In(..) And Like Xxxx% Performance

Jul 20, 2005

Hi,
I am experiencing strange SQL server behavior,

The table has an index on (filed1, field2) - which is primary key.
if I do select where field1 = 'a' and field2 like '123%' runs fast.
if I do select where field1 = 'b' and field2 like '123%' runs fast
too.

if I do select where field1 in ('a','b') and field2 like '123%' the
damn thing runs forever.

What is interesting, the SQL plan is perfectly using primary index and
selection is translated into "good" ranges for field2. It fills like
server does not take in consideration that field2 is in index.

Any ideas what's going on? I'd hate to use two selects to avoid
problem.

Thank you.
M.Q.

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The Package Contains Two Objects With The Duplicate Name Of Xxxx And Xxxx

Nov 20, 2006

Hi all,

I am creating a Data Flow custom component in SSIS, and my input/output columns are dynamically created depending on the value of a custom property of the component.

Then, as soon as I modify this custom property, I make some job in SetComponentProperty(), that I have overrided in my PipelineComponent, to create my input and ouput columns.

After validation, I have the following error message:

Error 3 Validation error. Data Flow Task: DTS.Pipeline: The package contains two objects with the duplicate name of "output column "AMOUNT" (4714)" and "input column "AMOUNT" (4711)". Package.dtsx 0 0

I create an input column named "AMOUNT" with an ID 4711 and an output column named "AMOUNT" with an ID of 4712.

What is surprising is that when I manualy create the same columns with the default advanced editor of my component, using the menu "Show Advanced Editor...", there is no error !!!

I think that I am doing something wrong but I don't know what...!

Have someone any idea about that?

Here is the code I use to create new input columns:

IDTSInputColumn90 newInputColumn = inputColumns.InputColumnCollection.New();

newInputColumn.Name = virtulaInputColumn.Name;

newInputColumn.LineageID = virtulaInputColumn.LineageID;

newInputColumn.UsageType = DTSUsageType.UT_READONLY;

newInputColumn.ErrorRowDisposition = DTSRowDisposition.RD_NotUsed;

The virtulaInputColumn is the linked real input column that I get from IDTSInput90.GetVirtualInput()



Here is the code I use to create new output columns:

IDTSOutputColumn90 newOutputColumn = defaultOutput.OutputColumnCollection.New();

newOutputColumn.Name = outputColumn.Alias;

newOutputColumn.SetDataTypeProperties(DataType.DT_WSTR, 0, 0, 0, 0);

The outputColumn is here one of my objects that I have created from the custom property of my custom component.

Thanks in advance for any help...

David

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May 11, 2005

Hi:
I need to change a column's datatype from tinyint to int as follows:
alter table tableName
alter column column1 int

but with error <<'DF__LandMarks__color__6A50C1DA' is depending on it.>>

However, this old default is not part of the constraint. Thus, the only way is to delete it from sysobjects.

unfortunately, the following code I have to commented since they could only be executed line by line, not within a begin...end block.
--exec master.dbo.sp_configure 'allow updates', 1
--reconfigure with override
--delete from sysobjects
-- where name = 'DF__LandMarks__color__6A50C1DA'
-- and type = 'D'
--exec master.dbo.sp_configure 'allow updates', 0
--reconfigure with override

I need to update 10 server around 2500 databases with this change.
I have looked INFORMATION_SCHEMA related views, but not found default related, maybe I missed something.

thanks
David

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Dec 7, 2006

Hi,


Is there any way to find out if "subscription to publication has expired" in advance using RMO?

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Mar 29, 2005

Hi,


This is the error that I am getting after an unsuccessful
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Error 21776: [SQL-DMO] The name 'XXXX' was not found in the Database
collection. If the name is a qualified name, use [] to separate various parts
of the name, and try again.

Any ideas how can I delete that database?

Thanks

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Jul 12, 2007

Been doing some research after getting this error:
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And realised that my nice responsive varchars had a maximum total size. so I changed them for 'slower' text data types. but my DB still won't allow any more input.

has the limit been reached now regardless of what I change or can I rebuild the DB to recover the space or something?

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Dec 4, 2014

Getting below error most of the times .

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I am doing below steps to clear the log everytime.

1.EXEC sp_repldone @xactid = NULL, @xact_segno = NULL, @numtrans = 0,@time = 0, @reset = 1

2.checkpoint

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Aug 5, 2015

We are facing issue on one of our databases on Availability Group replica. FYI, please refer the below messages we are receiving. Moreover, the errors don't happen consistently for the specified user.

