Help With Expression To Display A Per-week Daterange Value!

Jul 16, 2007

Here is the table I��m working with:

dbo.Reject

Rejections

Amount

Date

5

12

1/4/07

9

3

1/6/07

1

6

1/23/07

0

0

2/11/07

7

8

2/20/07

Is it possible to write an expression for RS2005 in the details row in a table that will separate and add the rejection and amount field values for each calendar week and lay them out to look like below:

Week

Rejections

Amount

1

14

15

2

0

0

3

0

0

4

1

6

5

0

0

6

0

0

7

0

0

8

7

8

I��m trying to make a report that shows the number of rejections and amounts on a week to week basis. So I need RS2005 to add the rejections and amounts for each week date range and display it line-by-line automatically on a per-week basis.

Week 1 is 1/1/07-1/6/07 according to DATEPART(WEEK,Date) and so on��

Thanks in advance!

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Display Records For This Week

Apr 15, 2008

hi friends,

how to display the records for this week?

for today i used this query to dispaly the values

select count(*) from tbl_voting v,tbl_lkvotefor l where v.voteforid=l.voteforid and v.creationdatetime=CONVERT(VARCHAR(10), GETDATE(), 101)

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Nov 4, 2015

I want to display week between two dates as below.

requirement is as:

suppose there are two dates.(which will comes dynamically, so no. of weeks varied)
10/20/2015 and 01/01/2016

Now between this two dates, i want to calculate number of weeks on another date which is coming from table.

Say for example the column date is coming as 10/23/2015 then it will fall in week-1

Same way if 11/01/2015 falls in week2.

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Oct 4, 2013

In our organization we have fixed two weeks menu. On our intranet i have database entries with two weeeks menu without dates. I want first six entries to appear in one week and next six entries to appear in another week. How can i achieve this with SQL query.

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Display Summary Week Total Rows From Sql Database

Sep 22, 2007

(I moved this thread from datagrid area) I have a sql database that has individual records consisting of name, date, hours worked among other fields.Date and name is part of a unique identifier, so there can NOT be two records for the same person for the same date. My users need a grid view that displays days worked in ONE LINE per user. I have gotten close, but can't quite get the last part. Ive tried group by, distinct, and with rollup and no luck.TABLE:dan       12/13/2012 12:00:00 AM9.123dan       12/14/2012 12:00:00 AM3.123123cara      12/12/2012 12:00:00 AM4.222cara      12/16/2012 12:00:00 AM3.3333cara      12/17/2012 12:00:00 AM2   CODE: Select distinct(name), (select (y.hours) from dbo.testtime y where y.name=YT.name AND y.hours = YT.hours and datename(dw, date)='Sunday')as Sunday, (select (y.hours) from dbo.testtime y where y.name=YT.name AND y.hours = YT.hours and datename(dw, date)='Monday')as Monday, (select (y.hours) from dbo.testtime y where y.name=YT.name AND y.hours = YT.hours and datename(dw, date)='Tuesday')as Tuesday, (select
(y.hours) from dbo.testtime y where y.name=YT.name AND y.hours =
YT.hours and datename(dw, date)='Wednesday')as Wednesday, (select
(y.hours) from dbo.testtime y where y.name=YT.name AND y.hours =
YT.hours and datename(dw, date)='Thursday')as Thursday, (select (y.hours) from dbo.testtime y where y.name=YT.name AND y.hours = YT.hours and datename(dw, date)='Friday')as Friday, (select
(y.hours) from dbo.testtime y where y.name=YT.name AND y.hours =
YT.hours and datename(dw, date)='Saturday')as Saturday,(select sum(hours)from dbo.testtime y where y.name=YT.name AND y.hours = YT.hours) as Totalfrom dbo.testtime YTgroup by date, name, hours RESULTS: cara          NULL    NULL    NULL    4.222    NULL    NULL    NULL    4.222cara          NULL    2    NULL    NULL    NULL    NULL    NULL    2cara          3.3333    NULL    NULL    NULL    NULL    NULL    NULL    3.3333dan           NULL    NULL    NULL    NULL    NULL    3.123123    NULL    3.123123dan           NULL    NULL    NULL    NULL    9.123    NULL    NULL    9.123 Like I said, I am SO close, I just need it to look like;NAME    SUN    MIN    TU    WED    TH    FR    SA    TOTAL  cara          3.333    2                            4.222            9.555
dan                        9.125    3.125                            12.5  TIAdan

