Grouping The Records On The Time Difference

Hi Guys,

I want to group the records on the time difference


declare @tbl as table(id int,intid int,val int,dt datetime)
insert into @tbl
select 1,1,10,'03/31/2006 15:05:22' union all
select 2,1,12,'03/31/2006 15:10:22' union all
select 3,1,15,'03/31/2006 15:15:22' union all
select 4,1,12,'03/31/2006 15:25:22' union all
select 5,1,8,'03/31/2006 15:30:22' union all
select 6,1,6,'03/31/2006 15:35:22' union all
select 7,1,4,'03/31/2006 15:40:22' union all
select 8,1,3,'03/31/2006 15:45:22' union all
select 9,1,10,'03/31/2006 15:50:22'

declare @tbl1 as table(intid int,Tm int,val int)
insert into @tbl1
select 1,5,10

I want a output such that when the val in @tbl goes below the val in @tbl1 for the Tm mentioned in @tbl1
then the time difference should be shown.For example record 1 it starts with 10 the records remain more than 10 till
record number 5.From 5 the records remains lower than 10 till record number 9.So I need to show the the time
difference from record number 5 till 9.
But there is a catch.In @tbl1 there is column named Tm.The time difference sould be calculated only if the diff
more than Tm value in @tbl1.
For example if the value of Tm is changed to say 25 then the there is no need to show the time difference since the
time difference value from record 5 to record 9 is less than 25.
Hope I am clear.

Please help me out.

Regards