How To Conditionally Count Distinct Values?
Mar 17, 2008
Here is my dataset used by my report definition. The combo of barcode and order id is unique. The 'isDiscountedItem' field indicates if the customer used a coupon to purchased an item at a lower price.
departmentId classId barcode orderId isDiscountedItem
----------------------------------------------------------------------------------------------------------------------
1 1 123 1 True
2 7 456 1 False
1 1 123 2 False
1 1 123 3 True
1 1 789 3 True
2 7 456 3 False
... ... ... ... ...
I want to group my report by department id, class id and barcode. Then, I want to count all distinct order ids for which there was at leat one discounted item.
My report would produce the following output considering the above dataset:
Merchandise Number of customers who used a coupon
--------------------------------------------------------------------------------------------------------------
Department 1 2
Class 1 2
Barcode 123 2
Barcode 789 1
Department 2 0
Class 7 0
Barcode 456 0
I've been looking at a possible solution using hash tables defined in the report code but I would like to find a 'cleaner' solution. Any help would be appreciated.
View 3 Replies
ADVERTISEMENT
Sep 21, 2015
I have the below query,
selectÂ
a.Assignment_UniqueID as DeploymentID,
a.AssignmentName as DeploymentName,
a.StartTime as Available,
a.EnforcementDeadline as Deadline,
sn.StateName as LastEnforcementState,-----Required Column
[Code] ....
o/p: is :
LastEnforcementState NumberOfComputers PComputers
Compliant 7056 91.54
Downloading update(s) 39 0.51
[code]....
I want to add these two rows information into single row,
Failed to Download Updates(s) Â Â 131(127+8) Â Â Â 1.66(1.65+0.1)
how to do this in my sql query?
View 12 Replies
View Related
Sep 7, 2015
We have SharePoint list which has, say, two columns. Column A and Column B.
Column A can have three values - red, blue & green.
Column B can have four values - pen, marker, pencil & highlighter.
A typical view of list can be:
Column A - Column B
red  - pen
red - pencil
red - highlighter
blue - marker
blue - pencil
green - pen
green - highlighter
red  - pen
blue - pencil
blue - highlighter
blue - pencil
We are looking to create a report from SharePoint List using SSRS which has following view:
          red   blue  green
  pen       2    0    1
  marker    0    1    0
  pencil      1    3    0
  highlighter  1    1    1Â
We tried Sum but not able to display in single row.
View 2 Replies
View Related
May 9, 2007
Hello,
I have a DB of professors and information related with them. I created the cube, it consist of:
Measures:
Measure group Professors:
Amount of projects (COUNT proj_id)
Amount of pulications (COUNT pub_id)
Amount of e_books (COUNT book_id)
--------------
Measure group Projects:
Distinct amount of projects (DISTINCT COUNT proj_id)
--------------
Measure group Publications:
Distinct amount of publications (DISTINCT COUNT pub_id)
--------------
Measure group E_books:
Distinct amount of e_books (DISTINCT COUNT book_id)
--------------
Calculated measures:
Amnt_Projects
iif ([Measures].[ Amount of projects ] = 0 OR [Measures].[ Amount of projects] = NULL,0,[Measures].[ Distinct amount of projects])
Amnt_Publications
(similar to the above one)
Amnt_E_books
(similar to the above one)
---------------------------
Dimensions:
dimPROFESSORS
- prof_id
-surname
-name
-gender
dimPROJECTS
- proj_id
-type name
-name
dimPUBLICATIONS
- pub_id
-type name
-name
dimE_BOOKS
- book_id
-name
Date_Projects
-date_id
-years
Date_Publications
-date_id
-years
Date_E_books
-date_id
-years
For example, when I browse the cube:
prof_id____Amount of projects___Distinct amount of projects___Amnt_Projects
1032------------------- 30 --------------------------1----------------1
1070-------------------90 --------------------------2----------------2
1111-------------------0 ---------------------------1----------------0
1137-------------------0 ---------------------------1----------------0
1234-------------------1404--------------------------9----------------9
1721-------------------504--------------------------7----------------7
2661-------------------85 --------------------------5----------------5
...--------------------...---------------------------...----------------...
6999------------------- 20---------------------------1-----------------1
9956-------------------50---------------------------5-----------------5
Unknown----------------(empty)---------------------(empty)-----------0
Grand Total------------ 2421------------------------11-----------------11
Grand Total “11“ is the amount of distinct projects +1 (because of the unknown member). So the last column shows the right amount of projects for the professor but I want Grand Total to sum those values and show, how many projects do the professors have (it should be „59“ if for all professors). How could I get the right value to be shown in Grand Total?
