Instr (vbscript) Function Explanation ???
Jan 15, 2001
I went to Microsoft to find some info about the function Instr. I need to
perform a search with a string similar to their example I found below. Can
anyone explain to me Microsoft's example?? I am little confused by the
parameters used and the explanation it gives back to me??
Dim SearchString, SearchChar, MyPos
SearchString ="XXpXXpXXPXXP" ' String to search in.
SearchChar = "P" ' Search for "P".
MyPos = Instr(4, SearchString, SearchChar, 1) ' A textual comparison
starting at position 4. Returns 6.
MyPos = Instr(1, SearchString, SearchChar, 0) ' A binary comparison
starting at position 1. Returns 9.
MyPos = Instr(SearchString, SearchChar) ' Comparison is binary by default
(last argument is omitted). Returns 9.
MyPos = Instr(1, SearchString, "W") ' A binary comparison starting at
position 1. Returns 0 ("W" is not found).
My problem is this:
I need to scan within SearchString for blanks/spaces characters. When I
find one, then place the values to the left and right of it in seperate
columns. For example, I would need to scan 'John Smith A' and then place
'John' in FirstName column, 'Smith' in LastName column, and 'A' in MidName
column.
I think this is how my code would read, but I am confused on how to place
the results into my table to the correct columns?
my search string would be SearchString = 'John Smith A'
my SearchChar would be SearchChar = ' ' (note I am searching for a
space/blank character)
So would then my code be like:
Dim SearchString, SearchChar, MyPos
SearchString = 'John Smith A'
SearchChar = ' '
MyPos = Instr(1, SearchString, SearchChar, 0)
How do I get whatever is returned from the Instr function to a column in a
table??
Any help would be great.
Rey
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Oct 26, 2006
Hi,In SQL SERVER 2005 Database I have a field called MedNames with values such as "sodium % 34ml" "desx chloride 9 % 76ml"I need to return the words before and including % so "sodium % 34ml" should return ""sodium % " Is it possible to do it in a select statement? I need to populate a dropdownlist with the shortened names.Thanks
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Oct 11, 2004
I am using the Instr(), Len(), and Mid() function in my SQL query and I keep getting errors stating those are not recognized functions. IS this correct? are there any equivelants?
thanks
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Jan 29, 2001
Hello there...
I am looking for the function that is the same as InStr in Access for SQL server. I have a column that has format like this.. Lastname,Firstname Middlename...
This column doesn't separate each one of them. However I need to separate Lastname and Firstname and Middlename.. I was told that in Access there is function(InStr) that can find a position of comma and separate it as Lastname like that....
I was searching BOL but I couldn't find like this function in SQL Server..
So I need help:-))))
Because everybody has a different length of the lastname, I have a problem.
I can not use SUBSTRING or LEFT or RIGHT because of the varying position of comma ...
Thanks in advance
Jay
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Dec 11, 2002
In VB there is InStr, in Excel you have SEARCH. what function can i use to search a string for a specific string. ie: how can i find where a space is in someones name?
our database has a table that is used for security. it contains a user code, user name and passcode. i need to split the username (currently forename and surname in same field) into two, around the space.
in VB i would write something like
strFName = left(<usernamefield>,InStr(1,<usernamefield>," ")-1)
to get the forename and similar to get the surname. how can i do this in SQL so that a view will supply the data apprpriately?
one of the reasons i want to do this is so that i can sort the users by surname! another is so that i can give options on their usercode - a combination of forename initial and 2 characters from surname.
any help welcomed.
