How To Create Rank Column
Jun 30, 2005If I have a column like this
View 9 RepliesIf I have a column like this
View 9 RepliesHi all!
I'm trying to script a view that does a simple query to some tables.
The catch is 2 of the columns are created on run time.
The first column is filled with a calculation with values of other columns. The 2nd column I would like to fill with the ranking of this calculated column
Example: (imagine caculatedcol is Sum(Col1+Col2+Col3)
Col1 Col2 Col3 CalculatedCol Ranking
10 10 10 30 1
9 9 9 27 2
8 8 8 24 3
7 7 7 21 4
How can I get the Ranking column filled based on the calculated column?
I'm desperate.
Thanks for any help.
---
Mário Ramos
i am trying to create a rank formula.i just need to return the highest MCC count for the mcc code and return the seller code...So eg row 3 and 4, there are two MMC CODE called 4772, i need the formula to return the seller code r10, this is because r10 has 9 counts against that mcc code, and r03 has 9,
View 2 Replies View RelatedHi,All,
I have one table like this
UserID,Name,GameScore
1 A 25
2 B 23
3 C 22
4 D 25
5 E 23
6 F 26
Now i want the query which return like this
Name Score Rank
F 26 1
A 25 2
D 25 2
B 23 3
E 23 3
C 22 4
Can anyone give me the sql 2000 query for this
I have a table that has the definition from the picture. Let's suppose I will sort the list based on last column (DATA.ORA - DESC). That means the last row inserted is the first one in the sorted list.
What I would like to do is to get only the records when the value of a specific column is different from the row below.
For instance I would like to get the rows where the column WHITE has different values. When the status for column WHITE changes from 0 to 1 or from 1 to 2 etc., then I need that row no matter if next 5 rows has the same status (1).
In the picture you see what the result of query should be:
Result: only the lines where the value of column WHITE is different than the row below.
Assuming that I have a table similar to this simplified version:
CREATE TABLE [SomeTable] ([Field1] NVARCHAR(50));
How could I count and rank the instances of specific values in the "field1" column? For example, let's say that I want to show the frequency of the column values like so:
field1 count
some value 24
another word 20
a value 5
(and so on...)
How can I do this?
- - - -
- Will -
- - - -
http://www.strohlsitedesign.com
http://blog.strohlsitedesign.com/
http://skins.strohlsitedesign.com/
I am looking to add a column to one of my tables that displays a running rank of how many times a customer has ordered in a given period.Â
I currently have such a column however this column ranks against ALL of the orders that a customer has placed and ignores filters, whereas I need one that ranks based on the filters that are active at any given time.Â
The current formula is:
CustOrderCountPersistant=RANKX(FILTER('Q1 Data Set',[k1_customer_id]=EARLIER([k1_customer_id])),[order_id],[order_id],1,DENSE)
For example, if I am looking at a full years worth of data and a customer has placed 10 orders in that period this formula will add a 1 in the column for first order, a 2 for the second and so forth all the way to 10, the last order.Â
However it will give me exactly the same results if I filter the data to just one month of that year where they may have order only 2 orders.Â
In this scenario I want to have another column with a table that is filter sensitive and would show 1 for the first order and 2 for the second order.Â
Now, I do understand that the issue here is probably the FILTER() I have on as, if I understand correctly, that means all other filters are ignored. My attempts at reworking the formula to remove this have been unsuccessful (such as using a CALCUALTE and trying to use filter properties within that forumula).
To explain the context - I want to create a measure that counts how many customers have placed x amount orders in y number of days e.g. how many customers have placed 2 orders in 30 days.
when creating a new table. How can I set the default value of the column to equal the value of another column in the same table?
View 5 Replies View RelatedI have two tables, one a data table, the other a product table. I want to perform a join on the two tables with values distributed into columns based on the value in the month field.
data_table
product_code month value
350 1 10
350 2 20
350 3 30
product_table
product_code profit_center
350 4520
result_view
product_code profit_center mon1 mon2 mon3
350 4520 10 20 30
My current query gives the following result
result_view
product_code profit_center mon1 mon2 mon3
350 4520 10 0 0
350 4520 0 20 0
350 4520 0 0 30
Any direction toward a solution would be appreciated. Am using SS2005.
