Help W/ Distance Calculation Query
Mar 28, 2007
I'm trying to run a dyncamic query that returns all records within a specific distance of a certain point. The longitude and latitude of each record is stored in the database. The query is constructed from two dynamic variables $StartLatitude and $StartLongitude with represent the starting point.
SELECT UserID, ACOS(SIN($StartLatitude * PI() / 180) * SIN(Latitude * PI() / 180) + COS($StartLatitude * PI() / 180) * COS(Latitude * PI() / 180) * COS(($StartLongitude - Longitude) * PI() / 180)) * 180 / PI() * 60 * 1.1515 AS Distance
FROM HPN_Painters
HAVING (Distance <= 150)
It runs fine until I add the 'HAVING (Distance <= 150)' clause, in which I recieve the error: Invalid column name 'Distance' It seems that Distance cannot be referenced in the HAVING clause.
View 5 Replies
ADVERTISEMENT
Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
View 1 Replies
View Related
Oct 15, 2007
Great Circle distance calculation
Is there any stored procedure or application that implements Great Circle distance calculation
View 1 Replies
View Related
Sep 17, 2015
I have created calcalated measures in a SQL Server 2012 SSAS multi dimensional model by creating empty measures in the cube and use scope statements to fill the calculation.
(so I can use measure security on calculations
as explained here )
SCOPE [Measures].[C];
THIS = IIF([B]=0,0,[Measures].[A]/[Measures].[B]);
View 2 Replies
View Related
Mar 1, 2007
Hello Friends
I have 3 tables
1) Product Id, ShortName
2) IncomingStockId, ProductId, Quantity, InDate
3) OutGoingStock Id, OutDate, ProductId, Quantity
I need to get the results like thisProduct name, quantity in stock today
the "quantity in stock today" = sum (quantity recieved) -sum (quantity sent)
Thank you for your timeSara
View 1 Replies
View Related
Sep 27, 2006
how do i calculate something like this if I have the table with names and count?
Name Count Percent
Name1 27 4.69%
Name2 2 0.35%
....
Totals 576 100.00%
View 3 Replies
View Related
Jul 19, 2007
Hi I am having to convert some oracle reports to Reporting Services. Where I am having difficulty is with the
calculations.
Oracle
TO_DATE(TO_CHAR(Visit Date+Visit Time/24/60/60,'DD-Mon-YYYY HH24:MISS'),'DD-Mon-YYYY HH24:MISS')
this is a sfar as I have got with the sql version
SQLSERVER2005
= DateAdd("s",Fields!VISIT_DATE.Value,Fields!VISIT_TIME.Value246060 )
visit_date is date datatype visit_time is number datatype. have removed : from MI(here)SS as was showing as smiley.
using:
VS 2005 BI Tools
SQLServer 2005
View 5 Replies
View Related
Oct 9, 2015
I have a table with the following creation sql script
CREATETABLE [dbo].[TEST_ENROLLMENT](
[ENROLLMENT_ID] [int]
NOTNULL,
[COURSE_OFFERING_ID] [int]
NOTNULL,
[STUDENT_ID] [int]
[Code] ....
Below is the sql insert for the above table’s data
INSERTINTO TEST_ENROLLMENT(ENROLLMENT_ID,COURSE_OFFERING_ID,STUDENT_ID,DEPT_ID,COURSE_CODE,CREDIT,SECTION_ID,
SEMESTER,ACAD_LEVEL,ACAD_YEAR,DATE_ENROLLED,[STATUS],TOTAL_MARK,GRADE_LETTER,QPE,Honor,INSTRUCTOR_ID,USERNAME
)VALUES(877,356,104,15,'IRD
[Code] ...
I was trying to calculate GPA and Commulative GPA (CGPA) for this student and the formula of GPA is SUM(Honor)/SUM(CREDIT) and the formula of the CGPA is the Average of the SUM(Honor)/SUM(CREDIT) grouped by semester and I wrote the below query which is calculating the GPA correctly but wrongly calculating the CGPA.
How to get the correct CGPA shown in the below desired result set table.
select x.STUDENT_ID,AVG(x.gpa)as
GPA,AVG(y.gpa)AS'COMMULATIVE GPA'
from
(
select STUDENT_ID,SUM(Honor)/SUM(CREDIT)
gpa,ACAD_YEAR,SEMESTER
[Code] ....
