IN Clause And CharIndex
Jan 20, 2004
Hi, The following stored procedure creates this error, "Syntax error converting the varchar value '17,18,405,408,406,493' to a column of data type int." I tried using a Convert and a Cast function but it still failed. I then read something about using the CharIndex function, but I can't figure it out. Any help would be much appreciated in getting this to work.
Thanks
CREATE PROCEDURE [ResourceProducts]
@ProductHtml varchar(200)
AS
SELECT Resources.ResourceId, Resources.Heading
FROM Resources
INNER JOIN Products
ON Resources.ResourceId IN (Products.Resources)
Where Products.ProductHtml = @ProductHtml
GROUP BY Resources.Heading, Resources.ResourceId
GO
View 5 Replies
ADVERTISEMENT
Jul 23, 2005
SQL Server 2000Ya know, it is always the simplest stuff that gets ya !!I am having the hardest time getting a simple piece of code working.Must be brain dead today.Goal: Get the users full name from a stringHere is sample data:"LDAP://blahblahblah/CN=Kevin Jones,OU=DevEng,DC=nobody,DC=priv,DC=com"Code:IF LEN(@strReturnValue) > 0 BEGINSELECT @strReturnValue = SUBSTRING(@strReturnValue,(CHARINDEX('CN=',@strReturnValue)+3),(CHARINDEX(',',@strReturnValue)-1))ENDIt will extract:"Kevin Jones,OU=DevEng,DC=nobody,DC=priv,DC=com"I want it to extract:Kevin JonesThanks.
View 3 Replies
View Related
Jul 20, 2005
Hi All,Just wondering if it's any more efficient to use the following SQLstatement to return a partial match from a column as opposed to thesecond statement.SELECT * FROM Table1 WHERE CHARINDEX('value', mycol) > 0Versus:SELECT * FROM Table1 WHERE mycol LIKE '%value%'Does anyone have any thoughts on whether or not either of thesestatements would return a result quicker than the other?Many thanks in advance!Much warmth,Murray
View 5 Replies
View Related
Feb 18, 2000
I am looking for a way to return only the numbers from the following example:
Column1 varchar(255)
Column1
---------------------
10 rows copied.
55004 rows copied.
1000004 rows copied.
Once I get the numbers I will then convert (Cast) them as Int.
Thank you in advance,
tw
View 1 Replies
View Related
May 26, 2005
Hi All,
I have an address field that has data that needs to parsed. The data has different formats. I have tried charindex and substring but I am not getting the results I need.
Here is what the data looks like:
Paper Mill Rd 3332
Allegheny Ave 13 1/2
Balto Nat'l Pike 6600 R-2
Rolling Rd N 3030
Here is the results I am looking for:
street dir street number street name street type street unit
3332 Paper Mill Rd
13 1/2 Allegheny Ave
6600 Balto Nat'l Pike R-2
N 3030 Rolling Rd
Can you help? Thanks.
View 5 Replies
View Related
Dec 18, 2007
Hi
I have a column col1 in a table having below strings. How do I get only the required part of the string as I explaind below. (Needed strings are followed by i.e as below).
txtString=duracell+alkaline+battery+&submit1=Search&OVR31&OVKWID=24137211531
i.e : duracell+alkaline+battery+
txtString=sealed+lead+acid+batteries+&submit&gclid=CMekn-fesZAodpzIcHA
i.e : sealed+lead+acid+batteries+
ID=3&Department=
i.e : 3
ID=22893
i.e : 22893
lngSessionId=837541253&pid=22714
i.e : 22714
CCcode=502&OrderId=INT10350&puramt=1773
i.e : INT10350
tduid=5c14526847651e9054552acc134e9a84&url=http://www.somedomain.co.uk/proddetails.asp?id=4204
i.e : 4204
Code I am using (Got this one from my other posting)
declare @QueryString nvarchar(255)
select@QueryString = 'ID=23456&Depatment='
selectsubstring(@QueryString, charindex('ID=', @QueryString) + 3,
charindex('&', @QueryString) - charindex('ID=', @QueryString) - 3) from Pageviews
1. But the above code only works if the string starts with 'ID='.
2. Because the col1 has strings starts with different letter this code fail to excute and gives error
3. Pathindex with regular express '(patindex('%[^0-9]%',v)-1)' cannot be used because it gets anynumber
in the string - string has mixer of numbers and letters
SO IF ANYONE LET ME KNOW HOW TO USE IF or CASE with 'charindex' or any other method to get the above said result would be greatfull.