View 1 Replies
View Related
May 10, 2007
Hello,
I am using SQL Server 2005. I have a DB of professors and information related with them. I created the cube, it consist of:
Measures:
Measure group Professors:
Amount of projects (COUNT proj_id)
Amount of publications (COUNT pub_id)
Amount of e_books (COUNT book_id)
--------------
Measure group Projects:
Distinct amount of projects (DISTINCT COUNT proj_id)
--------------
Measure group Publications:
Distinct amount of publications (DISTINCT COUNT pub_id)
--------------
Measure group E_books:
Distinct amount of e_books (DISTINCT COUNT book_id)
Calculated measures:
Amnt_Projects
iif ([Measures].[ Amount of projects ] = 0 OR [Measures].[ Amount of projects] = NULL,0,[Measures].[ Distinct amount of projects])
Amnt_Publications
(similar to the above one)
Amnt_E_books
(similar to the above one)
---------------------------
Dimensions:
dimPROFESSORS
- prof_id
-surname
-name
-gender
dimPROJECTS
- proj_id
-type name
-name
dimPUBLICATIONS
- pub_id
-type name
-name
dimE_BOOKS
- book_id
-name
Date_Projects
-date_id
-years
Date_Publications
-date_id
-years
Date_E_books
-date_id
-years
For example, when I browse the cube:
prof_id____Amount of projects___Distinct amount of projects___Amnt_Projects
1032------------------- 30 --------------------------1----------------1
1070-------------------90 --------------------------2----------------2
1111-------------------0 ---------------------------1----------------0
1137-------------------0 ---------------------------1----------------0
1234-------------------1404--------------------------9----------------9
1721-------------------504--------------------------7----------------7
2661-------------------85 --------------------------5----------------5
...--------------------...---------------------------...----------------...
6999------------------- 20---------------------------1-----------------1
9956-------------------50---------------------------5-----------------5
Unknown----------------(empty)---------------------(empty)-----------0
Grand Total------------ 2421------------------------11-----------------11
Grand Total “11“ is the amount of distinct projects +1 (because of the unknown member). So the last column shows the right amount of projects for the professor but I want Grand Total to sum those values and show, how many projects do the professors have (it should be „59“ if for all professors). How could I get the right value to be shown in Grand Total?
View 2 Replies
View Related
Aug 26, 2007
I am building a Table Report where I need to "count" the number of cells in a column conditionally.
I have a column of data where the values will be "Orange", "Apple", "Banana", NULL
The pseudocode would be something like this:
iCountOfOranges as Integer
iCountOfApples as Integer
iCountOfBananas as Integer
IF Cell.Value = "Orange" THEN
iCountOfOranges = iCountOfOranges + 1
ELSE IF Cell.Value = "Apple" THEN
iCountOfApples = iCountOfApples + 1
ELSE IF Cell.Value = "Banana" THEN
iCountOfBananas = iCountOfBananas + 1
The 3 count values would then be displayed in 3 footer rows at the bottom of the table.
Thanks
View 4 Replies
View Related
Jan 29, 2008
I have a sql server table column that can contain the following possible values. 1. 766/IT 2. 777/HR3. 890/EG4. 012/AS5. Trainee6. Contractor 7. Others I want to write an SQL query grouped by this column, Trainee should be one group, Contractor should be another different group, Others should be another different group and then every thing else ( 766/IT ,777/HR ,890/EG, 012/AS) should be grouped together as one group. Think of it in terms of a pie chart with those groups.
View 4 Replies
View Related
Aug 8, 2012
This should be a simple solution, but it has been a long time since I've done any query writing (mostly in Oracle) and I am stumped, so here goes:
We are in the process of converting Access database to MSSQL with web form front ends.
I have a table, all columns are nullable, and want users to be able to query from a form, which has a field for each column and defaults to a % wild card for the entered value.
I want the users to be able to put any string in any field, and have it return each row that matches that, including rows with null values in the other columns, but not the column with the entered criteria.
Here is a sample of the data:
Code:
SQL> select * from test;
COL1 COL2 COL3 COL4
----- ----- ----- -----
this is a test
this is not test
this is not
this is test too
is test too
is too
is too
7 rows selected.
