Image Data Type Size

Oct 5, 2005

I need to store images in MS SQL. I have the upload procedures and stuff but I'm missing the point about the image data type size.

It is supposed to be able to store up to 2Gb!!! but when I declare the data field image I can't specify the max size for the field and by default is 16 !!

16 bytes!! what can I do with that?
How can I insert a file?

Please help

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I'm using ODBC to interface a Microsoft SQL Server 2000. One of theoperations involves placing files within BLOBs. I'm using the imagedata type for this purpose. Most of the time this works okey, but whentrying to add a 21,3 MB file I get an error. The error code is 22001,which means "String right-truncation". But why? Does this mean thatthe field cannot accepts BLOBs with this size?

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here is my sample code


--note: [CUD_DOCUMENT] and [RES_DOCUMENT] are image data type

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thnx for the help.

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Jul 20, 2007

Hi everyone, I have an odd problem.  I have a generic upload/download ASP.net page that allows the upload and download of and type of file.  I have so far tested the following file types:
XLS, MDB, JPG, DLL, EXE, PDF, TXT, SWF, and GIF
All of these upload and download fine, EXCEPT PDF's.  I have tried 4 different PDF's and all open prior to upload/download, but after uploading and downloading, I get the following (from Adobe Reader) error upon trying to open:
"There was an error opening this document.  The file is damaged and could not be repaired"
 Here's my current code:
9      Protected Sub ItemCommand_Click(ByVal sender As System.Object, ByVal e As RepeaterCommandEventArgs)10   11       If e.CommandName = "open" Then12         Dim sqlConn As New SqlConnection(ConfigurationManager.ConnectionStrings("data_partsbranding").ConnectionString)13         Dim sSQL As New StringBuilder14         Dim sqlCmd As SqlCommand15         Dim sqlReader As SqlDataReader16         Dim byteArray(UploadedFile.PostedFile.InputStream.Length) As Byte17   18         sSQL.Append(" SELECT      * ")19         sSQL.Append(" FROM        [survey_document] ")20         sSQL.Append(" WHERE       [sd_document_code] = @sd_document_code ")21   22         sqlCmd = New SqlCommand(sSQL.ToString, sqlConn)23   24         sqlCmd.Parameters.AddWithValue("@sd_document_code", e.CommandArgument)25   26         sqlConn.Open()27         sqlReader = sqlCmd.ExecuteReader28   29         While sqlReader.Read30   31           Response.ContentType = sqlReader("sd_mime_type").ToString()32           Response.BinaryWrite(sqlReader("sd_document"))33           Response.AddHeader("Content-Disposition", "attachment;filename=" & sqlReader("sd_file_name").ToString())34         End While35   36         sqlReader.Close()37         sqlConn.Close()38   39       End If40   41     End Sub42   43     Protected Sub btnInsert_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnInsert.Click44   45       'Make sure a file has been successfully uploaded46       If UploadedFile.HasFile Then47   48         'Connect to the database and insert a new record into Products49         Dim sqlConn As New SqlConnection(ConfigurationManager.ConnectionStrings("data_partsbranding").ConnectionString)50         Dim sSQL As New StringBuilder51         Dim sqlCmd As SqlCommand52         Dim byteArray(UploadedFile.PostedFile.InputStream.Length - 1) As Byte53   54         'Read the files binary data into a Byte array55         UploadedFile.PostedFile.InputStream.Read(byteArray, 0, byteArray.Length)56   57         sSQL.Append(" INSERT INTO [survey_document] ")58         sSQL.Append(" (           sd_document ")59         sSQL.Append(" ,           sd_title ")60         sSQL.Append(" ,           sd_file_name ")61         sSQL.Append(" ,           sd_upload_date ")62         sSQL.Append(" ,           sd_mime_type ")63         sSQL.Append(" ) VALUES (  @sd_document ")64         sSQL.Append(" ,           @sd_title ")65         sSQL.Append(" ,           @sd_file_name ")66         sSQL.Append(" ,           @sd_upload_date ")67         sSQL.Append(" ,           @sd_mime_type ")68         sSQL.Append(" ) ")69   70         sqlCmd = New SqlCommand(sSQL.ToString, sqlConn)71   72         sqlCmd.Parameters.AddWithValue("@sd_title", FileTitle.Text.Trim())73         sqlCmd.Parameters.AddWithValue("@sd_mime_type", UploadedFile.PostedFile.ContentType)74         sqlCmd.Parameters.AddWithValue("@sd_file_name", System.IO.Path.GetFileName(UploadedFile.PostedFile.FileName))75         sqlCmd.Parameters.AddWithValue("@sd_upload_date", Now)76         sqlCmd.Parameters.AddWithValue("@sd_document", byteArray)77   78         sqlConn.Open()79         sqlCmd.ExecuteNonQuery()80         sqlConn.Close()81   82       Else83   84         'Either the file upload failed or no file was selected85   86       End If87   88     End SubI have also tried the following code as a result of searching far and wide, trying other peoples methods:
 1 Protected Sub ItemCommand_Click(ByVal sender As System.Object, ByVal e As RepeaterCommandEventArgs)
2
3 If e.CommandName = "open" Then
4 Dim sqlConn As New SqlConnection(ConfigurationManager.ConnectionStrings("data_partsbranding").ConnectionString)
5 Dim sSQL As New StringBuilder
6 Dim sqlCmd As SqlCommand
7 Dim sqlReader As SqlDataReader
8 Dim byteArray(UploadedFile.PostedFile.InputStream.Length) As Byte
9
10 sSQL.Append(" SELECT * ")
11 sSQL.Append(" FROM [survey_document] ")
12 sSQL.Append(" WHERE [sd_document_code] = @sd_document_code ")
13
14 sqlCmd = New SqlCommand(sSQL.ToString, sqlConn)
15
16 sqlCmd.Parameters.AddWithValue("@sd_document_code", e.CommandArgument)
17
18 sqlConn.Open()
19 sqlReader = sqlCmd.ExecuteReader
20
21 While sqlReader.Read
22
23 Dim buffer() As Byte = sqlReader("sd_document")
24 Dim blen As Integer = CType(sqlReader("sd_document"), Byte()).Length
25
26 Response.ContentType = sqlReader("sd_mime_type").ToString()
27 Response.OutputStream.Write(buffer, 0, blen,)
28 Response.AddHeader("Content-Disposition", "attachment;filename=" & sqlReader("sd_file_name").ToString())
29 End While
30
31 sqlReader.Close()
32 sqlConn.Close()
33
34 End If
35
36 End Sub
37
38 Protected Sub btnInsert_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles btnInsert.Click
39
40 'Make sure a file has been successfully uploaded
41 If UploadedFile.HasFile Then
42
43 'Connect to the database and insert a new record into Products
44 Dim sqlConn As New SqlConnection(ConfigurationManager.ConnectionStrings("data_partsbranding").ConnectionString)
45 Dim sSQL As New StringBuilder
46 Dim sqlCmd As SqlCommand
47 Dim byteArray(UploadedFile.PostedFile.InputStream.Length - 1) As Byte
48
49 'Read the files binary data into a Byte array
50 UploadedFile.PostedFile.InputStream.Read(byteArray, 0, byteArray.Length)
51
52 sSQL.Append(" INSERT INTO [survey_document] ")
53 sSQL.Append(" ( sd_document ")
54 sSQL.Append(" , sd_title ")
55 sSQL.Append(" , sd_file_name ")
56 sSQL.Append(" , sd_upload_date ")
57 sSQL.Append(" , sd_mime_type ")
58 sSQL.Append(" ) VALUES ( @sd_document ")
59 sSQL.Append(" , @sd_title ")
60 sSQL.Append(" , @sd_file_name ")
61 sSQL.Append(" , @sd_upload_date ")
62 sSQL.Append(" , @sd_mime_type ")
63 sSQL.Append(" ) ")
64
65 sqlCmd = New SqlCommand(sSQL.ToString, sqlConn)
66
67 'sqlCmd.Parameters.AddWithValue("@sd_title", PictureTitle.Text.Trim())
68 'sqlCmd.Parameters.AddWithValue("@sd_mime_type", UploadedFile.PostedFile.ContentType)
69 'sqlCmd.Parameters.AddWithValue("@sd_file_name", System.IO.Path.GetFileName(UploadedFile.PostedFile.FileName))
70 'sqlCmd.Parameters.AddWithValue("@sd_upload_date", Now)
71 'sqlCmd.Parameters.AddWithValue("@sd_document", byteArray)
72
73 sqlCmd.Parameters.Add(New SqlParameter("@sd_mime_type", SqlDbType.VarChar))
74 sqlCmd.Parameters.Add(New SqlParameter("@sd_title", SqlDbType.VarChar))
75 sqlCmd.Parameters.Add(New SqlParameter("@sd_upload_date", SqlDbType.DateTime))
76
77 sqlCmd.Parameters.Add(New SqlParameter("@sd_file_name", SqlDbType.VarChar))
78
79 sqlCmd.Parameters.Add(New SqlParameter("@sd_document", SqlDbType.Image))
80
81 Dim bArray(UploadedFile.PostedFile.ContentLength - 1) As Byte
82
83
84
85
86
87
88 UploadedFile.PostedFile.InputStream.Read(bArray, 0, UploadedFile.PostedFile.ContentLength)
89
90 sqlCmd.Parameters("@sd_mime_type").Value = UploadedFile.PostedFile.ContentType
91 sqlCmd.Parameters("@sd_title").Value = PictureTitle.Text.Trim()
92 sqlCmd.Parameters("@sd_upload_date").Value = Now
93
94 sqlCmd.Parameters("@sd_file_name").Value = System.IO.Path.GetFileName(UploadedFile.PostedFile.FileName).ToLower
95
96 sqlCmd.Parameters("@sd_document").Value = bArray
97
98
99 sqlConn.Open()
100 sqlCmd.ExecuteNonQuery()
101 sqlConn.Close()
102
103 Else
104
105 'Either the file upload failed or no file was selected
106
107 End If
108
109 End Sub
110

 This method atleast gives a different error:
 "Adobe Reader could not open '132-171510.pdf' because it is either not a supported file type or the file has been damaged (for examplc, it was sent as an email attachment and wasn't correctly decoded)."
 Please help, it would be appreciated.  Thanks
 

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Dec 5, 2007

Hi,
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