Identity Column In Query Result

Jul 20, 2005

I am firing a query like:

SELECT TaskName, StartDate FROMTasks
WHERE StartDate >= '01-Aug-2003'

Now the result comes as:

TaskName StartDate
--------------------------
Task1 01-Aug-2003
Task5 10-Oct-2003

etc.

Now what I want is this:


Sl. No. TaskName StartDate
----------------------------------
1 Task1 01-Aug-2003
2 Task5 10-Oct-2003


How do I get the Sl. No. field (it does not exist in the table).
Can I do it?

-surajit

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Jun 19, 2008

Hi,
I am having problem in bulk update of a sql server table haning identity column from a datatable( has no identity column) using sqlbulkcopy. I tried several approaches, but it does not show any error nor is the table getting updated. But the identity value seems to getting increased every time.
thanks.
varun

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result in Excel 2003 SQL OLE DB query

col-A col-B col-C
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May 9, 2015

I have a column colC in a table myTable that has a value (e.g. '0X'). The position of a non-zero character in column colC refers to the ordinal position of another column in the table myTable (in the aforementioned example, colB).

To get a column name (i.e., colA or colB) from table myTable, I can join ("ON cte.pos = cn.ORDINAL_POSITION") to INFORMATION_SCHEMA.COLUMNS for that table catalog, schema and name. But I want to show the value of what is in that column (e.g., 'ABC'), not just the name. Hoping for:

COLUMN_NAME Value
----------- -----
colB        123
colA        XYZ

I've tried dynamic SQL to no success, probably not executing the concept correctly...

Below is what I have:

CREATE TABLE myTable (colA VARCHAR(3), colB VARCHAR(3), colC VARCHAR(3))
INSERT INTO myTable (colA, colB, colC) VALUES ('ABC', '123', '0X')
INSERT INTO myTable (colA, colB, colC) VALUES ('XYZ', '789', 'X0')
;WITH cte AS
(
SELECT CAST(PATINDEX('%[^0]%', colC) AS SMALLINT) pos, STUFF(colC, 1, PATINDEX('%[^0]%', colC), '') colC

[Code] ....

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Jan 11, 2005

Simple example would look like that in MS SQL

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So that the display is

English
a

as we assume that

SELECT language_name FROM language WHERE language_id = 1

returns only English

I have tried to that with a variable but it does not work

declare @that as varchar(15);
set @that = (select language_name_u from language where language_id = 1);
select 'a' as @that

LOL

I just tried another way as i was going to post

declare @that as varchar(15);
set @that = (select language_name_u from language where language_id = 1);
select 'a' as "@that"

and it worked!

Posting anyway so people might answer with a better solution with no variable

Thanks a lot

Mordan

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Nov 23, 2007

Hi,

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cache_created (Datetime)



Orders
-------------
Order_ID
Order_amount
Order_Date
Order_Delivered


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I'm using sql 2000 server.

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Jun 3, 2004

I'm having a bit of a trouble explaining what I'm trying to do here.

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tblGroups - with GroupID, GroupName
tblSubGroups - with SubGroupID, GroupID and SubGroupName (groupID is the ID for the parent Group from tblGroups)

They are related in a table called
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One contact can be related to many subgroups.
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Kirikiri

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Apr 21, 2005

Hello Friends
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1165 6
1,173.0013
9740 6
9820 13
2271 6
2287 13
10,952.006
11,029.0013
4,074.006
4,103.0013

I want to achieve something like below. It should subtract the '13' row to '6' row and provide another column with the result. the '6' and '13' category code share the same Key.

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1,173.0013-8.00
9740 6 -80
9820 13 -80

[code]...

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May 1, 2008

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Tables I have are structured as follows:

SHOWS
showID
showTitle

SHOWACCESS
showID
remoteID

VIDEOS
videoDate
showID

SQL is as follows:

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AND showAccess.remoteID=21
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Today all ETL processes uses (select max(ID) + 1 from T) to insert new rows, so just picture the scenario. It is a mess! Everyday they get duplicate key error when 2 or more concurrent processes are trying to insert a row (with the max) at the same time.

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To sum up:

* I need to have processes in parallel inserting on T

* I can't change anything on T

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Hi all,

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Sep 7, 2007

Hi guys,
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[Name]
[RowID Table Level]
[RowID Data Level]
and I need to change the column type for the columns:
[RowID Table Level]
[RowID Data Level]
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What will be the right syntax using SQL SERVER 2000?

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http://forums.microsoft.com/MSDN/ShowPost.aspx?PostID=2093921&SiteID=1

Thanks in advance,
Aldo.

I have tried the code below, but getting syntax error...



ALTER TABLE #CTE
ALTER COLUMN
[RowID Table Level] INT IDENTITY(1,1),
[RowID Data Level] INT;


I have also tried:

ALTER TABLE #CTE
MODIFY
[RowID Table Level] INT IDENTITY(1,1),
[RowID Data Level] INT;







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Aug 3, 2006

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Mar 5, 2004

Hi,

I have a column that is unique that I would like to make into an IDENTITIY column after I insert some data into it.

I tried

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but it fails.


Ajay

WORD4LIFE
(http://www.word4life.com)

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Jul 20, 2005

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Apr 2, 2007



Hi,



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Table1 has id_value column which is int and it is idenity specification is yes and identity increment is 1 .



And I have a NEW_TABLE with column name new_id which should store current id_value of Table1.



This type of functionality is requirement for my project.



I should get a current value of id_value from table1 . if I say SELECT * FROM NEW_TABLE ;



Please help me out to fix this issue



Thanks

Purnima

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Dec 17, 2001

Hi, I want to change an int column (not null) to identity column. I tried
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Incorrect syntax near the keyword 'identity'.

Can someone please show me the correct statement (if it exists)>

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Jan 17, 2008

Hi
I need help to build the below data to my requirement
i have table having the following data's








NoofLive
Action
Sold
Ratio
EffDt

10-49
43
0
0
1/1/2008

50-99          
62
0
0
1/1/2008

100-199        
73
0
0
1/1/2008

200-299        
17
1
0.059
1/1/2008

300-499        
25
0
0
1/1/2008

500-999        
21
0
0
1/1/2008

1000+          
45
0
0
1/1/2008

100-199        
11
1
0.091
2/1/2008

1000+          
1
0
0
2/1/2008

100-199        
17
0
0
3/1/2008

500-999        
2
0
0
3/1/2008 
EffDt = (Jan-08,Feb-08,Mar-08)
I want creat result as follows from the above data's
















Jan-08
Feb-08
Mar-08

Eligible Lives
Quoted
Sold
Close Ratio
Quoted
Sold
Close Ratio
Quoted
Sold
Close Ratio

10 - 49
43
0
0
0
0
0
0
0
0

50 - 99
62
0
0
0
0
0
0
0
0

100 - 199
73
0
0
11
0
0
0
0
0

200 - 299
17
1
0.059
0
0
0
17
0
0

300 - 499
25
0
0
0
0
0
0
0
0

500 - 999
21
0
0
0
0
0
0
0
0

1000+
45
0
0
1
0
0
2
0
0
Please anybody can help build a query to generate the above result.
Thanks in advance
sthanika
 
 
 
 

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