Haversine SQL Trouble - Distance Between Zip Codes
Jul 20, 2005
I am trying to use the haversine function to find the distance between
two points on a sphere, specifically two zip codes in my database. I'm
neither horribly familiar with SQL syntax nor math equations :), so I
was hoping I could get some help. Below is what I'm using and it is,
as best as I can figure, the correct formula. It is not however,
giving me correct results. Some are close, others don't seem right at
all. Any ideas?
SET @lat1 = RADIANS(@lat1)
SET @log1 = RADIANS(@log1)
SET @lat2 = RADIANS(@lat2)
SET @log2 = RADIANS(@log2)
SET @Dlat = ABS(@lat2 - @lat1)
SET @Dlog = ABS(@log2 - @log1)
SET @R = 3956 /*Approximate radius of earth in miles*/
SET @A = SQUARE(SIN(@Dlat/2)) + COS(@lat1) * COS(@lat2) *
SQUARE(SIN(@Dlog/2))
SET @C = 2 * ATN2(SQRT(@A), SQRT(1 - @A))
/*SET @C = 2 * ASIN(min(SQRT(@A))) Alternative calculation*/
SET @distance = @R * @C
thnx,
cjrsumner
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Mar 28, 2007
This function computes the great circle distance in Kilometers using the Haversine formula distance calculation.
If you want it in miles, change the average radius of Earth to miles in the function.
create function dbo.F_GREAT_CIRCLE_DISTANCE
(
@Latitude1 float,
@Longitude1 float,
@Latitude2 float,
@Longitude2 float
)
returns float
as
/*
fUNCTION: F_GREAT_CIRCLE_DISTANCE
Computes the Great Circle distance in kilometers
between two points on the Earth using the
Haversine formula distance calculation.
Input Parameters:
@Longitude1 - Longitude in degrees of point 1
@Latitude1 - Latitude in degrees of point 1
@Longitude2 - Longitude in degrees of point 2
@Latitude2 - Latitude in degrees of point 2
*/
begin
declare @radius float
declare @lon1 float
declare @lon2 float
declare @lat1 float
declare @lat2 float
declare @a float
declare @distance float
-- Sets average radius of Earth in Kilometers
set @radius = 6371.0E
-- Convert degrees to radians
set @lon1 = radians( @Longitude1 )
set @lon2 = radians( @Longitude2 )
set @lat1 = radians( @Latitude1 )
set @lat2 = radians( @Latitude2 )
set @a = sqrt(square(sin((@lat2-@lat1)/2.0E)) +
(cos(@lat1) * cos(@lat2) * square(sin((@lon2-@lon1)/2.0E))) )
set @distance =
@radius * ( 2.0E *asin(case when 1.0E < @a then 1.0E else @a end ))
return @distance
end
Edit: corrected spelling
CODO ERGO SUM
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Jul 23, 2005
I'm looking to find out how I'd go about setting up a database where avisitor to my site could punch in their postal code, and find out how farthey are from another postal code. For example, AutoTrader has this featureI believe to tell you how far the vehicle is from you. Dating sites havethem so you can do proximity searches.Anyone have any ideas where I could start? I'm thinking the post office,but if anyone else has suggestions, I'm open to hear them.Thanks!
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Jan 21, 2004
Hi
How do I get a nearest distance of a point? For example, I have two tables A and B and I want to find the nearest distance between the records of the two tables. In addition, one of the tables should also give me the distance. The data I have geo spatial data. Can this be done in SQL
Help will be appreciated
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Mar 1, 2007
Is there a recommended practice for mirroring in regards to distance? Is it best practice to mirror with both nodes at the same physical location and use another method for failing over to a remote location or can one just put the other node in the mirror a few thousand miles away? I'm suspecting not.
Any comments??
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Mar 18, 2008
Hi,
please, it is possible to know the edit distance used in the fuzzy lookup/grouping.
On this forum I read fuzzy lookup use 4-gram with fix size.
Does exist any document explaining how fuzzy lookup calculate the similarity? In other word, what kind of edit distance, algorithm is used by fuzzy lookup/grouping?
I hope I was enough clear with my poor english.
