Organization Tree
Oct 14, 2005Any recomendations on how to store organization trees on a database with
lots of paths and branches? Any white papers out there that explain this?
Thanks
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SQL 2012 :: Sort Tree Members In Right (tree) Structure?
Apr 6, 2015I got assignment, how to make it appear in the right order .
/* DROP TABLE EMP
SELECT * INTO Emp FROM (
SELECT 'A' EmpID, NULL ManID, 'Name' EmpName UNION ALL
SELECT 'MAC' EmpID, 'A' ManID, 'Name__' EmpName UNION ALL
SELECT '1ABA' EmpID, 'MAC' ManID, 'Name____' EmpName UNION ALL
SELECT 'ABB' EmpID, '1ABA' ManID, 'Name______' EmpName UNION ALL
SELECT 'XB' EmpID, 'A' ManID, 'Name__' EmpName UNION ALL
SELECT 'BAC' EmpID, 'XB' ManID, 'Name____' EmpName ) b
*/
[code]....
Re-organization?
Dec 24, 2007what is re-organization.how do i implement it ,what are the steps which i need to take care if it is a production server
View 4 Replies View RelatedDisk Organization
Oct 30, 2007I understand the log files (LDF ) and data files (mdf ) should be on a different drives . I believe it leads to greater availabilty and speed . Are there any other reasons for to keep this on a separate drive.
Also what considerations I should take care while creating a database of around 100 GB . (use of filegroups , growth % etc ). Is there any connection of number of users to number of disks SQL data file to be spread to . Also do I need to take care (through hardware / software for a Quad core CPU ) to take full advanage of Quad core CPU.
Report Server Organization
Sep 18, 2007
I have several sub reports and some graphics I don't necessarily want the users to see or open. Is there a way to hide items from view but still have them available for execution? I tried creating a sub folder and moving the sub reports but the calling reports couldn't find them.
Thanks!
Query To Generate Hierarchy In Organization
Jun 8, 2014I need to write a sql that generate the hierarchy in an organization.
Below an example
emplid empname supervisor_id superv_name
1 subu null null
2 vid 1 sub
3 ram 4 satis
4 satis 2 vid
I need an output to this query as below and also one important the supervisor ie supervisor_id and name is null is the top level,every employee also has to report to him and also to his all above supervisors.
Whoever joining new to org the hierarchy
empid empname supervisor_id superv_name
3 ram 4 satis
4 satis 2 vid
2 vid 1 subu
4 satis 1 subu
3 ram 1 subu
3 ram 2 vid
5 kumar 1 subu
5 kumar 4 satis
5 kumar 2 vid
1 subu null null
Deploying SQL Express Throughout The Organization/Enterprise
May 17, 2007What are some recommended methods for deploying SQL Express throughout an entire organization? It appears that Active Directory/GPO deployment is out of the equation.
Thanks,
Shane
In A Typical Organization Who Would Supprt SSIS
Aug 22, 2007In a large organization who would typically be tasked with support ing SSIS - the database team, an application team, etc... SSIS is new to our Organization, we are attempting to put it into the correct organization. We current have SSRS that is supported by an application team, the SS DB is supported by the DB team.
Thanks
Budget On Different Granularity In Organization Hierarchy (which Is SCD)
May 27, 2008Hi everyone
I am struggling with adding budget numbers to a cube. The main reason being that the budget is *not* on the finest granularity (employee) with regard to the organization hierarchy but on a coarser one (team).
The organization hierarchy is a "flat" (not parent-child) hierarchy that looks about like that:
employee -> team -> teamgroup -> region -> country
As mentioned I now have budget numbers that are defined on the team-level (not on the employee level as "regular" measures). I would know assume that I could put the budget data into its own table and "link" it with the organization through the "team" attribute. I would do that on the "dimesion usage"-tab.
The problem with this approach is that the organization is changing (SCD type 2). This essentially means that by linking to the "team" attribute the aggregation of the budget data on higher levels of the organization hierarchy can be ambiguous (at least that is what I understand).
Example organization table:
Code Snippet
surrKey busKey empName teamId teamGroupId regionId countryId ... scdStuff
1 1 Raphael 1 1 1 1 ...
