I want to make a function which returns the next Friday, given a day in the week. I can't find a solution which works. For example:
Input -> Output
4/22/08 -> 4/23/08
4/23/08 -> 4/23/08
4/24/08 -> 4/30/08
I can't find a solution which works. According to one website, this should do it:
DECLARE @Friday DATETIME
SET @Friday = '20000107'
SELECT DATEADD(day, ((DATEDIFF(day, @Friday, GETDATE()) / 7) * 7), @Friday)
Hi,
I need to run report that shows activity for Paediatrics Consultants who starts their audit week on Fri 5pm and finish next Fri at 5pm.
Set datefirst would work Fri to Thur but not with hours. And does not always seem to work either.
I need to be able to see historical data and do not want people to enter dates (from to), will group it by wek, consultant
Any clues? Cheers
Petr
I have a weekly report that i want to display mon tues wed thur and fridays date from last week.
I know how to specifically pick one date:
=DateAdd(DateInterval.Day, -6,DateAdd(DateInterval.Day, 1-Weekday(today),Today))
that would set the parameter to monday. But how to do i make it select all the dates from monday-friday of the previous week?
We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.
I'm trying to produce a line chart with 2 axis:
- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders
The chart needs two series:
Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.
Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.
I have two tables:
Orders TableCalendar Table
The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.
My measure for counting orders is simply; # Orders: = countrows[orders].
How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:
- [URL] ...
- [URL] ...
But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.
How can I get Saturday's date given the week number?
This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.
i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday
CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES
[code]....
The output should look like this
weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000
Hi all,
I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.
At the moment, I'm doing this:
Code Snippet
create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]
select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?
So I guess there's two questions:
1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)
2)How come the Yesterday member is not returned by the .members function?
Thanks
Greg
I am adding week hrs using while loop , but it can continue next week hrs also.
I can get every week start hrs while update @tem1 table
employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439
My loop statement
while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end
this is the result while executing loop statement .
employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03
How to update only that week hrs , don't continue next week...
In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????
View 4 Replies View RelatedI need a Select sentence that return me the first week of the month for a given week.
For example If I have week number 12 (Begins 2015/03/16 and Ends 2015/03/22) I need that returns 9, I mean Week number 9 wich is the first week of march (having in mind @@DATEFIRST).
I only need give a week number of the year and then returns the week number of the first week of that month.
I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.
Example (assuming DATEFIRST has been set to 1) : Week 3, 2008 = January 14, 2008
Is there a SQL function that will do this?
Thanks,
Mike
Is there an easy way to find out what date was last friday to a given date? For example today is 20 Sep 2007, what would be the expression to find last friday to this date (14 Sep 2007) ?
View 9 Replies View RelatedHi all...I'm still trying to figure out a query related to the topic I posted yesterday about the table scan...got past that...it was smoke and mirrors...
Now...I have a table that looks like (essentially) this:
BegDate (smalldatetime)
EndDate (smalldatetime)
PortfolioID (int)
WklyPerPriceChg (float)
I am trying to come up with a query that returns a table that looks like this:
BegDate, EndDate, WklyPerPriceChg for PortfolioID1, WklyPerPriceChg for PortfolioID2, WklyPerPriceChg for PortfolioID3, WklyPerPriceChg for PortfolioID4
Here is my select:SELECT TOP 100 PERCENT
T.BegDate as StartDate,
T.EndDate as EndDate,
SP.WklyPerPriceChg as Sandp,
WR.WklyPerPriceChg as WeekRvw,
NA.WklyPerPriceChg as NewAm,
T.WklyPerPriceChg as T100
FROMdbo.WeeklyPortfolioIndex T (nolock) INNER JOIN
dbo.WeeklyPortfolioIndex WR (nolock) ON T.BegDate = WR.BegDate INNER JOIN
dbo.WeeklyPortfolioIndex NA (nolock) ON T.BegDate = NA.BegDate INNER JOIN
dbo.WeeklyPortfolioIndex SP (nolock) ON T.BegDate = SP.BegDate
WHERE((T.BegDate >= @FirstBegDate) AND
(T.EndDate <= @LastEndDate)) AND
SP.PortfolioID = 2 AND
WR.PortfolioID = 67 AND
NA.PortfolioID = 11 AND
T.PortfolioID = 90
ORDER BY T.BegDate DESC
I think you can disregard the date stuff that seems to be working.
What I am finding though, is that the self-join only returns rows for dates that have ALL FOUR of the target portfolioID's. What I want is a row for any day that has AT LEAST ONE of the portfolios, and would like NULL or zero returned in the columns for any portfolioID that does NOT have a row present in the table for that date(range).
I thought I would try a FULL OUTER join rather than the inner one (which I would expect to return an output row if ALL portfolio rows were present for that day)...but that returns more of a cartesian product type thang rather than what I am looking for.
I further thought I need something like a GROUP BY T.BegDate, for example, but then it complains that my select columns are not aggregates.
I know this should be fairly easy...I'm just missing the boat by mere inches, I think...
And missing by "mere inches" is still enough to leave me all wet ;)
Thoughts?
Thanks!
If I put this in crystal reports I can manipulate it ok, but actually translating it to a command isn't so easy for me. I'm terrible at cursors and need some help here, pretty pretty please.
I have a table...
CREATE TABLE [dbo].[StagePayment] (
[PaymentID] [uniqueidentifier] NOT NULL ,
[JobID] [uniqueidentifier] NOT NULL ,
[Paid] [bit] NOT NULL ,
[Sequence] [smallint] NOT NULL ,
[Amount] [decimal](10, 2) NOT NULL ,
[Activity] [varchar] (30) NULL ,
[ActivityID] [uniqueidentifier] NULL ,
[DueDate] [datetime] NULL ,
[InvoiceNumber] [varchar] (50) NULL ,
[DueNext] [bit] NOT NULL
) ON [PRIMARY]
GO
Simple example of the data I need to work with...
