HELP Me In This Datediff() Function....

Nov 23, 2006

Hi, I am facing problem rite now.. I want to calculate the date different minutes between 23:00:00 and 01:00:00.

My code :

datediff(Minute,'01:00:00','23:00:00')

The result is 1320 minutes. (22 hours)... But, the result that I want is 120 minutes (2 hours)....

Can anybody help ???

Thanks in advance...

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Using DateDiff Function For Age

Nov 12, 2007

Hi,I'm using the datediff function to display the ages of the users in my database. However the age rounds up once they are 35.5 etc...I could create another function which works similar to the DateDiff function, but use math.floor to always round down, but I need to use this function in a SQL statement WHERE clause. Is there any way around this?Thanks,Curt. 

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Datediff Function

Apr 25, 2007

hi
select datediff(m,'3/5/2003',getdate as experience

output is
Experience
----------
49

select (datediff(m,'3/5/2003',getdate()))/12 as experience

output is
Experience
----------
4

but 49/12 is 4.08333=4.1

how i can get this
Actually my task is to output as years.months

Thanks in advance


Malathi Rao

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Please Help With Datediff Function

Oct 5, 2006

I am trying to break up the age into column from a dob field for a cross tab report. I can query the datediff with an alias but can not individually change the columns I need like a virtual or temp column, but can't figure out how to accomplish it.

use 'Database'

Select datediff(Year, dob, getdate()) As "Under 22", datediff(Year, dob, getdate()) As "22-45",

datediff(Year, dob, getdate()) As "46-65", datediff(Year, dob, getdate()) As "Over 65"

from 'Table'

WHERE (DATEDIFF(yy, dob, GETDATE()) < 22 OR

DATEDIFF(yy, dob, GETDATE()) BETWEEN 22 AND 45 OR

DATEDIFF(yy, dob, GETDATE()) BETWEEN 46 AND 65 OR

DATEDIFF(yy, dob, GETDATE()) > 66) AND (status = 'Current' OR

status = 'Previous' OR

status = 'non-billable')

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A More Precise DateDiff Function

Feb 7, 2007

This will give you the time information about how apart two dates are.CREATE FUNCTION dbo.fnTimeApart
(
@FromTime DATETIME,
@ToTime DATETIME
)
RETURNS @Time TABLE ([year] SMALLINT, [month] TINYINT, [day] TINYINT, [hour] TINYINT, [minute] TINYINT, [second] TINYINT, [millisecond] SMALLINT)
AS
BEGIN
DECLARE@Temp DATETIME,
@Mts INT,
@year SMALLINT,
@month TINYINT,
@day TINYINT,
@hour TINYINT,
@minute TINYINT,
@second TINYINT,
@millisecond SMALLINT

IF @FromTime > @ToTime
SELECT@Temp = @FromTime,
@FromTime = @ToTime,
@ToTime = @Temp

SET@Mts =CASE
WHEN DATEPART(day, @FromTime) <= DATEPART(day, @ToTime) THEN 0
ELSE -1
END + DATEDIFF(month, @FromTime, @ToTime)

SELECT@year = @Mts / 12,
@month = @Mts % 12,
@Temp = DATEADD(month, @Mts, @FromTime)

SELECT@day = datediff(hour, @Temp, @ToTime) / 24,
@Temp = DATEADD(day, @day, @Temp)

SELECT@hour = DATEDIFF(minute, @Temp, @ToTime) / 60,
@Temp = DATEADD(hour, @hour, @Temp)

SELECT@minute = DATEDIFF(second, @Temp, @ToTime) / 60,
@Temp = DATEADD(minute, @minute, @Temp)

SELECT@second = DATEDIFF(millisecond, @Temp, @ToTime) / 1000,
@Temp = DATEADD(second, @second, @Temp),
@millisecond = DATEDIFF(millisecond, @Temp, @ToTime)

INSERT@Time (year, month, day, hour, minute, second, millisecond)
SELECT@year,
@month,
@day,
@hour,
@minute,
@second,
@millisecond

RETURN
ENDAnd to test the functionSELECTd.FromDate,
d.ToDate,
x.*
FROM(
SELECT'19690906' AS FromDate, '19760608' AS ToDate UNION ALL
SELECT'19991231', '20000101' UNION ALL
SELECT'20070207', '20070208' UNION ALL
SELECT'20000131', '20000228' UNION ALL
SELECT'20070202', '20070201' UNION ALL
SELECT'20070207', '20070307' UNION ALL
SELECT'20000131', '20000301' UNION ALL
SELECT'20011231 15:24:13.080', '20020101 17:15:56.343' UNION ALL
SELECT'20011231 17:15:56.343', '20020101 15:24:13.080' UNION ALL
SELECT'20020101 15:24:13.080', '20011231 17:15:56.343' UNION ALL
SELECT'20000131', '20000229'
) AS d
CROSS APPLYdbo.fnTimeApart(d.FromDate, d.ToDate) AS x
ORDER BYd.FromDate,
d.ToDateAnd the output isFromDateToDateyearmonthdayhourminutesecondmillisecond
19690906197606086920000
19991231200001010010000
200001312000022800280000
200001312000022900290000
20000131200003010110000
20011231 15:24:13.08020020101 17:15:56.34300115143263
20011231 17:15:56.34320020101 15:24:13.08000022816736
20020101 15:24:13.08020011231 17:15:56.34300022816736
20070202200702010010000
20070207200702080010000
20070207200703070100000
Peter Larsson
Helsingborg, Sweden