2 2 Jeanne 2 2 1 1 ...
3 3 George 3 3 1 1 ...
4 2 Jeanne 2 3 1 1 ...
That would mean that on some point in time team 2 (consisting of one employee, Jeanne) moved from teamgroup 2 to teamgroup 3. Just for the sake of a simple example.
Now, what am I to do with my budget data in this situation? I cannot link it to the teamId, because teamId = 2 for example cannot specify if the value should be aggregated into teamgroup 2 or teamgroup3...
I have a feeling that this got something to do with the design of the organization-table but I am unsure about what the actual problem is. Any hint, pointer or solution would be appreciated. If the question is unclear, please let me know and I will try to clarify.
Kind regards
scherand
Yearly Production - Total Per Organization Number
Apr 13, 2012I am attempting to sum the gas production for each organization number, and separate gas production into each year as such:
Organization_Number20082009201020112012
103 774 7313868470
But currently I am having trouble displaying this, and it's coming out as such:
Organization_NumberMonth20082009201020112012
103 1 774731386847NULL
103 2 810656654674NULL
202 1 27262702293725122048
202 2 2913205120202064NULL
I want to remove the month and have one total per organization number, as well as remove NULL as show as 0.
Code:
select *
from yearproduction
pivot(
sum(Gas_Prod)
for Year in ([2008], [2009], [2010], [2011], [2012]))
as YearlyProduction
order by Organization_Number, Month
Hierarchy Query To Form Organization Structure
Jun 8, 2014I need to write a sql that generate the hierarchy in an organization.Below an example
emplid empname supervisor_id superv_name
1 subu null null
2 vid 1 sub
3 ram 4 satis
4 satis 2 vid
i need an output to this query as below and also one important the supervisor ie supervisor_id and name is null is the top level,every employee also has to report to him and also to his all above supervisors.whoever joinng new to org the hierachy should be follwed
empid empname supervisor_id superv_name
3 ram 4 satis
4 satis 2 vid
2 vid 1 subu
4 satis 1 subu
3 ram 1 subu
3 ram 2 vid
5 kumar 1 subu
5 kumar 4 satis
5 kumar 2 vid
1 subu null null
Tree
May 20, 2004Dear all,
I would like to know how to create a single level hierachy structure in SQL.
Example, I have a single parent record in table A that may later on spawn one or child record in table B that relates back to the parent. It only needs a single level.
that means, one to many.
thanks and rgds.
Loke HC
Tree
Jan 2, 2008I have two tables.
table1 has 3 fields a , b and c. field "a" is a primary key.
table2 has 2 fields x and y. Fields x and y are nothing but the value of "a". Also, y is the child of x.
Therefore, x and y can never have same value. It means value of "a" either be child or parent.
But there is possibility that parent has no child.
Now, i wanted to write Select/Insert query for parent, b , c and child.
This tree is no a binary tree but N-Ary Tree.
Thanks,
sha
Tree-walking In T-SQL
May 18, 2007Hi,
I'm having a major brain-failure moment here.
Using T-SQL I want to be able to get all of the leaf nodes (e.g. nodes at the furthest end of a tree from the root) in a hierarchical relationship where the table structure is such NodeID|ParentID|NodeName.
Basically if I had the following tree structure:
Root
Child1
Grandchild1
Child2
Grandchild2
I want to get all of the Grandchild nodes. Number of levels will vary and I haven't got any kind of HasChilds column.
I know this is possible because I remember having done it on a course years ago but I can't for the life of me figure it out on this sunny Friday afternoon. I know it's going to involve either recursion, a while loop or cursors but my mind is currently jelly. Can anyone help?
How To Get All The Children In The MLM Tree..
Sep 10, 2007hi. I am working on Multiline Marketing Project.I have to calculate all the childens and display the whole tree..I have save records in tree format...But not able to calculate the all childrens.
SELECT count(*) FROM dfTree WHERE id in (SELECT id FROM dfTree WHERE lineage like '16%')
This query works properly.Problem is that it is not working in the project because in the like I have to pass a variable.
SELECT count(*) FROM dfTree WHERE id in (SELECT id FROM dfTree WHERE lineage like '@idl%')
Please Suggest me...
