OUTER JOIN And NULL Items - ASP VB Vs. Management Studio 2005

Feb 28, 2008

Hello,
please, is there SO who can help me resolve my problem? I'm developing a simple ASP application.

I have 2 tables - T_Employees , P_Users
T_Employees = all employees of a company, P_Users = users of the system, P_Users is sub-set of T_Employees, PERNR is link

I need result of:
SELECT e.Name, u.Permitions FROM T_Employees AS e LEFT OUTER JOIN P_Users AS u ON e.PERNR = u.PERNR and (e.PERNR = 1) .

If an employee with PERNR = x is not a user (is not in P_Users) , I expect to recieve 1 row with u.Permitions=null

But what happens!
If I put this query to Management studio, I recieve 1 row (as I expect). Than I run exactly the same query in ASP page and it doesn't return any row (recordcount=0).

And what is even more strange - it worked. Suddenly I met this problem in all my pages and I can't find where the problem consist in. I always take SQL query from ASP VB into query analyzer and it works. But not on my pages.

It looks like the ASP works with different settings or as QA corrects my query before execution.

I'm totaly confused by this. Have you ever met ST like this?

Thanks for your advice
Petr
petr DOT chary@gmail DOT c o m

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Unary Select On Items IF Then Else Outer Join ??

Apr 17, 2008

I have a table of products, and many products have the same name only they are different sizes. I want to only select a particular size like 20 oz, but if it does not exist in that size I want to select the next appropriate size (and which case if it does not exist i wish to select the next appropriate size and so on ..
Does any one know how I can accomplish this and would be willing to help me out by posting some code, some direction ??

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Oct 18, 2013

I've got 2 tables of towns. I'm using outer join because i need all the town from both tables. However I'm sometimes getting duplicates.

My query

select a.town, b.town
from a
outer join b on a.town = b.town
group by a.town, b.town

How to stop getting null values?

portsmouth null
portsmouth portsmouth
southampton southampton
null southampton
TownA null
null TownB

I'm looking for distinct values like this:

portsmouth portsmouth
southampton southampton
TownA null
null TownB
etc...

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Dec 31, 2007

Need some join help...

Table 1 - Modules:
ID | Name
1 | A
2 | B
3 | C

Table 2 - CompanyModules
ModuleID | CompanyID
1 | 1
2 | 1
3 | 1
1 | 2

I'd like to return the following result set:
CompanyModules.CompanyID | Modules.Name | Present
1 | A | True
1 | B | True
1 | C | True
2 | A | True
2 | B | False
2 | C | False

What would be the query for this? Thanks.

Edit: This is the query I have tried:

select CompanyModules.CompanyID, Modules.Name, count(Modules.ID) as Present from

CompanyModules RIGHT outer Join Modules on CompanyModules.ModuleID = Modules.ID

group By CompanyModules.CompanyID, Modules.Name

Order by CompanyID

However, it only returns a partial result set:

CompanyModules.CompanyID | Modules.Name | Present
1 | A | 1
1 | B | 1
1 | C | 1
2 | A | 1

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Aug 17, 2015

I have this View and want to also see Clubs that do not have current memberships.I have the IS NULL but not seeing the Clubs that do NOT have memberships. attribute.PersonMembership is a SQL table that has membership information.

SELECT dbo.v060ClubOfficersPresOrNot.ClubNo, dbo.v060ClubOfficersPresOrNot.SortName, dbo.v060ClubOfficersPresOrNot.ClubName,
dbo.v060ClubOfficersPresOrNot.BSProgram, dbo.v060ClubOfficersPresOrNot.ClubSection, dbo.v060ClubOfficersPresOrNot.Code,
RTRIM(attribute.PersonMembership.InvoiceNumber) AS InvNo, dbo.v060ClubOfficersPresOrNot.President, dbo.v060ClubOfficersPresOrNot.Email,

[Code]...