Now, if I have this SQL run, it will return only rows that have no nulls in any columns:
Code:
select
col1,
col2,
col3,
col4from test
where
col1 like'th%'
and col2 like '%'
and col3 like '%'
and col4 like '%';
COL1 COL2 COL3 COL4
----- ----- ----- -----
this is a test
this is not test
this is test too
Now, if I use an OR clause for each column, this mostly works, but the trouble is it will also return rows with null values for the field that has criteria entered in it:
Code:
select
col1,
col2,
col3,
col4from test
where
(col1 like'th%' OR col1 is null)
and (col2 like '%' OR col2 is null)
and (col3 like '%' OR col3 is null)
and (col4 like '%' OR col4 is null);
COL1 COL2 COL3 COL4
----- ----- ----- -----
this is a test
this is not test
this is not
this is test too
is test too
is too
is too
The idea is to only select the first 4 rows in the above example.
I was playing with ISNULL in the select clause, but all it does is substitute a string for a null, and I think CASE will do the same thing.
Is there a way I can write this query so it will return rows with NULL values in any column, except the one(column) that has user entered criteria in it?
View 9 Replies
View Related
Jul 3, 2013
I am trying to get count on a varchar field, but it is not giving me distinct count. How can I do that? This is what I have....
Select Distinct
sum(isnull(cast([Total Count] as float),0))
from T_Status_Report
where Type = 'LastMonth' and OrderVal = '1'
View 9 Replies
View Related
Jan 9, 2015
Okay, I've been working on this for a couple of hours with no success. I'm trying to find the number of telephone numbers that are associated with multiple students at different school sites. I've created a temp table that lists all phone numbers that are associated with more than one student. I'm now trying to query that table and count the number of telephone numbers that are associated with more than one site. Essentially, I'm looking for parent/guardians that have students at different sites.
Here's an example of what I'm hoping to accomplish:
*In this example, I'm just trying to get a count of the different/distinct school sites associated with each number. If I can, at the same time, limit it to a count of > 1 (essentially excluding parents with students at the same site), even better :)
===================================
Temp table
===================================
SCHOOL | STU_ID | STU_PHONE
101 | 12345 | 111-222-3333
101 | 23456 | 111-222-3333
102 | 34567 | 111-222-3333
101 | 45678 | 999-888-7777
101 | 56789 | 999-888-7777
101 | 67890 | 555-555-5555
102 | 78901 | 555-555-5555
103 | 89012 | 555-555-5555
==================================
Wanted query results
==================================
STU_PHONE | #Students | UNIQUE_SCHOOLS
111-222-3333 | 3 | 2
999-888-7777 | 2 | 1
555-555-5555 | 3 | 3
View 1 Replies
View Related
Oct 23, 2001
hi!
i am trying to get a count of 3 distinct values , one of them being a datetime - am running into errors - any suggestions are appreciated.
select count(distinct individualid + intakeseq + exitdate)from #temp
i am trying to do a distinct on individualid + intakeseq + exitdate,
& then get their count.
Thanks!
View 3 Replies
View Related
Mar 14, 2007
Hello
for mS SQL 2000
with
SELECT DISTINCT Name, Region
FROM Groups
GROUP BY Name, Region
I get 254 rows
but how can I get the COUNT only ?
something like
SELECT COUNT(SELECT DISTINCT Name, Region
FROM Groups
GROUP BY Name, Region) AS CPT FROM Groups
i must get 254
thank you for helpings
View 4 Replies
View Related
Mar 23, 2007
hi all,
sometimes, when tables are poorly joined, we have exactly same rows as a result.. so we use distinct.. but how can we count(*) the distinct rows?
select distinct d.docrefid from tbljobDocuments d
left join tbljobitems j on j.docrefid=d.docrefid
where d.docrefid='DC01C06027' and j.itemid='39J1667-H86700'
will return me
docrefid
DC01C06027
but when i try to count(*) only the distinct record, it count all..
select distinct d.docrefid, count(*) from tbljobDocuments d
left join tbljobitems j on j.docrefid=d.docrefid
where d.docrefid='DC01C06027' and j.itemid='39J1667-H86700'
group by d.docrefid
will return me
DocrefId Count
DC01C060272
when i expect
DocrefId Count
DC01C060271
~~~Focus on problem, not solution~~~
View 3 Replies
View Related
Nov 9, 2007
Hi,
I have write down following query ..
select a.patientid, a.providerid
from PatientDrugList a
JOIN Admin..Loadinstance b on a.intLoadInstanceId = b.intLoadInstanceId
where a.MailReasonTypeId = -1
and b.SubClientId = 22
and b.StatusTypeId > 0
Now how could I get distinct patientid count and distinct providerid count
Reply soon
View 2 Replies
View Related
Jul 20, 2006
Hi
I have a table which stores the shift information for employees. The table contains 10 columns as Employeename,Employeeno,month,year,shifttimings etc. If an employee works a day in a particular shift, then a row will be inserted in to the above table for that employee.