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Jul 20, 2005
Hi everybody,I was looking for an equivalent ORACLE INSTR Function in MSSQL but Idon´t found it and I don´t know if it exist so I must to write it andthis is the code. Maybe it will be helful to you:/************************************************** *************************Description:Looks for a string inside another string and returns an integerthat correspond to the position of first ocurrence.Parameters:Input:- strSource. Contains the string where the functions look for theother string- strToFind. Contains the string to look for inside strSourceSalida:- Integer value indicating the position of first occurrence ofstrToFind in strSource************************************************** *************************/CREATE FUNCTION posSubString(@strSource varchar(400),@strToFind varchar(200)) RETURNS intASBEGINDECLARE@position int,@maxPos int,@longSubStr int,@res int,@strSub varchar(200)SET @position = 0SET @res = 0SET @longSubStr = LEN(RTIRM(LTRIM(@strToFind)))SET @maxPos = LEN(@strSource) - @longSubStrWHILE (@position <= @strToFind)BEGINSET @strSub = SUBSTRING(@strSource, @position, @longSubStr)IF (@strToFind = @StrSub)BEGINSET @res = @position - 1RETURN @resENDELSESET @position = @position + 1ENDRETURN @resENDAlonso
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Sep 25, 2000
Hi
My question is about the INSTR function of MSAccess
I want to know
Goodbye at every
I would you like to know if in TransactSQL of SQLServer7 exist a function that return the position of a string into an other string .
that is a Instr function MSAccess like
INSTR([Start,]expression1,expression2[,Comparison])
I'm sorry for my bad English
Thank you for everything
Emiliano
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Jun 4, 2007
Hi All
My SQL is extremly rusted so I need some help with a very basic function. I have a character field which is built up using a category code + '-' + number. The problem I have is that the category codes are all different lengths and the items were added using 9 instead of 09. I'm trying to clean up the data so that the same item with e.g. category code DZ20 cannot be added as DZ20-1 and DZ20-01. How do I find the position of the '-' in the Query Analyser for MSSQL 2000?
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Aug 11, 2000
This function is useful for fixed width output. E.g.
String(expr,10-len(expr),'0') will give you a number with leading zeros so it is always 10 characters long.
Thanks in advance for your time.
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Jan 20, 2006
is there a sql keyword for find or instr?
i have a field i wish to make into two and i need the position of a string "-" in the field so i can do a select right and copy that data to a new colm
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Mar 21, 2007
TASK: At my work we want to categorize and summarize all our IIS web logs and make statistics from it and such. What I need to do is take the browser type from a certain column in the table. All the information is stored in 1 column, and I figure an instr function would be best to do this. I am new to SQL, so I was told to look up the cursor function. In summary, I want to take all the IIS data and match it up against a defined table and then have a sum function for each browser.
Here are some examples of what the column data looks like: (found in the [csMethod] column
Mozilla/4.0+(compatible;+MSIE+6.0;+Windows+NT+5.1;+SV1)
Mozilla/4.0+(compatible;+MSIE+6.0;+Windows+NT+5.1;+SV1;+.NET+CLR+2.0.50727)
Mozilla/4.0+(compatible;+MSIE+7.0;+Windows+NT+5.1;+.NET+CLR+2.0.50727;+.NET+CLR+3.0.04506.30;+InfoPath.2;+.NET+CLR+1.1.4322)
Mozilla/5.0+(Windows;+U;+Windows+NT+5.1;+en-US;+rv:1.8.0.8)+Gecko/20061025+Firefox/1.5.0.8
I made a define table which lists an ID (primary key) and instr to search for as well as the full browser name. (define.browser)
DEFINE.BROWSER
ID# INSTR# BROWSER NAME
###############################
1___Opera+7_______Opera 7
2___Opera/9_______Opera 9
3___Safari/_______Safari
4___Firefox/1.0___Mozilla Firefox 1.0
5___Firefox/1.5___Mozilla Firefox 1.5
6___Firefox/2.0___Mozilla Firefox 2.0
7___MSIE+5.5______Microsoft Internet Explorer 5.5
8___MSIE+5________Microsoft Internet Explorer 5
9___MSIE+6________Microsoft Internet Explorer 6
10___MSIE+7________Microsoft Internet Explorer 7
11_________________OTHER BROWSER
I am having problems getting a cursor to work. Are there any good tutorials out there, or can anyone be of assistance. Thank you in advance.