View 18 Replies
View Related
Jan 3, 2008
I have my column and the info is.
UserID=176&StoreID=210
sometimes there is more between the two so im tring to use a CHARINDEX and Substring
Substring(Parameters, CHARINDEX('UserID', Parameters),3)
When I do this it brings back just the 'USE' I need it to bring back the number associated with it. In this case the 176 how do i get that number?
View 2 Replies
View Related
Mar 4, 2008
I have used CHARINDEX successfully to search for a substring going from left to right in a string, but how do I search from the end of a string and go backwards?
Here is a sample of the problem I am trying to solve. Here is a list of cities, some with two names and some with more than two. I need a way to extract only those cities with two names. I wanted to do this by locating the first space in the string and the last space in the string. If the first space equals the last space, then the city should only be a two word city. Otherwise it is a three name city or greater. So what string functions can I use to locate the first and subsequent spaces in a string?
Here is the current version of my SQL statement:
SELECT
City.City,
CHARINDEX (' ' ,City.City) AS First_Space
FROM
City
WHERE
CHARINDEX (' ' ,City.City) <>0
AND HERE IS A SMALL SAMPLE OF WHAT IS RETURNED:
MARINE CITY7
MARINE ON SAINT CROIX7
MARION CENTER7
MARION HEIGHTS7
HIGH RIDGE5
HIGH ROLLS MOUNTAIN PARK5
HIGH SHOALS5
Thanks to all who understand and can offer usable advice in my dilemma.
Jason.
View 4 Replies
View Related
Mar 21, 2006
I have a field containing a string with '/' in it multiple times.How can I return the charindex of the last occurance of '/' in thestring?Regards,Ciarán
View 1 Replies
View Related
May 11, 2007
What is the best way to essentially use the charindex(find) functionif the value is could be more than one variable (A or B or C)I can't seem to get an "or", "if" or "select if" to workBelow is the code that works, I need 'GOV' to be either 'GOV' or 'FWD'or 'LIB'sqlstring = "SELECT Distinct substring([exposurename]," _& Len(Worksheets(4).Range("j5") & "_VAR_" _&Worksheets(4).Range("C4").Offset(Worksheets(4).Range("c3"), 0)) + 2 _& ",charindex('GOV',[exposurename])-" &Len(Worksheets(4).Range("j5") _& "_VAR_" &Worksheets(4).Range("C4").Offset(Worksheets(4).Range("c3"), 0)) + 3 _& ") AS Drivergrp2 " _& "FROM mars.dbo.mroInventoryProductGreeks_Latest" _& "Where producttype = 'creditdefaultswap' " _& "AND exposureName like '" &Worksheets(4).Range("j5") & "_VAR_" &Worksheets(4).Range("C4").Offset(Worksheets(4).Range("c3"), 0) & "%' "_Much appreciation if you can help
View 2 Replies
View Related
Jul 23, 2005
Hello,I need to be able to replace only the first occurance of a space characterin a column.Reason being is the data in the column I am trying to replace seems to haveumpteen space characters after each entry, so a simple replace functionwill replace all the spaces after it with what I want!I have thought of RTRIM to get rid of the spaces after and then replace, Ihave also thought of CHARINDEX to find the first occurance of a space andSTUFF to replace it.I have done my homework on these functions!But I am having trouble writing such a statement,I've never written a query which would use more then one function on onecolumn you see and I am getting confused!I'll tell you what I want to do in simple stepsReplace only the first found space in a name column, but then if a name hasa middle initial that will be a problem,Replace that with a dot.then concatanate '@emailaddress;@emailaddress2' after