The "PersonMembership" has all the membership records from 2015 through 2019 of membertypeid 1-4 for the sampling.Since the syntax used in Access do not carry over without modifications to SQL, SQL syntax to make it work in SQL.And if you know the proper SQL syntax for "Between Year(Date())+IIf(Month(Date())>=7,1,0) And Year(Date())+IIf(Month(Date())>=7,1,0)+4" instead of what I currently have in SQL, that would be wonderful.

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How To Write A Query To Return Null For Non-exist Record In An Outer Join.

Jun 2, 2004

I have two tables:

1. tblProducts
columns: ProductID, ProductName

2. tblProductCodes
columns: ProductID, CustomerID, ProductCode

The 2nd table is for storing product codes for customers, in other words, one product can have different ProductCode for different customers. But some customers do not have ProductCode for a ProductID.

I want to create a query to return all the Products and its ProductCode (null is valid) for a specific customer.

I tried:

SELECT dbo.tblProductCodes.ProductCode, dbo.tblProductCodes.CustomerID,
dbo.tblProducts.ProductName,
dbo.tblProducts.ProductID
FROM dbo.tblProducts LEFT OUTER JOIN
dbo.tblProductCodes ON dbo.tblProducts.ProductID = dbo.tblProductCodes.ProductID
WHERE dbo.tblProductCodes.CustomerID = 2

But the query left out all products that does not have ProductCode value in tblProductCodes table for CustomerID = 2. I want all the ProductName returned from query and render null or empty string for ProductCode value if the code does not exist in tblProductCodes table for the customer.

Any help is highly appreciated.

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Apr 26, 2002

Take the following scenario:

We have two tables that have somewhat of a parent-child relationship. We are trying to use a SQL-92 outer join that returns the same results as a TSQL *= outer join. The difficulty we are having is that some of the parent records do not have any corresponding child records, but we still want to see those parent records with 0 (zero) for the count. How can we accomplish this with a SQL-92 compliant join (if it is even possible)? In the query results below, we would like the first set of results.

Thanks in advance for any help.
-David Edelman

Test script below, followed by results
===========================================
create table parent (p_id int NOT NULL)
go
create table child (p_id int NOT NULL, c_type varchar(6) NULL)
go
insert parent values (1)
insert parent values (2)
insert parent values (3)
insert parent values (4)
insert parent values (5)
insert parent values (6)
insert parent values (7)
insert parent values (8)
insert parent values (9)
insert parent values (10)
go

insert child values (1, 'AAA')
insert child values (1, 'BBB')
insert child values (1, 'CCC')
insert child values (2, 'AAA')
insert child values (4, 'AAA')
insert child values (4, 'DEF')
insert child values (4, 'AAA')
insert child values (4, 'BBB')
insert child values (5, 'AAA')
insert child values (5, 'AAA')
insert child values (6, 'AAA')
insert child values (7, 'AAA')
insert child values (7, 'BBB')
insert child values (7, 'CCC')
insert child values (7, 'DDD')
insert child values (10, 'AAA')
insert child values (10, 'CCC')
go

select p.p_id, count(c.p_id) as num_rows
from parent p, child c
where p.p_id *= c.p_id
and c.c_type in ('AAA', 'BBB')
group by p.p_id

select p.p_id, count(c.p_id) as num_rows
from parent p left outer join child c on p.p_id = c.p_id
where c.c_type in ('AAA', 'BBB')
group by p.p_id

=========================================
Results:
(T-SQL *= outer join)
p_id num_rows
----------- -----------
1 2
2 1
3 0
4 3
5 2
6 1
7 2
8 0
9 0
10 1

(SQL-92 outer join)
Warning: Null value eliminated from aggregate.
p_id num_rows
----------- -----------
1 2
2 1
4 3
5 2
6 1
7 2
10 1

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I want to add pictures of products to my shopping site using an SQL database and I’ve been told that SQL Server Management studio is required as it is a graphical tool.

How would I go about obtaining the SQL server management studio. There seems to be different versions of SQL server that it is confusing to know which one to purchase.

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My goodness, it seems I still have so much to learn.

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Does this setting exist?

