Left Anti Semi Join
Jul 20, 2005Hi!
Whether there is an example where is used "Left Anti Semi Join"?
Join Bytes!
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Left Join Vs Left Outer Join Syntax Generates Different Execution Plans
Apr 16, 2008
Anyone know why using
SELECT *
FROM a LEFT OUTER JOIN b
ON a.id = b.id
instead of
SELECT *
FROM a LEFT JOIN b
ON a.id = b.id
generates a different execution plan?
My query is more complex, but when I change "LEFT OUTER JOIN" to "LEFT JOIN" I get a different execution plan, which is absolutely baffling me! Especially considering everything I know and was able to research essentially said the "OUTER" is implied in "LEFT JOIN".
Any enlightenment is very appreciated.
Thanks
Left Join Vs Left Outer Join
Apr 7, 2008Is there any difference between left join and left outer join in sql server 2000?please reply with example if any?
Thanks in advance
Left Join Vs Left Outer Join
May 14, 2008Hi,
Whats the diference between a left join and a left outer Join
Integration Services :: How To Perform Left Restricted Join In Merge Join Transformation
May 22, 2015I have two xml source and i need only left restricted data.
how can i perform left restricted join?
Transact SQL :: Difference Between Inner Join And Left Outer Join In Multi-table Joins?
Oct 8, 2015I was writing a query using both left outer join and inner join. And the query was ....
SELECT
S.companyname AS supplier, S.country,P.productid, P.productname, P.unitprice,C.categoryname
FROM
Production.Suppliers AS S LEFT OUTER JOIN
(Production.Products AS P
INNER JOIN Production.Categories AS C
[code]....
However ,the result that i got was correct.But when i did the same query using the left outer join in both the cases
i.e..
SELECT
S.companyname AS supplier, S.country,P.productid, P.productname, P.unitprice,C.categoryname
FROM
Production.Suppliers AS S LEFT OUTER JOIN
(Production.Products AS P
LEFT OUTER JOIN Production.Categories AS C
ON C.categoryid = P.categoryid)
ON
S.supplierid = P.supplierid
WHERE
S.country = N'Japan';
The result i got was same,i.e
supplier country productid productname unitprice categorynameSupplier QOVFD Japan 9 Product AOZBW 97.00 Meat/PoultrySupplier QOVFD Japan 10 Product YHXGE 31.00 SeafoodSupplier QOVFD Japan 74 Product BKAZJ 10.00 ProduceSupplier QWUSF Japan 13 Product POXFU 6.00 SeafoodSupplier QWUSF Japan 14 Product PWCJB 23.25 ProduceSupplier QWUSF Japan 15 Product KSZOI 15.50 CondimentsSupplier XYZ Japan NULL NULL NULL NULLSupplier XYZ Japan NULL NULL NULL NULL
and this time also i got the same result.My question is that is there any specific reason to use inner join when join the third table and not the left outer join.
'Left Outer Merge Join' Failing To Join Valid Row
Aug 10, 2007Scenario:
OLEDB source 1
SELECT ...
,[MANUAL DCD ID] <-- this column set to sort order = 1
...
FROM [dbo].[XLSDCI] ORDER BY [MANUAL DCD ID] ASC
OLEDB source 2
SELECT ...
,[Bo Tkt Num] <-- this column set to sort order = 1
...
FROM ....[dbo].[FFFenics] ORDER BY [Bo Tkt Num] ASC
These two tasks are followed immediately by a MERGE JOIN
All columns in source1 are ticked, all column in source2 are ticked, join key is shown above.
join type is left outer join (source 1 -> source 2)
result of source1 (..dcd column)
...
4-400-8000119
4-400-8000120
4-400-8000121
4-400-8000122 <--row not joining
4-400-8000123
4-400-8000124
...
result of source2 (..tkt num column)
...
4-400-1000118
4-400-1000119
4-400-1000120
4-400-1000121
4-400-1000122 <--row not joining
4-400-1000123
4-400-1000124
4-400-1000125
...
All other rows are joining as expected.
Why is it failing for this one row?
Select Command - Left Join Versus Inner Join
Aug 9, 2013Why would I use a left join instead of a inner join when the columns entered within the SELECT command determine what is displayed from the query results?