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Jul 20, 2005
I am trying to convert a complex function from Oracle to SQL Serverand have come across Oracle's Instr() function. I see SQL Server hasCHARINDEX() which is similar, however it does not provide some keyfunctionality I need. Here is an example of the Oracle code:if Instr( sTg , cDelim, 1, 3 ) > 0 thensd := SubStr( sTg, Instr( sTg , cDelim, 1, 1 ) + 1, Instr( sTg,cDelim, 1, 2 ) - Instr( sTg , cDelim, 1, 1 ) - 1)end if;Has anybody converted anything similar to this within SQL Server? Anyhelp is GREATLY appreciated!Thanks.
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May 1, 2007
Greetings All
I have some data-- specifically times for cell phone usage in the format of (7:00, 15:51, 1,200:45, etc). I need to find a way to remove the ":" and the ","-- sum the data and then return it to its previous format of (7:00, 15:51, 1,200:45, etc). Does anyone have some code they could post??
thanks as always
km
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Feb 2, 2005
The syntax for Oracle's INSTR function is
instr (string1, string2, [start_position], [nth_appearance])
string1 is the string to search.
string2 is the substring to search for in string1.
start_position is the position in string1 where the search will start. This argument is optional. If omitted, it defaults to 1. The first position in the string is 1. If the start_position is negative, the function counts back start_position number of characters from the end of string1 and then searches towards the beginning of string1.
nth_appearance is the nth appearance of string2. This is optional. If omiited, it defaults to 1.
In SQL Server, we are having CHARINDEX and PATINDEX functions. But they will not accept the fourth paremeter (nth_appearance)
Do anybody know the solution for this ????
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Nov 18, 2015
I have a field that contains a town  ex : New York. Sometimes, the field will have brackets to be more specific ex: New York (Brooklyn). What I need is a formula that will return only "Brooklyn" if there are brackets or  the whole field if there are no brackets.Here's what I thought would do the trick :
=Iif(InStr(First(Fields!Ville.Value, "MW1R017A_IdentificationTravailleur_AdresseTravailleur"), "(") > 0,
Left(Split(First(Fields!Ville.Value, "MW1R017A_IdentificationTravailleur_AdresseTravailleur"), "(")(1), len(Split(First(Fields!Ville.Value, "MW1R017A_IdentificationTravailleur_AdresseTravailleur"), "(")(1)) - 1)
, First(Fields!Ville.Value, "MW1R017A_IdentificationTravailleur_AdresseTravailleur"))
So if InStr returns more than 0, meaning that I have brackets, I'll split at the "(", get the second part and remove the last character which is the closing bracket I don't want. If there is no bracket, I'll return the whole field.Somehow, when there is no bracket, my report overview shows me "#Error" as if the first Iif was true and what's in the true part is not actually possible, because it's trying to take the second part of a split that couldn't split because there is no bracket to split.
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Jan 22, 2008
Hi,
I have a project that has been given to me and need help please. The complete class is as follows
Public Class CarAccessData
Public Function Getcarinfo() As List(Of CarInfo)
Dim AllCarInfo As New List(Of CarInfo)
Dim SQL As String SQL = "SELECT [SKU], [CarMake], [CarModel], [Carprice]"
Dim MyConnection As SqlConnection MyConnection = New SqlConnection(ConfigurationManager.ConnectionStrings("AntConnectionString1").ConnectionString)
Dim aCmd As SqlCommand aCmd = MyConnection.CreateCommand
aCmd.CommandText = SQL aCmd.CommandType = CommandType.Text
Dim aDataReader As SqlDataReader
Try
MyConnection.Open()
aDataReader = aCmd.ExecuteReader
While aDataReader.Read()
AllCarInfo.Add(New CarInfo(aDataReader)) End While
Catch ex As Exception Throw ex Finally
aDataReader.Close()
MyConnection.Close() End Try
Return AllCarInfo End Function
End Class
The bit I dont quite understand is the following snippet from above
Dim aCmd As SqlCommand aCmd = MyConnection.CreateCommand
aCmd.CommandText = SQL aCmd.CommandType = CommandType.Text
Dim aDataReader As SqlDataReader
Try
MyConnection.Open()
aDataReader = aCmd.ExecuteReader
While aDataReader.Read()
AllCarInfo.Add(New CarInfo(aDataReader)) End While
Catch ex As Exception Throw ex Finally
Can anyone explain this in real ABC style step by step please, just so I can start to understand this, ( I am quite new to this)
many thanks,
Anteater
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Jun 1, 2004
the statement
if ((columns_updated() & 2 + 4 + 8)) > 0) is supposed to tell me if the 2nd, 3rd or 5th columns were updated. My question is, what desginates the column 2,3,5, when 2,4,8 are in the statement
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Apr 28, 2005
I am having some problems with transactions, although it seems that the problem exists within the vb code making the db call it may be that sql is the source of the problem.