Thanks,

Dave

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Oct 12, 2006

I am having no luck reporting this bug on the feedback link. I type in all information and click "Submit" and it just refreshes the page. So, here it is, I hope someone from MS will post this for me.

The problem appears to be a RIGHT OUTER JOIN on a VIEW causes the query to never return, or return very, very slowly. In 2000 SP4 the query returns in 2 seconds, in 2005 (2153) 64bit, it ran for 42 MINUTES before I killed it.

The is a duplication script to show a problem I have. This script uses the AdventureWorks database to demonstrate the problem. This is script is not the best, but shows the problem.

Please no comments on how to work around the problem. This query is generated by a user using and AdHoc reporting tool. I have NO control over how the user or the tool generates the SQL query.

The word "FAILURE" shows the original query which as far as I can tell never returns. The queries after, are different solutions, if I was able to change the user query, which I am not able to do.

-- Create Test Data Table CustomerListTom and Views

USE AdventureWorks
GO

IF EXISTS (SELECT * FROM sys.views WHERE object_id = OBJECT_ID(N'ViewATom'))
DROP VIEW [ViewATom]

IF EXISTS (SELECT * FROM sys.views WHERE object_id = OBJECT_ID(N'ViewBTom'))
DROP VIEW [ViewBTom]

IF EXISTS (SELECT * FROM sys.objects WHERE object_id = OBJECT_ID(N'CustomerListTom') AND type in (N'U'))
DROP TABLE CustomerListTom
GO

CREATE TABLE [dbo].[CustomerListTom](
[CustomerID] [varchar](6) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[RegionID] [varchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[FirstName] [dbo].[Name] NOT NULL,
[LastName] [dbo].[Name] NOT NULL,
[EmailAddress] [nvarchar](50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
[AddressLine] [nvarchar](60) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressCity] [nvarchar](30) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressState] [nchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressZip] [nvarchar](15) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[AddressCountry] [dbo].[Name] NOT NULL,
[Phone] [dbo].[Phone] NULL,
[BillAddressLine] [nvarchar](60) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressCity] [nvarchar](30) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressState] [nchar](3) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressZip] [nvarchar](15) COLLATE SQL_Latin1_General_CP1_CI_AS NOT NULL,
[BillAddressCountry] [dbo].[Name] NOT NULL,
[BillPhone] [dbo].[Phone] NULL,
[ModifiedDate] [datetime] NOT NULL,
)

INSERT INTO CustomerListTom
SELECT
CustomerID = RIGHT(cu.AccountNumber,6),
RegionID = RIGHT('000'+CAST(cu.TerritoryID AS VARCHAR(3)),3),
FirstName = ct.FirstName,
LastName = ct.LastName,
EmailAddress = ct.EmailAddress,
AddressLine = ad.AddressLine1,
AddressCity = ad.City,
AddressState = sp.StateProvinceCode,
AddressZip = ad.PostalCode,
AddressCountry = sp.[Name],
Phone = ct.Phone,

BillAddressLine = ad.AddressLine1,
BillAddressCity = ad.City,
BillAddressState = sp.StateProvinceCode,
BillAddressZip = ad.PostalCode,
BillAddressCountry = sp.[Name],
BillPhone = ct.Phone,

ModifiedDate = cu.ModifiedDate
--,*
FROM Sales.Customer cu
JOIN Sales.Individual id ON id.CustomerID = cu.CustomerID
JOIN Person.Contact ct ON ct.ContactID = id.ContactID
JOIN Sales.CustomerAddress ca ON cu.CustomerID = ca.CustomerID
JOIN Person.Address ad ON ad.AddressID = ca.AddressID
JOIN Person.StateProvince sp ON sp.StateProvinceID = ad.StateProvinceID

