the week starts on Monday and ends on Sunday)
Thanks
Convert Date To Week Number
Apr 30, 2015I want to convert date to week consider saturday is first day of week and friday is end of week. for input is orderdate and output should be week. example orderdate 11.04.15 to 17.04.15 week should be 16. orderdate 18.04.15 week should change to 17.
Order DateWeek
11-Apr-201516
12-Apr-201516
13-Apr-201516
14-Apr-201516
15-Apr-201516
16-Apr-201516
17-Apr-201516
Order DateWeek
18-Apr-201517
Convert Week Number Back To First Date
Feb 28, 2008hi guys,
How could I convert 'week 9 2008' back into the first day of that week ?
is that even possible ?
How To Get Data Untill Last Week From The First Week Of The Year
Apr 29, 2008In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedHow To Get The Week Number Of A Specific Date In SQL Server 2005
Jan 10, 2008Hi,
Can anybody tell me to How to get the week number of a specific Date in SQL Server 2005.
Like : say Date "03/01/2008" belongs to the 1st week of the year 2008, same way "21/02/2008" is 8th week of the year 2008.
So, the same way I need to know the week number of a given (variable) date.
I need to write / use a Function in SQL server which will return the Number (INT) (i.e. 1 or 8 or 10 etc...) against a specific (Parameter) date.
regards,
Saibal
Note : Please feel free to write me if my question is not clear.
Return Number Of Days By Year From Date Fields
Dec 3, 2013I need to associate aggregate gross_revenue with calendar year, but do not have a date field that reflects payment dates, just contract periods a start_date and an end_date. The contract periods are typically 1 or 2 years and can start at any time I.e start_date 6/1/2012, end date 5/31/13. I think by finding the number of days that fall in each calendar year and storing in a temp table, I can create a simple formula to associate revenue to each year.
View 2 Replies View RelatedISO Year Week Day Of Week Function
Jan 18, 2006Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
How Can I Retrieving Records By Past One Week,past Month, Past Quarter Of Year And Then Half Year.
Apr 30, 2007Hi every one,
I have a database table and currently users may retrieve records for a specified date range by providing the start and end dates and then records between those dates provided are retrieved. For example if users wanted to view all records entered in april, they would have to select 04/01/2007 as the start date and then 04/30/2007 as the end date. The records for april would then be displayed in a gridview.
How can configure my sql query such that instead the user selectes a month from a dropdownlist of 12 months. I would love a user to just select the desired month from a list instead of selecting start and end dates. Eg if they are intrested in a report for june, then they should just select june from the list instead of specifying the start and stop dates. HOW can i achieve this.
How Can I Search By Week No Of The Year?
Mar 31, 2006How to define week of the year in sql? e.g. i want to search all the transcations in week 2, how can i do it?
View 2 Replies View RelatedISO Week Of Year Function
Jan 18, 2006This function returns the ISO 8601 week of the year for the date passed. The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day of each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_WEEK_OF_YEAR
go
create function dbo.F_ISO_WEEK_OF_YEAR
(
@Datedatetime
)
returnsint
as
/*
Function F_ISO_WEEK_OF_YEAR returns the
ISO 8601 week of the year for the date passed.
*/
begin
declare @WeekOfYearint
select
-- Compute week of year as (days since start of year/7)+1
-- Division by 7 gives whole weeks since start of year.
-- Adding 1 starts week number at 1, instead of zero.
@WeekOfYear =
(datediff(dd,
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end,@date)/7)+1
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aa
) a
return @WeekOfYear
end
go
-- Execute function on first day of first week of year from 1990 to 2030
select
DT,
ISO_WEEK_OF_YEAR =
dbo.F_ISO_WEEK_OF_YEAR(a.DT)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
CODO ERGO SUM
Week, Month Year Parameter
Jun 10, 2008My boss would like to see one report with parameter promts. I tried doing this, but I keep getting an error. Can someone help me out here?
Thanks.