1.
There is a number of stored procs that contain transactions most of which are inserts followed by a select statement to retrieve the most recently added ID. So to start with is a select the best way or is the @@Identity. I have read the @@Identity is global, so for a external server that is running a number of databases I stayed away from it. Did I take the right actions or is there a better way?
2.
Is having sql transactions within a call from vb.net ok? I know that the sqlClient class doesn't support nested transactions, but does that include transactions within sql?
3.
if a stored proc is called, from vb contained in a sqlClient transaction, are ALL the calls from within the sproc able to be rolled back?
If there is a reliable way to obtain the Identity without containing it in a transaction, and having the internal sql transactions in the problem, then I am home free, so I am hoping this is the case.
Thanks for any help
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Jul 23, 2005
PREDICATESUsed as a clause.A. What does PREDICATES mean?B. What does it mean when used in a where clause?I checked BOL (Glossary) but get no explanation there.ThanksJay
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Oct 31, 2007
I am wondering what are od1 and od2 used for in SQL Queries? Are they used for joining... can anyone explain their significance in the queries below... (especially the commands in red)
USE Northwind
SELECT OrderID, CustomerID
FROM Orders o
WHERE 20 < (SELECT Quantity
FROM [Order Details] od
WHERE o.OrderID = od.OrderID AND od.ProductID = 23)USE Northwind
SELECT DISTINCT ProductName, Quantity
FROM [Order Details] od1 JOIN Products p
ON od1.ProductID = p.ProductID
WHERE Quantity = (SELECT MAX(Quantity)
FROM [Order Details] od2
WHERE od1.ProductID = od2.ProductID)
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Jun 20, 2007
can anyone explain how this works:
USE NORTHWIND
GO
SELECT freight
FROM orders E1
WHERE (N =
(SELECT COUNT(DISTINCT (E2.freight))
FROM orders E2
WHERE E2.freight >= E1.freight))
replace N by a number. To find that Nth value from the table.
Ashley Rhodes
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Jul 23, 2005
In T sql for sql server, what is the technical difference between thecomparisons "is" and "="for example:set @test = nullprint @test is null -> trueprint @test = null -> false
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May 31, 2006
Ok, here is a asample table representing the problem more clearlyA | B | C | D-----------------a1 b1 c1 d1a1 b2 c2 d2a3 b3 c1 d3a4 b4 c4 d3a5 b5 c5 d5a6 b6 c6 d3Tha duplications are:row 1+2 in param Arow 1+3 in param Crow 3+4+6 in param Donly row 5 is unique in all parameters.conclusion: row 1+2+3+4+6 are the same usergoal: to find all duplicated rows & to delete them all accept oneinstance to leave.Note:Finding that row 1similar to 2 in A & deleting it will loose databecause we won't know that row 1 is ALSO similar to 3 on C & later onfinding that 3 is similar to 4 & 6 on D & so onThe simple time consuming (about 2 weaks) query to acomplish the taskis:SELECT count(*),A.B,C,DFROM tblGROUP BY A,B,C,DHAVING count(*)>1I THANK YOU ALL
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Feb 22, 2000
When a database is created in SQL Server, 4 files are made:
(example)
DB_Data.DAT
DB_data.mdf
DB_Log.DAT
DB_log.ldf
What do each of these files contain? I can figure out that the main database is the DB_Data.DAT, but why is the transaction log a .DAT and why is there four files instead of two? etceterea.