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Apr 28, 2008

I have a report which includes two fields of type date pFromDate and pEndDate.
My pFromDate Available values is 'No-queried', and Default values is 'Null'.
My pEndDate values is 'No-queried', and Default values is the
expression '=DateValue(Today)'.
After I upload my report to the report server and run it pEndDate is disabled until I choose value to pFromDate and a postBack occurs.
I want pEndDate display the evaluated expression automatically when I run the report.
How can I do it? Thanks in advance.

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How can i write expression for below input?

1858;# 1234;#Chun Yang

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Feb 24, 2004

It's late and I'm having a hard time figuring out how the heck to build my where clause.

Here's a sample table with data:

ID int
Value int
StartDate DateTime
EndDate DateTime

1 | 100 | 1/1/2004 | 1/23/2004
2 | 200 | 1/23/2004 | NULL

For all intents and purposes, the second record has a null end date because it's valid until a new value is entered. If I were to update the value again, the 3rd record would look like this.

3 | 300 | 1/24/2004 | NULL

And, since this was updated, I'd go back and update the 2nd record so that I know the End Date (the 3rd record's start date)

2 | 200 | 1/23/2004 | 1/24/2004

Ok, with that said, my application looks at each week in a year, and looks for a valid value for the given date. I need to say "for this week, give me the value." If 2 values fall within the given week, I want to grab the highest (MAX) value.

Any ideas on how I'd structure the SQL statement for this? The where clause is where I'm having funny (hey, that's kinda funny -- where and where).

Anyway, I appreciate any help that you all can give me on this one. It's getting late and my brain is burnt out for the day!

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How do you write an expression in report builder to only display the results that start with a certain string value..eg. Project Number - CUP1501, DPR1502, ENG1507 etc. These values will all get returned but I only want the Project Number that has CUP and DPR in it?

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I am running some query with the following where clause

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the default language on the server is British English.

Could anybody please tell me the reason why records from july are also coming

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I have a table called as Events and below are its columns

ID int
EventFromDate datetime
EventToDate datetime
EventDesc nvarchar
IsHoliday bit

This is a master table where the admin would enter the Events/Holidays for the entire year.

The data would be as below:

IDEventFromdateEventTodateEventDesc isHoliday
126-01-201526-01-2015RepublicdayYes
230-01-201531-01-2015TeamOutingNo
301-05-201501-05-2015Labour day Yes

Now, suppose a employee applies leave on 26/01/2015 to 26/01/2015 then it should not insert into table and return a value "Not updated"

How to handle the scenario if a employee applies leave between the range 23/01/2015 to 27/01/2015, since 26/01/2015 is a holiday in between. how the data can still be inserted excluding 26/01/2015

Can we exclude a non-working day or a sunday.

Leavedetails table to insert leaves applied by employee is as follows

LeaveDetailID int
LeaveTypeId int
FromDate datetime
EndDate datetime
Remarks nvarchar

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Nov 30, 2015

We are trying to compare our current calendar week (based on Monday being the first day of the week) with the previous calendar week.

I'm trying to produce a line chart with 2 axis:

- x axis; the day of the week (Mon, Tues, Wed etc - it is fine for this to be a # rather than text e.g. 1 = Mon, 2 = Tues etc)
- y axis; the cumulative number of orders

The chart needs two series:

Previous Week. The running count of orders placed that week.
Current Week. The running count of orders placed this week.