Current result set (Incorrect CUMULATIVE GPA)
STUDENT_ID GPA CUMULATIVE GPA
104 2.9 2.9
104 2.25 2.25
104 3 3
Desired result set
STUDENT_ID GPA COMMUTATIVE GPA
104 2.9 2.9
104 2.25 2.575
104 3 2.716
View 5 Replies
View Related
Sep 19, 2005
Hi,
I have a query which gives me the following results:
lLedgerCode sGLCode bDebit TotalSum sGLDesc
61 6843000701 0 600ALPS Holding
33 8345000701 0 1116ALPS Premium Due
56 1000000701 0 1116Regular Premium Income
63 6836000701 1 516ALPS Group Holding
61 6843000701 1 600ALPS Holding
30 6842000701 1 600ALPS Policy Clearing
33 8345000701 1 1116ALPS Premium Due
The Column bDebit has either value '0' or value '1' in it ('0' being debit - positive amount, and '1' - credit, negative amount).
I would like it to show the net amount for each account. Therefore in plain English I would like to take all GLCodes that are the same (eg 6843000701) and sum all amounts that have debit value of '0' and subtract all amounts that have debit value '1'. Therefore I would only see '6843000701' code once, and the amount would be '0' becase 600 - 600 = 0.
The current query is:
SELECT dbo.tbGLTransactions.lLedgerCode, dbo.tbGLTransactions.sGLCode, dbo.tbGLTransactions.bDebit, SUM(curAmount)As TotalSum, dbo.tbLedgerCode.sGLDesc
FROM dbo.tbGLTransactions
INNER JOIN dbo.tbLedgerCode
on dbo.tbGLTransactions.lLedgerCode = dbo.tbLedgerCode.lLedgerCode
WHERE dbo.tbGLTransactions.lGLExtractRun = '452'
Group By dbo.tbGLTransactions.lLedgerCode, dbo.tbGLTransactions.sGLCode, dbo.tbGLTransactions.bDebit, dbo.tbLedgerCode.sGLDesc
Order By dbo.tbGLTransactions.bDebit, dbo.tbLedgerCode.sGLDesc
Is someone able to help me as to how i need to modify this query to get the desired result?
Thanks!
View 8 Replies
View Related
Oct 6, 2004
Hi,
I get a no. of seconds (like '33450', varchar) for each day and I have a day field (like '19.10.2004', varchar).
How can I easily convert it into a datetime-field (like 2004-10-19 09:17:50) ?
Does anybody has an idea ?
:confused:
View 5 Replies
View Related
Nov 20, 2007
i have 3 question :
1. CAN MY MICROSOFT ACCESS Database imported to sql server 2005 ?
2. can i add field for queries with custom calculation like field 1*fiedld 2. like access can do?
3. is that any wizard to do no 1 and 2?
thanks
View 2 Replies
View Related
Nov 20, 2007
i have 3 question :
1. CAN MY MICROSOFT ACCESS Database imported to sql server 2005 ?
2. can i add field for queries with custom calculation like field 1*fiedld 2. like access can do?
3. is that any wizard to do no 1 and 2?
thanks
View 1 Replies
View Related
Aug 6, 2015
This is my syntax, and if I print the value that is stored in each variable @goodtries = 120 @badtries = 25 but when I run the syntax below it gives me 0.00
Declare @goodtries as int, @badtries as int
select @goodtries = convert(decimal(18,4),count(userID))
from table1
WHERE logintype IN ('Valid', 'Success')
select @badtries = convert(decimal(18,4),count(userID))
[code].....
View 7 Replies
View Related
Aug 30, 2007
Hi experts,I am working on SQL server 2005 reporting services and i am getting aproblem in writting a query.Situation is given below.There is one table in database Named ChildNow i have to find the All childrens whoes Age is 13 years Base onSome given parameter.If User select Augus 2007 then It has to calculate the Childs who bornin August 1994 And if he select September Then queryshould show only those child Who born in September 1994 and soon..... And use can select another year month also likeAugust 2009 ...I am writting the following querySelect Child_Name, DOb from Childwhere ((CONVERT(DateTime, A.Date_Of_Birth, 103) >= @ Parameter1And (CONVERT(DateTime, A.Date_Of_Birth, 103) <= @Parameter2)If i know already month and year then i can write easily parameter1and parameter2 But since these are comming from user so i m notfinding how to handle this.Now please suggest me what i have to write in Where statement I thinka lot but not getting any idea about it.Any help wil be appriciated.RegardsDinesh
View 2 Replies
View Related
Jan 21, 2004
Hi
How do I get a nearest distance of a point? For example, I have two tables A and B and I want to find the nearest distance between the records of the two tables. In addition, one of the tables should also give me the distance. The data I have geo spatial data. Can this be done in SQL
Help will be appreciated
View 12 Replies
View Related
Mar 1, 2007
Is there a recommended practice for mirroring in regards to distance? Is it best practice to mirror with both nodes at the same physical location and use another method for failing over to a remote location or can one just put the other node in the mirror a few thousand miles away? I'm suspecting not.