Llyal
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Apr 30, 2008
We've read about a single installation of SSIS applies to all SQL instances on a server. We've also read how by default SQL Server stores SSIS packages in the MSDB database on the default instance and if you want to have packages stored on a named instance you must modify msdtssrvr.ini.xml. Here are our questions.
1 - If msdtssrvr is modified to reference a named instance, such as <ServerName>SQLTESTINST1<ServerName>, when I connect to Integration Services through Management Studio do I still specify the default instance name in the login window? That's the only way we have been able to connect and despite specifying the default instance name, the packages displayed are those of the named instance.
2 - If I am correct that you must always specify the default instance name when connecting to Integration Services, then in order to eliminate confusion regarding what SQL instance's SSIS packages I am viewing under the folder structure I can create SQL Server folders by modifying msdtssrvr.ini.xml. For example:
<?xml version="1.0" encoding="utf-8"?>
<DtsServiceConfiguration xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance">
<StopExecutingPackagesOnShutdown>true</StopExecutingPackagesOnShutdown>
<TopLevelFolders>
<Folder xsi:type="SqlServerFolder">
<Name>MSDB</Name>
<ServerName>.</ServerName>
</Folder>
<Folder xsi:type="SqlServerFolder">
<Name>MSDB-INST1</Name>
<ServerName>SQLTESTINST1</ServerName>
</Folder>
<Folder xsi:type="SqlServerFolder">
<Name>MSDB-INST2</Name>
<ServerName>SQLTESTINST2</ServerName>
</Folder>
<Folder xsi:type="FileSystemFolder">
<Name>File System</Name>
<StorePath>..Packages</StorePath>
</Folder>
</TopLevelFolders>
</DtsServiceConfiguration>
I then restart the SSIS service and can now see the following folder structure.
Running Packages
Stored Packages
+ File System
+ MSDB
+ MSDB-INST1
+ MSDB-INST2
If I expand MSDB-INST1 I will only see packages saved on the instance named INST1. The same is true for INST2. If I expand MSDB I will only see packages saved on the default instance.
Does this sound like I am doing things correctly?
Thanks, Dave
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Jun 26, 2007
Hello,
In the ErrorLog of my Sql Server , i found this line :
2007-06-26 05:35:18.37 Serveur The SQL Network Interface library could not register the Service Principal Name (SPN) for the SQL Server service. Error: 0x54b, state: 3. Failure to register an SPN may cause integrated authentication to fall back to NTLM instead of Kerberos. This is an informational message. Further action is only required if Kerberos authentication is required by authentication policies.
Operating System XP Home SP2
SQL Server 2005 Express Edition with Advanced SP1 )
( idem for another workstation with XP Pro SP2 and same version of SQL Server 2005 Express
My problem is :
i want use the windows authentification but my computers are on Worhkgroup linked by a router ( no window server )
i have read that's possible to connect from a remote computer to a computer having a SQL Server 2005 Express through SPN
How can i do it ? ( activating NTLM ? but how ?)
I'm writing a C# program which must be executing on several computers with a SQL Server 2005 Express installed on a particular computer. These computers will belong to a domain of Windows Server 2003.
As i can't connect to this "normal" network, i am trying to simulate this network at home because i want to test this program and especially the possible locks problems.
I don't know whether i'm querying with the "correct" forum.
Sorry for my poor english.