Thanks All
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Mar 28, 2007
I'm trying to run a dyncamic query that returns all records within a specific distance of a certain point. The longitude and latitude of each record is stored in the database. The query is constructed from two dynamic variables $StartLatitude and $StartLongitude with represent the starting point.
SELECT UserID, ACOS(SIN($StartLatitude * PI() / 180) * SIN(Latitude * PI() / 180) + COS($StartLatitude * PI() / 180) * COS(Latitude * PI() / 180) * COS(($StartLongitude - Longitude) * PI() / 180)) * 180 / PI() * 60 * 1.1515 AS Distance
FROM HPN_Painters
HAVING (Distance <= 150)
It runs fine until I add the 'HAVING (Distance <= 150)' clause, in which I recieve the error: Invalid column name 'Distance' It seems that Distance cannot be referenced in the HAVING clause.
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Mar 20, 2007
Various posts have noted that mirroring over distance is not advisable or that either async connections should be used.
Are there any limits/recommendations i.e. if two datacenters are a couple of files part with 10GBs fibre links and <50ms response times would this be acceptable for high-availability mirroring?
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Mar 27, 2007
I am new to data mining so please excuse my ignorance. Lets assume
- i have created a cluser model
- identified 3 clusters ( a, b, c)
- each record consists of 15 columns
- collecting new records( 15 variables) real time
what i would like to do is plot these new records programmatically as i collect them realtime. I assume this new record will belong to one of these three clusters. I believe we can find the cluster this new record belongs to by ' SELECT Cluster()....' and distance from the center of the cluster by ClusterDistance(). To plot this on a 2-dimentional space i need (x, y).
ClusterDistance() could be Y but what will be X.
thanks.
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Jan 12, 2008
I have a user defined function, I want to determine the distance between the 2 points. I have it working but i'm having a problem getting to print.
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Code Snippetcreate function dbo.Distance( @lat1 float , @long1 float , @lat2 float , @long2 float)
returns float
as
begin
declare @DegToRad as float
declare @Ans as float
declare @Miles as float
set @DegToRad = 57.29577951
set @Ans = 0
set @Miles = 0
if @lat1 is null or @lat1 = 0 or @long1 is null or @long1 = 0 or @lat2 is
null or @lat2 = 0 or @long2 is null or @long2 = 0
begin
return ( @Miles )
end
set @Ans = SIN(@lat1 / @DegToRad) * SIN(@lat2 / @DegToRad) + COS(@lat1 / @DegToRad ) * COS( @lat2 / @DegToRad ) * COS(ABS(@long2 - @long1 )/@DegToRad)
set @Miles = 3959 * ATAN(SQRT(1 - SQUARE(@Ans)) / @Ans)
set @Miles = CEILING(@Miles)
return ( @Miles )
end
DECLARE @RC float
EXEC Distance '39.943762', '-78.122265', '32.334709', '-96.633546'
PRINT @RC /* in miles */
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Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
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Oct 15, 2015
DECLARE @Latitude NUMERIC(9, 6), @Longitude NUMERIC(9, 6)
DECLARE @MyLatitude NUMERIC(9, 6), @MyLongitude NUMERIC(9, 6)
Set @Latitude = 42.329596;
Set @Longitude = -83.709286;
Set @MyLatitude = 42.430883;
Set @MyLongitude = -82.923642;
Question: How do we calculate the distance in miles between the 2 points.
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Nov 22, 2013
I am trying to write a piece of SQL which gives me a list of enquiries within 10 metre distance of a enquiry.
The idea is to identify possible duplicates.
Table: enquiry
Primary key: enquiry_number
Co-ordinates data fields: enquiry.enquiry_easting and enquiry.enquiry_northing.
I will need to self-search on the same table to find possible enquiries within 10m distance.
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Jun 24, 2005
See here www.merriampark.com/ld.htm for information about the algorithm. This page has a link (http://www.merriampark.com/ldtsql.htm) to a T-SQL implementation by Joseph Gama: unfortunately, that function doesn't work. There is a debugged version in the also-referenced package of TSQL functions (http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=502&lngWId=5), but this still has the fundamental problem that it only works on pairs of strings up to 49 characters.
