Hi all,
I am trying to create a view with approx. 3000 columns... and got the following error message:
"CREATE VIEW failed because column 'HSEPRIN' in view 'MyTestView' exceeds the maximum of 1024 columns.
Is it mean the max number of columns for each table is 1024? I thought in SQL server the table can contain as much information as possible.
Anyone can help to answer my question?
Thank you in advance.
Write a CREATE VIEW statement that defines a view named Invoice Basic that returns three columns: VendorName, InvoiceNumber, and InvoiceTotal. Then, write a SELECT statement that returns all of the columns in the view, sorted by VendorName, where the first letter of the vendor name is N, O, or P.
This is what I have so far,
CREATE VIEW InvoiceBasic AS
SELECT VendorName, InvoiceNumber, InvoiceTotal
From Vendors JOIN Invoices
ON Vendors.VendorID = Invoices.VendorID
[code]...
I compared view query plan with query plan if I run the same statementfrom view definition and get different results. View plan is moreexpensive and runs longer. View contains 4 inner joins, statisticsupdated for all tables. Any ideas?
View 10 Replies View RelatedHi All,
I'm trying to create a proc for granting permission for developer, but I tried many times, still couldn't get successful, someone can help me? The original statement is:
Create PROC dbo.GrantPermission
@user1 varchar(50)
as
Grant create table to @user1
go
Grant create view to @user1
go
Grant create Procedure to @user1
Go
Thanks Guys.
I keep getting the following error message whenever I try to create a new view from my local machine.
An unexpected error happened during this operation...Query Designer encountere a Query error: Unspecified error
Any help would be greatly appreciated. Thanks
Hi,
I have currently a problem with setting up the permissions for some developers. My configuration looks like this.
DB A is the productive database.
DB B is a kind of "development" database.
Now we have a couple of users call them BOB, DAVID, ...
who are members of the db role db_reader and db_writer for the productive db a but they should be allowed to do nearly everything on db b.
Therefor I added them to the db role db_owner for db b.
For testing purposes I tried to "CREATE" a view TEST as BOB in database B but I received the error message
'Msg 262, Level 14, State 1, Procedure Test, Line 3
CREATE VIEW permission denied in database 'b'.'
I cross checked the permissions on db level and I even granted all available permissions on db level but nevertheless I receive this error message.
What's my mistake?
Of course it worked fine when I give them sysadmin rights but then they have far too much permissions.
Regards,
Stefan
I had given one of our developers create view permissions, but he wants to also modify views that are not owned by him, they are owned by dbo.
I ran a profiler trace and determined that when he tries to modify a view using query designer in SQLem or right clicks in SQLem on the view and goes to properties, it is performing a ALTER VIEW. It does the same for dbo in a trace (an ALTER View). He gets a call failed and a permission error that he doesn't have create view permissions, object is owned by dbo, using both methods.
If it is doing an alter view how can I set permissions for that and why does it give a create view error when its really doing an alter view? Very confusing.
Ok I have a query "SELECT ColumnNames FROM tbl1" let's say the values returned are "age,sex,race".
Now I want to be able to create an "update" statement like "UPATE tbl2 SET Col2 = age + sex + race" dynamically and execute this UPDATE statement. So, if the next select statement returns "age, sex, race, gender" then the script should create "UPDATE tbl2 SET Col2 = age + sex + race + gender" and execute it.
Hi,Just recently I am getting the following error when trying to connect to an SQL DB: Exception has been thrown by target of an invocation. This happens even if I create a new website/solution. Procedure I use:open server explorer and click on create a new connectionchoose SQL server from the listenter my IP address and credentials, click on test and everything is fine. When I go to select the DB the dropdown box is empty, if I type in my database name and click on ok I get the following message:Exception has been thrown by target of an invocationI know it is nothing to do with SQL or credentials as I can create a datasource to my SQL server using my colleagues computer!I have removed VS 2005 from my computer and reinstalled only to be met with the same problem.reinstalling my computer is a last resort!Any ideas?Cheers, Ps, I can connect to my DB using VB code behind.
View 3 Replies View RelatedHi,
View 3 Replies View RelatedI am trying to run a query on my sql server and get the following error message:
"An error occurred while executing batch. Error message is: The directory name is invalid."
how do I fix?
Hi when I am performing a merge replication between my PDA (SQL CE) and SQL I get the above message. There is no information about it anywhere.
Any ideas?
Thanks in advance.
