ISNULL Function And String Concatenation

Jul 20, 2005

Dear Group

Just wondered how I can avoid the CHAR(32) to be inserted if @String1 is NULL?

SET @String3 = ISNULL(@String1,'') + CHAR(32) + ISNULL(@String2,'')

Thanks very much for your expertise and efforts!

Best Regards,

Martin

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Help Using ISNULL Function

Apr 18, 2008

Hey, I'm taking an intro SQL Server class, and I have a pretty simple homework assignment. We were provided with a DB and asked to write several SELECT statements. However, I'm stuck up one of the questions. Here is the question: 12.Create a SELECT statement that displays all employees and their Qualifications. Display that individuals with no Qualifications as having ‘NoQual’. Hint: Use a function to determine this ‘empty’ field using ISNULL.

Here is what I have:

SELECT
FNAME + ' ' + LNAME AS 'Employee Name', ISNULL(QUALID, 'NoQual') AS 'Qualifications'
FROM
EMPLOYEE, QUALIFICATION
WHERE
EMPLOYEE.QUALID = QUALIFICATION.QUALID;

However, I do not get any results that have a NULL value in the QUALID column. Here is the code for the DB:

CREATE TABLE emplevel
(LevelNoint,
LowSalaryint,
HighSalaryint,
CONSTRAINT emplevel_levelno_pk PRIMARY KEY (LevelNo));
GO

CREATE TABLE position
(PositionIdint,
PosDescVARCHAR (10),
CONSTRAINT position_positionid_pk PRIMARY KEY (PositionId));
GO

CREATE TABLE qualification
(QualIdint,
QualDescVARCHAR (11),
CONSTRAINT qualification_qualid_pk PRIMARY KEY (QualId)
);
GO

CREATE TABLE dept
(DeptIdint,
DeptNameVARCHAR (12) ,
LocationVARCHAR (15),
EmployeeIdint,
CONSTRAINT dept_deptid_pk PRIMARY KEY (DeptId)
);
GO

CREATE TABLE employee
(EmployeeId int,
LnameVARCHAR (15) CONSTRAINT employee_lname_nn NOT NULL,
Fname VARCHAR (15) CONSTRAINT employee_fname_nn NOT NULL,
PositionId int,
Supervisorint,
HireDate DATETIME,
Salaryint,
Commissionint,
DeptIdint,
QualIdint,
CONSTRAINT employee_employeeid_pk
PRIMARY KEY (EmployeeId)
);
GO

CREATE TABLE dependent
(EmployeeId int,
DependentIdint,
DepDOBDATETIME,
RelationVARCHAR (8),
CONSTRAINT dependent_empiddepid_pk PRIMARY KEY (EmployeeId, DependentId)
);
GO

INSERT INTO position VALUES (1, 'President');
INSERT INTO position VALUES (2, 'Manager');
INSERT INTO position VALUES (3, 'Programmer');
INSERT INTO position VALUES (4, 'Accountant');
INSERT INTO position VALUES (5, 'Salesman');

INSERT INTO emplevel VALUES (1, 1, 25000);
INSERT INTO emplevel VALUES (2, 25001, 50000);
INSERT INTO emplevel VALUES (3, 50001, 100000);
INSERT INTO emplevel VALUES (4, 100001, 500000);

INSERT INTO qualification VALUES (1, 'Doctorate');
INSERT INTO qualification VALUES (2, 'Masters');
INSERT INTO qualification VALUES (3, 'Bachelors');
INSERT INTO qualification VALUES (4, 'Associates');
INSERT INTO qualification VALUES (5, 'High School');

INSERT INTO dept VALUES (10, 'Finance', 'Charlotte', 123);
INSERT INTO dept VALUES (20, 'InfoSys', 'New York', 543);
INSERT INTO dept VALUES (30, 'Sales', 'Woodbridge', 135);
INSERT INTO dept VALUES (40, 'Marketing', 'Los Angeles', 246);

INSERT INTO employee VALUES (111, 'Smith', 'John', 1, NULL,'04/15/1960', 265000, 35000, 10, 1);
INSERT INTO employee VALUES (246, 'Houston', 'Larry', 2, 111,'05/19/1967', 150000, 10000, 40, 2);
INSERT INTO employee VALUES (123, 'Roberts', 'Sandi', 2, 111,'12/02/1991',75000, NULL, 10, 2);
INSERT INTO employee VALUES (433, 'McCall', 'Alex', 3, 543,'05/10/1997',66500, NULL, 20, 4);
INSERT INTO employee VALUES (543, 'Dev', 'Derek', 2, 111,'03/15/1995',80000, 20000, 20, 1);
INSERT INTO employee VALUES (200, 'Shaw', 'Jinku', 5, 135,'01/03/00',24500, 3000, 30, NULL);
INSERT INTO employee VALUES (135, 'Garner', 'Stanley', 2, 111,'02/29/1996',45000, 5000, 30, 5);
INSERT INTO employee VALUES (222, 'Chen', 'Sunny', 4, 123,'08/15/1999',35000, NULL, 10, 3);