CREATE FUNCTION edit_distance(@s1 nvarchar(3999), @s2 nvarchar(3999))
RETURNS int
AS
BEGIN
DECLARE @s1_len int, @s2_len int, @i int, @j int, @s1_char nchar, @c int, @c_temp int,
@cv0 varbinary(8000), @cv1 varbinary(8000)
SELECT @s1_len = LEN(@s1), @s2_len = LEN(@s2), @cv1 = 0x0000, @j = 1, @i = 1, @c = 0
WHILE @j <= @s2_len
SELECT @cv1 = @cv1 + CAST(@j AS binary(2)), @j = @j + 1
WHILE @i <= @s1_len
BEGIN
SELECT @s1_char = SUBSTRING(@s1, @i, 1), @c = @i, @cv0 = CAST(@i AS binary(2)), @j = 1
WHILE @j <= @s2_len
BEGIN
SET @c = @c + 1
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j-1, 2) AS int) +
CASE WHEN @s1_char = SUBSTRING(@s2, @j, 1) THEN 0 ELSE 1 END
IF @c > @c_temp SET @c = @c_temp
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j+1, 2) AS int)+1
IF @c > @c_temp SET @c = @c_temp
SELECT @cv0 = @cv0 + CAST(@c AS binary(2)), @j = @j + 1
END
SELECT @cv1 = @cv0, @i = @i + 1
END
RETURN @c
END
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Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
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Feb 1, 2007
hi everyone:
the report show two tables two matrixs
how can i control the distance between them
I want to set the same distance between the table and matrix
or (table and table )
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Jan 2, 2008
Could I implement a failover cluster solution on the two DBs which are based in two different cities?
Possible?
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Jun 14, 2006
I need to be able to take the latitude and logitude of two locations and compare then to determine the number of miles between each point. It doesn't need to account for elevation, but assumes a flat plane with lat and long.
Does anyone have any algorithms in T-SQL to do this?
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Mar 11, 2014
Given the following example;
declare @CustIfno table (AccountNumber int, StoreID int, Distance decimal(14,10))
insert into @CustIfno values ('1','44','2.145223'),('1','45','4.567834'),
('1','46','8.4325654'),('2','44','7.8754345'),('2','45','1.54654323'),
('2','46','11.5436543'), ('3','44','9.145223'),('3','45','8.567834'),
('3','46','17.4325654'),('4','44','7.8754345'),('4','45','1.54654323'),
('4','46','11.5436543')
How can I show the shortest Distance by AccountID and StoreID. Results would look like this;
AccountNumberStoreID Distance
1 44 2.1452230000
2 45 1.5465432300
3 45 8.5678340000
4 45 1.5465432300
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Apr 28, 2008
Hi All,
Does anyone have a Stored Procedure that works perfectly to retrieve all zipcodes within a specified zipcode and distance radius - a zipcode and radius is passed and the Store Procedure result shows all zipcodes that falls within that range.
Thanks in advance
Ade
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Apr 29, 2015
I have the two following locations.
They're both towns in Australia , State of Victoria
Fitzroy,-37.798701, 144.978687
Footscray,-37.799736, 144.899734
After running geography::Point(Latitude, Longitude , 4326) on the latitude and longitude provided for each location, my Geography column for each row is populated with the following:
Fitzroy, 0xE6100000010C292499D53BE642C0A7406667511F6240
Footscray, 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240
In my SQL Query, I have the following which works out the distance between both towns. Geo being my Geography column
DECLARE @s geography = 0xE6100000010C292499D53BE642C0A7406667511F6240 -- Fitzroy
DECLARE @t geography = 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240 -- Footscray
SELECT @s.STDistance(@t)
The result I get is
6954.44911927616
I then looked at formatting this as in Australia we go by KM so after some searching I found two solutions one for Miles and the other KM
So I changed Select statement to look like this
select @s.STDistance(@t)/1000 -- format to KM
My result is then
6.95444911927616
When I go to google maps and do a direction request between the locations provided above it says 10.2km (depending on traffic)
Now I'm new to this spatial data within SQL, why would I get a different result from google maps?
Also I would like to round this number so its easier to use within my where statement so I'm using Ceiling as shown here:
SELECT CEILING(@s.STDistance(@t)/1000)
Is ceiling the correct way to go?