Need Help For Tree Functionality
Jun 2, 2008HI,
I am working on a Family tree portal which need tree functionality to display family members in tree structure. on click on any node the adding option should be displayed
for this i need a table and procedure to complete family tree
Thanks
@mbi
Help Me Please, About Operator Tree
Jan 3, 2006Consider the following SQL query:
SELECT ENAME,SAL
FROM EMP,ASG,PAY,PROJ
WHERE EMP.ENO=ASG.ENO
AND PAY.TITLE=EMP.TITLE
AND ASG.PNO=PROJ.PNO
AND ASG.DUR=48 AND BUDGET>200000
Give the possible operator trees:right-deep,left-deep and bush
Tank you very much!
Tree Structures In SQL
Jun 11, 2006Hi,
i'm writing a app in c# and have to store Trees in a Database.
I'm working with Datasets for the exchange between the DB and the App.
The trees have the same options like the windows folders. If u delete a node, all subnodes should be deleted too.
But something a Foreign Key from ParentID references (Id) with the delete-Rule on cascade seems not to be possible, because of multiple cascade Paths or cycles. Do i have to add some xtra constarins:
Not Possible:
create Table tree (
Id varchar Not null,
ParentId varchar Not null,
Constraint pk1 Primary Key (Id),
Constraint fk1 Foreign Key (ParentId) references tree(Id)
On Update Cascade
On delete CAscade
)
Do i have to write triggers, which delete The subnodes too and set the Update-/deleterulr on NO Action
Greetz
Tree Structures...
Oct 24, 2006Does anyone know any good links for SQL tree structures and example queries and stuff... I cant really find anything part from the standard example of emplyee, boss, salary which explains how to create the tree table...(dun dis bit) I did notice a book but I live in a little village so cant go get it till wekend?
I'm desperate, reli need to work out how too do this.....
Tree Selection
Jun 13, 2008SELECT a.Network_ID, b.Last_Name + ', ' + b.Preferred_FirstName AS full_name, c.Security_Class_Description,
d.Security_Type_Description, a.Security_Value
FROM Company_Hierarchy_Security a
JOIN V_Entity_Employee_Active b on a.Network_ID= b.Network_ID
JOIN Company_Security_Class c on a.Security_Class_Code=c.Security_Class_Code
JOIN Company_Security_Type d on a.Security_Type = d.Security_Type
inner join (select e.Budget_Center_ID + ' - ' + e.Budget_Center_Description As Budget_Center_Description,
f.Company_Name, g.Enterprise_Description, h.Business_Segment_Description,
i.Team_Description
from Company_Hierarchy_Security a.
Inner JOIN Budget_Center e on a.Security_Value = e.Budget_Center_ID
Inner JOIN Company f on a.Security_Value = f.Company_ID
Inner JOIN Enterprise g ON a.Security_Value = Cast(g.Enterprise_Number As Varchar(5))
Inner JOIN Business_Segment h on a.Security_Value = h.Business_Segment_ID
Inner JOIN Team i on a.Security_Value = i.Team_ID
Ok. I have the Security Value located in Company_Hierarchy_Security table. All those values are divided into 5 other tables that I need to join together. I found all of them separate but I have not been able to figue it out how to put it together with the rest of the querie.
Thanks for the help!!!!!
Tree Selection
Jun 16, 2008Thank You visakh16 --- The following section of my querie works but doesn't give the exact information that I need. This is what is giving me:
NetworkId Full Name Sec Class Desc Sec Type Desc SecValue
tte Test Scenario Accounting Budget Center 142- ?
SELECT a.Network_ID, b.Last_Name + ', ' + b.Preferred_FirstName AS full_name, c.Security_Class_Description,
d.Security_Type_Description, a.Security_Value
FROM Company_Hierarchy_Security a
JOIN V_Entity_Employee_Active b on a.Network_ID= b.Network_ID
JOIN Company_Security_Class c on a.Security_Class_Code=c.Security_Class_Code
JOIN Company_Security_Type d on a.Security_Type = d.Security_Type
------------------
inner join (select e.Budget_Center_ID + ' - ' + e.Budget_Center_Description As Budget_Center_Description,
f.Company_Name, g.Enterprise_Description, h.Business_Segment_Description,
i.Team_Description
from Company_Hierarchy_Security a.
