Need Help On SQL Server Functions Part 2
Sep 6, 2001
I am sorry to continue bothering this forum with the
continuation of this question but here it is. And thank you to Craig for
giving me the equivalent of the function Date() in SQL. Now when I pull from
the SQl Server with the old ASP pull with this statement using GETDATE()
strSQLQuery1 = "SELECT * FROM cocoitem WHERE CustNum = '" & strcustnum & "' AND (stat = 'O' OR stat = 'F') AND [due-date] > DateAdd('yyyy', -1, GETDATE()) Order By [cust-item], [due-date] ASC;"
I get this:
Microsoft OLE DB Provider for SQL Server error '80040e14'
Invalid parameter 1 specified for dateadd.
/scripts/order/shippingstatsopen.asp, line 28
So I guess I need to also know the equivalent of DateAdd . Also, does anyone
know of a Access Function to Sql 7 function comparison chart so I can write
for the new database comprehendingly?
Thank you very much for your help in advance.
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May 26, 2006
I was playing around with the new SQL 2005 CLR functionality andremembered this discussion that I had with Erland Sommarskog concerningperformance of scalar UDFs some time ago (See "Calling sp_oa* infunction" in this newsgroup). In that discussion, Erland made thefollowing comment about UDFs in SQL 2005:[color=blue][color=green]>>The good news is that in SQL 2005, Microsoft has addressed several of[/color][/color]these issues, and the cost of a UDF is not as severe there. In fact fora complex expression, a UDF in written a CLR language may be fasterthanthe corresponding expression using built-in T-SQL functions.<<I thought the I would put this to the test using some of the same SQLas before, but adding a simple scalar CLR UDF into the mix. The testinvolved querying a simple table with about 300,000 rows. Thescenarios are as follows:(A) Use a simple CASE function to calculate a column(B) Use a simple CASE function to calculate a column and as a criterionin the WHERE clause(C) Use a scalar UDF to calculate a column(D) Use a scalar UDF to calculate a column and as a criterion in theWHERE clause(E) Use a scalar CLR UDF to calculate a column(F) Use a scalar CLR UDF to calculate a column and as a criterion inthe WHERE clauseA sample of the results is as follows (time in milliseconds):(295310 row(s) affected)A: 1563(150003 row(s) affected)B: 906(295310 row(s) affected)C: 2703(150003 row(s) affected)D: 2533(295310 row(s) affected)E: 2060(150003 row(s) affected)F: 2190The scalar CLR UDF function was significantly faster than the classicscalar UDF, even for this very simple function. Perhaps a more complexfunction would have shown even a greater difference. Based on this, Imust conclude that Erland was right. Of course, it's still faster tostick with basic built-in functions like CASE.In another test, I decided to run some queries to compare built-inaggregates vs. a couple of simple CLR aggregates as follows:(G) Calculate averages by group using the built-in AVG aggregate(H) Calculate averages by group using a CLR aggregate that similatesthe built-in AVG aggregate(I) Calculate a "trimmed" average by group (average excluding highestand lowest values) using built-in aggregates(J) Calculate a "trimmed" average by group using a CLR aggregatespecially designed for this purposeA sample of the results is as follows (time in milliseconds):(59 row(s) affected)G: 313(59 row(s) affected)H: 890(59 row(s) affected)I: 216(59 row(s) affected)J: 846It seems that the CLR aggregates came with a significant performancepenalty over the built-in aggregates. Perhaps they would pay off if Iwere attempting a very complex type of aggregation. However, at thispoint I'm going to shy away from using these unless I can't find a wayto do the calculation with standard SQL.In a way, I'm happy that basic SQL still seems to be the fastest way toget things done. With the addition of the new CLR functionality, Isuspect that MS may be giving us developers enough rope to comfortablyhang ourselves if we're not careful.Bill E.Hollywood, FL------------------------------------------------------------------------- table TestAssignment, about 300,000 rowsCREATE TABLE [dbo].[TestAssignment]([TestAssignmentID] [int] NOT NULL,[ProductID] [int] NULL,[PercentPassed] [int] NULL,CONSTRAINT [PK_TestAssignment] PRIMARY KEY CLUSTERED([TestAssignmentID] ASC)--Scalar UDF in SQLCREATE FUNCTION [dbo].