Now at the end of the month i wanted to calculate the shift details for each employee for a particular month of a given year like employeename,employeeno, noofdays(countof shiftdays).
Can some body help?
Thanks in Advance!
Santhosh
View 4 Replies
View Related
Nov 30, 2003
I have an SQL statement that looks like the following:
SELECT [Docs-Entities].entityID, entityName, COUNT([Docs-DocsEntities].filename) AS numDocs
FROM [Docs-Entities] LEFT JOIN [Docs-DocsEntities]
ON [Docs-Entities].entityID = [Docs-DocsEntities].entityID
GROUP BY [Docs-Entities].entityID, entityName
but the problem is that numDocs (the COUNT) is not returning a distinct count. In the DocEntities table, a particular document can actually have multiple entries with the same entityID so that produces inflated numbers for numDocs. But when I do a SELECT DISTINCT on a particular entityID, the results are less and don't match the numDocs number because I only need to list the document one time. This is not a huge issue, but it looks bad on my site.
Is there a way that I can make COUNT count distinctly?
Thanks for the help and I hope I worded that cllearly...
View 2 Replies
View Related
Aug 17, 2005
I'm struggling to fin a way to use DISTINCT keyword with ROLLUP (or Cube).For example,SELECT employee_city, employee_country, COUNT(DISTINCT employee_name)FROM employeeGROUP BY employee_city, employee_country WITH ROLLUPthat query does not work.Is there a workaround?Thx.
View 2 Replies
View Related
Jan 28, 1999
hi, I have a table that contain(custname,ordno,ordchange,ordlocation,reaso n)
I want to determine the following:
how many orders per customer,how many orders changed per customer,how many order location per customer, what reason for change per customer,
here what I wrote as a query, tell me if I am right. I thank you for your help
select custname, COUNT(DISTINCT ordno) ,
COUNT(DISTINCT ordchange) ,
COUNT(DISTINCT ordlocation) ,
COUNT( reason)
from customers a, orders b
where a.custname =b.custname
group by custname
View 1 Replies
View Related
Jul 19, 2006
helloi want to do only one query for :SELECT DISTINCT Name FROM UsersSELECT COUNT(Name) AS Names FROM Users WHERE (Name LIKE 'xxx')something like :SELECT Name, COUNT(Name) AS Names FROM Users WHERE Name IN (SELECT DISTINCT Name FROM Users)i must get :Joe 23julie 17.....thank you
View 3 Replies
View Related
Aug 30, 2006
Hi,
I want a count of distinct rows in a table through a single query -- is it possible?
eg.
table-
create table ch1 (a int, b int, c int, d int)
insert ch1 values (1,1,1,1)
insert ch1 values (2,2,2,2)
insert ch1 values (1,1,1,1)
insert ch1 values (2,2,2,2)
insert ch1 values (1,3,4,5)
Here distinct row count in a table is 3 which I want to achieve thro a query.
if I do
select count(distinct a) from ch1 it works fine and gives me output as 2.
but this is not working
select count(distinct a,b,c,d) from ch1 - any workaround to find the distinct row count in a table??
Please reply.
Cheers!
Ram.
View 7 Replies
View Related
Dec 11, 2007
I have a table with following fields
tdate
custcode
prodcode
table is filled with full year data and i want following result
I want count of distinct custcode in every past three months.
for example
Result like this
month tjan tfeb tmar tapr tmay ..... tdec
prod1
prod2
.
.
prod5
And data under tmar should be count of distinct custcode of (jan,feb and mar) for corresponding prod code is required.
Under tapr, count of distinct custcode of (feb,mar and apr) for corresponding prod code is required.
Can any1 help me please.