WHERE
(@YEAR(CLM_Dout) = YEAR(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND MONTH(CLM_DOUT) = MONTH(GetDate()))or
(@YEAR(CLM_DOUT) = YEAR(GetDate()) AND DATEPART(wk, CLM_DOUT) = DATEPART(wk, GETDATE()))
Sum By Week / Month / Quarter / Year
Aug 20, 2014I am trying to group counts by week,month,quarter, year for a particular activity type and I'm having issues.Here's my code so far:
SELECT
distinct
EmailAddressID,
emailaddress,
SUM(CASE WHEN [ActivityDate] >= DATEADD(WEEK, DATEDIFF(WEEK, 0, @DT), 0)
THEN
SUM(CASE WHEN EmailActivityType = 'OPEN' THEN 1 ELSE 0 END) END AS WeekTotalOpens
FROM EmailActivity
WHERE DATEPART(YEAR, [ActivityDate]) = DATEPART(YEAR, @DT)
GROUP BY EmailAddressID,emailaddress
Desired Output:
EmailAddressId EmailAddress WeekTotalOpens MonthTotalOpens etc. then WeekTotalClicks and so on....
SQL doesn't seem to like the sub-aggregate. What is the best way to approach?
How To Find The Current Year And Week
Jul 20, 2007Hi,
I have a Serial No which has a length as 14.For eg IL010730123456. IL01 is The Default Code. 07 is the current year and 30 is the week of the year. 123456 is Serial. How shoud I find The Year and week with the help of this serial no ie The First day of the 30th week of 2007.Is it Possible?
Plz Help me with an appropriate solution.
Thanks.....
Transact SQL :: How To Generate Week Ranges For A Year In 2005
Mar 22, 2011I have to insert YEAR WEEKNUMBER STARTDATE ENDDATE values to a datatable (sayweekrange), if I pass 2011 as year.
Week range starts at 2011-03-28 to 2011-04-03 (because in my database 2010 last week range ends with 2011-03-27) like this I have to generate for 52 weeks.
I want to write a stored procedure, that takes only year as parameter. with this year I have to generate week ranges and insert into my table as shown above.
How can I do this ?
To Send The Date Format If The User Has Specified Only Month And Year, Or Only The Year
Aug 30, 2004I have three web form controls, a ddl that contains the day, another ddl that contains the month and a textbox that contains the current year. To send the date chosen by the user to the database, I join the three web form control values so that the resultant string is ‘day/month/year’ thus:
CmdInsert.Parameters("@Date").Value = day.SelectedItem.Value + "/" + month.SelectedItem.Value + "/" + year.Text()
And the resultant string is: dd/mm/yyyy, for example 30/08/2004.
But the problem is if the user does not select any day or any day and month, then the resultant string is for example; 00/08/2004 or 00/00/2004, but the problem is the database does not accept this format as datetime. How can I do it?
I want the user has the possibility to chose as well only the month and year, and as well only the year. Is it possible to send to the database the datetime format with only the month and year, or only the year?
Thank you,
Cesar
Date Of First Day Of Week For Current Week
Jun 6, 2006seriously now
View 1 Replies View RelatedCalculating Average Count By Day / Week / Month / Quarter / Year
Aug 18, 2014I need developing a query to get the average count by the following:
Day - use daily info for the last ??? days
Weekly - average
- Add all days and divide by 7
- As of Saturday midnight
Monthly - average
- Add all days and divide by days in the month
- As of last save on last day of month
Quarter - average
- Add all days and divide by number of days in the quarter
- As of last day of quarter
Year - average
I don't have requirements for year as of yet.
How can I get the avery count per these timeframes?
SQL Server 2012 :: Comparing Data For A Certain Day Of Week By Month For Every Year
Oct 21, 2014I need to build a report that compares a count on a certain day of the week by month by year by stacks. That is,for first Monday in October 2012 against first Monday in October 2013 for stack DM1 against first Monday in October 2014 stack DM1, same for second Monday, first Tuesday, second Tuesday, ect. Attached is a sample dataset and what I want to achieve.
