Inserting Multiple Records Using A @start And @count With One INSERT (and No Loop)

Is there a way to insert multiple records into a database table when you're just given "count" of the number of rows you want? I want to do this in ONE insert statment, so I don't want a solution that loops round doing 100 inserts - that would be too inefficient.

For example, suppose I want to create 100 card records starting it card number '1234000012340000'. Something like this ...

declare @card_start dec(16)
set @card_start = '1234000012340000'
declare @card_count int
set @card_count = 100

drop table card_table

create table card_table (
card_number dec(16),
activated char default 'N'
)

insert into card_table
select
... ???? ....

But WITHOUT using a while-loop (or any other kind of loop). I'm looking for fast and efficient code! Thanks.