itso when SQLServer does the select it will bring back something likejoe.bloggs@emailaddress;emailaddressBut I guess I'd also need joe.n.bloggs@emailaddress;emailaddressThe data in the column looks like this at the momentjoe bloggsBut I guess there may come a time when we havejoe n bloggs, just to complicate things!What is your advice, and how do I write a query like thisI have been playing around with it in Query Analyser but as I said I amgetting confused and need some help if you don't mindThanks a lot to all who reply :-)RegardsJayne
View 2 Replies
View Related
Jul 23, 2005
HelloI am quite hopeless and of course a newbe.The situation: Sql2k / queryI would like it ot break down the following string:2004 Inventory:Ex.Plant Farm1:1st Cut:Premium:0094Whereby:Year = '2004 Inventory'plant= 'Ex.Plant Farm1'cut = '1st Cut'grade = 'Premium'lot# = '0094'It is always seperate by ':', but it can be 5 fields or 4 or 3 and sooncode to create the view:CREATE VIEW dbo.TESTASSELECT FullName, LEFT(FullName, CHARINDEX(':', FullName + ':') -1) AS year, CASE WHEN LEN(FullName) - LEN(REPLACE(FullName, ':', ''))[color=blue]> 0 THEN LTRIM(SUBSTRING(FullName,[/color]CHARINDEX(':', FullName) + 1, CHARINDEX(':', FullName + ':',CHARINDEX(':', Fullname) + 1) - CHARINDEX(':',FullName) - 1)) ELSE NULL END AS Plant, CASEWHEN LEN(FullName) - LEN(REPLACE(FullName, ':', '')) > 1 THENLTRIM(SUBSTRING(FullName,CHARINDEX(':', FullName + ':', CHARINDEX(':',FullName) + 1) + 1, CHARINDEX(':', FullName + ':', CHARINDEX(':',Fullname) + 1) - CHARINDEX(':',FullName+':') - 1)) ELSE NULL END AS [Cut]FROM dbo.ItemInventoryCan anyone help me with this? I am stuck half the way and get for cutthe rest of the string: '1st Cut:Premium:0094'Thanks!
View 5 Replies
View Related
Feb 15, 2008
Hello,I was hoping someone could help me with this SQL statement.The column 'options.optionDescrip' is a varchar field.Some values of the 'options.optionDescrip' contain commas, some donot.We are trying to evaluate against any data in the'options.optionDescrip' column located to the left of a comma (if acomma does exist, which it may not). If no comma exists, then we tryand evaluate against the entire field, not just the part to the leftof the comma.SELECT options_optionsGroups.idProduct FROM options_optionsGroupsJOIN Options ON options_optionsGroups.idOption=options.idOptionJOIN products ON options_optionsGroups.idProduct=products.idProduct WHERE (CASE WHEN CharIndex(',',options.optionDescrip) = 0 THENoptions.optionDescrip LIKE '" & gauge & "%' ELSELeft(options.optionDescrip,CharIndex(',',options.o ptionDescrip)) LIKE'" & gauge & "%' END)Thanks for any input you can provide, I appreciate it.
View 1 Replies
View Related
Jul 10, 2015
What is the best way to convert 3/1/1/12/0 into xxx-xx-xx-xx-xx format by appending zeros if required. final result should be
300/10/10/12/00.
View 9 Replies
View Related
Jan 15, 2008
Hi,
I've the following query. I'm using the yellow highlighted to join 2 tables, as these tables dont have a relationship between them.
The format of the name field is 'AAAA-BBBBBB-123'
here A will be only 4 chars, followed by '-' B can be any number of chars again followed by '-' and the last is the id which I'm using to do a join. This query will fail if the id is just 1 digit as its taking the last 3 chars as the id.
I dont know how to get the id from the right using charindex. Charindex would search for the first occurence of '-' from the right and get the chars after hypen i.e 123. How can this be achieved?