[fnIsEven](@intValue int)RETURNS bitASBEGINDeclare @bitReturnValue bitIf @intValue % 2 = 0Set @bitReturnValue=1ElseSet @bitReturnValue=0RETURN @bitReturnValueEND--Scalar CLR UDF/*using System;using System.Data;using System.Data.SqlClient;using System.Data.SqlTypes;using Microsoft.SqlServer.Server;public partial class UserDefinedFunctions{[Microsoft.SqlServer.Server.SqlFunction(IsDetermini stic=true,IsPrecise=true)]public static SqlBoolean IsEven(SqlInt32 value){if(value % 2 == 0){return true;}else{return false;}}};*/--Test #1--Scenario A - Query with calculated column--SELECT TestAssignmentID,CASE WHEN TestAssignmentID % 2=0 THEN 1 ELSE 0 END ASCalcColumnFROM TestAssignment--Scenario B - Query with calculated column as criterion--SELECT TestAssignmentID,CASE WHEN TestAssignmentID % 2=0 THEN 1 ELSE 0 END ASCalcColumnFROM TestAssignmentWHERE CASE WHEN TestAssignmentID % 2=0 THEN 1 ELSE 0 END=1--Scenario C - Query using scalar UDF--SELECT TestAssignmentID,dbo.fnIsEven(TestAssignmentID) AS CalcColumnFROM TestAssignment--Scenario D - Query using scalar UDF as crierion--SELECT TestAssignmentID,dbo.fnIsEven(TestAssignmentID) AS CalcColumnFROM TestAssignmentWHERE dbo.fnIsEven(TestAssignmentID)=1--Scenario E - Query using CLR scalar UDF--SELECT TestAssignmentID,dbo.fnIsEven_CLR(TestAssignmentID) AS CalcColumnFROM TestAssignment--Scenario F - Query using CLR scalar UDF as crierion--SELECT TestAssignmentID,dbo.fnIsEven_CLR(TestAssignmentID) AS CalcColumnFROM TestAssignmentWHERE dbo.fnIsEven(TestAssignmentID)=1--CLR Aggregate functions/*using System;using System.Data;using System.Data.SqlClient;using System.Data.SqlTypes;using Microsoft.SqlServer.Server;[Serializable][Microsoft.SqlServer.Server.SqlUserDefinedAggregate (Format.Native)]public struct Avg{public void Init(){this.numValues = 0;this.totalValue = 0;}public void Accumulate(SqlDouble Value){if (!Value.IsNull){this.numValues++;this.totalValue += Value;}}public void Merge(Avg Group){if (Group.numValues > 0){this.numValues += Group.numValues;this.totalValue += Group.totalValue;}}public SqlDouble Terminate(){if (numValues == 0){return SqlDouble.Null;}else{return (this.totalValue / this.numValues);}}// private accumulatorsprivate int numValues;private SqlDouble totalValue;}[Serializable][Microsoft.SqlServer.Server.SqlUserDefinedAggregate (Format.Native)]public struct TrimmedAvg{public void Init(){this.numValues = 0;this.totalValue = 0;this.minValue = SqlDouble.MaxValue;this.maxValue = SqlDouble.MinValue;}public void Accumulate(SqlDouble Value){if (!Value.IsNull){this.numValues++;this.totalValue += Value;if (Value < this.minValue)this.minValue = Value;if (Value > this.maxValue)this.maxValue = Value;}}public void Merge(TrimmedAvg Group){if (Group.numValues > 0){this.numValues += Group.numValues;this.totalValue += Group.totalValue;if (Group.minValue < this.minValue)this.minValue = Group.minValue;if (Group.maxValue > this.maxValue)this.maxValue = Group.maxValue;}}public SqlDouble Terminate(){if (this.numValues < 3)return SqlDouble.Null;else{this.numValues -= 2;this.totalValue -= this.minValue;this.totalValue -= this.maxValue;return (this.totalValue / this.numValues);}}// private accumulatorsprivate int numValues;private SqlDouble totalValue;private SqlDouble minValue;private SqlDouble maxValue;}*/--Test #2--Scenario G - Average Query using built-in aggregate--SELECT ProductID, Avg(Cast(PercentPassed AS float))FROM TestAssignmentGROUP BY ProductIDORDER BY ProductID--Scenario H - Average Query using CLR aggregate--SELECT ProductID, dbo.Avg_CLR(Cast(PercentPassed AS float)) AS AverageFROM TestAssignmentGROUP BY ProductIDORDER BY ProductID--Scenario I - Trimmed Average Query using built in aggregates/setoperations--SELECT A.ProductID,CaseWhen B.CountValues<3 Then NullElse Cast(A.Total-B.MaxValue-B.MinValue ASfloat)/Cast(B.CountValues-2 As float)End AS AverageFROM(SELECT ProductID, Sum(PercentPassed) AS TotalFROM TestAssignmentGROUP BY ProductID) ALEFT JOIN(SELECT ProductID,Max(PercentPassed) AS MaxValue,Min(PercentPassed) AS MinValue,Count(*) AS CountValuesFROM TestAssignmentWHERE PercentPassed Is Not NullGROUP BY ProductID) BON A.ProductID=B.ProductIDORDER BY A.ProductID--Scenario J - Trimmed Average Query using CLR aggregate--SELECT ProductID, dbo.TrimmedAvg_CLR(Cast(PercentPassed AS real)) ASAverageFROM TestAssignmentGROUP BY ProductIDORDER BY ProductID
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I have SSRS 2005 SP2 configured to work in Sharepoint integration. Everything works fine except that I am not able to programmatically change any property of report viewer web part (instance) that I have added on on home page of my sharepoint site.