INSERT INTO dependent VALUES (543, 1,'09/28/1958','Spouse');
INSERT INTO dependent VALUES (543, 2,'10/14/1988','Son');
INSERT INTO dependent VALUES (200, 1,'06/10/1976','Spouse');
INSERT INTO dependent VALUES (222, 1,'02/04/1975','Spouse');
INSERT INTO dependent VALUES (222, 2,'08/23/1997','Son');
INSERT INTO dependent VALUES (222, 3,'07/10/1999','Daughter');
INSERT INTO dependent VALUES (111, 1,'12/12/1945','Spouse');

ALTER TABLE dept
ADD CONSTRAINT dept_employeeid_fk FOREIGN KEY(EmployeeId)
REFERENCES employee(EmployeeId);
GO
--ALTER TABLE employee
--ADD CONSTRAINT employee_supervisor_fk FOREIGN KEY(Supervisor)
--REFERENCES employee(EmployeeId);

ALTER TABLE employee ADD CONSTRAINT employee_positionid_fk FOREIGN KEY (PositionId)
REFERENCES position (PositionId);
GO

ALTER TABLE employee ADD CONSTRAINT employee_deptid_fk FOREIGN KEY (DeptId)
REFERENCES dept (DeptId);
GO

ALTER TABLE employee ADD CONSTRAINT employee_qualid_fk FOREIGN KEY (QualId)
REFERENCES qualification (QualId);
GO

ALTER TABLE dependent ADD CONSTRAINT dependent_employeeid_fk FOREIGN KEY (EmployeeId)
REFERENCES employee (EmployeeId);
GO

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Dec 29, 2006

okay, using isnull function we could replace null value..
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Note : this is for select statement
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How to replace something if it's not null
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SELECT JS_ID = ISNULL(ID.JS_ID,'-')
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is there any mistake i made? because it still return NULL when no data is found. how do i make it return '-' if a null is found

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Aug 27, 2007

What is wrong with this code. I can not get ISNULL function to work

IF ISNULL([JRL_Req].[MDN])


UPDATE JRL_Req


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FROM JRL_Req


INNER JOIN [order]


ON [JRL_Req].[Order ID]= [order].[OrderId]


INNER JOIN [OrderItem]


ON [order].[OrderId] = [OrderItem].[OrderId]




ELSE


UPDATE JRL_Req


SET [JRL_Req].[Product Code] = [OrderItem].[ProductCode]


FROM JRL_Req


INNER JOIN [order]


ON [JRL_Req].[Order ID]= [order].[OrderId]


INNER JOIN [OrderItem]


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Mar 20, 2008

Hi,
I created a new column in Derived column editor wich depends on two columns that I'm evaluation.

This is my function for the new column:

(COLUMN1 == "Hello") || ISNULL(COLUMN1) ? COLUMN2 : COLUMN3

The problem is that when a NULL data comes for COLUMN1, it doesn't insert the value of COLUMN2 as the formula estipulates. It looks like is not understanding de ISNULL function.
Any suggestion?
Thanks in advance.

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i'm trying to run an append query using data from 2 tables. i want to replace nulls with blanks ('') bellow is my statment. when i run this statment with out the iif(isnull)) statmentes the query works fine. is there another way of replacing my nulls with blanks.
Thank you,
Thomas

insert into tblcustomers (cusName, cusNumber, Active, cusContact, cusCrLimit,cusTerms)
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Hello all,

I have a problem that some of the data I reciave from the DB is null.
I would like to replace it with '0'.
I used the function IsNull on the SQL statment.
The problem is that I recaived a false/true values..
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this is the SQL:

SELECT OrderDetails.itemID, OrderDetails.itemName, OrderDetails.quantityToPick, OrderDetails.quantityPicked, OrderDetails.colorDescription,
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WITH MEMBER [Measures].[Parm1] AS
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Hi,

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WHILE @LoopCount <= 10

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I m getting this error.
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FYI
LogMsg is a sproc

create procedure
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