SELECT id AS 'ID',
name AS 'name',
sequence AS 'num'
FROM
FirstTable A
INNER JOIN SecondTable q
ON (CONVERT(INT,RIGHT(name,3))= a.id)
INNER JOIN ThridTable t
ON(t.id = q.id)
INNER JOIN FourthTable s
ON (q.name = s.name )
WHERE A.id = @ID
AND t.name=LEFT(s.name,((CHARINDEX('-',s.name))-1))
ORDER BY 'ID','num'
One more question on this is: Is this a good way of joining tables? If I dont use this I've a very large query containing unions. Which one should be bug-free and more efficient?
Thanks,
Subha
View 9 Replies
View Related
Jan 8, 2008
Hi
I've got a problem which looks like it might be a bug with the CHARINDEX function for Microsoft SQL Server.
The following line of code returns TRUE (1), but you would expect it to return FALSE (0):
SELECT CHARINDEX('Prausse', 'Prauße', 1)
Is there a way around this problem?
Thanks in advance for your responses.
View 3 Replies
View Related
Jun 11, 2013
I have this OR in a simple query:
Code:
DECLARE @searchString nvarchar(100)
SET @searchString = 'sample'
SELECT TOP(1) * FROM user
WHERE (user.identity LIKE @searchString OR
CHARINDEX(@searchString, user.firstname + ' ' + user.lastname) > 0)
PS: Handwritten...
If I pass in a searchString that matches the Identity and a different users lastname, this query will return the user with the lastname-match (which is wrong in my eyes, it should have matched the Identity first, then returned that row [Identity is a Primary key, indexed non-clustered]).
I've tried various things:
Removing LastName: (CHARINDEX(@searchString, user.firstname + ' ') > 0), then the returned row is from a matching identity, due to the lastname of a user was a match, but lastname was removed...so :P
Flipping the conditions around
Adding/removing paranthesis... without any luck.
Is there some option somewhere, to force the OR statement to return on the first true condition. I've always thought OR-statements (in a computer that is) breaked and returned true on the first true condition it found (from left to right, not bother to check the rest of the conditions...)?Or do I have to rewrite the query, with an IF, checking if the @searchString is a valid identity-format, if it is, query on the identity, if not query on the username...?
View 12 Replies
View Related
Mar 24, 2014
I have a column that has 50 records and they are INT. I am trying to place them into a single parameter using the CHARINDEX using the IF Statement. I got an error saying convertinh from varchar to int type data.
Basically, this is what I did:
@RoomID varchar(max)
Then I declare it:
DECLARE @RoomId varchar(4)
SET @RoomID = 0
The IF part that I need to express this CHARINDEX function.
Then in Where clause I filtered it as:
WHERE r.roomid = @RoomId
Or what other way to handle INT data type and make them available for user to choose multiple value?
View 1 Replies
View Related
May 24, 2006
This script doesn't work. Why?UPDATE [460zz_Relma_Comment_Parse]SET [Comments 1] = LTRIM(SUBSTRING([Comments], 1,convert(bigint, CHARINDEX(',', Comments)-1)))WHERE NOT([COMMENTS] IS NULL) AND LEN([Comments]) > 8Basically, I'm trying to move everything before a comma into [Comments1] and everything after the comma into [Comments 2]. The comments 2script works. See below.UPDATE [460zz_Relma_Comment_Parse]SET[Comments 2] = LTRIM(SUBSTRING([Comments], convert(bigint,charindex(',', [Comments])+1), Len([Comments]) - charindex(',',[Comments])))WHERE NOT([COMMENTS] IS NULL) AND LEN([Comments]) > 8This script [Comments 2] runs perfectly but the first one [Comments 1]above gives me the following error.Msg 536, Level 16, State 5, Line 1Invalid length parameter passed to the SUBSTRING function.The statement has been terminated.They are basically the same script except I'm adding +1 to one scriptand minusing one -1 from the other.Thanks,db55
View 1 Replies
View Related
Jul 20, 2005
My code prints out 0 for the value of charindex ( 'Hello.', '.' ).Did I miss something? I think it should print out 6!