Obviously in such a chart the 'Current Week' series is going not going to have values along the whole axis until the end of the week. This is expected and the aim of the chart is to see the current week compares against the previous week for the same day.

I have two tables:

Orders TableCalendar Table

The calendar table's main date column is [calDate] and there are columns for the usual [calWeekNum], [calMonth] etc.

My measure for counting orders is simply; # Orders: = countrows[orders].

How do I take this measure and then work out my two series. I have tried numerous things such as adapting TOTALMTD(), following articles such as these:

- [URL] ...
- [URL] ...

But I have had no luck. The standard cumulative formulas do work e.g. if I wanted a MTD or YTD table I would be ok, it's just adjusting to a WTD that is causing me big issues.

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How can I get Saturday's date given the week number?

This is my week number, SELECT DATEPART(WEEK, DATEADD(MONTH, +3, ApptDt2)). I need to get Saturday's date from this week.

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Sep 17, 2015

i have the following table I need to select dates grouping them by weeks, my week start is Saturday to Friday

CREATE TABLE weekdays
(
datevalue datetime NOT NULL
, numericvalue INT NOT NULL
);
INSERT INTO weekdays (datevalue, numericvalue) VALUES

[code]....

The output should look like this

weeknototalvalue
362015-09-01 00:00:00.000
362015-09-02 00:00:00.000
372015-09-07 00:00:00.000
372015-09-08 00:00:00.000
382015-09-12 00:00:00.000
382015-09-13 00:00:00.000
382015-09-14 00:00:00.000
392015-09-19 00:00:00.000

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May 23, 2007

Hi all,

I'd like to add a yesterday dimension member to a new dimension, like a "Time Utility" dimension, that references the second last day of non empty data in a cube.

At the moment, I'm doing this:

Code Snippet

create member [MIA DW].[DATE TIME].[Date].[Yesterday]
as [DATE TIME].[Date].&[2007-01-01T00:00:00]

select [Measures].members on 0,
non empty [DATE TIME].[Date].members on 1
from [MIA DW]
But the [yesterday] member does not seem to belong to [DATE TIME].[Date].members?

So I guess there's two questions:

1) Can I have a new empty dimension which contains all these special members like "Yesterday" or "This Week" and "Last Week" (these last two obviously refer to a set of Dates)

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Thanks

Greg

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Oct 16, 2006

The following objects are placed on the Report body of the Report pane of SQL Server 2005 Reporting Services :

<textbox: expression1>
<textbox: expression2>

<table:table1 with at least 30 columns and 30 expressions>

<textbox: string1> - considered as the Title in the Footer section of the report

<texbox:string2> <textbox:expression3>
<textbox:string3> <textbox:expression4>
<textbox:string4> <textbox:expression5>
<textbox:expression6>

I can't find any explanation why is it string1 and string 2 of the footer section of my report displayed separately from the expression3 which is aligned on it and the rest of the object on the second page.

The expected design is that all Footer items should be displayed together of whether it is placed on the first page or on the last page.

As a workaround of this, I converted string 1 into an expression (Added = and enclosed the string with double quote).. As a result, all of the items in the Footer section are now placed together on the last page of the report.

I also remember one of the issue I encountered before where the Footer items where placed together on the first page and still have space at the bottom of the page, but then expression 6 is forced to display (alone) on the last page of my report.

I can't find any discussion related to this, I wish somebody could give me an idea why RS behaved like this.

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Jan 29, 2014

I am adding week hrs using while loop , but it can continue next week hrs also.