View 4 Replies View RelatedRight Join Returns Same Results As Left Join
Feb 5, 2015Why does this right join return the same results as using a left (or even a full join)?There are 470 records in Account, and there are 1611 records in Contact. But any join returns 793 records.
select Contact.firstname, Contact.lastname, Account.[Account Name]
from Contact
right join Account
on Contact.[Account Name] = Account.[Account Name]
where Contact.[Account Name] = Account.[Account Name]
How To Join 3 Tables Using Left Or Right Join Keyword?
Aug 17, 2007Hi guys,
I'll appreciate any help with the following problem:
I need to retrieve data from 3 tables. 2 master tables and 1 transaction table.
1. Master table TBLOC contain 2 records :
rcd 1. S01
rcd 2. S02
2. Master table TBCODE contain 5 records:
rcd 1. C1
rcd 2. C2
rcd 3. C3
rcd 4. C4
rcd 5. C5
3. Transaction table TBITEM contain 4 records which link to 2 master table:
rcd 1. S01, C1, CAR
rcd 2. S01, C4, TOY
rcd 3. S01, C5, KEY
rcd 4. S02, C2, CAR
I use Left Join & Right Join to retrieve result below (using non-ASNI method) but it doesn't work.
Right Join method:
SELECT C.LOC, B.CODE, A.ITEM FROM TBITEM A RIGHT JOIN TBCODE B ON A.CODE = B.CODE
RIGHT JOIN TBLOC C ON A.LOC = C.LOC
GROUP BY C.LOC, B.CODE, A.ITEM ORDER BY C.LOC, B.CODE
When I use Non-ASNI method it work:
SELECT C.LOC, B.CODE, A.ITEM FROM TBITEM A, TBCODE B, TBLOC C
WHERE A.CODE =* B.CODE AND A.LOC =* C.LOC
GROUP BY C.LOC, B.CODE, A.ITEM ORDER BY C.LOC, B.CODE
Result:
LOC CODE ITEM
-----------------------------
S01 C1 NULL
S01 C2 NULL
S01 C3 CAR
S01 C4 TOY
S01 C5 KEY
S02 C1 NULL
S02 C2 CAR
S02 C3 NULL
S02 C4 NULL
S02 C5 NULL
Please Help.
Thanks.
Why Is Left Table In LEFT JOIN Limited By Where Clause On Right Table
Jan 25, 2015-- Why is the left table in a LEFT JOIN limited by the where clause on the right table?eg
DECLARE @LeftTable TABLE (LeftID INT NOT NULL IDENTITY(1, 1), LeftValue INT NULL)
INSERT @LeftTable (LeftValue)
VALUES (111)
INSERT @LeftTable (LeftValue)
VALUES (222)
[code]....
SQL LEFT JOIN Help
Jan 26, 2007I'm trying to join 2 tables. I thought I was getting the correct results but it turns out I'm not.
My Query:
SELECT IVINVA, IVORDN, IVCSLN, IVRESR, IVCITM, CONVERT(varchar(12),CAST(IVIAMT as money),1) AS ExtPrice, CONVERT(varchar(12),CAST(IVPIVC as money),1) AS DistPrice, IVCSUM, IVQYCS, IVDESC, OIRESR, OIDPCT, CONVERT(varchar(12),CAST(IVPIVC - (OIDPCT / 100 * IVPIVC) as money),1) AS NetPrice FROM INVDET1_TBL LEFT JOIN ORDDIS_TBL ON ORDDIS_TBL.OIORDN = INVDET1_TBL.IVORDN AND ORDDIS_TBL.OIRESR = INVDET1_TBL.IVRESR WHERE IVORDN = '0859919' AND IVINVA = '00324024'
Basically, my problem lies in the seonc condition of the LEFT JOIN. I needed to set the two tables equal my item number, because in some situations I need that logic to get the correct result. It most other cases, that item column in the ORDDIS_TBL is NULL, thus giving me the wrong results. In that case, I would want the JOIN to only be ORDDIS_TBL.OIORDN = INVDET1_TBL.IVORDN, and not include the second part. Is there a way I can condition this with an If statement, If ORDDIS_TBL.OIRESR is Null then do this join, if not, then do this? I'm confused how to get the proper result here.