Any comments??
View 2 Replies
View Related
Mar 18, 2008
Hi,
please, it is possible to know the edit distance used in the fuzzy lookup/grouping.
On this forum I read fuzzy lookup use 4-gram with fix size.
Does exist any document explaining how fuzzy lookup calculate the similarity? In other word, what kind of edit distance, algorithm is used by fuzzy lookup/grouping?
I hope I was enough clear with my poor english.
Thanks All
View 1 Replies
View Related
Jul 23, 2005
I'm looking to find out how I'd go about setting up a database where avisitor to my site could punch in their postal code, and find out how farthey are from another postal code. For example, AutoTrader has this featureI believe to tell you how far the vehicle is from you. Dating sites havethem so you can do proximity searches.Anyone have any ideas where I could start? I'm thinking the post office,but if anyone else has suggestions, I'm open to hear them.Thanks!
View 4 Replies
View Related
Mar 20, 2007
Various posts have noted that mirroring over distance is not advisable or that either async connections should be used.
Are there any limits/recommendations i.e. if two datacenters are a couple of files part with 10GBs fibre links and <50ms response times would this be acceptable for high-availability mirroring?
View 4 Replies
View Related
Mar 27, 2007
I am new to data mining so please excuse my ignorance. Lets assume
- i have created a cluser model
- identified 3 clusters ( a, b, c)
- each record consists of 15 columns
- collecting new records( 15 variables) real time
what i would like to do is plot these new records programmatically as i collect them realtime. I assume this new record will belong to one of these three clusters. I believe we can find the cluster this new record belongs to by ' SELECT Cluster()....' and distance from the center of the cluster by ClusterDistance(). To plot this on a 2-dimentional space i need (x, y).
ClusterDistance() could be Y but what will be X.
thanks.
View 6 Replies
View Related
Jan 12, 2008
I have a user defined function, I want to determine the distance between the 2 points. I have it working but i'm having a problem getting to print.
+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
Code Snippetcreate function dbo.Distance( @lat1 float , @long1 float , @lat2 float , @long2 float)
returns float
as
begin
declare @DegToRad as float
declare @Ans as float
declare @Miles as float
set @DegToRad = 57.29577951
set @Ans = 0
set @Miles = 0
if @lat1 is null or @lat1 = 0 or @long1 is null or @long1 = 0 or @lat2 is
null or @lat2 = 0 or @long2 is null or @long2 = 0
begin
return ( @Miles )
end
set @Ans = SIN(@lat1 / @DegToRad) * SIN(@lat2 / @DegToRad) + COS(@lat1 / @DegToRad ) * COS( @lat2 / @DegToRad ) * COS(ABS(@long2 - @long1 )/@DegToRad)
set @Miles = 3959 * ATAN(SQRT(1 - SQUARE(@Ans)) / @Ans)
set @Miles = CEILING(@Miles)
return ( @Miles )
end
DECLARE @RC float
EXEC Distance '39.943762', '-78.122265', '32.334709', '-96.633546'
PRINT @RC /* in miles */
View 3 Replies
View Related
Oct 15, 2015
DECLARE @Latitude NUMERIC(9, 6), @Longitude NUMERIC(9, 6)
DECLARE @MyLatitude NUMERIC(9, 6), @MyLongitude NUMERIC(9, 6)
Set @Latitude = 42.329596;
Set @Longitude = -83.709286;
Set @MyLatitude = 42.430883;
Set @MyLongitude = -82.923642;
Question: How do we calculate the distance in miles between the 2 points.
View 5 Replies
View Related
Nov 22, 2013
I am trying to write a piece of SQL which gives me a list of enquiries within 10 metre distance of a enquiry.
The idea is to identify possible duplicates.
Table: enquiry
Primary key: enquiry_number
Co-ordinates data fields: enquiry.enquiry_easting and enquiry.enquiry_northing.