-- Create a big enough set of data for testing
DECLARE @i INT
SET @i = 1
WHILE (@i < 30)
BEGIN
INSERT INTO CustomerListTom
SELECT TOP 15 PERCENT
CustomerID = RIGHT(cu.AccountNumber,6),
RegionID = RIGHT('000'+CAST(cu.TerritoryID+@i AS VARCHAR(3)),3),
FirstName = ct.FirstName,
LastName = ct.LastName,
EmailAddress = ct.EmailAddress,
AddressLine = ad.AddressLine1,
AddressCity = ad.City,
AddressState = sp.StateProvinceCode,
AddressZip = ad.PostalCode,
AddressCountry = sp.[Name],
Phone = ct.Phone,

BillAddressLine = ad.AddressLine1,
BillAddressCity = ad.City,
BillAddressState = sp.StateProvinceCode,
BillAddressZip = ad.PostalCode,
BillAddressCountry = sp.[Name],
BillPhone = ct.Phone,

ModifiedDate = cu.ModifiedDate + CASE WHEN @i > 3 THEN 10 ELSE -25 END + @i

FROM Sales.Customer cu
JOIN Sales.Individual id ON id.CustomerID = cu.CustomerID
JOIN Person.Contact ct ON ct.ContactID = id.ContactID
JOIN Sales.CustomerAddress ca ON cu.CustomerID = ca.CustomerID
JOIN Person.Address ad ON ad.AddressID = ca.AddressID
JOIN Person.StateProvince sp ON sp.StateProvinceID = ad.StateProvinceID

SET @i = @i + 1
END

-- Cleanup - Delete Dups for PK
DELETE FROM CustomerListTom
WHERE CustomerID+RegionID IN (
SELECT CustomerID+RegionID
FROM CustomerListTom cu
GROUP BY CustomerID, RegionID
HAVING COUNT(*) > 1)

ALTER TABLE [CustomerListTom]
ADD CONSTRAINT [PK_CustomerListTom] PRIMARY KEY CLUSTERED
(
[CustomerID] ASC,
[RegionID] ASC
)

GO

-- Create Views
GO
CREATE VIEW ViewATom
AS
SELECT *
FROM CustomerListTom cu
WHERE cu.RegionID = '004'
UNION
SELECT *
FROM CustomerListTom cu
WHERE CustomerID NOT IN
(SELECT CustomerID FROM CustomerListTom c2 WHERE c2.RegionID = '004')
AND (CustomerID + CONVERT(char(8), ModifiedDate, 112) + RegionID IN
(SELECT MAX(CustomerID + CONVERT(char(8), ModifiedDate, 112) + RegionID)
FROM CustomerListTom
GROUP BY CustomerID))

GO
CREATE VIEW ViewBTom
AS
SELECT DISTINCT CustomerID
FROM CustomerListTom
GO

QUERY:

USE AdventureWorks

-- FAILURE
-- This query FAILS to return in over 15 mins, cancelled
SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- SOLUTIONS
-- Change WHERE TABLEB to WHERE TABLEA, this query returns in less than 1 second
SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEA.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- Remove RIGHT OUTER on TABLEB, this Query returns in less than 2 seconds
SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- Drop PK and run ORIGINAL query, returns in less than 4 seconds

IF EXISTS (SELECT * FROM sys.indexes WHERE object_id = OBJECT_ID(N'[dbo].[CustomerListTom]') AND name = N'PK_CustomerListTom')
ALTER TABLE [dbo].[CustomerListTom] DROP CONSTRAINT [PK_CustomerListTom]
GO

SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

-- Create PK with NONCLUSTERED and run ORIGINAL query, returns in less than 1 second

IF EXISTS (SELECT * FROM sys.indexes WHERE object_id = OBJECT_ID(N'[dbo].[CustomerListTom]') AND name = N'PK_CustomerListTom')
ALTER TABLE [dbo].[CustomerListTom] DROP CONSTRAINT [PK_CustomerListTom]
GO
ALTER TABLE [CustomerListTom]
ADD CONSTRAINT [PK_CustomerListTom] PRIMARY KEY NONCLUSTERED
(
[CustomerID] ASC,
[RegionID] ASC
)
GO

