How To Get Group Wise Distinct Count

May 9, 2008

Hi,

I need to get the groupwise distinct count .
For eg. Lets assume we have group as Category and under this there are two childs Category1 and Category2.
I need the distinct count under Category1 and Category2 separately with the count resetting after Category1 and Category2.
Any help will be greatly appreciated.

Regards,
Ravi

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COUNT (Distinct Column) = 0 With GROUP BY

Mar 20, 2008

I have a table of users and date when they logged on to a system. I am trying to count how many distinct users logged on for each day of the week. The SQL below works when there's at least a user for each day. But when there is no user for a particular day such as Sunday, I still want it to return "SUN



0 "

I learned that you can use GROUP BY ALL and it works but the "ALL" is deprecated beyond SQL 2005.

------------------------------------
SELECT UPPER(LEFT(DATENAME(dw, StartTime), 3)) AS DayOfWeek,
COUNT(DISTINCT UserID) AS NumberOfUser

FROM testUserLoginDuration
WHERE Archived = 0
GROUP BY UPPER(LEFT(DATENAME(dw, StartTime), 3))
ORDER BY
CASE WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'MON' THEN 1
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'TUE' THEN 2
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'WED' THEN 3
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'THU' THEN 4
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'FRI' THEN 5
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'SAT' THEN 6
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'SUN' THEN 7
END

--------------
returns

MON 6
TUE 3
WED 5
THU 3
FRI 2
SAT 1

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Apr 3, 2008

Hi all,
i am using sql server 2005.
let me explain the scenario.
i am writing a function that return no of call a sales execituve done.

an executive can present n no of product to one customer but that call will be only one

my table record look like

empid custid product date and other field
em111 iimran aaaa 01-04-2008 ........
em111 iimran bbbb 01-04-2008 ........
em111 iimran cccc 01-04-2008 ........
em111 xxxxxx aaaa 01-04-2008 ........
em111 xxxxxx 2222 01-04-2008 ........
em111 iimran aaaa 02-04-2008 ........
em111 iimran bbbb 02-04-2008 ........
em111 iimran cccc 02-04-2008 ........
em111 xxxxxx aaaa 02-04-2008 ........
em111 xxxxxx 2222 02-04-2008 ........

Now if i select total no of call it should give me four call
also i am getting this through this query

select dcr_date , cust_id from vwdcrdtl where emp_id = @empcode and dcr_date between @stdate and @enddate group by dcr_date , dcr_cust_id


this query correctly return 4 rowcount(which i am gerring though @@rowcount) but i want this rowcount to return from function

i assinged this to rowcount to int veriable but this giving me error .

i would like to know how can i get count of these records

Please Help

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Apr 26, 2007

Hi Folks,

Please help me in writing a query. I need to get current strength of employee's, monthwise (till each month).

Table Structure
----------------
Employee_Master

ED_EmpId ED_DOJ ED_Name
-------- ------- ---------
2006-01-02 SRINIVASA
2006-01-02 KAVITA
2006-01-02 VIVEK
2006-02-20 CHANDRA
2006-02-25 PARIMAL
2006-02-30 SATISH
........
2007-01-10SANJEEV SHARMA
2007-01-14 JITENDRA PRATAP SINGH
2007-03-15 SANDEEP
2007-03-02 SUNIL KUMAR SHARMA


I require the data in the below format..

For the year '2007-2008'

Month Count
----- -----
April(07) 10
May . 10
June . 10
July . 10
August . 10
Sept 10
Oct 10
Nov 10
Dec 10
Jan (08) 10
Feb . 10
March . 10



Thanks.

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Jul 23, 2005

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Apr 25, 2008

I have a group and a subgroup in a report. in the subgroup there are repetitive rows. But i want to display them at only once within the subgroup. So I hide them. Now I want to have the sum of a field viz. "quantity" group wise, having the only single value of the subgroup. But problem is in the sum the values which are hidden also included. But i don't want them to include in the sum of the group.
Can anybody give the suggestions how to resolve the problem..
I am fighting with it from a long back but i am not able to solve the issue.. plz help me out..

location invoice no. date quantity item
delhi inv/del/1 1/1/2008 3 item-1
item-2
item-3
inv/del/2 2/1/2008 2 item-4
item-5
Location Total 5


This is what i want... for invoice inv/del/1 there are 3 items, i hide rest of two rows using "Hide Duplicates", But the group sum i.e. Location Total in the report is coming out as '13' as it includes the quantities of hidden rows also. But in actual I want '5'.



thanx you..

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Oct 7, 2015

I am trying to get count of  records by month wise when they select year .It was showing  the out put correctly but its showing months arer in numbers,but I want to display Jan,Feb ...

SELECT DISTINCT Standard, COUNT(Standard) AS Total,month(ReportDate) Month
FROM CPTable where
year(ReportDate) = '2015'
GROUP BY Standard, Standard ,
month(ReportDate)

Output

Standard Total Month
NULL 0 1 //Jan
NULL 0 2 //Feb
NULL 0 3
NULL 0 4
NULL 0 5
OSHA 18001, 1 5
NULL 0 6
NULL 07
NULL 08
OSHA 18001,158
TL 9000,18
NULL 09
OSHA 18001,139

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May 13, 2015

is there any more efficient way for example to implement the next query?

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JOIN (
SELECT article, MAX(price) AS price
FROM shop
GROUP BY article) AS s2
ON s1.article = s2.article AND s1.price = s2.price;
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May 1, 2014

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group by state
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[code[...