Reason I need to round this is because we are allowing the end user to search by radius so if they pass in 50km I will then say
Where CEILING(@s.STDistance(@t)/1000) < 50
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Nov 19, 2014
I've got a working query which returns all leads within a supplied proximity to a city. I followed a tutorial I googled a couple months ago (can't find it now). It works, but would love others to look the query over (provided DDL and sample data) and tell me if it's as it should be.
Two things I don't like about query:
1. I have to do a UNION to another query that retrieves everything that is in the same city in order to have complete results.
2. very slow to retrieve results (> 1 minute)
Sample DDL: 2 tables
create table dim_lead
(
date_created datetime,
[contact_first_name] varchar(20),
[contact_last_name] varchar(20),
lead_id int,
[Code] .....
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Oct 4, 2006
Hi , I have a database that records the users entrance to a building.The dates are recorded also .I have written some codes that to detect the period of dates that the person has entered.Lets say that a person named as jhon has entered the building on the days 02/08/2006 and 05/08/2006 and 11/08/2006 .Those dates are formated as dd/mm/yyyy . So that john has entered building for 3 times and the periods for the dates are one after another entrance is 3 days + 6 days =9 days .If you divide 9 by 3 we get the arithmetic average number 3 .So that we can say as john visits this building every 3 days and we can guess the next day that he may come. I have coded this and works great .I will paste the codes to the end of my message.But a master programmer friend of mine has said that I should have get this result by without writing code , by just using sql database .But some kind of stored procedure I mustn't use.So that I thought it can be done by views in sqldb .By using sql server enterprise manager I tried to use views but I could not succees. Can anyone guess this ? Here are my vb codes ... database data types : entry_id : int , identity user_id : int movie : nvarchar (50) dateenter : datetime stored procedure that selects the data from db: CREATE PROCEDURE veri_al ( @user_id int ) AS SELECT entry_id ,user_id, movie, dateenter from uye_aktiviteleri where (user_id=@user_id) ORDER BY entry_id ASC GO Code:Dim conn As New SqlClient.SqlConnection conn.ConnectionString = "data source=localhost;initial catalog=AFM;uid=nusret;pwd=araz" Dim command As New SqlClient.SqlCommand command.CommandText = "[veri_al]" command.CommandType = CommandType.StoredProcedure command.Connection = conn command.Parameters.Add("@user_id", SqlDbType.Int, 4).Value = Val(TextBox1.Text) If Not IsNumeric(TextBox1.Text) Then Exit Sub End If Try Dim adapter As New SqlClient.SqlDataAdapter adapter.SelectCommand = command Dim ds As New DataSet adapter.Fill(ds, "uyeler") DataGrid1.DataSource = ds.Tables("uyeler") Dim recordcount As Integer 'Found the recordcount recordcount = ds.Tables("uyeler").Rows.Count Dim mydatarow_ilk As DataRow Dim mydatarow_son As DataRow 'in stored procedure I used ORDER BY entry_id ASC so that first datarow 'will always be the first visit date and the last record of the 'datarow will be the last visit date mydatarow_first= ds.Tables("uyeler").Rows(0) mydatarow_last = ds.Tables("uyeler").Rows(recordcount - 1) Dim first_date As String Dim last_date As String first_date = mydatarow_first("dateenter") last_date =mydatarow_last("dateenter") Dim average_ As Integer 'What is the aveare of the visits ortalama = DateDiff("d", first_date , last_date ) / recordcount Label2.Text = "Member had visited for " & recordcount & "times" Label3.Text = "by average he/she comes here " & ortalama & " day to another." Dim last_time_visit As Integer last_time_visit = DateDiff("d", last-date , DateTime.Today()) Label4.Text = "Until the last visit it had been" & last_time_visit & " days" Label5.Text = "Guess for the next visit is" & DateAdd("d", average_ , last_date) ' MsgBox("average visits" & ortalama & " days" ) Catch z As Exception MsgBox("error : " & z.Message()) Finally MsgBox("Successfully calculated") End Try End Sub
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Jul 20, 2005
Hi,I have a table of Locations around the country. My system produces reportsbased on these Locations. I also have a table containing Brick Codes e.g.Brick Post CodeAB51 AB51AB52 AB52AB55 AB55AB56 AB56AL01 AL1AL02 AL2AL03 AL3AL04 AL4How can I compare the first 3 or 4 letters of the postcode in the Locationstable to the corresponding entry in the Brick Codes table so I can add it tomy report?Thanks for your help
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Oct 10, 2006
Hi,
I have another question about ADO (using C++). I have searched the MSDN but I haven't found a answer to my question (maybe I'm just too stupid)... If I make a connection to my SQL Server there may occur some errors, but how to find out what went wrong ?