How Can I Create Two Column with Math Function In one Column  Like Below.Â
Create Table Tbl_V_Voucher_Details
(
Id Int IDentity (1,1) Primary Key,Â
Catid Int Foreign Key References Tbl_V_Voucher_Info(Id),
ItemId Int Foreign Key References Tbl_V_Item(Id),
Discription varchar
(100),
Qty Int,
Price Float,
Qty * Price As TotalÂ
)
I am trying to add a column to query based on the value of another column in the query.
I first tried creating a calculated field in SSRS 2008 with this statement:
=IIF(Fields!ChargeableFlag.Value=1,Fields!Negamt.Value,0)
The report runs but I get a "#ERROR" when I place the field on the report.
I next tried creating a new column with the SQL statement:
SELECT Project.ProjectCode AS PC, Project.StatusCode AS SC, Time.StandardHours AS Hours,
Time.StandardChargeAmt AS StdAmt, Time.TaskUID as UID,
Time.StandardChargeRate as Rate, ChargeableFlag, 'Bill' =
Case
When TaskRule.ChargeableFlag = 0 Then 'Non-Bill'
When TaskRule.ChargeableFlag = 1 Then 'Billable'
[Code] .....
This query, less the case statement for BLAmt creates the dataset for the SSRS. Adding the Case statement for the BLAmt produces the error: "Invalid column name 'Negamt'."
Can anyone assist me with a script that adds a new column to a table then inserts new values into the new column based on the Table below. i have included an explanation of what the script should do.
Column from
Parts Table Column from
MiniParts New Column in
(Table 1 ) (Table 2 ) MiniParts (Table2)
PartsNum
MiniPartsCL
NewMiniPartsCL
1
K
DK
1
K
K
1
Q
Q
0
L
L
0
L
LC
0
D
G
0
S
S
I have 2 tables in a database. Table 1 is Parts and Table 2 is MiniParts. I need a script that adds a new column in the MiniParts table. and then populate the new column (NewMinipartsCL) based on Values that exist in the PartsNum column in the Parts Table, and MiniPartsCL column in the MiniParts columns.
The new column is NewMiniPartsCL. The table above shows the values that the new column (NewMiniPartsCL) should contain.
For Example
Anytime you have "1" in the PartsNum column of the Parts Table and the MiniPartsCL column of the MiniParts Table has a "K" , the NewMiniPartsCL column in the MiniParts Table should be populated with "DK" ( as shown in the table above).
Anytime you have "1" in the PartsNum column of the Parts Table and the MiniPartsCL column of the MiniParts Table has a "K" , the NewMiniPartsCL column in the MiniParts Table should be populated with "K" ( as shown in the table above). etc..
Hi,
Why adidas is better-ranked than nike??
Table "indice":
idcCod fabCod mcaCod catCod fabNom mcaNom catNom
1111NikeNikeRopa
2221AdidasAdidasRopa
3113NikeNikeMedias
4118NikeNikeLargas
SELECT[RANK] ,[KEY],idc.*
FROMFREETEXTTABL (dbo.indice,mcaNombre,fabNombre,catNombre),
'ropa adidas nike',
LANGUAGE 3082, 5) res left join
dbo.indice idc with (nolock) on idc.idcCodigo=res.[key]
ORDER BY [RANK] DESC;
Result:
RANK KEY
182
03
04
01
Why idcCods's 1 and 2 have different rank??
because idcCod's 3 and 4 affects ?? or it's just thinks of language??
Thank's in advance
Ok. Im not able to understand this logic please help. As you can see we have 2 columns of ranks, 1)normal 2)corrective. what is the logic behind this and how do u write a query for this? these ranks are for the Salary Column.
Imran,
"You truly do not know someone untill you fight them."-THE MATRIX.