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Jul 19, 2015

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sl.no     Zone    District    no.of.region

1                      hyd           24
2          ZONE1 chn           12
3                      bang         2
1                      raj            4
2          ZONE2  vizag       3
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Feb 6, 2008

HiI am new to SQL and am having a problem. I need to fix my query to do the following...2) get a total of the number of rows returned.
DECLARE @StartDate varchar(12)DECLARE @EndDate   varchar(12)DECLARE @Region    varchar(20)
SET @StartDate = '01/01/2002'SET @EndDate   = '12/31/2008'SET @Region    = 'Central'
SELECTA.createdon,A.casetypecodename,A.subjectidname,A.title,A.accountid,A.customerid,A.customeridname,B.new_Region,B.new_RegionName
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Jan 29, 2007

I'm new to MSSQL 2005 and want to get a summary of a log table. I want to count all the rows for each date based on a DATETIME field called 'post_date' that holds the date and time of each record's creation.

this is the best I can come up with:

Code:


SELECT
DISTINCT(LEFT(post_date,11)) AS post_date, COUNT(DISTINCT(LEFT(post_date,11))) AS total_posts
FROM log_directory_contacts
GROUP BY post_date



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What am I doing wrong? Thanks!

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Oct 23, 2001

hi!
i am trying to get a count of 3 distinct values , one of them being a datetime - am running into errors - any suggestions are appreciated.


select count(distinct individualid + intakeseq + exitdate)from #temp

i am trying to do a distinct on individualid + intakeseq + exitdate,
& then get their count.

Thanks!

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Mar 14, 2007

Hello

for mS SQL 2000

with

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something like

SELECT COUNT(SELECT DISTINCT Name, Region
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GROUP BY Name, Region) AS CPT FROM Groups

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thank you for helpings

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Mar 23, 2007

hi all,

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select distinct d.docrefid from tbljobDocuments d
left join tbljobitems j on j.docrefid=d.docrefid
where d.docrefid='DC01C06027' and j.itemid='39J1667-H86700'

will return me

docrefid
DC01C06027

but when i try to count(*) only the distinct record, it count all..

select distinct d.docrefid, count(*) from tbljobDocuments d
left join tbljobitems j on j.docrefid=d.docrefid
where d.docrefid='DC01C06027' and j.itemid='39J1667-H86700'
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DC01C060272

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DC01C060271




~~~Focus on problem, not solution~~~

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Nov 9, 2007

Hi,

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JOIN Admin..Loadinstance b on a.intLoadInstanceId = b.intLoadInstanceId
where a.MailReasonTypeId = -1
and b.SubClientId = 22
and b.StatusTypeId > 0



Now how could I get distinct patientid count and distinct providerid count


Reply soon

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Jul 20, 2006

Hi



I have a table which stores the shift information for employees. The table contains 10 columns as Employeename,Employeeno,month,year,shifttimings etc. If an employee works a day in a particular shift, then a row will be inserted in to the above table for that employee.

Now at the end of the month i wanted to calculate the shift details for each employee for a particular month of a given year like employeename,employeeno, noofdays(countof shiftdays).

Can some body help?



Thanks in Advance!

Santhosh



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Nov 30, 2003

I have an SQL statement that looks like the following:

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FROM [Docs-Entities] LEFT JOIN [Docs-DocsEntities]
ON [Docs-Entities].entityID = [Docs-DocsEntities].entityID
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but the problem is that numDocs (the COUNT) is not returning a distinct count. In the DocEntities table, a particular document can actually have multiple entries with the same entityID so that produces inflated numbers for numDocs. But when I do a SELECT DISTINCT on a particular entityID, the results are less and don't match the numDocs number because I only need to list the document one time. This is not a huge issue, but it looks bad on my site.

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Thanks for the help and I hope I worded that cllearly...

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Aug 17, 2005

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Jan 28, 1999

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here what I wrote as a query, tell me if I am right. I thank you for your help

select custname, COUNT(DISTINCT ordno) ,
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Aug 30, 2006

Hi,

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eg.

table-

create table ch1 (a int, b int, c int, d int)

insert ch1 values (1,1,1,1)
insert ch1 values (2,2,2,2)
insert ch1 values (1,1,1,1)
insert ch1 values (2,2,2,2)
insert ch1 values (1,3,4,5)

Here distinct row count in a table is 3 which I want to achieve thro a query.

if I do

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but this is not working

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Cheers!
Ram.

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Dec 11, 2007

I have a table with following fields
tdate
custcode
prodcode


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I want count of distinct custcode in every past three months.

for example
Result like this

month tjan tfeb tmar tapr tmay ..... tdec

prod1
prod2
.
.
prod5

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Can any1 help me please.

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Sham

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May 15, 2008

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Oct 14, 2007

hello,
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i need to select the number of distinct users who commented that user too, so i added this at SELECT statement, COUNT(DISTINCT UserName) AS 'Expr1'
i get that error:
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here are the table rows, if you need that
CommentID --- UserName --- PictureID --- DateCommented
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Mar 28, 2007

It doesn't seem possibly, but maybe?
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Apr 17, 2008

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Calls
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id_tag(unique id) | status | call_num | entry_id(timestamp)

1 HOLD 0123456789 2008-04-17 05:07:00.080
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Which produces the following, The number of fdmsaccountno under parentid is two. Its two because one of the fdmsaccountno is = to parentid

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878028271889878028271889
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Mar 12, 2007

Hello,

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6 Northbound 1 03/03/2007
6 Northbound 2 NULL
6 Other 1 NULL
6 Other 2 NULL
20 Proof 0 19/07/2006
20 TCP 0 21/07/2006
24 40-Day 1 16/01/2006
24 40-Day 2 16/03/2006
24 Other 0 NULL
44 Northbound 1 16/01/2006
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44 Northbound 3 16/12/2006
44 Northbound 4 01/01/2007

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