I recently installed VB Studio Express 2008, which also installed SQL Server Compact Edition. I was going thro the online tutorial from Microsoft, which tells you to create a connection to the Northwind DB. But, when I tried to connect, I get an error message saying access is not allowed. Note that the is running under Vista Home Premium. I have tried searching for an answer to this question, but have not found an answer that solves my problem. The closest was a similar problem for a C# application running in Internet Explorer, and the answer for that one was to change security settings in IE. But, for this demo, IE was not involved.
View 11 Replies View RelatedDear All,I have written an update trigger that should write a message to an audittable When I try to update any field in the table I recieve the followingerror message -[ODBC Sql Server Driver] [Sql Server] Stirng or Binary data would betrunicated[ODBC Sql Server Driver] [Sql Server] The statement has been termined.I have looked and what has been suggested is to use the response.write len()to check the length of field that I am updating. Being fairly new toSQL-Server, I do not know how to do this. Any help will be most welcome.Thanks,Jeff
View 2 Replies View RelatedWhen I use following command it works fine.
CREATE VIEW dbo.[ikw_custom]
AS
SELECT * FROM rns_keyword.dbo.ikw_custom
but if I use following command with condition it gives me an error.
if not exists(select * from sysobjects where name ='ikw_custom' and type='V')
begin
CREATE VIEW dbo.[ikw_custom]
AS
SELECT * FROM rns_keyword.dbo.ikw_custom
end
help will be appriciated.
Thanks in advance
-Balbir
I am learning how to work with MSSQL
here is what I like to do
I have a table with URLs like this "www.urls.com" I need to create a view that will insert this "http://" before "www.urls.com" can some please let me know what I need to do
Thank you
Hello All;
I'm new to SQL, and developing my first application using SQL 2000 as the back end for my data.
Can anyone tell me if I can create an SQL View from VBA?
I'm trying to create a data view that access various records from a single table, and it has to distribute that data 2 14 different subforms, representing different days in a 2 week period, which is distingiushed by a field called "Day", that is numbered from 1 to 14.
I also have a summary subform that has the weekly summary (days 1 to 7 and 8 to 14) on seperate subforms. In total I have 16 subforms, which actually source from a single table, just split depending on the day in the period.
As I see it now, creating views iis the best way for me to go, but I also have to be able to change the period id on the fly, so I'm think I have to use VBA to generate these views.
Does any of this make sense, and am I on the right track??
hi,if the below query
select DISTINCT group_module_menu_info.menulink FROM
user_group_role_info,group_role_module_info,group_ module_menu_info
where user_group_role_info.userid=user_table.userid and
((group_module_menu_info.moduleid = user_group_role_info.moduleid)OR
(user_group_role_info.roleid=group_role_module_inf o.roleid and
group_module_menu_info.moduleid = group_role_module_info.moduleid))
if i want to create a view
how ?
thank you!
Create a view showing every order that was shipped to Spain. Name the destination column "DestinationSpain". Include code that checks if the view already exists. If it does, it should be dropped and re-created.
Use Northwind
Go
DROP VIEW Spain_Orders
Go
CREATE VIEW Spain_Orders
AS
SELECT *
FROM Orders
WHERE ShipCountry = 'Spain'
this is what I get.
server: Msg 3701, Level 11, State 5, Line 1
Cannot drop the view 'Spain_Orders', because it does not exist in the system catalog.
albanie
I know IIf doesn't exist in SQL. However, I am creating a view and want to check the value of a field and if it is 1 the field returns 'This value' if it is 2 then 'That value' , if 3 then 'Another value'.
How can I do this ?
Hi Gurus,I'm a beginner. Would you please tell me if it's possible to create a viewhaving a calcuated column based on the condition of the column on the sqltable.create view vwImaging ASselectEmpID, LastName, FirstName, EmpTag = 'Act' ifFROM tblPerPayI have a table EMP:SSN (char 9)A view giving a formatted SSN (XXX-XX-XXXX,) a--Message posted via http://www.sqlmonster.com
View 3 Replies View RelatedHi.I created a simple view with the following statements:CREATE VIEW dbo.VIEW1ASSELECT dbo.VIEW_ALL.ID,dbo.VIEW_ALL.Code,Another.dbo.OTHER_VIEW.Label as SpecialCodeFROM dbo.VIEW_ALL LEFT OUTER JOINAnother.dbo.OTHER_VIEW ON(dbo.VIEW_ALL.Code + '_0') = Another.dbo.OTHER_VIEW.LabelWhen I run :select * from VIEW1 where code = 'abcde',I would get all 10 rows that are of the same data where the code is'abcde'. But what I thought it should return is really just one rowsince the rest of the 9 rows are exactly the same! I know that I canget my result if I useselect DISTINCT * from VIEW1 where code = 'abcde'But, is there any way I could change my SQL statements(CREATE VIEW)above so that I automatically get 1 row instead of 10 rows of exactlythe same value without using DISTINCT?Thank you for any help.