Left Join Help
Jul 7, 2005I need to make a left join from the freezefile f, to sped s, instead of having f.studentid = s.id in the where clause. Any help??
select f.studentid, f.studentname, f.sex, fs.mealstatus, s.except, s.lre, r.description, g.testid, g.scale_la, g.scale_ma, t.test_name, t.year
from freezefile f, fsapps fs, sped s, regtb_exception r, gqe_scores g, test_info t
where
f.type = 'ADM'
and
s.except = r.code
and
t.test_name = 'ISTEP'
and
t.year = 2004
and
g.testid = t.testid
and
f.studentid = fs.id
and
f.studentid = s.id
and
f.studentid = g.studentid
Left/right Join
Aug 2, 2004i'm shure it's some smal stiupid mistake bat I can't find it, PLZ help.
1)
select komorka from #plantemp
--result
komorka
09
10
I-P
II-P
III-P
SI/1
SI/2
SI/3
2)
select komorka,ustalenia from analiza_1 a where a.koniec between '20040701'and '20040731'
komorka ustalenia
SI/1788138.9300
SI/246638.4900
SI/216218.4000
08.0000
3)
select p.komorka,isnull(sum(ustalenia),0)
from #plantemp p left join analiza_1 a on p.komorka=a.komorka
where a.koniec between '20040701'and '20040731'
group by p.komorka
komorka ustalenia (sum)
08.0000
SI/1788138.9300
SI/262856.8900
I need all rows from table 1 bat right and left join gives me the same results, WHY
Left Join
Jan 9, 2007There are two tables:
tblIndices:
IndexID, Name
1index1
2index2
3index3
.
.
.
tblBasketConstituents
ID, ParentIndexID, ChildIndexID, Weight
121 20
223 80
313 50
412 50
As you can see the ParentIndexID and ChildIndexID fields refer to tblIndices.IndexID
I would like a stored procedure as follows:
show all index names and show the wights for the indexID you passed.
This is what I have so far and it is not correct yet. Not sure what the syntax should be.
alter PROCEDURE [dbo].[uspBasketIndices_Get]
@IndexIDint
AS
select
i.IndexID,
i.[Name],
bc.Weight
from
tblIndices as i left join tblBasketConstituents as bc on i.IndexID = bc.ParentIndexID
and i.IndexID = @IndexID
order by
i.[Name]
How Many 'LEFT JOIN' Is Too Many?
Feb 26, 2004Any one know any facts and figures about maximum Left Joins allowed (or recommended) in one query?
I am running a MS SQL 2000 my database is full of relational data and most of my foreign keys (INT data type) are a Clustered Indexed, Usually I will only be pulling one record from collection of about a dozen tables, but the Database is expected to grow fast and become big.
Right now I have a Stored Proc that has eight(8) LEFT JOINs in it. My worry is that this query will kill me as the database approaches 50,000 records.
Lito
Left Join
Mar 6, 2007Hi all. My query works fine, it generates reports but not my expected result.
select d.fullname, p.nickname, p.birthdate, p.birthplace,
p.gender, p.civilstatus, p.religion, p.nationality, p. weight, p.height,
p.haircolor, p.eyecolor, p.complexion, p.bodybuilt, p.picture, p.dialectspoken,
d.mobilephone, d.prprovince,[Age] = dbo.F_AGE_IN_YEARS( birthdate, getdate() ),
c.name, c.address, c.telno, c.email, c.occupation, ed.year1, ed.year2, ed.degree, sch.schname
from hremployees as e
inner join psdatacenter as d on e.empdcno = d.dcno
inner join pspersonaldata as p on e.empdcno = p.dcno
left join hrappempcharrefs as c on e.empdcno = c.empdcno
left join hrappempeducs as ed on e.empdcno = ed.empdcno
left join hrsetschools as sch on ed.schoolcode = sch.schcode
the above query gives a 77 records
if i ran "select * from hremployees" generates 60 records
i think the error is in the left joining.
hrappempcharrefs, hrappempeducs and hrsetschools must be left joined to hremployees.
thanks
-Ron-
Left Join Using Vb 9.0 And LINQ
Dec 2, 2007Hi Guys,
I started working with linq and vb9.0 but i have a small problem i could feagure how to solve in c# but not in vb
I wanted to make left join or right join on vb 9.0 and linq is it possible or this is only c# feature ?