The client was unable to reuse a session with SPID 420, which had been reset for connection pooling. The failure ID is 46. This error may have been caused by an earlier operation failing. Check the error logs for failed operations immediately before this error message.

Error: 18456, Severity: 14, State: 46.
Error: 18056, Severity: 20, State: 46.

Login failed for user 'XXXX'. Reason: Failed to open the database 'YYYY' configured in the login object while revalidating the login on the connection. [CLIENT: aa.bb.cc.nn]

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Mar 3, 2008

hi,
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Login failed for the user'xxxx'(Microsoft SQL Server 2005. Error:18456)

if you have solution for my problem please send a reply as early as possible.

thanks,
ravi kishore.ch

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Jul 21, 2015

Running a report on sqlserver RS 2008 R2 that uses a data source that looks at a database on a sql express 2012 server.

I can run the report in preview mode from bits on the sql 2008 r2 server.

I have tested the connection of the  deployed data source on the sql 2008 R2 reporting services web page and connection has been successful.

I can logon to sql express 2012 using  management studio and logon as the user and access the database run stored procedures etc.

windows server 2003, sql server 2008 R2 reporting services server.

windows server 2012 sql express 2012 data source database location.

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Mar 18, 2007

hi,
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Everything seems exactly the same settings and user-wise from my old box to my new one, but nevertheless everything I've tried gives me the same error.
I've tried creating new users in SQL Server and giving them appropriate permissions to my database.  I've even tried just using the built in 'sa' account.  Nothing seems to change the error, except when I give it the incorrect password then it just says 'login failed'
This leads me to believe that i'm successfully logging into the SQL Server, but it doesn't want to give me access to the database I'm requesting access too.  But "apparently" the account i'm using should have access to the database.  If nothing else the 'sa' account should, but that didn't work either.
I'm stumped.  Any ideas?
 

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Jun 23, 2006

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Very Poor Performance - Identical DBs But Different Performance

Jun 22, 2006

Hello Everyone,I have a very complex performance issue with our production database.Here's the scenario. We have a production webserver server and adevelopment web server. Both are running SQL Server 2000.I encounted various performance issues with the production server witha particular query. It would take approximately 22 seconds to return100 rows, thats about 0.22 seconds per row. Note: I ran the query insingle user mode. So I tested the query on the Development server bytaking a backup (.dmp) of the database and moving it onto the devserver. I ran the same query and found that it ran in less than asecond.I took a look at the query execution plan and I found that they we'rethe exact same in both cases.Then I took a look at the various index's, and again I found nodifferences in the table indices.If both databases are identical, I'm assumeing that the issue isrelated to some external hardware issue like: disk space, memory etc.Or could it be OS software related issues, like service packs, SQLServer configuations etc.Here's what I've done to rule out some obvious hardware issues on theprod server:1. Moved all extraneous files to a secondary harddrive to free up spaceon the primary harddrive. There is 55gb's of free space on the disk.2. Applied SQL Server SP4 service packs3. Defragmented the primary harddrive4. Applied all Windows Server 2003 updatesHere is the prod servers system specs:2x Intel Xeon 2.67GHZTotal Physical Memory 2GB, Available Physical Memory 815MBWindows Server 2003 SE /w SP1Here is the dev serers system specs:2x Intel Xeon 2.80GHz2GB DDR2-SDRAMWindows Server 2003 SE /w SP1I'm not sure what else to do, the query performance is an order ofmagnitude difference and I can't explain it. To me its is a hardware oroperating systemrelated issue.Any Ideas would help me greatly!Thanks,Brian T

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Mar 9, 2007

We have the same application installed on a few different environments with similar servers and similar hardward.  The only difference is the versions of SQL and the colations.
Is SQL 2005 a lot faster that SQL 2000?  Could colation type make a big effect on performance?
ScAndal

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Aug 31, 2007

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Dec 8, 2003

I have a following problem with SQL performance:

this line 'select * from [viewUserLatestFee]' executes instantly (in Query Analiser)
this line 'select * from [viewUserLatestFee] where orgID = 1' takes up to 30 seconds for 1000 rows (still in Query analiser)

can anyone please help - I seem to have ran out of ideas

I have a feeling people might be curious about the view so here it is:

SELECT dbo.viewUserPosition.id, dbo.viewUserPosition.username, dbo.viewUserPosition.password, dbo.viewUserPosition.title,
dbo.viewUserPosition.firstName, dbo.viewUserPosition.lastName, dbo.viewUserPosition.email, dbo.viewUserPosition.address1,
dbo.viewUserPosition.address2, dbo.viewUserPosition.suburb, dbo.viewUserPosition.postcode, dbo.viewUserPosition.country,
dbo.viewUserPosition.state, dbo.viewUserPosition.mailAddress1, dbo.viewUserPosition.mailAddress2, dbo.viewUserPosition.mailSuburb,
dbo.viewUserPosition.mailPostcode, dbo.viewUserPosition.mailCountry, dbo.viewUserPosition.mailState, dbo.viewUserPosition.birthDate,
dbo.viewUserPosition.joinDate, dbo.viewUserPosition.lastUpdated, dbo.viewUserPosition.orgID, dbo.viewUserPosition.positionID,
dbo.viewLatestPaidFee.feeID, dbo.viewLatestPaidFee.mshipID, dbo.viewLatestPaidFee.name, dbo.viewLatestPaidFee.[desc],
dbo.viewLatestPaidFee.terms, dbo.viewLatestPaidFee.period, dbo.viewLatestPaidFee.periodType, dbo.viewLatestPaidFee.fee,
dbo.viewLatestPaidFee.startDate, dbo.viewLatestPaidFee.endDate, dbo.viewLatestPaidFee.deleted, dbo.viewLatestPaidFee.feePaidID,
dbo.viewLatestPaidFee.paidDate, dbo.viewLatestPaidFee.effectiveDate, dbo.viewLatestPaidFee.approved, dbo.viewLatestPaidFee.optionID,
dbo.viewLatestPaidFee.paidAmount, dbo.viewLatestPaidFee.feePaidEndDate
FROM dbo.viewUserPosition LEFT OUTER JOIN
dbo.viewLatestPaidFee ON dbo.viewUserPosition.id = dbo.viewLatestPaidFee.userID

Here is viewUserPosition:
SELECT dbo.tblUser.id, dbo.tblUser.username, dbo.tblUser.password, dbo.tblUser.title, dbo.tblUser.firstName, dbo.tblUser.lastName, dbo.tblUser.email,
dbo.tblUser.address1, dbo.tblUser.address2, dbo.tblUser.suburb, dbo.tblUser.postcode, dbo.tblUser.country, dbo.tblUser.state,
dbo.tblUser.mailAddress1, dbo.tblUser.mailAddress2, dbo.tblUser.mailSuburb, dbo.tblUser.mailPostcode, dbo.tblUser.mailCountry,
dbo.tblUser.mailState, dbo.tblUser.birthDate, dbo.tblUser.joinDate, dbo.tblUser.lastUpdated, dbo.tblRelPosition.orgID,
dbo.tblRelPosition.positionID
FROM dbo.tblUser INNER JOIN
dbo.tblRelPosition ON dbo.tblUser.id = dbo.tblRelPosition.userID

and viewLatestPaidFee:
SELECT dbo.tblMshipFee.id AS feeID, dbo.tblMshipFee.mshipID, dbo.tblMshipFee.name, dbo.tblMshipFee.[desc], dbo.tblMshipFee.terms,
dbo.tblMshipFee.period, dbo.tblMshipFee.periodType, dbo.tblMshipFee.fee, dbo.tblMshipFee.startDate, dbo.tblMshipFee.endDate,
dbo.tblMshipFee.deleted, fp.id AS feePaidID, fp.paidDate, fp.effectiveDate, fp.approved, fp.optionID, fp.paidAmount, fp.endDate AS feePaidEndDate,
fp.userID
FROM dbo.tblRelMshipFeePaid fp INNER JOIN
dbo.tblMshipFee ON dbo.tblMshipFee.id = fp.feeID AND fp.endDate =
(SELECT MAX(fp2.[endDate])
FROM [dbo].[tblRelMshipFeePaid] fp2
WHERE fp2.[userID] = fp.[userID])

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Jan 17, 2002

Hi,

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Mar 31, 2001

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HI
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Hello,

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Thanx in advance!


DECLARE @table TABLE (Contract nvarchar(15), Item nvarchar(12), Change_date datetime)

INSERT INTO @table
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