View 7 Replies View RelatedI have a table in my program which going all the invoices,and I want to create a view where I can see the quantity of the products as many times by 1 as the quantity in the invoice:
Invoice:
Product name quantity
woods 3
at the view
woods 1
woods 1
woods 1
Thank you.
how to create view in sql server 2005 that recognize Identity And Primary key of base table
View 2 Replies View RelatedGood afternoon,
I have a user that needs read only access to all tables in a particular database - Which is working fine.
He also needs to create views, as well as the above, but nothing else.
Is this possible?
Many thanks.
CREATE VIEW getUsedColumns AS SELECT * FROM (SELECT DISTINCT attr FROM iba UNION SELECT DISTINCT attr FROM new_iba) WHERE attr != 0;
its working with oracle
how to chenge in t-sql
thanx
Hey guys, im really new ASP.net. I just upsized my access database to SQL Server Express and I'm trying to mimic some view functionalitty I had in access. I think they call it the expression builder.So bassically Im trying to make a column that does some calculations on other columns. Like:if columnA-columnB > 100 then columnC='YES' else columnC='NO'Does anyone know how to do this? I want to add this column in a view. Can i perhaps just do it in the datagrid? I'm so frusterated at the moment, ive been trying for about 3 hours!Thanks in advance for your help.
View 1 Replies View RelatedI need to create view from the results of executing dynamic SQL.Query like this have incorrect syntax: CREATE VIEW vModuleCatalogObjectValues AS EXECUTE sp_executesql @sql, @paramDefinition, @moduleId; ENDWhat i need to do to get it work?!
View 1 Replies View RelatedHi,
Is there a way you can give a user a permission to "Create View" only but not to create other objects like tables or SP's in a database.
Thanks
Hi,
I tried to create a view on following 4 tables with two different syntaxes. One with ANSI syntax and other with conventional(using WHERE clause). Both SELECT work fine and return same result sets. Views are created in both cases. SELECT from Conventional_View works fine But SELECT from the ANSI_View returns error message without Error Number as :
'DB-Library Process Dead - Connection Broken'
CREATE TABLE dbo.SILT01 (
SILF01A varchar (8) NOT NULL ,
SILF01B varchar (25) NULL ,
SILF01C smallint NULL ,
CONSTRAINT SILT01_PK PRIMARY KEY CLUSTERED
(SILF01A)
)
GO
CREATE TABLE dbo.SILT19 (
SILF23A varchar (8) NOT NULL ,
SILF01A varchar (8) NOT NULL ,
CONSTRAINT aaaaaSILT19_PK PRIMARY KEY CLUSTERED
(
SILF23A,
SILF01A
)
)
GO
CREATE TABLE dbo.SILT20 (
SILF23A varchar (8) NOT NULL ,
SILF15A varchar (8) NOT NULL ,
SILF01A varchar (8) NOT NULL ,
CONSTRAINT aaaaaSILT20_PK PRIMARY KEY CLUSTERED
(
SILF23A,
SILF15A,
SILF01A
)
)
GO
CREATE TABLE dbo.SILT23 (
SILF23A varchar (8) NOT NULL ,
SILF23B varchar (30) NULL ,
SILF23C varchar (40) NULL ,
SILF23D varchar (8) NULL ,
SILF23E varchar (1) NULL ,
SILF23F text NULL ,
SILF23G varchar (25) NULL ,
SILF23H varchar (8) NULL ,
SILF23I varchar (25) NULL ,
SILF23J varchar (25) NULL ,
SILF23K text NULL ,
SILF23L varchar (25) NULL ,
SILF23M varchar (8) NULL ,
SILF23N varchar (25) NULL ,
SILF23O varchar (25) NULL ,
SILF23P text NULL ,
SILF23Q varchar (25) NULL ,
SILF23R varchar (8) NULL ,
SILF23S varchar (25) NULL ,
SILF23T varchar (25) NULL ,
SILF23U varchar (15) NULL ,
SILF23V varchar (15) NULL ,
