Image Graph Wont Show In HTML Report

Oct 9, 2007

I have a graph in my rdl which retrieves data from database.It works fine in report viewer and also when i export it in PDF and Excel format,but in HTML,it wont show?What could i do about this,i can see in the property that it is looking for the getimage.aspx.I had tried to incorporate the code i have seen from the internet but it seems to me,that the new reporting services now dont have the method renderstream?and what would be my parameters for whatever method that would act as substitute for that missing method..Thanks..

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Should I convert the input type of function to varbinary instead of byte array?

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Dim MS As MemoryStream
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[Code] ....

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I have created a report with subreport.My subreport contains a graph/chart control which retrieves data from the database.My problem now,is when i deploy my report in HTML,the graph wont show.But it works perfectly in PDF and Excel..I am currentlt using now the getimage.aspx codes.I am confused now,what fornat will be used in the code(getimage.aspx.cs)Would i be evaluating the subreport??use HMTL as format??or PNG as fornat(because as i have read,PNG will be the format of the chart)??

This is my current code :



{

/// <summary>

/// Summary description for getimage.

/// </summary>

public partial class getimage : System.Web.UI.Page

{

protected void Page_Load(object sender, System.EventArgs e)

{

try

{

string reportPath = Server.UrlDecode(Request.Params["report"].ToString());

string streamID = Request.Params["streamid"].ToString();

string format = "HTML4.0";

ReportingService2005 rs = new ReportingService2005();

rs = (ReportingService2005)Session["rs"];

string mimeTypeImage = "";

string encodingImage = "";

byte[] image;

ReportExecutionService rptExec = new ReportExecutionService();

string deviceInfo;

string streamRoot;

streamRoot = "getimage.aspx?report=" + reportPath + "&amp;streamid=" + streamID;

string extension = "";

Virtx.VF_ReportExecution.Warning[] warning = null;

string[] streamIDS = null;

switch (format)

{

case "HTML4.0":

case "HTML3.2":

{

deviceInfo = "<DeviceInfo>";

deviceInfo += "<StreamRoot>" + streamRoot + "</StreamRoot>";

deviceInfo += "<Toolbar>False</Toolbar>";

deviceInfo += "<Parameters>False</Parameters>";

deviceInfo += "<HTMLFragment>False</HTMLFragment>";

deviceInfo += "<StyleStream>False</StyleStream>";

deviceInfo += "<Section>0</Section>";

deviceInfo += "<Zoom></Zoom>";

deviceInfo += "</DeviceInfo>";

}

break;

default:

deviceInfo = "<DeviceInfo></DeviceInfo>";

break;

}

image = rptExec.Render("IMAGE", deviceInfo, out extension, out mimeTypeImage, out encodingImage, out warning, out streamIDS);

//image = rptExec.RenderStream(format, streamID, deviceInfo, out encodingImage, out mimeTypeImage);

Response.Clear();

Response.ContentType = mimeTypeImage;

Response.AppendHeader("content-length", image.Length.ToString());

Response.BinaryWrite(image);

Response.Flush();

Response.Close();

}

catch (System.Threading.ThreadAbortException) { }

catch (Exception ex)

{

Trace.Write(ex.Message);

Virtx.Tracer.WriteTrace(1, "Exception caught while performing getimage(): " + ex.Message);

}

}

#region Web Form Designer generated code

override protected void OnInit(EventArgs e)

{

//

// CODEGEN: This call is required by the ASP.NET Web Form Designer.

//

InitializeComponent();

base.OnInit(e);

}

/// <summary>

/// Required method for Designer support - do not modify

/// the contents of this method with the code editor.