In terms of code I have e.g. something like that:
try { connection->Open(ConnectionString,Username,Password,ADODB::adConnectUnspecified);
...} catch (_com_error& e) { long numErrors = connection->Errors->Count; for (long i=0; i<numErrors; i++) { ADODB::ErrorPtr pErr = connection->Errors->GetItem(i); ..... }}
Now I could get the error number by pErr->GetNumber().
But with which symbolic constant has this to be compared to find out which error occured ?? I didn't find any...Or is there another better way to do this ?
P.S. I am using SQL Server 2005 Express
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Jan 8, 2008
How can I test sql codes and don't want to connect to company database?
My company is using sql server 2000.
Below is the test codes which create a simple table, calculate and just want to check before
writing more complicated codes.
Thanks
Daniel Ku
-------------------------------------------------------------------------------------------------------------------------------
create table EquipmentUptime (
equipmentId int not null
,transactionId int not null
,dateOccured datetime not null
)
go
--
insert into EquipmentUptime values (1,200,'01/01/2007')
insert into EquipmentUptime values (2,200,'01/01/2007')
insert into EquipmentUptime values (3,200,'01/01/2007')
insert into EquipmentUptime values (2,100,'02/12/2007')
insert into EquipmentUptime values (1,100,'02/25/2007')
insert into EquipmentUptime values (3,100,'03/10/2007')
insert into EquipmentUptime values (1,200,'03/14/2007')
go
--
select
equipmentId
,100*(cast((cast(sum(UpDays)as decimal(6,3))/cast(365 as decimal(6,3))) as decimal(4,3))) 'PctUpTime'
from
(
select
c.equipmentId
,datediff(dd,c.[UpDate],c.DownDate) 'UpDays'
from
(
select
a.equipmentId
,a.dateOccured as 'UpDate'
,coalesce(
(select top 1
b.dateOccured
from
EquipmentUptime b
where
transactionId=100
and b.equipmentId=a.equipmentId
and b.dateOccured >= a.dateOccured
order by
b.dateOccured asc
),'01/01/2008') as 'DownDate'
from
EquipmentUptime a
where
a.transactionId=200
) c
) d
group by
d.equipmentId
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Jun 28, 2007
My data flow component is throwing an error and the only help I get is the following:
error code: -1071607694
error column: 257
What in the world does this mean? Can it get more cryptic than this?
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Jul 29, 2001
Hi,
I have a table with a primary key, what I really need is something like an IDENTITY, but with the character 'X' and the last to digits of the year added on the front. Is there another way to update the field automatically like an IDENTITY would do, automatically incrementing as fields are inserted.
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Mar 2, 1999
I apologize for the length of this message, but I think I need to include all this info so that the problem is understood. I am having what appears to be a problem capturing the return code from a failed BCP.
I create a stored proc to use BCP to load a table:
create procedure sp_bcp_load as
declare @RC int
execute @RC = master..xp_cmdshell "bcp JON..W4KPV in e:inetpubftprootfinreslaw4kpv.g4000.data /Sdbmtss1 /m 0 /f d:mssqluserdatafinresW4KPV.fmt /Usa /P /e d:mssqluserdatafinrescp1.err /t""|"" /r "
select 'Return code from bcp = ', @RC
if @RC <> 0
BEGIN
print 'BCP Error.'
return (8)
END
GO
If I execute the SP, and encounter a transaction log full error, the return code is still zero:
1000 rows sent to SQL Server. 45000 total
1000 rows sent to SQL Server. 46000 total
Msg 1105, Level 17, State 2:
Server 'DBMTSS1', Line 1:
Can't allocate space for object 'Syslogs' in database 'Jon' because
the 'logsegment' segment is full. If you ran out of space in Syslogs,
dump the transaction log. Otherwise, use ALTER DATABASE or sp_extendsegment to increase the size of the segment.