SILF23W varchar (15) NULL ,
SILF23X varchar (15) NULL ,
SILF23Y varchar (15) NULL ,
SILF23Z varchar (15) NULL ,
SILF23A1 varchar (15) NULL ,
SILF23A2 varchar (15) NULL ,
SILF23A3 varchar (15) NULL ,
SILF23A4 varchar (15) NULL ,
SILF23A5 varchar (15) NULL ,
SILF23A6 varchar (3) NULL ,
CONSTRAINT aaaaaSILT23_PK PRIMARY KEY CLUSTERED
(
SILF23A
)
)
GO
create view ANSI_View as
SELECT DISTINCT SILT01.SILF01A, SILT23.SILF23A,
SILT23.SILF23B, SILT20.SILF15A
FROM ((SILT01 INNER JOIN SILT19 ON SILT01.SILF01A = SILT19.SILF01A)
INNER JOIN SILT23 ON SILT19.SILF23A = SILT23.SILF23A)
LEFT JOIN SILT20 ON (SILT19.SILF01A = SILT20.SILF01A) AND
(SILT19.SILF23A = SILT20.SILF23A)
create view Conventional_View as
SELECT DISTINCT SILT01.SILF01A, SILT23.SILF23A,
SILT23.SILF23B, SILT20.SILF15A
FROM SILT01, SILT19,SILT23, SILT20
WHERE ( SILT01.SILF01A = SILT19.SILF01A AND
SILT19.SILF23A = SILT23.SILF23A ) AND
( ( SILT19.SILF01A *= SILT20.SILF01A) AND
(SILT19.SILF23A *= SILT20.SILF23A) )
SELECT * FROM ANSI_VIEW
'DB-Library Process Dead - Connection Broken'
SELECT * FROM Conventional_View (Works fine)
Expecting Help or Suggestions from experts.
Thanx,
Gunvant Patil( gunvantp@mail.usa.com )
G'day all.
I am trying to create an index on a view that joins two tables.
I get the classic error of course:
'Cannot index the view 'dbname.dbo.HJC_net'. It contains one or more disallowed constructs.'
Thing that gets me is that it all seems pretty normal stuff and I can't see what is stopping it.
Code is below and any help greatly appreciated.
CREATE VIEW dbo.HJC_net WITH SCHEMABINDING AS
SELECTt_number
FROM dbo.ticket_cancellations RIGHT OUTER JOIN
dbo.tickets ON dbo.ticket_cancellations.tc_system_ref = dbo.tickets.t_number
WHERE dbo.tickets.t_cancelled <> - 1 OR
-- Add all cancellation codes that are to be excluded from the NET view below
(dbo.ticket_cancellations.tc_cancellation_code <> 83943
AND dbo.ticket_cancellations.tc_cancellation_code <> 83946)
GO
-- Create a clustered index, it MUST be unique
CREATE UNIQUE CLUSTERED INDEX t_number_unique ON HJC_net(t_number)
I have to try and get my head around this question and ive never seen sql this advanced before.please set me in the right direction.thanks in advance.Using the meeting table schema below provide a SQL statement to create a view in Microsoft SQL Server that will return only 1 record displaying the contents of the MEETING_NUMBER field. The rules for the view are as follows:• The START_DATE field which contains the start date of the meeting record must contain a value before the current system date.• The START_DATE field must be the closest date to the current system date.ID int (4)DOC_CLASS varchar (30)DOC_NUMBER int (4)REVISION int (4)START_DATE datetime (8)FINISH_DATE datetime (8)MEET_TIME varchar (5)VENUE varchar (50)TYPE varchar (50)MEETING_NUMBER varchar (11)CUTOFF_PERIOD int (4)CUTOFF_TIME varchar (5)AGENDA_STATUS varchar (50)SUBJECT varchar (50)SPONSORING_MIN varchar (50)SUPP_AGENDA_STATUS varchar (50)Possible answer:select meeting_numberfrom meetingwhere start_date < getdate()order by start_date desc
View 14 Replies View Relatednow i have two table
1st table
type_id type_name
4 a
5 b
6 c
2nd table
category_id category_name type_id
6 aaa 4
7 bbb 5
9 ccc 6
i want to join two table to create view
autonumber type_name category_name
1 c ccc
2 b bbb
3 a aaa
how can i write this sql to create autonumber field
thanks