Listing Results Based On The Starting Alphabet

Mar 27, 2007

Hi,



I have a report which lists out the employees' details. I need A-Z links above the report, On clicking on an alphabet, say "C", should display all the employee details whose name starts with the selected alphabet. In the stored procedure we can accept the character and return back those results. But it is not a drill report and we need the result in the same report. Is there any way so that on clicking each link, the output will be shown in the same report. Any help is appreciated.



Thanks in advance,

Sonu

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May 13, 2014

I'm having problems with my website. I wish to make a section that has names starting with numbers only. For example, with every name beginning with "A", I have this code:

select * from names where name like "a%" order by name

and this works fine, but I want it so it will only list titles starting with 0-9..

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A solution comes to mind that would be very long and db intensive, by querying on 'like 'D', followed by like 'E', followed by like 'F', etc, but I'm sure that there is a much more efficient way to do this. Below is the code that I'm using now.





' where @SortString = 'd' and @Test is a temp Table



BEGIN

Insert into @Test

Select CompanyName,ContactId, CompanyId

from vContacts where CompanyName like @SortString +'%'

Order by CompanyName



Insert into @Test

Select CompanyName,ContactId, CompanyId

from vContacts where CompanyName not like @SortString +'%'

Order by CompanyName

END



Thanks in advance for your help

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I would like to generate a working schedule for employees for x-days ahead based on a starting date that the user can enter.

I have got 3 relevant tables:

1. Table X with (1) resourcenumber, (2) starting date working schedule and (3) the daynumber representing the starting date (this is ISO so 1 for Monday, 2 for Tuesday etc.)

2. Table Y has the schedule itself and can hold a 7-days schedule or a 14-days schedule. In case of 7 days schedule there a 14 (!) records with (1) resourcenumber, (2) daynumber, (3) starting hour a.m. (4) ending hour a.m (5) starting hour p.m and (6) ending hour p.m. In case of a 14-days schedule there are 28 records (a.m. and p.m. records)

3. Table Z with resource data.

An example to clarify (for fake employee 100):

Table X:
Resource: 100
Starting date: 2012-03-01 (from this date the schedule will be effective)
Daynumber: 4 (2012-03-01 was a Thursday)

Table Y (Resource has a 14 days schedule because per 2 weeks Monday is an off-day):

Record 1 shows: Resource: 100, Daynumber: 1 (= Monday, working day), AM-Starting hour: 09:00, AM-Ending hour: 13:00, PM-starting hour: 13:30, PM-ending hour: 17:30
Record 2: same but daynumber is 2
Record 3: same but daynumber is 3 etc.
...
Record 8 shows: Resource: 100, Daynumber: 8 (= Monday, off-day), AM-Starting hour: 00:00, AM-Ending hour: 00:00, PM-starting hour: 00:00, PM-ending hour: 00:00
Record 9: same as record 2 but daynumber is 9.
etc.
...
Record 14: same as record 7 but day is 14 (= last day)

The weekend days show as 00:00 for the hours (same as day 8 in example)

I generated the working schedule with a CROSS APPLY function based on the starting date and the x-number of days ahead.

I then evaluate the actual daynumber corresponding with that date with the daynumber in table Y. That works fine with a 7-days schedule but I can't get it fixed with a 14-days schedule. Day 8 in that schedule represents an actual day 1 but how do I know what actual date day 8 is ... I think I have to start with the starting date in table X ...

I think ideally I would like to have the generated days as follows (as an example in case of a 14-days schedule starting 2014-05-01 for 30 days ahead):

2014-05-01 = day 4 (= actual daynumber)
2014-05-02 = day 5
2014-05-03 = day 6
...
2014-05-10 = day 13
2014-05-11 = day 14
2014-05-12 = day 1
2014-05-13 = day 2
2014-05-14 = day 3
...
2014-05-24 = day 13
2014-05-25 = day 14
2014-05-26 = day 1
2014-05-27 = day 2
...
2014-05-31 = day 6

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Table A Data:
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1, 6/18/2008 @ 2:31:02, This is my message
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Hi,

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Dear Pals,

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insert into test(ename) select 'abc'
insert into test(ename) select 'Reg'
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Reg
Regsxysn
psReg

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Thanks in Advance.

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Dear Pals,

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789A                       01/21/2012
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2, Baseball, Sports
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===============
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