EmpID Empname EmpSalary RankNormal RankCorrective
1 A 150001 1
2 B 100002 4
3 C 150001 1
4 D 40003 5
5 E 150001 1
6 F 15004 6
7 G 15004 6
8 H 5005 8
I have table :
Result1 Rank
5
6
78
4
27
3
How to rank in above table ?
Thank you very much !
Hi All,
Please let me know the equivalent of RANK() over ( order by...)
in SQL server 2000.
I thought this was supported in SQL server 2000.
Please let me know if there exists a user defined function.
Thanks in Advance.
Thanks
I would like to write a query that gives me the values of a set ofobservations, and their rank.CREATE TABLE #Values(val int)INSERT #Values SELECT 1INSERT #Values SELECT 5INSERT #Values SELECT 10I would like to select this:1 10 -- rank 1, value 102 53 1I can put them into a temp table with an identity column, ordered bythe column I'm interested in, and then retrieve in order by theidentity column. I'm wondering if there's a way to do that with asubquery.Thanks,Jim
View 3 Replies View RelatedI've written a bunch of code using contains for fts. Then as I was trying to run the sorting, I realized that I have to use containstable in order to sort by rank. Is that correct? When I was using contains, I just used it as a where clause so I would have something like...
WHERE ((PostedUntil >= '5/22/2006') AND (SiteId=199)) AND (CONTAINS (PositionTitle, '"sales"') OR CONTAINS (Description, '"sales"'))
From the examples I've seen, in order to use containstable, I have to join a new dynamic table to the freetext enabled table and it only uses 1 containstable phrase for the new table. In my case, I may have multiple containstable phrases, so would they all fall in a () set like..
FROM Categories AS FT_TBL INNER JOIN
(CONTAINSTABLE (table, col1, searchphrase) OR (CONTAINSTABLE(table, col2, searchphrase2) OR CONTAINSTABLE (table, col3, searchphrase3)) AS KEY_TBL
... or would each containstable have to be a new join? I don't want to spend anymore time going back and rewriting code just to test it since it's about a days worth of recoding. Thanks.
ive created a photo sharing site, and im trying to show the statisics for certain users, so far i can COUNT all the photos the user has upload, and show them in descending order, but i need to be able to see the ranking of the user, like :
RANK USERID No. Of Photos
1 10 100
2 8 70
3 9 85
is there anyway of doing this? thanks Si!
My data:
Code:
CUST NO | StoreName| Rank
Cust1 0781 1
Cust1 0246 2
Cust1 0481 3
Cust2 2101 1
Cust2 8876 2
Cust2 5445 3
Cust3 3243 1
Cust3 4545 2
Cust3 3223 3
Im trying to find a way to rank as shown in the third column.
This is the code im using:
Code:
SELECT top 100 (CustomerNo)as CustomerNo, StoreName,
(SELECT COUNT(DISTINCT CustomerNo)
FROM dbo.Top3CustomerNoStores AS O2
WHERE O2.CustomerNo < O1.CustomerNo) + 1 AS drnk
FROM Top3CustomerNoStores as O1
... and getting this result
Code:
CUST NO | StoreName| drnk
Cust1 0781 1
Cust1 0246 1
Cust1 0481 1
Cust2 2101 2
Cust2 8876 2
Cust2 5445 2
Cust3 3243 3
Cust3 4545 3
Cust3 3223 3
... and using this code
Code:
SELECT top 100 (CustomerNo)as CustomerNo, StoreName,
(SELECT COUNT(*)
FROM dbo.Orders AS O2
WHERE O2.qty < O1.qty) + 1 AS rnk
.... which gives me ...