I am using MS SQL 2005 and above table is a big table (approx 10 million records)
Sham
View 13 Replies
View Related
May 15, 2008
how can i count in sql the number or records taht would be returned if i did
select distinct site,date from allrecords
View 1 Replies
View Related
Apr 16, 2014
How to count the number of values that exist in a row based on the values from an array of numbers. Basically the the array of numbers I want to look for are in row 1 of table [test 1] and I want to search for them and count the "out of" in table [test 2]. Excuse me for not using the easiest way to convey my question below. I guess in short I have 10 numbers and like to find how many of those numbers exist in each row. short example:
Table Name: test1
Columns: m1 (int), m2 (int), m3 (int) >>> etc
Array/Row1: 1 2 3 4 5 6 7 8 9 10
------
Table Name: test2
Columns: n1 (int), n2 (int), n3 (int), n4 (int), n5 (int)
Row 1: 3, 8, 18, 77, 12
Row 2: 1, 4, 5, 7,18, 21
Row 3: 2, 4, 6, 8, 10
Answer: 2 out of 5
Answer: 4 out of 5
Answer: 5 out of 5
View 2 Replies
View Related
Oct 14, 2007
hello,
i have a working stored procedure SELECT CommentID, UserName, PictureID, DateCommented, COUNT(CommentID) OVER (PARTITION BY PictureID) AS 'NrOfComments'
FROM Comments WHERE PictureID = @PictureID
witch returns among others the number of comments for a picture
i need to select the number of distinct users who commented that user too, so i added this at SELECT statement, COUNT(DISTINCT UserName) AS 'Expr1'
i get that error:
"Colum 'Comments.CommentID' is invalig in the select list beacuse it is not contained in either an aggregate function or the GROUP BY clause."
what should i do, to select the number of distinct users who commented on a specific picture?
here are the table rows, if you need that
CommentID --- UserName --- PictureID --- DateCommented
please help me, thank you
View 5 Replies
View Related
Mar 28, 2007
It doesn't seem possibly, but maybe?
Is there a way to have an expression be used, but also benefit from using distinct on a column?
I'm looking for something like:
sum(case when dtEntered > '1-1-2006' then 1 else 0 end)
but also encorporating somehow a distinct count on UserName. So a username showing twice would only count once, and this would only be counted if the record's dtEntered date was greater than Jan 1, 2006.
The reason I'm writing the statement that way is because there are 5 columns which aggregate data by different time periods.
If it's not possible, I will just end up joining to the table multiple times, putting the date filter in the where clause.
View 3 Replies
View Related
Jul 12, 2004
I am trying to get the below query to work and can't seem to get past this error. Not sure but everywhere I look I think my syntax is right. I am probably missing something obvious but I'm just back from vacation and trying to get in the swing of things. Any help would be appreciated.
Select Distinct(chadcd) as Adjustor, Count (Distinct chclno) as NumberOfCases, Count (Distinct chclno,chwkno)as NumberofClauses
from clmhdr
where chpddt = '20040630'
Group By chadcd
Order by Adjustor
Server: Msg 170, Level 15, State 1, Line 1
Line 1: Incorrect syntax near ',chwkno'.
View 1 Replies
View Related
Apr 17, 2008
I need a query to return the number of distinct call_num(s) between two timestamps.
For example search between 2008-04-17 05:00:00.000 and
2008-04-19 05:00:00.000
Calls
----------
id_tag(unique id) | status | call_num | entry_id(timestamp)
1 HOLD 0123456789 2008-04-17 05:07:00.080
2 ONSCENE 012345679 2008-04-17 05:10:00.012
3 ENROUTE 321654987 2008-04-19 04:00:00.000
so the sample answer would be : 2
View 2 Replies
View Related
Feb 19, 2014
Aim- Need to count how many [FDMSAccountNo] fall under a unique parentid
This is my query
SELECT [FDMSAccountNo]
,ParentID
FROM [FDMS].[dbo].[Dim_Outlet]
where ParentID = '878028271889'
Which produces the following, The number of fdmsaccountno under parentid is two. Its two because one of the fdmsaccountno is = to parentid
FDMSAccountNo ParentID
878028271889878028271889
878028272887878028271889
878028273885878028271889
Desired result
Parentid #_of_outlets
878028271889 2
View 5 Replies
View Related
Mar 12, 2007
Hello,
I'm fairly new to SQL as so am looking for help with an ad hoc query. The data in focusing on is from table named APs:
FileNo Type PartNo Completed
6 Northbound 1 03/03/2007
6 Northbound 2 NULL
6 Other 1 NULL
6 Other 2 NULL
20 Proof 0 19/07/2006
20 TCP 0 21/07/2006
24 40-Day 1 16/01/2006
24 40-Day 2 16/03/2006
24 Other 0 NULL
44 Northbound 1 16/01/2006
44 Northbound 2 16/06/2006
44 Northbound 3 16/12/2006
44 Northbound 4 01/01/2007
I've tried variations on a SELECT statement like below but have been unable to find a way to count only those types per fileNo that have all partNo completed (and to count all types per fileNo with a partNo of 0 and a completed date as they have no parts):
SELECT [FileNo], COUNT(DISTINCT [Type]) AS CountOfAPs
FROM APs
WHERE (completed IS NOT NULL)
GROUP BY [File]
Total count should be: 4
View 9 Replies
View Related
Jul 20, 2005
I want to build query to return how many rows are in this query:select distinct c1, c2 from t1But SQL won't accept this syntax:select count (distinct c1, c2) from t1Does someone know how to count multiple distinct columns? Thanks.--Disclaimer: This post is solely an individual opinion and does not speak onbehalf of any organization.
