Last Day In A Random Month

Mar 7, 2006

So i've got to generate these queries that go from the first of a one month to the last day of a month. the user provides the starting and ending months.

What I was wondering was is there an easy way to set the last day of the month in sql without having to go in and hard code which months end on the 30 and which ones end on the 31.

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Returning Random Records And NOT Similar (random Questions)

Jul 20, 2005

Hi,I need to extract randomly 5 records from the table "Questions". Now I useSELECT TOP 5 FROM Questions ORDERBY NEWID()And it works. The problem is that I need an additional thing: if SQLextracts record with ID=4, then it should not extract record with ID=9,because they are similar. I mean, I'd like something to tell SQL that if itextracts some questions, then it SHOULD NOT extract other ones.How can I do it?Thanks!Luke

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Apr 5, 2008

Hello what I'd like to display the following in a matrix report:

Parameter selected: 3 (March), 2008 (Year)

Monthly TO Summed up
ArtNo March <=March
1210 20,500 50,900
1220 21,200 64,000
1230 15,400 40,300
... ... ...

So, in the rows I have the articles and in the column the selected month via parameter. In another column I need to sum up all monthly values up to the selected month, meaning in this example the sum of jan, feb and mar per article.

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Oct 14, 2004

I'm using ASP and SQL Serv 2000. What I need to get from 2 tables (company & customers) is random 10 customers from random 20 comp.
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Help is greatly appreciated.

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Apr 22, 2015

following table global_usage

ID varchar (contains alphanumeric values,not unique)
Territory (combined with ID unique)
Total_Used int can be null
Date_ date (date of the import of the data)
ID Territory Total_Used Date_
ACASC CAL071287 2014-06-01
ACASC CAL071287 2014-08-01
ACASC CAL071288 2014-09-01

[Code] .....

Now the problem,per month I need the most recent value so I'm expecting

ACASC CAL071287 2014-06-01
ACASC CAL071287 2014-08-01
ACASC CAL071288 2014-09-01
ACASC CAL071288 2014-11-01
ACASC CAL071190 2014-12-14
ACASC CAL071286 2015-01-22
ACASC CAL071165 2015-02-01
ACASC CAL071164 2015-03-01

I've tried a few thing like group,having even row_number() but I keep getting wrong results

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Nov 9, 2015

I have two tables Costtable (Id,ResourceId, Amount,Date) and ResourceTable (ResourceId,Name) which shows output as below.

I want to show 0 amount for rest of the name in case of September. For e.g. if rest of the Resources does not appear in cost table they should appear 0 in amount

My Desired output

My current query

SELECT
RG.Id AS Id,
RG.Name AS Name,
ISNULL(SUM(AC.Amount), 0) AS Amount,
RIGHT(CONVERT(varchar(10), AC.[Date], 105), 7) AS [YearMonth]

[Code] ....

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Sep 10, 2014

This is my table and data

CVID | WorkExperience
--------------------------------
2838736
68181101
96568122
1135484

I need to convert into this result

CVID | WorkExperience
--------------------------------
283873 years
681818 years 5 months
9656812 years 2 months
1135484 months

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Aug 11, 2015

Most of the data is in one table. 

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RSP RSP RSP RSP
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AMERICAN ESCROW & CL//AECC $2,650 4 $0 0 $3,720 8 $0 0 $2,339 4 $0 0 $2,460 2 $0 0
American Internation//AIRCO $9,131 30 $2,340 9 $10,927 35 $2,340 9 $9,142 31 $2,600 10 $18,406 54 $3,900 15
American Internation//AIR $20,611 63 $1,820 8 $23,892 75 $1,040 4 $35,038 111 $3,120 12 $3,778 16 $1,560 6
American Internation//Ab $64,248 206 $6,240 24 $59,800 187 $5,200 20 $87,115 264

I did something similar doing just record counts but this is far more complicated. I'm at a loss that this is even possible.