Waiting to hear from u guys,
Thanks
Softy
Left Outer Join-please Help!
Jan 7, 2002Hello!
I need to write a query using left outer join and I'm having trouble with it.
I have 2 tables:customer and cust_info.
I want to pull all records from customer table and cust_info table even if there is no related data in cust_info table.
But I need one condition in this query:only records from customer table where cus_type in ("A","B","C").
I don't need all other types ("D","E").
So my query looks like this:
select customer.cus_name,customer.cus_address,customer.cu s_type,cus_info.status
from customer
left outer join cus_info ON customer.sxdat_pk = cus_info.sxdat_pk
and cus_type in ("A","B","C")
AND cus_info.cus_table = 'CUSTOMER'
The result should be like this:
cus_name cus_address cus_type status
Amoco 457 bent A new
Bingo 47 lone oak C NULL
Sears 1020 Magic dr. B exist
But my query pulls records for customers with type "D" and "E" that I'm trying to exclude from result.
Please help.
Thanks,
lena
LEFT JOIN Problem
Apr 18, 2008Hello everybody!!!
I have to left join 2 tables. The first consists of columns:id, description, descr_num.
The second table: id, descr_num, value.
I need to extract description from table1 where descr_num is in the range , say, 1-10.
LEFT JOIN
extract value from table2 ,descr_num should be in the same range. in table2 some values from (1,10) and desc_num could be not present.
BUT i want this left join to be limited as i said.
Is there any solution to this prob. without creating temp tables. Or actually can i do such a join?
Thank you
Left Join Table
Jul 18, 2006Now I have a table with the table design as following :
table cst_EmpProfile
intEmpId nvcEmpName nvcEmpAddress intEmployeeType bitActiv
1 Peter Null Null true
2 Juli 1, xxxx 2 true
3 Sam Null Null False
table cst_EmpType
intEmpType nvcEmployeeType
1 Free Enginner
2 Manager
3 Operator
To join the table but MUST follow the condition as bitActiv = TRUE:
select emp.nvcEmpName, emp.nvcEmpAddress, ety. nvcEmployeeType from cst_EmpProfile emp left join cst_EmpType on emp.intEmployeeTypee = ety.intEmpType and emp.bitActiv = 1.
But, the sql statement doesnt output the my expected result.
Because the data row return must be 1st and 2nd row as it bitActiv = true.
So, how's I going achieve what i want. tq.
Stumped - LEFT JOIN
Jan 10, 2007Hi, I'm getting the error Syntax error (missing operator) in query expression 'dbPWork.id = dbPWorkWord.work_id LEFT JOIN words ON dbPWorkWord.word_id = words.id'." on the query below. Everything looks in place to me. Do you see anything that shouldn't work?
Query:
Code:
Code:
SELECT DISTINCT dbPWork.id, description_e as description, w_id , dateStart, dateEnd FROM dbPWork
LEFT JOIN dbPWorkW ON dbWork.id = dbPWorkW.work_id
LEFT JOIN words ON dbPWorkW.word_id = words.id
Everything works fine until I add the second LEFT JOIN statement. Any ideas? I'm stumped.
Left Join Question
Sep 22, 2005I have a left join that doesn't suit my request.
select * from A
left join B
on A.x=B.x
The problem is that for a specific record in A we can find 1 or more entries in B. What I want is to return only the 1st entry found on B.
thx
Difference Between LEFT N RIGHT JOIN
Dec 6, 2005Hi,
I have got a query for you guys. Can any one temme the difference between
"FROM Table_A LEFT JOIN Table_B" and "FROM Table_B RIGHT JOIN Table_A"
;)
Thanks,
Rahul Jha
Left Join And Subquery
May 1, 2004Hi,
Iwant to make a left join between two tables connected with a specific field
but I also want to have some criteria on the right table.