SELECT TABLEB.CustomerID,
TABLEC.RegionID,
TABLEC.LastName,
TABLEC.FirstName
FROM ViewATom TABLEA
RIGHT OUTER JOIN ViewBTom TABLEB ON TABLEA.CustomerID = TABLEB.CustomerID
RIGHT OUTER JOIN CustomerListTom TABLEC ON TABLEC.CustomerID = TABLEB.CustomerID
WHERE TABLEB.CustomerID IN
('012870','012997','011000','011001','011002','011003','011004','011005','011006','011007',
'011008','011009','011010','011011','011012','011013','011014','011015','011016','011017',
'011018','011019','011020','011150','011153','011144','017230','017220','017254','017257',
'025338','025333','025338','025397','025389','025424','025483','025485','025682','025673',
'029478','029405','029402','029317','029109','018393'
)

return

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prty pa,

adduser ad

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===============
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SQL 2005 Management Studio Bugs

Apr 6, 2006

There are four limitations or apparent bugs I have experienced in 2005MS. Two I know are for real.Two real limitations/bugs --1. Can't edit table-valued function.2. Can't get nulls to be missing (blank) in text output paneTwo more I just encountered, and am wondering about --3. DB->All Tasks->Import Data->Load CSV file (exported from Excel) ->garbled table as some rows end up being extra columns. The samespreadsheets load okay from XLS format.Table should have shape A, instead has shape B:A B|...| |...||...| |...||...| |......||...| |......||...| |...||...||...|4. SET NOCOUNT OFF has no effect after SET NOCOUNT ONIs there a way to work around these, or are they real bugs?

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Regarding SQL SERVER 2005 Management Studio

May 15, 2007

just now i've installed SQL SERVER 2005 Management studio. i was throwed by an error when i started to run this Management Tool or EXE. the error was as follows:

"Unhandled exception has occurred in a component in your application.If you click continue, the application will ignore this error and attempt to continue.
cannot create a stable subkey under a volatile parent key."

what i've to do now?

the below lines are displayed when i clicked the "Details" button:

See the end of this message for details on invoking
just-in-time (JIT) debugging instead of this dialog box.

************** Exception Text **************
System.IO.IOException: Cannot create a stable subkey under a volatile parent key.

at Microsoft.Win32.RegistryKey.Win32Error(Int32 errorCode, String str)
at Microsoft.Win32.RegistryKey.CreateSubKey(String subkey, RegistryKeyPermissionCheck permissionCheck, RegistrySecurity registrySecurity)
at Microsoft.Win32.RegistryKey.CreateSubKey(String subkey)
at Microsoft.SqlServer.Management.UI.ConnectionDlg.RegisteredServersUtils.CreateKeyValueIfNotExist(String regPath, String keyName)
at Microsoft.SqlServer.Management.UI.ConnectionDlg.RegisteredServersUtils.RegisterLocalInstancesIfFirstTimeUser()
at Microsoft.SqlServer.Management.UI.ConnectionDlg.ConnectionDialog.OnLoad(EventArgs e)
at System.Windows.Forms.Form.OnCreateControl()
at System.Windows.Forms.Control.CreateControl(Boolean fIgnoreVisible)
at System.Windows.Forms.Control.CreateControl()
at System.Windows.Forms.Control.WmShowWindow(Message& m)
at System.Windows.Forms.Control.WndProc(Message& m)
at System.Windows.Forms.ScrollableControl.WndProc(Message& m)
at System.Windows.Forms.ContainerControl.WndProc(Message& m)
at System.Windows.Forms.Form.WmShowWindow(Message& m)
at System.Windows.Forms.Form.WndProc(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.OnMessage(Message& m)
at System.Windows.Forms.Control.ControlNativeWindow.WndProc(Message& m)
at System.Windows.Forms.NativeWindow.Callback(IntPtr hWnd, Int32 msg, IntPtr wparam, IntPtr lparam)