 SUM(CASE datepart(month, tbFile.openedDate) WHEN 1 THEN 1 ELSE 0 END) AS 'January', 

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Aug 2, 2002

Does anyone know how I can get last day of month
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@Month = 2
@Year = 2004
The result I would need is 29 because there are 29 in
the month of February in the 2004.
Any help on this is greatly appreciated.
Kellie

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Select
Jan 1- 23rd
feb 1-23rd
march 1-23rd
april 1-23rd
,value
from
table

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Sep 10, 2007

Hi I trying to find a way to determine the number of working days per month starting from the current date to the last day of the current month.And within the same store procedure determine the number of working days as normal (each month is independent from the next). For example: The store procedure is executed

September:
@CurrentDate = 9/10/2007
@EndDate = last working day 9/30/2007

Total# of working days = 15

October:
@CurrentDate = 10/1/2007
@EndDate = last working day 10/31/2007

Total# of working days = 23

November:
@CurrentDate = 11/1/2007
@EndDate = last working day 11/30/2007

Total# of working days = 22
etc.
Any ideas of how i can approch this?

Thanks in advance.

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Dec 11, 2006

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how do i wirte my sql so it only gives me the dictinct groups month/year  of the classes I have so that it comes out like so..
11/2006
12/2006
1/2007
3/2007
i try with my sql below but i cant get the groups th come out in order. i dont think it sees it as a date value.
dbo.classgiven.classdate date of the class.thank you all 
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Nov 16, 1999

Hi,

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Jun 22, 2001

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This is the function: select rand()

Alberto.

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thanks in advance

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Jan 1, 2005

Hello guys , I am new here,

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See this screenshot: Click Here
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Also I don't know how can I add that Random thing *See the arrow in the screenshot*

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May 4, 2006

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Any idea on how to do this using SQL2000 or coding.
I feel this is much better than Identity Column as using autonumbers in quesrystring is too much risky as they easily readable.

Please help.
Thanks

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Mar 8, 2005

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For example: 1 327 a
2 327 b
3 327 c
4 328 aa
5 328 bb......

I need to retrieve each time SiteCode with random SiteName.
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328 aa 328 bb 328 aa.

I need it very urgent, so any ideas will be very helpful. Thanks to all,

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Nov 23, 2007

How Can I select a Random set of records from a database table?

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Jan 9, 2004

I have a customer that wants to be able to generate a random list...
-----------------------
The list is case numbers, and I can get those easy enough by saying

SELECT
dbo.table_case.id_number
FROM
dbo.table_case


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Is this something I can do via a SQL query?

Thanks,
Dan

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Jan 26, 2004

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Jun 10, 2008

Hi Experts ,
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TIA

RKNAIR

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Jun 10, 2008

Hi Experts ,
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RKNAIR

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Apr 15, 2002

Generates a true random number from xxx to zzz. Uses a table variable so it all depends on the boundaries you specify how long it will take.

create procedure random_number
@lower int = 0,
@upper int = 256,
@number int = null output
as
set nocount on

declare @numbers table (number_id int identity(1,1), value int)

if @lower > @upper
begin
set @number = @lower
set @lower = @upper
set @upper = @number
end

set @number = rand((datepart(mm, getdate()) * 100000) + (datepart(ss, getdate()) * 1000) + datepart(ms, getdate()))

while (select count(*)
from @numbers) < (@upper - @lower + 1)
begin
insert into @numbers (value)
select (@upper - @lower + 1) * rand() + @lower
end

select @number = value
from @numbers
order by newid()
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Apr 15, 2002

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create procedure random_password
@length smallint,
@password nvarchar(256) = null output
as
set nocount on

declare @number int
declare @lower int
declare @upper int
declare @part tinyint

if @length > 256 set @length = 256
set @password = ''

while len(@password) < @length
begin
exec random_number 0, 3, @part output

if @part = 0
select @lower = ascii('a'),
@upper = ascii('z')
else if @part = 1
select @lower = ascii('A'),
@upper = ascii('Z')
else if @part = 2
select @lower = ascii('0'),
@upper = ascii('9')

set @part = null
set @number = null
exec random_number @lower, @upper, @number output
set @password = @password + ltrim(char(@number))
if substring(@password, len(@password), 1) = char(0) set @password = left(@password, len(@password) - 1)
end
go

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I have a table

IDCODENAME
611GI08Gian
610GI07Gian
618GI15Gian
620 FT Rope
320 ST Soler
345 ST01 Soler

I need the output one random value from same name

like
IDCODENAME
611GI08Gian (it should be random)
620 FT Rope
320 ST Soler (it should be random)

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Oct 8, 2005

I need to update an integer column in my table with a random number. Here's what I've done so far (with the table name and column names changed):

UPDATE dbo.MyTable
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My question is, how come the values in my column all have the same value? I thought the RAND function gives out a random number? How can I update my table to generate random numbers?

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