I can get every week start hrs while update @tem1 table

employeeidreportdatereportatleftattoaccountwrhrn
12902014-01-29 00:00:00.00009:3019:1556001
12902014-01-28 00:00:00.00009:0018:4555802
12902014-01-27 00:00:00.00009:0018:455585583
12902014-01-25 00:00:00.00008:0010:0012004 -- week end
12902014-01-24 00:00:00.00009:1718:4554105
12902014-01-23 00:00:00.00009:1918:4654606
12902014-01-22 00:00:00.00009:1718:4754507
12902014-01-21 00:00:00.00009:1618:3552608
12902014-01-20 00:00:00.00009:1818:555435439

My loop statement

while(select MAX(wrh) from @tem1 where wrh = 0) < 1
begin
update @tem1
set wrh = (select toaccount from @tem1
where reportdate = (select min(reportdate) from @tem1 where wrh = 0))+(select max(wrh) from @tem1)
where wrh = (select max(wrh) from @tem1 where wrh = 0 )
and reportdate = (select min(reportdate) from @tem1 where wrh = 0)
end

this is the result while executing loop statement .

employeeidreportdatereportatleftatdehdrhwehwrh
129029 Jan 201409:3019:15008:0009:20024:00065:54
129028 Jan 201409:0018:45008:0009:18016:00056:34
129027 Jan 201409:0018:45008:0009:18008:0009:18
129025 Jan 201408:0010:00005:0002:00045:00047:16 -- week end
129024 Jan 201409:1718:45008:0009:01040:00045:16
129023 Jan 201409:1918:46008:0009:06032:00036:15
129022 Jan 201409:1718:47008:0009:05024:00027:09
129021 Jan 201409:1618:35008:0008:46016:00018:04
129020 Jan 201409:1818:55008:0009:03008:0009:03

How to update only that week hrs , don't continue next week...

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Apr 29, 2008

In my reports I am extracting the data of number of people joined in all the weeks of the year. And in one of reports I have to extract the data of the number of people joined until the last week from the first week. I am trying out all the logics but nothing is working for me as such. Can any one help me with this issue??????

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Jul 23, 2015

I need a Select sentence that return me the first week of the month for a given week.

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I only need give a week number of the year and then returns the week number of the first week of that month.

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Feb 2, 2008

I'm looking for a way to convert the [week number, year] back to the date for the 1st day of that week.

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Is there a SQL function that will do this?

Thanks,
Mike

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Jun 6, 2006

seriously now

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Aug 15, 2006

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ISO Year Week Day Of Week Function

Jan 18, 2006

Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.

The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.

This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.

drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin

declare @YearWeekDayOfWeekvarchar(10)

Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a

return @YearWeekDayOfWeek

end
go

-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.

select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a

Function Test Results:

DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1

(43 row(s) affected)

CODO ERGO SUM

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May 2, 2007

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Cheers,

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Feb 8, 2007

Error 3 Error loading MLS_AZ_PHX.dtsx: The result of the expression ""C:\sql_working_directory\MLS\AZ\Phoenix\Docs\Armls_Schema Updated 020107.xls"" on property "ConnectionString" cannot be written to the property. The expression was evaluated, but cannot be set on the property. c:documents and settingsviewmastermy documentsvisual studio 2005projectsm l sMLS_AZ_PHX.dtsx 1 1

"C:\sql_working_directory\MLS\AZ\Phoenix\Docs\Armls_Schema Updated 020107.xls"

Directly using C:sql_working_directoryMLSAZPhoenixDocsArmls_Schema Updated 020107.xls
as connectionString works

However - I'm trying to deploy the package - and trying to use expression:
@[User::DIR_WORKING] + "\Docs\Armls_Schema Updated 020107.xls"
which causes the same error to occur

(Same error with other Excel source also:
Error 5 Error loading MLS_AZ_PHX.dtsx: The result of the expression "@[User::DIR_WORKING] + "\Docs\Armls_SchoolCodesJuly06.xls"" on property "ConnectionString" cannot be written to the property. The expression was evaluated, but cannot be set on the property. c:documents and settingsviewmastermy documentsvisual studio 2005projectsm l sMLS_AZ_PHX.dtsx 1 1
)

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