PayIDJobIDPaidSequenceAmountDueNext
609412110.000
6B1E 18110.000
297C 25110.000
E175 30114390.000
8CF9 30124390.000
916839114400.000
59F4 39126632.000
BCAF 5411417.500
59225402417.500
8DA0 68112988.000
76C5 68129958.000
0C13 68137566.000
F3F4 68142390.000
What I need to accomplish is flagging the DueNext field if the amount due has not been paid. I cannot rely on the Paid field as it's currently user controlled. I need to compare what's due with the total already paid (stored in another table).
So for instance,
Job #68 - the total amount due would be $22902.00
If the customer has paid $15000.00 then Sequence 3, PayID 0C13, should be flagged as DueNext.
Anyone have a very simple example of a running total cursor that I can reference or a better idea of how to work with this? I appreciate any and all suggestions!
Thanks!
abbra_doo
seriously now
View 1 Replies View RelatedI have a query that run every day to update a summary table which has week number and day of week. what I currently do is delete all records from the summary table and then summarize all the data availabe from four tables adn then populate the table daily. I want to know if I can run the update query to run only for the week number and day of week depending on getdate. Can I do this?
Please help..
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.
The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.
This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.
drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin
declare @YearWeekDayOfWeekvarchar(10)
Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a
return @YearWeekDayOfWeek
end
go
-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.
select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a
Function Test Results:
DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1
(43 row(s) affected)
CODO ERGO SUM
'twas the friday before Christmas,
and all through the company,
everyone appeared to be gone,
except for lil' ol' me.
when I gander at Lotus Notes,
I can see that they are dialed in,
surely asleep on their couch,
but "available over IM".
To be there myself,
is all that I wish.
The highlight of the day
was a lunch of fried fish.
Back to the query analyzer,
dutifully I shall go,
just thought I would post,
to wish you all a merry ho ho...
Here is what I need to accomplishiif(len(sMemoText) > 15, left(sMemoText, 15) + '...', sMemoText)How to convert this into a case or anyother way to get this into aselect statement...Thanks MUCH!Jeff
View 3 Replies View RelatedI have a query and am trying to just return the difference between two dates but not include weekends.For instance, if I have 08/21/2006 - 08/28/2006, there are 6 weekdays. I tried this, but I am getting 7 as a result.SELECT DATEDIFF(weekday, request_start_date, request_end_date) AS days_off, request_id
FROM request Any help would be greatly appreciated.
I am having one requirement where I want to show only first Friday of every month of 2014,2015 and 2016 year.
View 9 Replies View RelatedAttendee Registration URL: http://msevents.microsoft.com/CUI/EventDetail.aspx?EventID=1032290575&Culture=en-US
I'll be talking about database mirroring starting @ 9:30 AM Pacific Daylight Time.
Thanks,
Mark
hi friends,
how to get the date of the first/last day of the week in sql...
can any one help me
Cheers,
raj
Here below is the perfect query i made which is working fine and giving me the sql output but just only need is how to convert to excel and automate the job scheduling so that it run on everyday and send the mail with attachment .
SELECT DN, cn, displayName, mail, objectClass, sAMAccountName, Company, givenName, sn
FROM
(
SELECT DN, cn, displayName, mail, objectClass, sAMAccountName, Company, givenName, sn, 1 [ordering] FROM alpha.dbo.DCADFeed
where sAMAccountName collate SQL_Latin1_General_CP1_CI_AS in
[Code] ....
How to find the saturday in the current week using sql server 2000
View 5 Replies View RelatedI am trying to convert a field that has a Date and Time in smallDateTime format into something that will give me the day of the week that each Date corresponds to. For example, if my Date/Time field says "Jun 7 2001 09:30:00" I want my Day field to automatically say "Thursday". Is there a function that will do this? Or is there something close that will convert a variable of smalldatetime format into a number 0-6 which then can be converted to a day of the week?
View 3 Replies View RelatedIs it possible to write a sql querry to display day of the week?
If it is what is the syntax Pls.
Elsie Reed
Is there a way I can filter dates for last week (May 4 - 10)? This mean that every Mondays, I'll be getting last week's date range. Thanks
View 17 Replies View RelatedHow do I see which is the first day of the week setting in my server?
I was reading about @@DATEFIRST and SET FIRSTDATE, etc. But I don't want to set anything, I just want to know what is the first day of the week set on my server.
Any help will be appreciated.
Thanks
OPi
I need to write a user defined function that will return the date of the first day of a week when provided with the week number. I had an idea of using a while loop with that will keep adding 1 day from January 1st until the week number (found via the DATEPART function) is equal to the supplied week number. Not sure if this is the best way though - any ideas?
Donald.
Is there anyway to get SQL to convert a date to days of the week?
Example, I have a query where the date is "01/01/2006" but I would like it to display "Sunday". Thank you.
this might not be considered a sql problem but here goes anyways.
it was 53 weeks in 1998. however it seems like my computer considered week 53 last year as week 1 in 1999.
so when i perform an operation like this:
select datepart(wk, getdate())
next weeks number is returned. what to do?
Hi,
Is there an easy way to get the position (or number) of the week from a date? By position, I mean week number 1 if we are january 1st. For example:
Date | Week postion
=====================
2001-01-05 | 1
1996-12-28 | 52
1987-06-15 | 26
Thanks a lot,
Skip.