************** Loaded Assemblies **************
mscorlib
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/Microsoft.NET/Framework/v2.0.50727/mscorlib.dll
----------------------------------------
Microsoft.SqlServer.Express.AppIDPackage
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.AppIDPackage.DLL
----------------------------------------
Microsoft.SqlServer.Express.VSIntegration
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.VSIntegration.DLL
----------------------------------------
Microsoft.VisualStudio.Shell.Interop
Assembly Version: 7.1.40304.0
Win32 Version: 7.0.4054
CodeBase: file:///C:/WINDOWS/assembly/GAC/Microsoft.VisualStudio.Shell.Interop/7.1.40304.0__b03f5f7f11d50a3a/Microsoft.VisualStudio.Shell.Interop.dll
----------------------------------------
Microsoft.VisualStudio.OLE.Interop
Assembly Version: 7.1.40304.0
Win32 Version: 7.0.4054
CodeBase: file:///C:/WINDOWS/assembly/GAC/Microsoft.VisualStudio.OLE.Interop/7.1.40304.0__b03f5f7f11d50a3a/Microsoft.VisualStudio.OLE.Interop.dll
----------------------------------------
System
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC_MSIL/System/2.0.0.0__b77a5c561934e089/System.dll
----------------------------------------
System.Windows.Forms
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC_MSIL/System.Windows.Forms/2.0.0.0__b77a5c561934e089/System.Windows.Forms.dll
----------------------------------------
System.Drawing
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC_MSIL/System.Drawing/2.0.0.0__b03f5f7f11d50a3a/System.Drawing.dll
----------------------------------------
Microsoft.SqlServer.Express.SqlTDiagM
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.SqlTDiagM.DLL
----------------------------------------
Microsoft.DataWarehouse.SQM
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.DataWarehouse.SQM.DLL
----------------------------------------
Microsoft.SqlServer.Instapi
Assembly Version: 9.0.242.0
Win32 Version: 9.00.1399.00
CodeBase: file:///C:/WINDOWS/assembly/GAC_MSIL/Microsoft.SqlServer.Instapi/9.0.242.0__89845dcd8080cc91/Microsoft.SqlServer.Instapi.dll
----------------------------------------
Microsoft.SqlServer.Express.ObjectExplorer
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.ObjectExplorer.DLL
----------------------------------------
Microsoft.SqlServer.Express.ConnectionDlg
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.ConnectionDlg.DLL
----------------------------------------
Microsoft.SqlServer.Express.RegSvrEnum
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.RegSvrEnum.DLL
----------------------------------------
Microsoft.SqlServer.Express.CustomControls
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.CustomControls.DLL
----------------------------------------
Microsoft.SqlServer.Express.SqlWorkbench.Interfaces
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.SqlWorkbench.Interfaces.DLL
----------------------------------------
Microsoft.VisualStudio.TextManager.Interop
Assembly Version: 7.1.40304.0
Win32 Version: 7.0.4054
CodeBase: file:///C:/WINDOWS/assembly/GAC/Microsoft.VisualStudio.TextManager.Interop/7.1.40304.0__b03f5f7f11d50a3a/Microsoft.VisualStudio.TextManager.Interop.dll
----------------------------------------
Accessibility
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC_MSIL/Accessibility/2.0.0.0__b03f5f7f11d50a3a/Accessibility.dll
----------------------------------------
Microsoft.SqlServer.Express.SqlMgmt
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.SqlMgmt.DLL
----------------------------------------
System.Data
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC_32/System.Data/2.0.0.0__b77a5c561934e089/System.Data.dll
----------------------------------------
Microsoft.SqlServer.Express.SQLEditors
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.SQLEditors.DLL
----------------------------------------
Microsoft.SqlServer.Express.ConnectionInfo
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.ConnectionInfo.DLL
----------------------------------------
EnvDTE
Assembly Version: 8.0.0.0
Win32 Version: 8.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC/EnvDTE/8.0.0.0__b03f5f7f11d50a3a/EnvDTE.dll
----------------------------------------
Microsoft.SqlServer.Express.SqlEnum
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.SqlServer.Express.SqlEnum.DLL
----------------------------------------
Microsoft.NetEnterpriseServers.Express.ExceptionMessageBox
Assembly Version: 9.0.242.0
Win32 Version: 9.00.2047.00
CodeBase: file:///C:/Program%20Files/Microsoft%20SQL%20Server/90/Tools/Binn/VSShell/Common7/IDE/Microsoft.NetEnterpriseServers.Express.ExceptionMessageBox.DLL
----------------------------------------
System.Xml
Assembly Version: 2.0.0.0
Win32 Version: 2.0.50727.42 (RTM.050727-4200)
CodeBase: file:///C:/WINDOWS/assembly/GAC_MSIL/System.Xml/2.0.0.0__b77a5c561934e089/System.Xml.dll
----------------------------------------