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Feb 9, 2007

I have two date columns one is sent_date and other is approved_date
my requirment is to find the difference between the two dates
which can be minutes/hrs/days.
using datediff function iam able to get it in minusts or hrs but my
output should be of the format hh:mm
23:10 (ie 23 hrs and 10 min) or say
48:00 (for 2 days)

sample date
sent_date approved_date
2/28/06 11:06 2/28/06 11:39
2/2/06 17:42 2/2/06 18:03
2/8/06 16:55 2/8/06 17:38
1/27/06 17:00 1/27/06 17:54
1/26/06 12:08 1/26/06 12:09
2/28/06 15:46 2/28/06 16:26
1/23/06 10:01 1/23/06 10:43
1/26/06 13:46 1/26/06 13:59
1/13/06 13:51 1/13/06 14:47

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Nov 2, 2007

recently i created a system using php and mysql to record faults that the ict technicians could get reported faults out of. so far it does everything i want but some senior members of staff now want the front end to give a report of status, one of the things they wish to see is how many jobs have been completed this week month and year

within my tables is a field date. naturally it has the date submited contained within it. the code i have been using to try and get an output is

mysql_query("SELECT date, datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");

the complete feild is another contained within the datebase. i have also tried SELECT * datediff('day', date, CURRENTDATE) FROM softwarerepairtable WHERE datediff<= '7' and complete='yes' ");

unfortunatly my limited knowledge of php and sql is holding me back on this. any help guys would be appriacted

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Query On Datediff Function

May 18, 2007

Hi,



I am trying to use DataDiff function and I have used the following queries:



1.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.320') as test

Expected Result: 0 milliseconds

Actual Result: 0 milliseconds



2.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.321') as test

Expected Result: 1 milliseconds

Actual Result: 0 milliseconds



3.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.322') as test

Expected Result: 2 milliseconds

Actual Result: 3 milliseconds



4.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.323') as test

Expected Result: 3 milliseconds

Actual Result: 3 milliseconds



5.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.324') as test

Expected Result: 4 milliseconds

Actual Result: 3 milliseconds



6.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.325') as test

Expected Result: 5 milliseconds

Actual Result: 6 milliseconds



7.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.326') as test

Expected Result: 6 milliseconds

Actual Result: 6 milliseconds



8.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.327') as test

Expected Result: 7 milliseconds

Actual Result: 6 milliseconds



9.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.328') as test

Expected Result: 8 milliseconds

Actual Result: 6 milliseconds



10.

select datediff(ms, '2007-05-18 19:35:07.320','2007-05-18 19:35:07.329') as test

Expected Result: 9 milliseconds

Actual Result: 10 milliseconds



Does any one know, why datediff does not return the Expected Result? There does not seem to be any consistency.



Thanks,

Tim

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Jan 25, 2008

I want to create and expression that basically says if a datetime value is today minus 2 days then do another formula.

Right now it looks like this...




Code Snippet
=iif(Fields!Channel_Id.Value="SFE1" and Fields!Report_Date.Value=Today-2,0,(Fields!Total_Apps.Value-Fields!total_apps_null_status.Value))





Basically, it spits an error saying [BC30452] Operator '-' is not defined for types 'Date' and 'Integer'.

Should this be done with DateDiff? if so, how can you specify two days ago?

Thanks much

C-

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Hi



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e.g.



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returns 2007-05-01 00:00:00.000



i.e the first of the current month at midnight.

However, when I try to use a similar expression as a derived column in SSIS it returns a completely different date.



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Any ideas why and how I can obtain the first of a particualr month using SSIS derived column?





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Jan 12, 2007

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Jun 14, 2007

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Sep 28, 2007

hello,
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AS

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May 6, 2008

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The following is my code -
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Hi,

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My first problem is that I'm not able to show hour AND minutes. I wrote this for instance:
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Hello everyone.

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To find @PurchaseTotal for the year, I have to write the following:


SELECT
@PurchaseTotal = Sum(PurchaseTotal)
FROM
_Expenses
WHERE
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To find @PurchaseTotal for a month, I have to write the following:


SELECT
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_Expenses
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To find @PurchaseTotal for all the records, I have to write the following:


SELECT
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It seems you have to write a different select statement for month, day and year. Also If you want a total from all the records you have to write yet another select statement.

Does anyone know of a DateTime function that allows parameters to specify for month, day and Year? Also does anyone know of a DateTime function that works like the COALESCE function to where you can send it a NULL value and give you all the records?

Thank you ahead for any direction you can give.


Alec

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