Code:
CUST NO | StoreName| rnk
Cust1 0781 1
Cust1 0246 1
Cust1 0481 1
Cust2 2101 4
Cust2 8876 4
Cust2 5445 4
Cust3 3243 7
Cust3 4545 7
Cust3 3223 7
I have noticed in SQL 2005, this is accomplished much easier with built in functions.
any help appreciated
Hi all,
until recently ive been using a rank equation to calculate rank,
essentially doing a select statement and selecting this as the rank field, where query 2 is the same as query 1:
((select count(*) from (query1) where (query1).value < (query2).value) +1)) as Rank
problem is that this is now running like a dog (takes 10 secs) and i'd like to try and do this another way- 2005 has a rank function, how can i do this in 2000?
here is the full statement :
SELECT StudentId, GCSE_Score, LTRIM(STR
((SELECT COUNT(*)
FROM dbo.[Score2004-05]
WHERE GCSE_score < s.GCSE_Score) + 1)) AS GCSE_Rank, SetId
FROM dbo.[Score2004-05] S
WHERE (SetId = '2004/2005')
greg
Is there a way to use the Rank function like in 2005 for sql 2000
View 6 Replies View RelatedI need help in understanding how the rank is calculated in FREETEXTABLE. I have a following query
select ft_tbl.saon
,ft_tbl.paon
,ft_tbl.street
,ft_tbl.postcode
,key_tbl.rank
from temp as ft_tbl
INNER JOIN freetextTABLE(temp, (saon, paon, street), '80 ridge avenue', 15) as key_tbl
ON FT_tbl.ID = key_tbl.[key]
First, the resulting rows does have one record which has an address 80 ridge avenue but it appears at 15th place. Ideally it should appear on 1st. All the ranks of the results are same.
Second, the results are also showing two rows which does not contain the specified search string at all. They not only appears above in the resulting table but also have the same rank as the result in question (80 ridge avenue). For example result shows €œLong Ridges, Flat 21, Fortis Green€? at fifth place which is no way near the search string. And actual record shows up at 15th Place
Is there any way we can influence the rank to show exact match first. Just to clarify I have removed the digits from noise file as we need to search house numbers. Digits appears in noise file as default.
Hi ,
I have a report created and within the report is columns that perform additions on the fields from the database.
I want to create a rank column to show the rank of the row compare with the rest.
Col1 Col2 Total Ranks
1 2 3 3
2 3 5 1
2 2 4 2
On the above Col 1 and 2 would come form my database, Total is calculated by the report. How can I get ranking on this total? I cannot sort by the total as the report should only showing rankings but not be ordered by the rank.
I am using SQL Server 2005 Reporting Services...anny help is much appreciated.
Thanks
This query:
SELECT xx.JumpHeight, xx.HeightRank, xx.NoEvents, xx.MinRunDate, xx.DogIdent,
Dogs.CallName, DogOwner.LastName, DogOwner.FirstName
FROM
(SELECT JumpHeight, DogIdent, MIN(RunDate) as "MinRunDate", COUNT(Event_ID) AS "NoEvents",
RANK() OVER (PARTITION BY JumpHeight ORDER BY COUNT(Event_ID) DESC, MIN(RunDate)) AS "HeightRank"
FROM EventData
WHERE Event=@Event
GROUP BY JumpHeight, DogIdent) AS xx, Dogs, DogOwner
WHERE (Dogs.Breed = @Breed AND xx.DogIdent = Dogs.DogIdent and Dogs.Owner_ID = DogOwner.Owner_ID) AND
(xx.HeightRank <= 10)
ORDER BY xx.JumpHeight, xx.HeightRank
produces this output:
Jump Ht.
Rank
# of Events
First Event
Owner
Call Name
08
3
1
2/19/2006
Some Owner
Otto
08
4
1
3/12/2006
Some Owner
Schotzie
I want it to produce this output:
Jump Ht.
Rank
# of Events
First Event
Owner
Call Name
08
1
1
2/19/2006
Some Owner
Otto
08
2
1
3/12/2006
Some Owner
Schotzie
I have tried several things and cannot correct the problem. Obviously, RANK is being evaluated in the wrong place, but placing it elsewhere has failed to produce the above results.
I appreciate any help I can get. Thanks!
Hi,
I am trying to create a inline function which is listed below.
USE [Northwind]
SET ANSI_NULLS ON
GO
CREATE FUNCTION newIdentity()
RETURNS TABLE
AS
RETURN
(SELECT ident_current('orders'))
GO
while executing this function in sql server 2005 my get this error
CREATE FUNCTION failed because a column name is not specified for column 1.