************** JIT Debugging **************
To enable just-in-time (JIT) debugging, the .config file for this
application or computer (machine.config) must have the
jitDebugging value set in the system.windows.forms section.
The application must also be compiled with debugging
enabled.

For example:

<configuration>
<system.windows.forms jitDebugging="true" />
</configuration>

When JIT debugging is enabled, any unhandled exception
will be sent to the JIT debugger registered on the computer
rather than be handled by this dialog box.

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About SQL Server 2005 Management Studio

Aug 9, 2007

i would like to ask if there is a way to FILTER THE IPADDRESSES of users who wants to login the SQL Server Management Studio. right now, we are using Enterprise Edition of SQL Server 2005.

i just want to limit the users who can log in at Management Studio, the users know the password of SA, and i can't change the password coz we have deployed the programs with odbc connection using SA. so i thought of filtering the ipaddress of computers i want to grant access to SQL Server Management Studio, if its possible.

need a help.

thanks

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May 27, 2008

Hello:

I installed enterprise sql server 2005, sql server 2005 backward compatibility, aql server 2005 mobile(ENU) deverloper tools on the window XP. How to install 2005 management studio in this same machine?

Your help is highly apprecaited,

S

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Mar 6, 2008

hi
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Jun 30, 2005

I'm trying to apply some security to my database, so i've created a role, added my user to the role and then set the security rights for the role. Everything work great, the security right behave exactly as defined....However, when I go back the the Permissions pages, the values that i've already set don't appear in the lists (the all still work). In Fact they don't show up anywhere either in the permissions for the table / sp concerned or the right for the user or role.Is it just me, or is it a problem with SQL 2005 Management Studio? or can anybody suggest a way of finding the securty rights of any given database object?Microsoft SQL Server 2005 Beta 2Microsoft SQL Server Management Studio 9.00.1116.00RegardsGary T

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Dec 6, 2007

Hi there,

I am just starting to learn SQL 2005 Express. After opening the Management Studio Express, I right Click on the Databases node and create new database. then create a name etc. The problem is that when I click ok to create the new database, I get a warning saying that Input a filename. However when I click on filename (after filepath) it is greyed out and I cant add a filename.

Does anyone know how to remedy this?

Regards

DML

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Dec 1, 2006

Found some bad behavior in the 2005 Management Studio Import and Export Wizard.

In the Select Source Tables and Views box, I selected multiple objects, and then clicked Edit Mappings.

The Transfer Settings dialog box appears, and states: "Define the settings that can be applied to all selected table transfers."
I selected the "Delete rows in existing destination tables" option to overwrite the existing data. But Management Studio DID NOT DELETE THE ROWS IN THE EXISTING TABLES. Instead, the records were appended to existing data, wreaking havoc on our month-end accounting system.
This happened multiple times, and occured even though the final screen confirmed that existing records would be deleted in each of the individual tables.

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Sep 30, 2006

I have just downloaded VB Express, that comes with SQL Express

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but not any Mgt tool or DB Engine......

Maybe my installation is incomplete?

thanks

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Apr 27, 2006

I handle all licensing for our companies. I am trying to completely understand the licensing and want to insure if I approve the installation of Mgmt Studio 2005, that it is covered by SQL Developer licenses?

THANK YOU!

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