/// </summary>

private void InitializeComponent()

{

}

#endregion

}

}

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4




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TABLE [userImages] (
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Dear people,
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1 column with: Image_title    text
1 column with:Image_stream  <binary data>
1 column with image_type  image/pjpeg
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Is there a helping hand
Below is the script for uploading the image.....and more
 
 1
2 Imports System.Data
3 Imports System.Data.SqlClient
4 Imports System.IO
5
6 Partial Class Images_toevoegen
7 Inherits System.Web.UI.Page
8
9
10 Protected Sub btnUpload_Click(ByVal sender As Object, ByVal e As System.EventArgs) Handles btnUpload.Click
11
12 Dim imageSize As Int64
13 Dim imageType As String
14 Dim imageStream As Stream
15
16 ' kijkt wat de groote van de image is
17 imageSize = fileImgUpload.PostedFile.ContentLength
18
19 ' kijk welke type image het is
20 imageType = fileImgUpload.PostedFile.ContentType
21
22 ' Reads the Image stream
23 imageStream = fileImgUpload.PostedFile.InputStream
24
25 Dim imageContent(imageSize) As Byte
26 Dim intStatus As Integer
27 intStatus = imageStream.Read(imageContent, 0, imageSize)
28
29 ' connectie maken met de database
30 Dim myConnection As New SqlConnection(ConfigurationManager.ConnectionStrings("Personal").ConnectionString)
31 Dim myCommand As New SqlCommand("insert into tblMateriaal(Image_title,Image_stream,Image_type,ArtikelGroep,ArtikelMaat,Aantal,Vestiging,ArtikelNaam,ContactPersoon,DatumOnline) values(@Image_title,@Image_stream,@Image_type,@ArtikelGroep,@ArtikelMaat,@Aantal,@Vestiging,@ArtikelNaam,@ContactPersoon,@DatumOnline)", myConnection)
32
33 ' Mark the Command as a Text
34 myCommand.CommandType = CommandType.Text
35
36 ' geef alle parameters mee aan het command
37 Dim Image_title As New SqlParameter("@Image_title", SqlDbType.VarChar)
38 Image_title.Value = txtImgTitle.Text
39 myCommand.Parameters.Add(Image_title)
40
41 Dim Image_stream As New SqlParameter("@Image_stream", SqlDbType.Image)
42 Image_stream.Value = imageContent
43 myCommand.Parameters.Add(Image_stream)
44
45 Dim Image_type As New SqlParameter("@Image_type", SqlDbType.VarChar)
46 Image_type.Value = imageType
47 myCommand.Parameters.Add(Image_type)
48
49 Dim ArtikelGroep As New SqlParameter("@ArtikelGroep", System.Data.SqlDbType.NVarChar)
50 ArtikelGroep.Value = ddl1.SelectedValue
51 myCommand.Parameters.Add(ArtikelGroep)
52
53 Dim ArtikelMaat As New SqlParameter("@ArtikelMaat", System.Data.SqlDbType.NVarChar)
54 ArtikelMaat.Value = ddl2.SelectedValue
55 myCommand.Parameters.Add(ArtikelMaat)
56
57
58 Dim Aantal As New SqlParameter("@Aantal", System.Data.SqlDbType.NVarChar)
59 Aantal.Value = ddl3.SelectedValue
60 myCommand.Parameters.Add(Aantal)
61
62 Dim Vestiging As New SqlParameter("@Vestiging", System.Data.SqlDbType.NVarChar)
63 Vestiging.Value = ddl4.SelectedValue
64 myCommand.Parameters.Add(Vestiging)
65
66 Dim ArtikelNaam As New SqlParameter("@ArtikelNaam", System.Data.SqlDbType.NVarChar)
67 ArtikelNaam.Value = tb6.Text
68 myCommand.Parameters.Add(ArtikelNaam)
69
70 Dim ContactPersoon As New SqlParameter("@ContactPersoon", System.Data.SqlDbType.NVarChar)
71 ContactPersoon.Value = tb1.Text
72 myCommand.Parameters.Add(ContactPersoon)
73
74 Dim DatumOnline As New SqlParameter("@DatumOnline", System.Data.SqlDbType.NVarChar)
75 DatumOnline.Value = tb2.Text
76 myCommand.Parameters.Add(DatumOnline)
77
78 Try
79 myConnection.Open()
80 myCommand.ExecuteNonQuery()
81 myConnection.Close()
82
83 Response.Redirect("toevoegen.aspx")
84 Catch SQLexc As SqlException
85 Response.Write("Insert Failure. Error Details : " & SQLexc.ToString())
86 End Try
87
88
89 End Sub
90 End class
 

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----
Code



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