I can do same thing via sharepoint UI but not through program. When my programs runs it fetches all web parts been added on home page, then I need to iterate through each one and find report viewer web part.
While iterating, as soon as I arrive to report viewer web part it is named as "Error web part" with error message as
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If someone has a solution, please respond at your earlist.
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Jan 28, 2015
I have made the following Scalar-valued function:
CREATE FUNCTION [dbo].[TimeCalc]
(
@OriginalTime AS INTEGER
, @TenthsOrHundredths AS INTEGER -- code 2: 1/10, code 4: 1/100
)
RETURNS NVARCHAR(8)
[Code] ....
What it does is convert numbers to times
E.g.: 81230 gets divided by 10 (times in seconds: 8123). This 1 1 full minute, and the remainder = 2123 making it 1.21.23 mins)
So far so good (function works perfectly)
My question: sometimes times are in 1/100 (like above sample), sometimes in 1/10.
This means that, e.g. with a time like 3.23.40 the last zero must be deleted.
My thoughts are to use the results from the Return Case part, and as the code = 4: leave it as it is,
is the code 2 the use LEFT(... result Return Case ..., Len(..result Return Case.. - 1))
There are 5 codes: 0 1 2 3 and 4
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Jun 28, 2001
I have another question regarding migration process to diffrent SQL Server.
Last time when I did migration I didn't restore system databases (master in particular).
I only restored user databases and of course I've got login errors such
Microsoft SQL-DMO (ODBC SQLState: 42000) Error 15023: User or role '%s' already exists in the current database.
I just used sp_change_users_login to fix those orphans.
I've read articles in MS knowledge base and not quite sure is this a good idea to restore master database prior to restoring all user databases on the new server in order to keep all logins?
I'll try to use recommended article for transfering logins with password instead of restoring master database from backup
http://support.microsoft.com/support/kb/articles/Q246/1/33.ASP
Any advice is greatly appreciated.
Lena
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Sep 6, 2001
Hello all,
Recently I changed over a ASP script from our old Access 97 database to our new SQL database. When I changed it over, some of my SQL pulls on my Active Server Page started to give me erros. One of them is the function
date(). When I used it pulling from Access like this :
strSQLQ = "SELECT * FROM cocoitem WHERE CustNum = '" & strcustnum & "' AND stat = 'C' AND [due-date] > DateAdd('yyyy', -1, Date()) Order By [cust-po], [due-date] ASC ;"
Then it worked fine. When I redirected the ASP to the new SQL server I recieved an error like this:
Microsoft OLE DB Provider for SQL Server error '80040e14'
'Date' is not a recognized function name.
/scripts/order/shippingstatsclose.asp, line 45
So my question is, what is the SQL server equivalent of the function Date()?
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Feb 4, 2007
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Jan 7, 2002
Can someone tell me if this is a SQL Server bug? I tried this in both
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DECLARE @timeA DATETIME
DECLARE @timeB DATETIME
DECLARE @msDiff INT
SET @timeA = GETDATE()
SET @msDiff = 0
WHILE @msDiff <= 10
BEGIN
SET @timeB = DATEADD(ms,@msDiff,@timeA)
PRINT 'If adding ' + CONVERT(VARCHAR,@msDiff) + ' milliseconds to Time
B, then Time B is ' + CONVERT(VARCHAR,DATEDIFF(ms,@timeA,@timeB)) + '
millisecond greater than Time A'
SET @msDiff = @msDiff + 1
END
This seems like a serious bug if an application depends heavily on
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Thanks,
Aiden
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Jul 26, 2000
Hi,
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thanks in advance.
srini
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Apr 10, 2002
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Hi,
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Jul 20, 2005
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Hi everybody,
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So an example would be the following:
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SELECT
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, ot2.Order_No
FROM
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How can I do this?
