How To Get String Representation Of A Hex Number?

Jul 20, 2005

Hi,
I want to get the string representation of a hex number from a
varBinary column of a table.
For example I want to get the output : 'The Hex value is 0xFF'
but
select 'The Hex value is ' + convert(varchar(10), 0xFF)
retruns the ascii charecter for 0xFF

Any idea how do I get the hex form as it is?
thanks.
Supratim

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Is It Possible To Get The Month Name With Only An Integer Representation Of The Number

Aug 15, 2007

Hi,
Is it possible to get the month name with only an integer representation of the number.

i.e January ,February..... the DATENAME only takes a date as a value.

thanks in advance

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Nov 10, 2006

I am trying to take a hexadecimal representation of a binary number and convert to the true binary representation so that I can compare it against a binary field in one of my tables.

After reading the documentation it seems I should be able to do this with the CAST or CONVERT function. However it does not appear to be working correctly.

Can you tell me why this T-SQL code produces the wrong binary value:

DECLARE @value binary(16)

SELECT @value = CONVERT(binary, '0764DE49749F274EB924E1552FFE09EC')

PRINT @value

This prints out: 0x30373634444534393734394632373445

That is not correct it should be: 0x0764DE49749F274EB924E1552FFE09EC



Thanks

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Jul 14, 2015

I have a text field which has entries of variable length of the form:

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or
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or
"airplane:app.apx&resultid=123489,clientip"

I'm trying to pick out the numbers between resultid='...',clientip no matter what the rest of the string looks like. So in this example it would be the numbers:

1234
123
12389

the part of the string of the form resultid='...',clientip always stays the same except the length of the number can vary.

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Sep 14, 2004

Kinda general question -but before I embark on my own design I thought I ask around. . .

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Jul 23, 2005

My company is working on a bond derivative portfolio analysis tool andwe're facing a problem that I did not see adequately addressed anywhere in literature. I really did RTFM. I'm very experienced inrelational modelling (10+ years) so this is not a case of notunderstanding the principles. Here is the problem stripped ofirrelevant context. The problem below is simplified for the sake of theexample so don't sweat the details.THE PROBLEM1. There are many types of bonds, each type has a different set ofattributes, different attribute names, different attribute datatypes.For example, bond A has two variables: a yearly interest rate anddate of issue, B has five variables: an interest rate and 4 specificdates on which various portions of principal need to be paid, bond Chas a set of 4 variables: interest rate in period 1, interest rate inperiod 2, the date on which the bond can be put back to the issuer,and two dates on which the bond can be called by the issue. And so on.So, on the first attempt I could represent each bond type as its owntable. For example,create table bond_type_a (rate INTEGER, issue_date DATE)create table bond_type_b (rate INTEGER, principle_date1 DATE,principle_date2 DATE, principle_date3 DATE, principle_date4 DATE)create table bond_type_c (rate1 INTEGER, rate2 INTEGER, put_date DATE,call_date DATE)This is the nice relational approach but it does not work because:2. There are many thousands of bond types thus we would have to havemany thousands of tables which is bad.3. The client needs to be able construct the bond types on the flythrough the UI and add it to the system. Obviously, it would be bad ifeach new type of bond created in the UI resulted in a new table.4. When a user loads the bond portfolio it needs to be very fast. Inthe table per type approach if a user has a 100 different types if bondin the portfolio you would have to do 100 joins. This is a heavilymulti user environment so it's a non-starter. It's impossibly slow.THE SOLUTIONSSo now that we ditched the table per bond type approach we can considerthe followiing solutions (unpleasant from the relational point ofview):1. Name-Value pairs.create table bonds (bond_id INTEGER, bond_type INTEGER, attribute_idINTEGER, value VARCHAR(255))Comment: The client does not like this approach because they want torun various kinds of reports and thus they doe not want the values tobe stored as VARCHAR. They want the DB to enforce the datatype.2. Typed Name-Value pairs.create table bonds (bond_id INTEGER, bond_type INTEGER, attribute_idINTEGER, int_val INTEGER, string_val VARCHAR(255), date_val DATE_Comment: The client does not like this because the table is sparse.Every row has two empty fields.3. Link table with table per data type.create table bonds (bond_id INTEGER)create table bond_int_data (bond_id INTEGER REFERENCES bonds(bond_id),value INTEGER)create table bond_string_data (bond_id INTEGER REFERENCESbonds(bond_id), value VARCHAR(255))create table bond_date_data (bond_id INTEGER REFERENCES bonds(bond_id),value DATE)Comment: This meets most of the requirements but it just looks ugly.4. Dynamic Mappingcreate table (bond_id INTEGER, int_val1 INTEGER, int_val2 INTEGER,date_val1 DATE, date_val2 DATE, string_val1 VARCHAR(255), string_val2VARCHAR(255))Then you have to add some dynamic mapping in your code which willprovide bond specific mapping (say, stored in an XML file). Forexample,For bond_A: yearly_rate maps to int_val1, issue_date maps to date_val1For bond_C: rate1 maps to int_val1, rate2 maps to int_val2, put_datemaps to date_val1, call_date maps to date_val2)Comment: This is very good for performance because when I load aportfolio of different bond types I can pull them all in in one SELECTstatement. However this approach has a problem that the table issparse. The number of fields of each type has to be as high as toaccmodate the most complex bond while simple bonds will only be usingtwo or three.THE QUESTIONS:Are the four approaches I described above exhaustive? Are there anyother that I overlooked?