I will need to self-search on the same table to find possible enquiries within 10m distance.
View 1 Replies
View Related
Jun 24, 2005
See here www.merriampark.com/ld.htm for information about the algorithm. This page has a link (http://www.merriampark.com/ldtsql.htm) to a T-SQL implementation by Joseph Gama: unfortunately, that function doesn't work. There is a debugged version in the also-referenced package of TSQL functions (http://www.planet-source-code.com/vb/scripts/ShowCode.asp?txtCodeId=502&lngWId=5), but this still has the fundamental problem that it only works on pairs of strings up to 49 characters.
CREATE FUNCTION edit_distance(@s1 nvarchar(3999), @s2 nvarchar(3999))
RETURNS int
AS
BEGIN
DECLARE @s1_len int, @s2_len int, @i int, @j int, @s1_char nchar, @c int, @c_temp int,
@cv0 varbinary(8000), @cv1 varbinary(8000)
SELECT @s1_len = LEN(@s1), @s2_len = LEN(@s2), @cv1 = 0x0000, @j = 1, @i = 1, @c = 0
WHILE @j <= @s2_len
SELECT @cv1 = @cv1 + CAST(@j AS binary(2)), @j = @j + 1
WHILE @i <= @s1_len
BEGIN
SELECT @s1_char = SUBSTRING(@s1, @i, 1), @c = @i, @cv0 = CAST(@i AS binary(2)), @j = 1
WHILE @j <= @s2_len
BEGIN
SET @c = @c + 1
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j-1, 2) AS int) +
CASE WHEN @s1_char = SUBSTRING(@s2, @j, 1) THEN 0 ELSE 1 END
IF @c > @c_temp SET @c = @c_temp
SET @c_temp = CAST(SUBSTRING(@cv1, @j+@j+1, 2) AS int)+1
IF @c > @c_temp SET @c = @c_temp
SELECT @cv0 = @cv0 + CAST(@c AS binary(2)), @j = @j + 1
END
SELECT @cv1 = @cv0, @i = @i + 1
END
RETURN @c
END
View 20 Replies
View Related
Jul 20, 2005
I am trying to use the haversine function to find the distance betweentwo points on a sphere, specifically two zip codes in my database. I'mneither horribly familiar with SQL syntax nor math equations :), so Iwas hoping I could get some help. Below is what I'm using and it is,as best as I can figure, the correct formula. It is not however,giving me correct results. Some are close, others don't seem right atall. Any ideas?SET @lat1 = RADIANS(@lat1)SET @log1 = RADIANS(@log1)SET @lat2 = RADIANS(@lat2)SET @log2 = RADIANS(@log2)SET @Dlat = ABS(@lat2 - @lat1)SET @Dlog = ABS(@log2 - @log1)SET @R = 3956 /*Approximate radius of earth in miles*/SET @A = SQUARE(SIN(@Dlat/2)) + COS(@lat1) * COS(@lat2) *SQUARE(SIN(@Dlog/2))SET @C = 2 * ATN2(SQRT(@A), SQRT(1 - @A))/*SET @C = 2 * ASIN(min(SQRT(@A))) Alternative calculation*/SET @distance = @R * @Cthnx,cjrsumner
View 7 Replies
View Related
Feb 1, 2007
hi everyone:
the report show two tables two matrixs
how can i control the distance between them
I want to set the same distance between the table and matrix
or (table and table )
View 3 Replies
View Related
Jan 2, 2008
Could I implement a failover cluster solution on the two DBs which are based in two different cities?
Possible?
View 6 Replies
View Related
Jun 14, 2006
I need to be able to take the latitude and logitude of two locations and compare then to determine the number of miles between each point. It doesn't need to account for elevation, but assumes a flat plane with lat and long.
Does anyone have any algorithms in T-SQL to do this?
View 5 Replies
View Related
Mar 11, 2014
Given the following example;
declare @CustIfno table (AccountNumber int, StoreID int, Distance decimal(14,10))
insert into @CustIfno values ('1','44','2.145223'),('1','45','4.567834'),
('1','46','8.4325654'),('2','44','7.8754345'),('2','45','1.54654323'),
('2','46','11.5436543'), ('3','44','9.145223'),('3','45','8.567834'),
('3','46','17.4325654'),('4','44','7.8754345'),('4','45','1.54654323'),
('4','46','11.5436543')
How can I show the shortest Distance by AccountID and StoreID. Results would look like this;
AccountNumberStoreID Distance
1 44 2.1452230000
2 45 1.5465432300
3 45 8.5678340000
4 45 1.5465432300
View 7 Replies
View Related
Mar 28, 2007
This function computes the great circle distance in Kilometers using the Haversine formula distance calculation.