I want to display all the rows from the first(left) table and only the rows from the secod (right) table that match the join and the criteria.
However If I have criteria on the second table the join behaves like an inner join displaying only the rows that exist in both tables.
In MS Access instead of the right table I use a query in which I enter the criteria and then I connect it with a left join in a new query in order to get the right results. How can I do itin MSSQLServer without using Views?
Must I use a subquery with Exists and what is the right syntax in order to achieve this?
Best Regards,
manolis Perrakis
Left Outer Join?
Jun 17, 2008Hi there,
I have three tables
Job
JobID
WeightIn
WeightOut
Operator
OperatorID
NameFirst
NameLast
JobOperator
JobOperatorID
JobID
OperatorID
a job can be done with 1 or more operators
I want to be able to show user both assigned and unassigned operator on the front end on a certain job so I haev only parm being passed in @jobID.
How do I got about showing all the operators but somehow differentiate ones already assigned to job
Thanks!
Duplicate When Do Left Join
Jan 27, 2014select a.[Cuno], [doc_type], [Doc_name]
from [assembly] a
left join [assembly_Doc] doc
ON a.id = doc.assembly_id
left join [assembly_Recog] re
ON a.id = re.assembly_id
where [activate] =1
and doc.doc_type = 1
I only have two records for doc_type =1 in the [assembly_Doc] table. Without joining the third table [assembly_Recog], the results is corrected, 2 records returned. I need to join with [assembly_Recog] table, but when it joined, I got the duplicate records. It listed twice. pls see the results below:
CusNoDocType DocName
CUS-022 1B1489-01 Rev 1
CUS-022 1B1489-01 Rev 1
CUS-022 1B149-02 Rev 2
CUS-022 1B149-02 Rev 2
Basic Left Join
Feb 12, 2015I want to join file a and file b where a.ent = b.ent and a.suf - b.suf i want one col from file b which is grc# even if blank.
Select * from mylib.filea a left join
hislib.fileb b
where a.ent = b.ent
and a.suf = b.suf
Delete With Left Join
Feb 20, 2015What is the logic of the below DELETE statement?It deletes all records where the file_modified column value is smaller then the maximum value in the same column, but not crystal clear how...
delete a
from Staging a
left join (select max(file_modifieddate) as file_modifieddate from Staging) b on
a.file_modifieddate = b.file_modifieddate
where b.file_modifieddate is null
Left Outer Join
Dec 4, 2006Good evening!
Well,in relational algebra we have left outer join.
In SQL is any command for that?
How can i use left outer join?
Left Outer Join
Jan 15, 2007I'm relatively new to SQL and I am wondering about when to use left outer joins. When should you use left outer joins?
View 2 Replies View RelatedLeft Join Error
Apr 27, 2007I am trying to do a left join from one table a to table B on a column CEO_ID which is of datatype varchar(5) in table A and of datatye nvarchar(20) in table b.The resultset gives me all the rows that are in both the tables except a few..So when I looked at the records that are missing, it is stored as 00392 in table A and 392 in table b and that is the reason it is not showing that record in the result.How can I show these records?
Query
Select p.CEO_ID,p.Part_ID,ct.CEO_ID__c
from
Contact ct
left join
Main5.dbo.Part p
on
p.CEO_ID = Convert(varchar(5),ct.CEO_ID__c) collate database_default
where
ct.CEO_ID__c = 392
ResultSet
CEO_ID CEO_ID__c
------ ---------
NULL 392
Please help me !
LEFT JOIN Trouble
Jul 19, 2007Hello forum , I'm interested in solving LEFT JOIN problem:
I've made 3 sentences with LEFT JOIN, and then, and each one I've put in one sentence.
When I perform each sentence one by one, they works correctly. But when I execute the last one the results are diferent and I don't know why it occurs.