View 9 Replies View RelatedHow To Do A Year-to-date SQL Query Where Year Commences In August?
Jul 20, 2005Does anyone have an example of an SQL query which returns rows for theyear-to-date, but where the "year" commences on August 1st?e.g. select * from mytable where datefield > last august 1stTIA for any helpIsabel
View 2 Replies View RelatedSQL Server 2008 :: Return Fiscal Year Based On YYYY-week Format
Nov 6, 2015I have a table where hours are being loaded in a weekly basis. The YearWeek is populated when the data is loaded. The value format of the Year Week is 2015-39, 2015-41, etc. I need to calculate the total hours per Fiscal Year.For example, week '2015-39' will be return FY15 and week '2015-41' will return FY16, and so on. By extracting the year, I can do a group by and have total hours for each year.
Currently, I have it working by splitting the value into year and week and then looping through each year and week, so I can assign the totals to the corresponding FY.select sum(hours) as total, yearweek from tablename group by yearweek...Then I loop through using C#.I can return the FY using an actual date,how to do it for year-week format for any given year.
select CASE
WHEN CAST(GETDATE() AS DATE) >
SMALLDATETIMEFROMPARTS(DATEPART(YEAR,GETDATE()),09,30,00,000)
THEN
DATEPART(YEAR,GETDATE()) + 1 ELSE DATEPART(YEAR,GETDATE())
END AS FY
Fiscal Year Date Help??? I Need The First Day Of The Year To Be 01/27.
Feb 4, 2008
Greetings All,
I have a SQL question that maybe someone out there can help me with. Our fiscal year starts on 01/27. I want to write a query that I can pass a date to and it will return the week number (DATEPART("ww", someDate)) of the year using the Fiscal Year Start Date as the base. Datepart works great except it figures the first day of the year as 1/1. Does anyone know how I can make it work with a first day of the year equal to the fiscal year date 01/27. Any help would be appreciated.
TIA,
~ck
Week Number
Jan 23, 2008Hi all!
I'm working on a report that will look like this.
WeekNb - Item - QtySold
1 - Item1 - 25
1 - Item2 - 6
2 - Item1 - 10
2 - Item3 - 73
etc...
I use this function to get the week number DATEPART(wk, transactionDate)
But now I have a problem,
Lets says I want the sells for 2008.
The 1st of January is a Tuesday, but I also want the sells that I made on the 31st of December 2007 as it's on the 2008 1st week (monday).
How can I get this to work ?
Help please
Regards,
Or Tho
Week Number Conversion
Aug 29, 2002I am working with Week Numbers and was wondering if there is a way to display Week 1 as 01.
The problem that I am having is that when I list the weeks from Week 1 to Week 12 is that the sorting is 1, 10, 11, 12, 2, 3 and I would like to get it to look like 01, 02, 03....09, 10.
Thanks......
Week Number Calcluation
Aug 2, 2006Hi Chaps,
I want to calculate the week number by the following rule
"For the week that has the 1st January included if any days are not in January then set the next week as week number 1"
Can any tell me the piece of code
thanx
Anas
Transact SQL :: Get Week Number From DateTime Field?
Aug 21, 2015Any easier way to do what I am trying, without having a table with all the dates and week numbers.
Scenario: Week number of a DateTime Field where the year does not start on January 01<sup>st</sup> but April 1<sup>st</sup> to 31 Mach.
Issue: A week always starts on a Monday so if the 1<sup>st</sup> is on Tuesday, the first week is Tuesday – Sunday, if the 1<sup>st</sup> April is on Friday, the 1<sup>st</sup> week is Friday – Sunday and 7 day periods from there.
CREATE
TABLE [dbo].[DailyCanx](
[ID] [int] IDENTITY(1,1)
NOT NULL,
[DateCancelled] [datetime] NULL
)
ON [PRIMARY]
[code]....
I could create a table with all the start date and end dates of all the week numbers but I think there must be a better way. using SQL Server 2008 R2.