I shall appreciate any help about this problem
Have a nice day
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Jun 9, 2007
Hello Everyone,
I am reading DataMining Tutorial and right now I am at the Mining Algorithms section. I cannot understand any of the algorithms. For example take the following text... what a bunch of mouthful bla bla bla it is ....
"The Microsoft Decision Trees algorithm supports both classification and regression and it works well for predictive modeling. Using the algorithm, you can predict both discrete and continuous attributes.
In building a model, the algorithm examines how each input attribute in the dataset affects the result of the predicted attribute, and then it uses the input attributes with the strongest relationship to create a series of splits, called nodes. As new nodes are added to the model, a tree structure begins to form. The top node of the tree describes the breakdown of the predicted attribute over the overall population. Each additional node is created based on the distribution of states of the predicted attribute as compared to the input attributes. If an input attribute is seen to cause the predicted attribute to favor one state over another, a new node is added to the model. The model continues to grow until none of the remaining attributes create a split that provides an improved prediction over the existing node. The model seeks to find a combination of attributes and their states that creates a disproportionate distribution of states in the predicted attribute, therefore allowing you to predict the outcome of the predicted attribute"
In the above text what is meant by discrete and continious attributes? what is regression? what is predicted attributes? what are input attributes? what is distribution of states?
Is there a source which explains these algorighms in a easier way ....
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Sep 21, 2005
I've been reconfiguring my Windows service accounts for the SQL Server service and the SQL Agent service to comply with the security best practices for SQL Server 2005. Specifically, I created two new network accounts. One account runs the SQL Server service, the other runs the SQL Agent service.
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Jan 7, 2008
If you know the answer please explain what you're doing if possible, that'll help me :)I have the following tables:CREATE TABLE [dbo].[tblUserData]( [UserCode] [int] IDENTITY(1,1) NOT NULL, [UserName] [nvarchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL, [DisplayName] [nvarchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,) ON [PRIMARY]CREATE TABLE [dbo].[tblFriends]( [UserCodeOwner] [int] NOT NULL, [UserCodeFriend] [int] NOT NULL, [createdate] [datetime] NOT NULL CONSTRAINT [DF_tblFriends_createdate] DEFAULT (getdate())) ON [PRIMARY]in tblFriends relations are stored twice, so for a relation between user 5 and 6, there will be 2 rows: 5-6 and 6-5Now, I want to get the columns (UsercodeOwner,UsercodeFriend,createdate,username,displayname) for relations that were created in tblFriends in the last 10 days for the FRIENDS of a person with usercode 5.Example:tblUserdata5 peter Petertje6 john Johnny11 simon SimonSays15 monique MontjetblFriends5 6 'createdate 30 days ago'5 11 'createdate 5 days ago'6 5 'createdate 30 days ago'6 11 'createdate 3 days ago'6 15 'createdate 7 days ago'11 5 'createdate 5 days ago'11 6 'createdate 3 days ago'15 6 'createdate 7 days ago'The resultset for a query on usercode 5 would now be (usercode1, username1, displayname1,usercode2, username2, displayname2,createdate):6 john Johnny 11 simon SimonSays 'createdate 3 days ago'6 john Johnny 15 monique Montje 'createdate 7 days ago'As you can see each relation is only returned twice even though there are always two entriesWhat would be the SQL statement, if possible without temp table..Thanks!
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Apr 3, 2006
I am getting a new server online at a customer, and our system shows very funny erorrs under full load. No explanations could be found. Anyone has some?
Here we go:
Server failed to resume the transaction, desc: 360000054a. The transaction active in this session has been committed or aborted by another session.,
at System.Data.SqlClient.SqlCommand.ExecuteNonQuery()
and
New request is not allowed to start because it should come with valid transaction descriptor.
System.Data.SqlClient.SqlException
I am a little lost on those. Simple fact is that I do not find any description of those. Anyone an idea what causes these?
