How To Display The Managers And The Employees Working Under That Manager
Sep 8, 2006
Hello,
I'm facing with a problem though it may look very simple for many of
u it is a bit complicated for me So kindly please help me out
i have a table emp with employee id,name and mgrid
I need to display the managers and the employee working under that
manager . How should this be done.
Thanking u
Broken Arrow
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Nov 15, 2007
Ok, I have the following table
CREATE TABLE employees (
employee_number char(6) NOT NULL
, known_as char(20)
, surname char(20)
, job_title char(20)
, manager_number char(6) NULL
, unique_identifier char(6) NOT NULL PRIMARY KEY
)
--unique_identifier is in the format 000123456789
Now I have a conundrum when trying to create organization charts in Visio, so I figured I'd try reproduce the format that a bunch of walkthroughs suggest, which is with the first column being an int identity(1,1) column as the employeeID with the managerID being an int column also, referencing the employeeID.
Hope I've not lost you just yet ;)
So here's what I figured - create a new table with the new integer columns, slap my current data into it and then update the managerID as necessary...
Except I can't work out the update statement for this!
CREATE TABLE gvVisioTest (
employeeID int identity(1,1)
, employee_number char(6)
, job_title char(40)
, department_reference char(10)
, managerID int
, manager_number char(6)
)
GO
INSERT INTO gvVisioTest(employee_number, job_title, department_reference, manager_number)
SELECT employee_number, job_title, department_reference, manager_number
FROM employees
GO
--Update managerID with relevant employeeID
GO
DROP TABLE gvVisioTest
Any ideas?
Oh and this is legacy so the design is flawed, modified over time (the manager field is a bodge put in 5 years ago), so yeah unfortunately I have to work with what I've got :(
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May 8, 2007
I need to figure out the number of managers without listing them. Label the column Number of Managers.
any help is appricated.
Number of Managers
-------------------------
6
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Jan 31, 2008
I am using SqlServer 2000 with asp.net 2.0, I have a table tbl_employees, with fields (empId, empName, empManagerId), with following data...
empId
empName
empManagerId
1
A
2
B
1
3
C
2
4
D
2
5
E
4
Now the question is that what should be the single line query or best solution if i want to get all employess under a perticular manager ?For example; Employees under 'A' are (B,C,D,E) //(C,D,E are also indirectly under A)Emplloyess under 'B' are (C,D & E; E is also under B as his because his managwer 'D' is himself under 'B')
Please advise..Thanks alot.
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Apr 5, 2007
I have an employee table with manager id and employee ids , i need to find all the employee ids for a manager id . Each employee can be a manager in turn . So I need to find all the employees under one manager and if any of the employee is in turn a manager , i need to find the employees under him as well .
The table structure is defined and i cannot edit it .
Please let me know if we could have a single query to do this .
Thank you
kishore
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Jul 15, 2013
I have this column Sdate in my Employees table. This value represent the start date working.
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May 6, 2014
I would like to generate a working schedule for employees for x-days ahead based on a starting date that the user can enter.
I have got 3 relevant tables:
1. Table X with (1) resourcenumber, (2) starting date working schedule and (3) the daynumber representing the starting date (this is ISO so 1 for Monday, 2 for Tuesday etc.)
2. Table Y has the schedule itself and can hold a 7-days schedule or a 14-days schedule. In case of 7 days schedule there a 14 (!) records with (1) resourcenumber, (2) daynumber, (3) starting hour a.m. (4) ending hour a.m (5) starting hour p.m and (6) ending hour p.m. In case of a 14-days schedule there are 28 records (a.m. and p.m. records)
3. Table Z with resource data.
An example to clarify (for fake employee 100):
Table X:
Resource: 100
Starting date: 2012-03-01 (from this date the schedule will be effective)
Daynumber: 4 (2012-03-01 was a Thursday)
Table Y (Resource has a 14 days schedule because per 2 weeks Monday is an off-day):
Record 1 shows: Resource: 100, Daynumber: 1 (= Monday, working day), AM-Starting hour: 09:00, AM-Ending hour: 13:00, PM-starting hour: 13:30, PM-ending hour: 17:30
Record 2: same but daynumber is 2
Record 3: same but daynumber is 3 etc.
...
Record 8 shows: Resource: 100, Daynumber: 8 (= Monday, off-day), AM-Starting hour: 00:00, AM-Ending hour: 00:00, PM-starting hour: 00:00, PM-ending hour: 00:00
Record 9: same as record 2 but daynumber is 9.
etc.
...
Record 14: same as record 7 but day is 14 (= last day)
The weekend days show as 00:00 for the hours (same as day 8 in example)
I generated the working schedule with a CROSS APPLY function based on the starting date and the x-number of days ahead.
I then evaluate the actual daynumber corresponding with that date with the daynumber in table Y. That works fine with a 7-days schedule but I can't get it fixed with a 14-days schedule. Day 8 in that schedule represents an actual day 1 but how do I know what actual date day 8 is ... I think I have to start with the starting date in table X ...
I think ideally I would like to have the generated days as follows (as an example in case of a 14-days schedule starting 2014-05-01 for 30 days ahead):
2014-05-01 = day 4 (= actual daynumber)
2014-05-02 = day 5
2014-05-03 = day 6
...
2014-05-10 = day 13
2014-05-11 = day 14
2014-05-12 = day 1
2014-05-13 = day 2
2014-05-14 = day 3
...
2014-05-24 = day 13
2014-05-25 = day 14
2014-05-26 = day 1
2014-05-27 = day 2
...
2014-05-31 = day 6
With this done I can compare the actual daynumber with the daynumber in Table Y.
The rownumber that the CROSS APPLY function generates has to be reset to 1 after day 14. I tried PARTITION BY in THE ROW_NUMBER function but to no avail ... The only field I can partition by is the maximum value of the daynumber (14 is the example) but that is not allowed in the rownumber function.
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Mar 23, 2006
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At home I've been following the excellent video series on the msdn
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Hello Experts,
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Have someone an idea?
Best regards,
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Dec 4, 2006
i have 2 tables emp and dept
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List of the employees and their department who is top salary earner of the department.
wht i can think of is:
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from emp e,dept d
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help appreciated
cheers
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Dear all,
I have a table that contains the following columns:
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apologies if this is the wrong group ..
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[Code] .....
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