SENTENCE N1:
SELECT A.MATERIAL, A.AMPLADA, M.NOM, SUM(BM.METRES) AS STOCK, SUM(BM.METRES) * A.AMPLADA / 1000 AS METRES_QUADRATS_STOCK, COUNT(BM.BOBINA) AS BOBINES_STOCK
FROM ARTICLES A
LEFT OUTER JOIN MATERIAL M ON (A.MATERIAL = M.MATERIAL)
LEFT OUTER JOIN BOBINES_MATERIAL BM ON (A.MATERIAL = BM.MATERIAL AND A.AMPLADA = BM.AMPLADA AND BM.BOBINA NOT IN (SELECT BOBINA FROM BOBINES_OTS) AND BM.DATA = (SELECT MAX(DATA) FROM BOBINES_MATERIAL WHERE BOBINA = BM.BOBINA) AND BM.METRES > 0)
GROUP BY A.MATERIAL, A.AMPLADA, M.NOM
ORDER BY A.MATERIAL, A.AMPLADA
Result-->
1.......125.......VELLUM/RP51/HG65.......NULL.......NULL.......0
1.......150.......VELLUM/RP51/HG65.......NULL.......NULL.......0
1.......167.......VELLUM/RP51/HG65.......156438.......26125.......79
1.......180.......VELLUM/RP51/HG65.......36150.......6507.......18
1.......200.......VELLUM/RP51/HG65.......109336.......21867.......59
1.......220.......VELLUM/RP51/HG65.......92530.......20356.......47
1.......230.......VELLUM/RP51/HG65.......61350.......14110.......31
1.......240.......VELLUM/RP51/HG65.......NULL.......NULL.......0
1.......250.......VELLUM/RP51/HG65.......18865.......4716.......10
1.......260.......VELLUM/RP51/HG65.......1500.......390.......1
1.......330.......VELLUM/RP51/HG65.......NULL.......NULL.......0
-------------------------------------------------------------------------------------
2nd sentence:
SELECT A.MATERIAL, A.AMPLADA, M.NOM, SUM(CM.METRES_LINEALS_BOBINA * CM.BOBINES) AS STOCK_DEMANAT, SUM(CM.METRES_LINEALS_BOBINA * CM.BOBINES) * A.AMPLADA / 1000 AS METRES_QUADRATS , SUM(CM.BOBINES) AS BOBINES_DEMANADES
FROM ARTICLES A
LEFT OUTER JOIN MATERIAL M ON (A.MATERIAL = M.MATERIAL)
LEFT OUTER JOIN COMANDES_MATERIAL CM ON (A.MATERIAL = CM.MATERIAL AND A.AMPLADA = CM.AMPLADA)
GROUP BY A.MATERIAL, A.AMPLADA, M.NOM
ORDER BY A.MATERIAL, A.AMPLADA
Result-->
1.......125.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......150.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......167.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......180.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......200.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......220.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......230.......VELLUM/RP51/HG65.......44000.......10120.......22
1.......240.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......250.......VELLUM/RP51/HG65.......16000.......4000.......8
1.......260.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
1.......330.......VELLUM/RP51/HG65.......NULL.......NULL.......NULL
-----------------------------------------------------------------------------------------------------------
3th setence:
SELECT A.MATERIAL, A.AMPLADA, M.NOM, SUM(PREVISIO_METRES_PREPARACIO) + SUM(PREVISIO_METRES_PRODUCCIO) AS STOCK_RESERVAT_OTS, SUM(PREVISIO_METRES_PREPARACIO) + SUM(PREVISIO_METRES_PRODUCCIO) / 1000 * A.AMPLADA AS METRES_QUADRATS_RESERVAT_OTS
FROM ARTICLES A
LEFT OUTER JOIN MATERIAL M ON (A.MATERIAL = M.MATERIAL)
LEFT OUTER JOIN PLANNING P ON (A.MATERIAL = P.MATERIAL AND A.AMPLADA = P.AMPLADA)
GROUP BY A.MATERIAL, A.AMPLADA, M.NOM
ORDER BY A.MATERIAL, A.AMPLADA
Result-->
1.......125.......VELLUM/RP51/HG65.......1300.0.......188.75