(54 row(s) affected)
----------------------- -----------
Return code from bcp = 0
If I execute the SP again, it correctly returns a non-zero value:
Msg 1105, Level 17, State 2:
Server 'DBMTSS1', Line 1:
Can't allocate space for object 'Syslogs' in database 'Jon' because
the 'logsegment' segment is full. If you ran out of space in Syslogs, dump the transaction log. Otherwise, use ALTER DATABASE or sp_extendsegment to increase the size of the segment.
(6 row(s) affected)
----------------------- -----------
Return code from bcp = 1
(1 row(s) affected)
BCP Error.
Does anybody have an idea why this behaves this way? Any suggestions on how to trap an error on the first call?
Thanks,
Jon Carter
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Jul 6, 2004
hey all
i am stuck with this little problem
I have a table with people's names and addresses and i have one column for the zip codes. sometimes it includes 5 digit zip codes like '70820' and some times it includes all nine digits like '70820-4565'
is there anyway to move the last 4 digits of the long zip codes into a new column? and remove the dash?
thanks
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Aug 28, 2007
Aloha !
I am posting this information simply as an FYI. This is in reference to the MS-SQL command "CONVERT"
I spent over 2 hours :rolleyes: screwing around trying to find out different ways of formatting dates from MS-SQL into something that makes sense for what I needed. I googled everything I could think of and found multiple references that said the info is available on MSDN.. but I could not find it. What I did find were thousands of relatively useless references to "format codes" for converting dates, but with no references to what the different format codes would ultimately yield, or what format codes were available to use.
What I ended up doing was writing a small script to generate a list of all of the variations I could find.
Below is the script, and the output that it yielded.
Now, before I get bombarded with "there is a better way" I know there probably is. But this is the way that I needed to do it this particular time. If there are technical errors in my explanation, anyone is welcome to correct them. But after 2 hours of messing with this for what should have been a super simple single .0009 second command, I am just irritated beyond belief that it had to be this complicated to find any useful information on the subject. That is why I am creating this. Hopefully it helps someone else.
The format for the MS SQL CONVERT command is :
CONVERT( length_of_output, date, format_code )
length_of_output : is exactly that . the number of characters that you want returned as your result. If you use a length of 6 you will only see the first 6 characters that are returned. I found the longest valid length to be 28 characters, but I went as high as 128 just for giggles and to see if it revealed any secrets.
date : is a valid date, I used directly the getdate() function
format_code : well.. that's the tricky part. See below.
What I did was ran a script that originally went from 1 to 20,000. It crashed at 15. Apparently the format codes are not totally sequential. So I put in an on error resume next.
What I found is that :
1) the codes are not uninterrupted sequential numbers.
2) the code output repeats every 255
3) negative numbers can be used, but its pointless.
4) useful valid codes are in the ranges of : 0-14, 20-25, 100-114, 120, 121, 126, 130 and 131
5) 0-25 typically represent "short dates" with the year being only 2 digits, but there are exceptions
6) 100 and above always returned a 4 digit year. the exception was 130 and 131, I don't know what it was trying to do.