View 1 Replies
View Related
Aug 25, 2015
The charindex can run this
LEFT([Description], CHARINDEX('(', [Description]) + 1) Â as NewDesc,
But I can't run
LEFT([Description], CHARINDEX('(', [Description]) - 1) Â as NewDesc,
View 5 Replies
View Related
May 23, 2007
Hello to all,
I hope that somebody can help me.
I have written a sql query to search Partner. I have a wtcomValidRelationships Table. There are two Fields (IDMember(type: Int) and RelationshipIDs(type: varchar(1000)) in this table.
Example: 3418 has 3422 RelationshipID and 3422 has 4088 RelationshipID, if i want to check if there is a relationship between 3418 and 4088.
declare @IDM int;
declare @IDO char(100);
set @IDM = 3418;
set @IDO = '4088';
select B.IDMember
from wtcomValidRelationships as A, wtcomValidRelationships as B
where A.IDMember = @IDM and charindex(cast(B.IDMember as char(100)),A.RelationshipIDS) > 0
and charindex(@IDO,B.RelationshipIDs) > 0
Using this query i get nothing.
I try to use constant in charindex and i get result.
declare @IDM int;
declare @IDO char(100);
set @IDM = 3418;
set @IDO = '4088';
select B.IDMember
from wtcomValidRelationships as A, wtcomValidRelationships as B
where A.IDMember = @IDM and charindex('3422',A.RelationshipIDS) > 0
and charindex('4088',B.RelationshipIDs) > 0
So i think that charindex doesn't work with variable. But I must use variable. Can someone help me? What should i do ?
Thanks
Best Regards
Pinsha
View 1 Replies
View Related
Mar 30, 2015
SELECT LEFT(InstanceName,CHARINDEX(' ',InstanceName)-1)
FROM ServerDB
Returns the following error.
Invalid length parameter passed to the SUBSTRING function.
View 2 Replies
View Related
Jul 9, 2014
I have a column that contains the follwoing string I need to compare.
ek/df/cv/
ek/df/cv/f
All fields bfore the third / are not fixed but behind the third/ is eiter nothing or one letter I need a function to extract all the fields before the third / to compare if they are equal.
I can't do it by using the combination of Substring() and charindex() and Len()
View 9 Replies
View Related
Aug 26, 2014
Looking at a trace table and trying to remove all the "erroneous" bits in a string e.g the declares etc so I can purely get to proc names.
An example string
declare @p2 varchar(10) set @p2=NULL exec sp_proc @Code='TF',@TypeCode=@p2 output select @p2
I've tried
select top 5000 textdata,substring(textdata,charindex('exec',textdata)+5,charindex('@',textdata)-1)
from trace_table
where TextData like '%sp_%'
and TextData like '%declare%'
And it fails dismally...
View 8 Replies
View Related
Apr 21, 2014
I am trying to extract the IP address from a command string, the problem I am running into is there are 3 types of command strings.
SENDAUTO IP192.168.1.32L0O11 Z1 5(E=00:00,F=00:00,G=00:00,H=00:00,I=00:00,J=00:00)
SENDCREATEEXCEPTION -1,IP192.168.1.32,0,11,0,Z1,Free text-label,19,3,19,3,06:00|24:00,I|O,1,288003,1
SENDWEEKTIMES IP192.168.1.32,0,11,Z1,3,100,23:00|24:00|24:00|24:00|24:00|24:00,I|O|O|O|O|O
The IP address length can vary, and the character after the IP is either a L or ,
How can I edit the following function to look for both characters?
SUBSTRING(Command, CHARINDEX('IP', Command), CHARINDEX('L', Command) - (CHARINDEX('IP', Command)))
View 6 Replies
View Related
Jun 22, 2015
Select
left(
[Description],(charindex(';',[Description],1)-1))
from xxxx
Example of Description contains
Ankle Supports; Color=Black; Size=S
So I want the left side up to and NOT including the semi colon.