1.......150.......VELLUM/RP51/HG65.......NULL.......NULL
1.......167.......VELLUM/RP51/HG65.......30216.0.......5937.3820000000005
1.......180.......VELLUM/RP51/HG65.......NULL.......NULL
1.......200.......VELLUM/RP51/HG65.......5385.0.......1325.0
1.......220.......VELLUM/RP51/HG65.......20026.0.......4795.7200000000003
1.......230.......VELLUM/RP51/HG65.......52085.0.......12349.15
1.......240.......VELLUM/RP51/HG65.......NULL.......NULL
1.......250.......VELLUM/RP51/HG65.......2577.0.......666.75
1.......260.......VELLUM/RP51/HG65.......NULL.......NULL
1.......330.......VELLUM/RP51/HG65.......NULL.......NULL
-----------------------------------------------------------------------------------------------------------
Sentence 3 in 1:
SELECT A.MATERIAL, A.AMPLADA, M.NOM, SUM(BM.METRES) AS STOCK, SUM(BM.METRES) / 1000 * A.AMPLADA AS METRES_QUADRATS_STOCK, COUNT(BM.BOBINA) AS BOBINES_STOCK
, SUM(CM.METRES_LINEALS_BOBINA * CM.BOBINES) AS STOCK_DEMANAT, SUM(CM.METRES_LINEALS_BOBINA * CM.BOBINES) / 1000 * A.AMPLADA AS METRES_QUADRATS , SUM(CM.BOBINES) AS BOBINES_DEMANADES
, SUM(PREVISIO_METRES_PREPARACIO) + SUM(PREVISIO_METRES_PRODUCCIO) AS STOCK_RESERVAT_OTS, SUM(PREVISIO_METRES_PREPARACIO) + SUM(PREVISIO_METRES_PRODUCCIO) / 1000 * A.AMPLADA AS METRES_QUADRATS_RESERVAT_OTS
FROM ARTICLES A
LEFT JOIN MATERIAL M ON (A.MATERIAL = M.MATERIAL)
LEFT JOIN BOBINES_MATERIAL BM ON (A.MATERIAL = BM.MATERIAL AND A.AMPLADA = BM.AMPLADA AND BM.BOBINA NOT IN (SELECT BOBINA FROM BOBINES_OTS) AND BM.DATA = (SELECT MAX(DATA) FROM BOBINES_MATERIAL WHERE BOBINA = BM.BOBINA) AND BM.METRES > 0)
LEFT JOIN COMANDES_MATERIAL CM ON (A.MATERIAL = CM.MATERIAL AND A.AMPLADA = CM.AMPLADA)
LEFT JOIN PLANNING P ON (A.MATERIAL = P.MATERIAL AND A.AMPLADA = P.AMPLADA)
GROUP BY A.MATERIAL, A.AMPLADA, M.NOM
ORDER BY A.MATERIAL, A.AMPLADA
Result-->
1.......125.......VELLUM/RP51/HG65.......NULL.......NULL.......0.......NULL.......NULL.......NULL.......1300.0.......188.75
1.......150.......VELLUM/RP51/HG65.......NULL.......NULL.......0.......NULL.......NULL.......NULL.......NULL.......NULL
1.......167.......VELLUM/RP51/HG65.......2659446.......444053.......1343.......NULL.......NULL.......NULL.......2387064.0.......469053.17800000001
1.......180.......VELLUM/RP51/HG65.......36150.......6480.......18.......NULL.......NULL.......NULL.......NULL.......NULL
1.......200.......VELLUM/RP51/HG65.......218672.......43600.......118.......NULL.......NULL.......NULL.......317715.0.......78175.0
1.......220.......VELLUM/RP51/HG65.......370120.......81400.......188.......NULL.......NULL.......NULL.......941222.0.......225398.84
1.......230.......VELLUM/RP51/HG65.......368100.......84640.......186.......8184000.......1882320.......4092.......1614635.0.......382823.65000000002
1.......240.......VELLUM/RP51/HG65.......NULL.......NULL.......0.......NULL.......NULL.......NULL.......NULL.......NULL
1.......250.......VELLUM/RP51/HG65.......18865.......4500.......10.......160000.......40000.......80.......25770.0.......6667.5
1.......260.......VELLUM/RP51/HG65.......1500.......260.......1.......NULL.......NULL.......NULL.......NULL.......NULL
1.......330.......VELLUM/RP51/HG65.......NULL.......NULL.......0.......NULL.......NULL.......NULL.......NULL.......NULL