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When we access Talker we have a login failure:
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hai,
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Hi,
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Hi all!!Does anybody know how I can create a function in SQL 7.0?? I have tocreate functions that return a value that can be used in a selectstatement. I think SQL Server version 7.0 doesn't support CREATEFUNCTION, does it?Ex:Select MyFunction(Parameter)From MyTableThanks a lot,
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Oct 4, 2006
Hi
I am trying to build a tree similar to the one in SQL Server Management Studio for the system functions in the SQL language.
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Apr 23, 2008
Hi ,
I have a question about calling functions in SQl Server 2005.
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If I want to call it from T-SQL I will write Select dbo.Calculations (arguments if any) etc.
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Should I create the function as supervisor ? Does Sql Server has a property or something which will allow me to call the function without using the "dbo." ?
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Oct 7, 2015
I'm trying to replace a particular part of a row in a table with a new value.
The row is called "DataPath" and it has a lot of values like so:
mashOperationsComponent Data FilesSantec
I want to run a query to replace the mash with our DFS namespace share name companysharesDepartments but keep everything else past the mash part of the original row.
I'm currently running this query, it says it is altering 30,000 rows, but it doesn't look like it's doing anything at all..
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Jul 26, 2007
On a SQL Server 2005 x64 Standard Edition cluster I get the error listed below and then the SQL server service restarts. The SQL server is unavailable for 5-10 minutes during that time. Any ideas?
Error:
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Nov 14, 2006
Hello,
I use IBM WebSphere Portal and am desperately trying to move data from the default Cloudspace Database to MS SQL Server 2005, of course following the official guidelines.
What happens is that WebSphere's Configuration Wizard fails because of an error caused by the SQL Script. Trouble is, I can't bring it to work not even in the SQL Server Management Studio.
What follows is the code generated by the script. The error is caused by the last "check"-constraint (colored in red).
CREATE TABLE community.APP_DESC ( OID BINARY(18) NOT NULL, TYPE INTEGER NOT NULL, APP_NAME NVARCHAR(255) NOT NULL, IS_ACTIVE INTEGER NOT NULL, JSR_VERSION NVARCHAR(255), GUID NVARCHAR(255), WEB_MOD_OID BINARY(18), WEB_MOD_SL BINARY(18), WSRP_PROD_OID BINARY(18), WSRP_PROD_SL BINARY(18), DEFAULT_LOCALE NVARCHAR(64), CREATED BIGINT NOT NULL, MODIFIED BIGINT NOT NULL, WSC_GROUP_ID NVARCHAR(255), CONSTRAINT PK20 PRIMARY KEY NONCLUSTERED (OID), CONSTRAINT FK20A FOREIGN KEY (WEB_MOD_OID) REFERENCES community.WEB_MOD (OID) ON DELETE CASCADE, constraint FK20B FOREIGN KEY (WSRP_PROD_OID) REFERENCES community.WSRP_PROD (OID) ON DELETE CASCADE, CONSTRAINT CC20A CHECK (((community.APP_DESC.WEB_MOD_OID IS NULL) AND (community.APP_DESC.WEB_MOD_SL IS NOT NULL)) OR ((community.APP_DESC.WEB_MOD_OID IS NOT NULL) AND (community.APP_DESC.WEB_MOD_SL IS NULL))) )
And that's what SQL Server 2005 told me:
Msg 4104, Level 16, State 1, Line 1The multi-part identifier "community.APP_DESC.WEB_MOD_OID" could not be bound.Msg 4104, Level 16, State 1, Line 1The multi-part identifier "community.APP_DESC.WEB_MOD_SL" could not be bound.Msg 4104, Level 16, State 1, Line 1The multi-part identifier "community.APP_DESC.WEB_MOD_OID" could not be bound.Msg 4104, Level 16, State 1, Line 1The multi-part identifier "community.APP_DESC.WEB_MOD_SL" could not be bound.
BTW, as this is a generated script I do not have the possibility to change it. Because it has been released by IBM I am rather convinced that it is correct - therefore I was wondering whether SQL Server 2005 has a known bug that makes it refuse "check"-constraints.
Any hint is very appreciated.
Thanks in advance,
adapter
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Jul 7, 2006
Hi everyone,
I have developed a VB6 application that works with SQL server 2000. My client does not have a SQL server installed on their machine. I wonder do I have to purchase a copy of SQL server 2000 and install it to client's computer ?
How much would a basic version of SQL server 2000 cost ?
I am new to the softwarel world. Please give me some advise.
Thanks
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