View 14 Replies
View Related
Jul 20, 2015
I’ve got an issue with extracting specific data from one field using charindex. Here’s an example of the dataset:
Cl_nr Var_data
20059942 ?;;300134BL10;?;;;;;;
20059958 ;2698;020225PU20;?;;;;;;
20059975Â Â Â Â ;;100777ST20;?;;;;;;
20059976 ;;;;;;;;;
11001980 ;;051168PU20;?;;;;;;1001980
20034832 ;;060253BO10;?;;;;;;
20055246 ;;1108731;?;?;;;;;
20043656Â Â ;;1022509;?;;;;;;
20059366 ;;1181750;31-12-2015;2;;;;;
20052712Â Â Â Â ;;230626NO10;?;;;;;;
Goal is to get the data after the 2<sup>nd</sup> ;Â until the next ; starts. Ideal would be to catch everything between the 2<sup>nd</sup> ; en 3<sup>rd</sup> ; (number should be 10 characters).
If I try to select this data just using charindex it only goes until it finds the first ; (of course), what’s the best approach in this?
View 4 Replies
View Related
Jun 26, 2007
I have a stored procedure that receives a list of ids, to get the emails of each of those ids. The problem that I'm having is that I'm using a char data type that is max length is 8000, but the contact lists are getting bigger and soon they might reach the variable max length. The contact list that I receive will look something like this "1234,67523,67875,789687,", I'm using "," as a separator. Right now what I do is this
@array_value = LEFT(@ContactList, @separator_position - 1)
The LEFT function doesn't work with data types text and ntext. But I'm in need of a string data type with a max length bigger than 8000. So I will apreciate if anyone knows of another function that does the same or similar and works with text data type, or any other ideas will be welcome.
Thanks,
Erick
View 8 Replies
View Related
Apr 3, 2015
I have written a query to search for a string in an expression by the number of it's appearance. Script is like this:
DECLARE @Expression VARCHAR(8000) = 'abcd_e_fgh',
@SearchString VARCHAR(10)= '_',
@OccuranceNumber SMALLINT = 1
DECLARE @SearchIndex INT = 0, @SearchIndexPrevious INT = 0, @Sno INT = 0
WHILE @Sno < @OccuranceNumber BEGIN
[Code] .....
Here i'm trying to search "_" in expression "abcd_e_fgh" where it is appearing for first time. it gives me 5 correctly. Now when i change the @OccurenceNumber to 2 or 3, it gives correct values 7 and -1 respectively. However now when i change it to 4, it gives me 5. So when it's trying to check for fifth appearance of "_", it's not actually giving 0 or -1 but repeating the value 5.
View 9 Replies
View Related
Jun 16, 2015
I am trying to erase some erroneous bad data in my table. The description column has a lot of </div>oqwiroiweuru</a> weird data attached to it, i want to keep the data to the left of where the </div> erroneous data begins
update MyTable
set Description = LEFT(Description(CHARINDEX('<',Description)-1)) where myid = 1
that totally works.
update MyTable
set Description = LEFT(Description(CHARINDEX('<',Description)-1)) where myid >= 2
gives me a Invalid length parameter passed to the LEFT or SUBSTRING function. The statement has been terminated error.
View 2 Replies
View Related
Aug 5, 2013
SQL Query. What i need is to be able to extract specific characters from data.
Eg name
1.2-KPIA1-App-00001 this is a name i require, but i also require the '1.2' and the 'KPIA1' to be displayed in new columns in the results
i.e. 1.2-KPIA1-App-00001 1.2 KPIA1
*I need this in part of a script as there is thousands of rows of data.
View 4 Replies
View Related
Nov 4, 2015
I have a quite big SQL query which would be nice to be used using UNION betweern two Select and Where clauses. I noticed that if both Select clauses have Where part between UNION other is ignored. How can I prevent this?
I found a article in StackOverflow saying that if UNION has e.g. two Selects with Where conditions other one will not work. [URL] ....
I have installed SQL Server 2014 and I tried to use tricks mentioned in StackOverflow's article but couldn't succeeded.
Any example how to write two Selects with own Where clauses and those Selects are joined with UNION?
View 13 Replies
View Related