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Feb 25, 2007

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In SQL Server for the same field, it appears that decimal precision is hard coded resulting in a fixed representation (i.e. 1.000, 0.750, 1.125)

Is there a way to make the decimal representation in SQL Server more like Access where trailing zeros are truncated?

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Jan 29, 2008

Hi,

Here is my sample table creation and insertion script.
I want represent as a summary-result using just one record.
How can I ?
Please note the below red color text.


create table policy
(
id int not null,
name nvarchar(50) not null,
constraint pk_policy primary key(id)
);


create table localhost
(
policy_id int not null,
id int not null,
ip_begin binary(4) not null,
ip_end binary(4) not null,
prefix tinyint not null default 0,
constraint pk_localhost primary key(policy_id,id)
);


create table remotehost
(
policy_id int not null,
id int not null,
ip_begin binary(4) not null,
ip_end binary(4) not null,
prefix tinyint not null default 0,
constraint pk_remotehost primary key(policy_id,id)
);


create table rate
(
policy_id int not null,
inbound int not null,
outbound int not null,
constraint pk_rate primary key(policy_id)
);



-------------
insert into policy values(0,N'policy0');

insert into localhost values(0,0,0xC0A80101,0xC0A80101,24);
insert into localhost values(0,1,0xC0A80A01,0xC0A80B01,0);

insert into remotehost values(0,0,0xACA80101,0xACA80101,0);
insert into remotehost values(0,1,0xACA80A01,0xACA80B01,0);
insert into remotehost values(0,2,0xACA80C01,0xACA80C01,24);

insert into rate values(0,1000,2000);

-------------
select * from policy;
select * from localhost;
select * from remotehost;
select * from rate;

-- result of policy table
0 policy0

-- result of localhost table
0 0 0xC0A80101 0xC0A80101 24
0 1 0xC0A80A01 0xC0A80B01 0

-- result of remotehost table
0 0 0xACA80101 0xACA80101 0
0 2 0xACA80C01 0xACA80C01 24

-- result of rate table
0 1000 2000

------------------------------------------------------
desired result set
id name localhost remotehost rate
-- ---------- ---------------------------------------------------------------- ------------------------------------------- -----------------
0 policy0 (192.168.1.1/24),(192.168.10.1~192.168.11.1) (172.168.1.1),(172.168.12.1/24) 0,1000,2000


descriptin of desired result set :
0. key value is id column and is referenced by each policy_id column.
1. id and name column is the same as policy table's.
2. localhost and remotehost columns are intigration of ip_begin,ip_end,prefix.
3. ip_begin and ip_end should be converted dotted presention from numeric format.
4. if prefix greater than 0, it should be displayed using '/'.
5. if ip_begin and ip_end are equal, show just one ip.
6. if the two ips are different from each other, they separated by '~'.
7. rate field is packed divided by ','.

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Jul 20, 2005

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Apr 25, 2008

SQL/SERVER 2000:

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thanks for any help

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Aug 26, 2005

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Oct 15, 2001

I've just upgraded from Access to SQL 2000 and am having problems with a line of SQL code.

In Access I sorted on a text column of part numbers where a number within the text was the important sort value.

Text was typically "AB 1234 A" "AB 34 B" "AB 73000"
The important sort has to be on the numeric value of the part number.


Access Code that worked was:
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Seeing both Val() and MID() are not acceptable in SQL 2000 I ended up using
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Can anyone help point me in the right direction?
Many thanks
Peter

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Jan 13, 2005

Quick question I hope:

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For example:
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select checksum('COPENBARGER AND COPENBARGER')
both yield -2027749374.

Can someone suggest an alternative function?
Many thanks :)!

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Dec 14, 2007

Hi

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Jul 7, 2006

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Apr 11, 2008

Hi guys,

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Then I have a join table between the two

Unit_Part( unit_id, part_id )


Each unit NAME and part NAME is unique. So what kind of performance would I be losing if I were to do something like:

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Versus

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Dec 6, 2014

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[URL] .....

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Dec 14, 2007

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Hi,
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Thank you,

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Apr 24, 2008

Hi,

In short:
I want my following problem to work with a LIKE instead of exact match and if possible be faster. (currently 4s)

Problem:
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All those tables relate to a central Colour table.
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Current Situation:
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)
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(
@param varchar(50),
@splitChar char = ''
)
RETURNS
@T TABLE (keyWord varchar(50))
AS
BEGIN
WHILE LEN( @param ) > 0 BEGIN
declare @val varchar(50)
IF CHARINDEX( @splitChar, @param ) > 0
SELECT @val = LEFT( @param, CHARINDEX( @splitChar, @param ) - 1 ) ,
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ELSE
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END
RETURN
END
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@keyWords varchar(255) = ''
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SET NOCOUNT ON;
select clr_id, keyWord, fieldType
from dbo.commonSearch
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END

So, how can I use a LIKE statement in the IN statement of the last query.
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