View 3 Replies
View Related
Mar 20, 2008
I have a table of users and date when they logged on to a system. I am trying to count how many distinct users logged on for each day of the week. The SQL below works when there's at least a user for each day. But when there is no user for a particular day such as Sunday, I still want it to return "SUN
0 "
I learned that you can use GROUP BY ALL and it works but the "ALL" is deprecated beyond SQL 2005.
------------------------------------
SELECT UPPER(LEFT(DATENAME(dw, StartTime), 3)) AS DayOfWeek,
COUNT(DISTINCT UserID) AS NumberOfUser
FROM testUserLoginDuration
WHERE Archived = 0
GROUP BY UPPER(LEFT(DATENAME(dw, StartTime), 3))
ORDER BY
CASE WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'MON' THEN 1
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'TUE' THEN 2
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'WED' THEN 3
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'THU' THEN 4
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'FRI' THEN 5
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'SAT' THEN 6
WHEN UPPER(LEFT(DATENAME(dw, StartTime), 3)) = 'SUN' THEN 7
END
--------------
returns
MON 6
TUE 3
WED 5
THU 3
FRI 2
SAT 1
View 4 Replies
View Related
Nov 30, 2007
We have a table of students with fields for the ID of the school district and their school name. For example:
DistrictID
StudentName
SchoolName
10001
John Smith
Washington Elementary
10001
Jane Smith
Lincoln Middle
10002
David White
Hill High
...
...
...
I want is a listing with the school district ID, the student name, and the number of schools in the district.
I believe the following statement should give me what I want:
SELECT DistrictID, StudentName, COUNT(DISTINCT SchoolName) OVER (PARTITION BY DistrictID)
FROM StudentData
However, I get the error:
Msg 102, Level 15, State 1, Line 1
Incorrect syntax near 'distinct'.
If I take out the DISTINCT it runs fine, however it counts all the rows as expected, which is not what I want.
If I remove the OVER clause it runs fine, however, it counds the schools across all the districts, which is not what I want.
I can remove the OVER clause and use GROUP BY, but not while also retrieving StudentName.
The SQL 2005 Online Books don't seem to indicate that my statement is invalid. Here are the links just for reference:
Count: http://msdn2.microsoft.com/en-us/library/ms175997.aspx
Over: http://msdn2.microsoft.com/en-us/library/ms189461.aspx
Anyone have an idea one what I'm doing wrong or how to go about getting this information?
Thanks!
Matt Penner
View 3 Replies
View Related
May 22, 2008
Thanks for taking the time to read my post. I greatly appreciate it!
What i'm trying to do is get a distinct count of account numbers within a rolling period. My actual take is rather large but i've created a smaller-like version below. Please reference this table.
Account
Date
1
1/1/08
2
1/2/08
3
1/2/08
2
2/8/08
4
2/9/08
1
2/15/08
1
3/5/08
5
3/6/08
4
3/9/08
3
3/10/08
1
4/1/08
5
4/9/08
2
4/15/08
3
4/26/08
1
5/3/08
2
5/15/08
3
5/29/08
6
5/30/08
Let's say i want to return distinct count of accounts within a 2-month rolling period meaning in February, i'd get a distinct count for accounts in January & February, then in March i'd get a distinct count for February & March, then in April i'd get it for March & April, and so on... my results table would like the table below:
Account
Month
3
1
4
2
5
3
5
4
5
5
I had asked this before but it was a summing equation and not a unique count. I've tried to play with the summing equation to kind of make it work, but i'm starting to get a headache. It's probably so simple!
Here's my previous post: http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=2289509
View 8 Replies
View Related