If you want it in miles, change the average radius of Earth to miles in the function.
create function dbo.F_GREAT_CIRCLE_DISTANCE
(
@Latitude1 float,
@Longitude1 float,
@Latitude2 float,
@Longitude2 float
)
returns float
as
/*
fUNCTION: F_GREAT_CIRCLE_DISTANCE
Computes the Great Circle distance in kilometers
between two points on the Earth using the
Haversine formula distance calculation.
Input Parameters:
@Longitude1 - Longitude in degrees of point 1
@Latitude1 - Latitude in degrees of point 1
@Longitude2 - Longitude in degrees of point 2
@Latitude2 - Latitude in degrees of point 2
*/
begin
declare @radius float
declare @lon1 float
declare @lon2 float
declare @lat1 float
declare @lat2 float
declare @a float
declare @distance float
-- Sets average radius of Earth in Kilometers
set @radius = 6371.0E
-- Convert degrees to radians
set @lon1 = radians( @Longitude1 )
set @lon2 = radians( @Longitude2 )
set @lat1 = radians( @Latitude1 )
set @lat2 = radians( @Latitude2 )
set @a = sqrt(square(sin((@lat2-@lat1)/2.0E)) +
(cos(@lat1) * cos(@lat2) * square(sin((@lon2-@lon1)/2.0E))) )
set @distance =
@radius * ( 2.0E *asin(case when 1.0E < @a then 1.0E else @a end ))
return @distance
end
Edit: corrected spelling
CODO ERGO SUM
View 20 Replies
View Related
Apr 28, 2008
Hi All,
Does anyone have a Stored Procedure that works perfectly to retrieve all zipcodes within a specified zipcode and distance radius - a zipcode and radius is passed and the Store Procedure result shows all zipcodes that falls within that range.
Thanks in advance
Ade
View 5 Replies
View Related
Apr 29, 2015
I have the two following locations.
They're both towns in Australia , State of Victoria
Fitzroy,-37.798701, 144.978687
Footscray,-37.799736, 144.899734
After running geography::Point(Latitude, Longitude , 4326) on the latitude and longitude provided for each location, my Geography column for each row is populated with the following:
Fitzroy, 0xE6100000010C292499D53BE642C0A7406667511F6240
Footscray, 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240
In my SQL Query, I have the following which works out the distance between both towns. Geo being my Geography column
DECLARE @s geography = 0xE6100000010C292499D53BE642C0A7406667511F6240 -- Fitzroy
DECLARE @t geography = 0xE6100000010C89B7CEBF5DE642C02D23F59ECA1C6240 -- Footscray
SELECT @s.STDistance(@t)
The result I get is
6954.44911927616
I then looked at formatting this as in Australia we go by KM so after some searching I found two solutions one for Miles and the other KM
So I changed Select statement to look like this
select @s.STDistance(@t)/1000 -- format to KM
My result is then
6.95444911927616
When I go to google maps and do a direction request between the locations provided above it says 10.2km (depending on traffic)
Now I'm new to this spatial data within SQL, why would I get a different result from google maps?
Also I would like to round this number so its easier to use within my where statement so I'm using Ceiling as shown here:
SELECT CEILING(@s.STDistance(@t)/1000)
Is ceiling the correct way to go?
Reason I need to round this is because we are allowing the end user to search by radius so if they pass in 50km I will then say
Where CEILING(@s.STDistance(@t)/1000) < 50
View 2 Replies
View Related
Nov 19, 2014
I've got a working query which returns all leads within a supplied proximity to a city. I followed a tutorial I googled a couple months ago (can't find it now). It works, but would love others to look the query over (provided DDL and sample data) and tell me if it's as it should be.
Two things I don't like about query:
1. I have to do a UNION to another query that retrieves everything that is in the same city in order to have complete results.
2. very slow to retrieve results (> 1 minute)
Sample DDL: 2 tables
create table dim_lead
(
date_created datetime,
[contact_first_name] varchar(20),
[contact_last_name] varchar(20),
lead_id int,
[Code] .....
View 9 Replies
View Related