Ordering Date In Asc Order ?

SELECT
LEFT(CONVERT(CHAR(11),convert(datetime,task_date),109),3) + ' ' +
RIGHT(CONVERT(CHAR(11),convert(datetime,task_date),109),4) as Date,
SUM(CASE a.status_id WHEN 1000 THEN b.act_point ELSE 0 END) as Programming,
SUM(CASE a.status_id WHEN 1016 THEN b.act_point ELSE 0 END) as Design,
SUM(CASE a.status_id WHEN 1752 THEN b.act_point ELSE 0 END) as Upload,
SUM(CASE a.status_id WHEN 1032 THEN b.act_point ELSE 0 END) as Testing,
SUM(CASE a.status_id WHEN 1128 THEN b.act_point ELSE 0 END) as Meeting,
SUM(CASE a.status_id WHEN 1172 THEN b.act_point ELSE 0 END) as Others
From
task_table a,act_table b where a.status_id=b.act_id and
a.user_id=(select user_id from user_table where user_name='Raghu') and
a.task_date like '%/%/2006'
GROUP BY
LEFT(CONVERT(CHAR(11),convert(datetime,task_date),109),3) + ' ' + RIGHT(CONVERT(CHAR(11),convert(datetime,task_date),109),4)

Output :

Aug 2006 294 0 0 80 0 0
Jan 2006 14 0 0 0 0 0
Oct 2006 336 0 0 0 0 0
Sep 2006 3262 20 24 8 16 0

How to sort the date in ascending Order ?

Jan 2006
Aug 2006
Sep 2006
Oct 2006