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Jul 23, 2005
Hi,I can see that by using the object ID rather that the object name, thefollowing SQL query works. Has anybody got any idea what is causing theerror?-- Works OKselect o.id,checksum_agg(binary_checksum(m.text))from sysobjects o,syscomments mwhere o.id = m.idand o.xtype in ('FN','IF','P','TF','TR','V')group by o.id-- Error-- Server: Msg 1540, Level 16, State 1, Line 1-- Cannot sort a row of size 8096, which is greater than the-- allowable maximum of 8094.select object_name(o.id),checksum_agg(binary_checksum(m.text))from sysobjects o,syscomments mwhere o.id = m.idand o.xtype in ('FN','IF','P','TF','TR','V')group by object_name(o.id)-- Error-- Server: Msg 1540, Level 16, State 1, Line 1-- Cannot sort a row of size 8096, which is greater than the-- allowable maximum of 8094.select o.name,checksum_agg(binary_checksum(m.text))from sysobjects o,syscomments mwhere o.id = m.idand o.xtype in ('FN','IF','P','TF','TR','V')group by o.name-- Workaroundselect getdate(),object_name(x.id),check_sumfrom (select m.id,checksum_agg(binary_checksum(m.text)) as check_sumfrom syscomments minner joinsysobjects oon m.id = o.idwhere o.xtype in ('FN','IF','P','TF','TR','V')group by m.id) as xRegardsLiam
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Jan 22, 2007
We are trying to create a model of linear regression with nested table. We used the create mining model sintax as follow :
create mining model rate_plan3002_nested2
( CUST_cycle LONG KEY,
VOICE_CHARGES double CONTINUOUS predict,
DUR_PARTNER_GRP_1 double regressor CONTINUOUS ,
nested_taarif_time_3002 table
( CUST_cycle long CONTINUOUS,
TARIFF_TIME text key,
TARIFF_VOICE_DUR_ALL double regressor CONTINUOUS
)
) using microsoft_linear_regression
INSERT INTO MINING STRUCTURE [rate_plan3002_nested2_Structure]
(CUST_cycle ,
VOICE_CHARGES ,
DUR_PARTNER_GRP_1 ,
[nested_taarif_time_3002](SKIP,TARIFF_TIME ,TARIFF_VOICE_DUR_ALL)
)
SHAPE {
OPENQUERY([Cell],
'SELECT CUST_cycle ,
VOICE_CHARGES ,
DUR_PARTNER_GRP_1
FROM dbo.panel_anality_3002
order by CUST_cycle ')}
APPEND
({OPENQUERY([Cell],
'select CUST_cycle,
TARIFF_TIME,
CYCLE_DATE
from dbo.nested_taarif_time_3002
order by CUST_cycle,TARIFF_TIME')
}
relate CUST_cycle to CUST_cycle
) as nested_taarif_time_3002
The results we got are a model with intercept only. if we don't use the nested variable (the red line) we get a rigth model . (we had more variable ....)
Is there a way to do this regression correctly?
Thanks,
Dror
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May 1, 2008
(I wish I was able to attach pictures....anyhow I'll try my best without them)
The customer's goal is to via ReportBuilder to select fields from multiple
many-to-many relationships. They are able to see the fields that exists
within the various many-to-many relationships but IS ONLY able to select
fields from ONE many-to-many relationship. Example using AdventureWorks:
DataSourceView (relationships automatically generated by wizard)
Contact ---< VendorContact >--- Vendor
Contact ---< StoreContact >--- Store
Contact ---< ContactCreditCard >--- CreditCard
So the goal in the ReportBuilder is to be able select fields from
Contact/Vendor/Store/ and CreditCard.
PROBLEM is that the ReportBuilder ONLY allows user to select fields from
Contact/Vendor OR Contact/Store OR Contact/CreditCard (exclusively)
The only workaround I've found is to reverse the relationships in the
DataSourceView to the following
Contact >--- VendorContact ---< Vendor
Contact >--- StoreContact ---< Store
Contact >--- ContactCreditCard ---< CreditCard
This works however we need an explanation as to why it only works this way?
Thanks in advance
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