Pleae help me to fix this error
thanks
Purnima
Hi all:
In the Sql below, sample from William Pearson, the amount Spend is in descending order and the Rank number is in ascending order. Like this:
Spend Rank
24 1
12 2
10 3
9 4
What I wish to accomplish is:
Spend Rank (descending)
24 4
12 3
10 2
9 1
Please let me know what I need to accomplish it.
Thanks for the help
Victor
SELECT
CompanyName, Spend,
(SELECT COUNT(*)
FROM
ACC0704 AS CoSpendTotal
WHERE
ACC0704.Spend <= CoSpendTotal.Spend)
AS Rank
FROM
ACC0704
ORDER BY
Spend DESC
Hi,
i want to create a report so that a list of the top 30 records are returned to the report user. In the report i want to have the records position in the list shown (ie the first row should have 1. and the second should be 2. right on down to the 30th having 30.)
how do i achieve this please?
many thanks
FatherJack
Hi all,
I don't know how to explain what I wanna do in english so here's a concrete example:
I have this data
Item - Qty
IT1 - 2
IT2 - 2
IT1 - 4
IT1 - 5
IT2 - 2
And I wanna do something like this
Item - Rank - Qty
IT1 - 1 - 2
IT1 - 2 - 4
IT1 - 3 - 5
IT2 - 1 - 2
IT2 - 2 - 2
So basically I want to assing a rank (on the fly) in a SELECT statement
Thanks in advance
Or Tho
Using FoodMart, how can i add time to this:
WITH MEMBER [Measures].[Rank] AS 'Rank ( Product.CurrentMember,Order( {Product.CurrentMember.Parent.Children} ,[Profit], DESC) ) '
SELECT
{[Profit] , [Rank]} ON COLUMNS,
Drink.Children ON ROWS
FROM Sales
I need to get the previous price for all my PROMOTION records but not when the previous record is a type PROMOTION also it needs to keep going back to get the price.
I have created a table with RANK in which works OK to get previous price for all but how can I say if previous price is type PROMOTION go to next previous prices...
Bets way to show an example is with a jpeg image I have but having trouble inserting into this message...
SELECT a.[StartPrice]
,a.[ProductID]
,a.[Colour]
,ISNULL(b.[Price],a.[Price]) AS [Price Before]
,a.[Price] AS [Promotion Price]
[Code] ...
Table
PriceCodeStartPriceEndPriceProductIDColourPriceRank
RETAIL21-Oct-1324-Dec-13Bike15BLUE39.001
PROMOTION29-Nov-1301-Dec-13Bike15BLUE31.202
PROMOTION12-Dec-1323-Dec-13Bike15BLUE31.203
MARKDOWN25-Dec-1314-Jan-14Bike15BLUE31.204
[Code] ....
Want I'm trying to do select PriceCode PROMOTION and get previous price:
Get previous price
PROMOTION29-Nov-1301-Dec-13Wheel1BLACK31.2039.00
But in this example it picks up the PROMOTION before and I need to ignore this and get rank 1 price for both
PROMOTION29-Nov-1301-Dec-13Bike15BLUE31.2039.00
PROMOTION12-Dec-1323-Dec-13Bike15BLUE31.2039.00
Hi,
I am trying to return the 100th ranking in my SQL, ie
SELECT DailyValueChange, BUSINESS_DATE, RANK() OVER (order by DailyValueChange) AS RANK_Vals
FROM Table
WHERE (BUSINESS_DATE = @CurrentBusDate) AND (RANK_Vals = 100)
However when I try to update the Stored Procedure it tells me RANK_Vals is an invalid column name, which is not the case as if I run it without the Where clase it runs and returns all results.
Any advice on how to get around this would be greatly appreciated.
Cheers
Mark
Hi - Can someone point me to a single document that tells me how to get started from nothing with SQL Server 2005 Express? I keep getting pointed to lists of many documents, none of which does what I specifically need. They all seem to have many general instructions, but I just want to get started with some simple database that I load with a bit of data and then perform some queries.
I have ordered a book from Amazon but don't have much hope that it will do what I need.
Doug