Here is the script i ran
<%
on error resume next
for iintCounter = 0 to 256
SQL = "SELECT CONVERT(CHAR(128), getdate(), " & iintCounter & " ) as TheDate"
Set rsTheDateFormat = TheDatabase.Execute(SQL)
response.write SQL & " = " & rsTheDateFormat("TheDate") & "<br>"
set rsTheDateFormat = nothing
next
%>
and here is the output
SELECT CONVERT(CHAR(128), getdate(), 0 ) as TheDate = Aug 28 2007 6:46AM
SELECT CONVERT(CHAR(128), getdate(), 1 ) as TheDate = 08/28/07
SELECT CONVERT(CHAR(128), getdate(), 2 ) as TheDate = 07.08.28
SELECT CONVERT(CHAR(128), getdate(), 3 ) as TheDate = 28/08/07
SELECT CONVERT(CHAR(128), getdate(), 4 ) as TheDate = 28.08.07
SELECT CONVERT(CHAR(128), getdate(), 5 ) as TheDate = 28-08-07
SELECT CONVERT(CHAR(128), getdate(), 6 ) as TheDate = 28 Aug 07
SELECT CONVERT(CHAR(128), getdate(), 7 ) as TheDate = Aug 28, 07
SELECT CONVERT(CHAR(128), getdate(), 8 ) as TheDate = 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 9 ) as TheDate = Aug 28 2007 6:46:45:507AM
SELECT CONVERT(CHAR(128), getdate(), 10 ) as TheDate = 08-28-07
SELECT CONVERT(CHAR(128), getdate(), 11 ) as TheDate = 07/08/28
SELECT CONVERT(CHAR(128), getdate(), 12 ) as TheDate = 070828
SELECT CONVERT(CHAR(128), getdate(), 13 ) as TheDate = 28 Aug 2007 06:46:45:507
SELECT CONVERT(CHAR(128), getdate(), 14 ) as TheDate = 06:46:45:507
SELECT CONVERT(CHAR(128), getdate(), 20 ) as TheDate = 2007-08-28 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 21 ) as TheDate = 2007-08-28 06:46:45.540
SELECT CONVERT(CHAR(128), getdate(), 22 ) as TheDate = 08/28/07 6:46:45 AM
SELECT CONVERT(CHAR(128), getdate(), 23 ) as TheDate = 2007-08-28
SELECT CONVERT(CHAR(128), getdate(), 24 ) as TheDate = 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 25 ) as TheDate = 2007-08-28 06:46:45.540
SELECT CONVERT(CHAR(128), getdate(), 100 ) as TheDate = Aug 28 2007 6:46AM
SELECT CONVERT(CHAR(128), getdate(), 101 ) as TheDate = 08/28/2007
SELECT CONVERT(CHAR(128), getdate(), 102 ) as TheDate = 2007.08.28
SELECT CONVERT(CHAR(128), getdate(), 103 ) as TheDate = 28/08/2007
SELECT CONVERT(CHAR(128), getdate(), 104 ) as TheDate = 28.08.2007
SELECT CONVERT(CHAR(128), getdate(), 105 ) as TheDate = 28-08-2007
SELECT CONVERT(CHAR(128), getdate(), 106 ) as TheDate = 28 Aug 2007
SELECT CONVERT(CHAR(128), getdate(), 107 ) as TheDate = Aug 28, 2007
SELECT CONVERT(CHAR(128), getdate(), 108 ) as TheDate = 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 109 ) as TheDate = Aug 28 2007 6:46:45:913AM
SELECT CONVERT(CHAR(128), getdate(), 110 ) as TheDate = 08-28-2007
SELECT CONVERT(CHAR(128), getdate(), 111 ) as TheDate = 2007/08/28
SELECT CONVERT(CHAR(128), getdate(), 112 ) as TheDate = 20070828
SELECT CONVERT(CHAR(128), getdate(), 113 ) as TheDate = 28 Aug 2007 06:46:45:930
SELECT CONVERT(CHAR(128), getdate(), 114 ) as TheDate = 06:46:45:930
SELECT CONVERT(CHAR(128), getdate(), 120 ) as TheDate = 2007-08-28 06:46:45
SELECT CONVERT(CHAR(128), getdate(), 121 ) as TheDate = 2007-08-28 06:46:45.943
SELECT CONVERT(CHAR(128), getdate(), 126 ) as TheDate = 2007-08-28T06:46:45.990
SELECT CONVERT(CHAR(128), getdate(), 130 ) as TheDate = 15 ????? 1428 6:46:46:040AM
SELECT CONVERT(CHAR(128), getdate(), 131 ) as TheDate = 15/08/1428 6:46:46:040AM
SELECT CONVERT(CHAR(128), getdate(), 256 ) as TheDate = Aug 28 2007 6:46AM
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Jan 29, 2004
I have files with area codes that are several years old. Everything I've seen about updating area codes deals with area codes that are current and are about to split in the near future. How would I go about bringing old area codes up to date?
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May 2, 2007
I am working with a table that has zip codes listed in lengths of 9,8,5 and 4 digits. The table is created this way and I have no way of changing the data outside of SQL. I am trying to get the last four digits off of all the zip codes so that I only have to work with zip codes in lengths of 5 and 4
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Pizzo36
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