Inner JOIN Budget_Center e on a.Security_Value = e.Budget_Center_ID
Inner JOIN Company f on a.Security_Value = f.Company_ID
Inner JOIN Enterprise g ON a.Security_Value = Cast(g.Enterprise_Number As Varchar(5))
Inner JOIN Business_Segment h on a.Security_Value = h.Business_Segment_ID
Inner JOIN Team i on a.Security_Value = i.Team_ID
_____________________________________________________________________
What I need is the Description that are located in 4 other different tables that matches the Security Value from my first querie.
The result should look like this...
Network Id full Name Sec Class Desc Sec Type Desc Security Value
tst , Test Example , Accounting ,Budget Center , 142-Accountig dept
Thank you very much,
Tree Table
Sep 12, 2006Hello,I have a "tree" table:Id - primary keyParrentId - (foreign key) related to IdTitle.....when I delete some record I want to delete it with all childs (cascadedeleting). I can't set cascade deleting on the same table :(. Is thereany easy way in the MSSQL 2005 to do this ? There is one idea - usingcursors + recursive functions but I think this solution is not easyand elegant.Thakns for any help and sugestions.Regards.Andy
View 4 Replies View RelatedTree View
Mar 5, 2008Hi:
Is there a resource or an object in Reporting Services that I could make a tree view in a report file .rdl and see the result on it?
If not, is there a software of MS that a could make a component for it, and connect this component in the report file .rdl ?
PLZ HELP ME WITH THE DECISION TREE!!
Apr 16, 2007I'm having this problem.....
I wanted to use the Decision Tree to show a result..... after i configure the Mining Structures..... and set all the input.... my decision tree shows only until level 2..... i have 3 input and one PredictOnly column.....where is the other input?
Say.... i have House Owner, Marital Status, Num Cars Owned and Number Of Children(PredictOnly)
my Tree only shows All ---- > Marital Status when i input all 3 together...... the other 2 doesn't seems to show.
wat should i do?? my database in SQL Server and the other keys are all correct and deploying finely.....why is this happening.....?
i'm a newbie in this software.......so any pro here can plz help me if there's actually something that i might have missed out along the way.......
Thank you again.........
Rescursive Tree
Feb 28, 2008
Alright what im trying to do is build a classic tree, i have id's like this set up in my table referencing itself in sql 2000
cmponent_prt_no parent_part_no
--------------- --------------
112837A2A L115100-1
114379A1A L115100-1
115623A1A L115100-1
203604A L115100-1
203790A L115100-1
203791A L115100-1
115623A 115623A1A
M010137 115623A1A
115623A 115623A1A
20766CR 115623A1A
DRAWINGS 20766CR
M010137 20766CR
i have tried 3 different solutions all coming to a crash at some point, if ANYONE can help me out i would appreciate it, i know the logic will be recursive, i just dont know how to implement
Convert A Table Into Tree
Aug 21, 2007Hi..I have a table register..in this fields are username,parent id,downline ; I have to determine all the child of a particular parent.
suppose table is like this. username parentid downline
B A left
C A right
D B left
E B right....
I have to also determine the level in the tree....please help...
Does Anyone Know How To Traverse A Simple Tree Using SQL?
Dec 6, 2000Hello all!
I have a table defined as:
create table OrgTree (parent int, child int)
OrgTree has the following data:
1,2
1,3
2,4
2,5
3,6
4,7
4,8
8,9
Is there a SQL stmt that will return, given a particlar parent, all of the children (and children's children, etc.) of that parent?
So, parent value 1 returns 2,3,4,5,6,7,8,9
parent value 2 returns 4,5,7,8,9
parent value 3 returns 6
etc.
Thanks in advance for your help!!
Palmer F
Database Tree Says 'No Items' ???
Oct 30, 2001I just started having this problem. When I log into SQL2000 enterprise manager and click on my database, the main directory tree shows up. When I click on the Database tree to display all of the different databases on the SQL server, the text 'No Items' shows up. I can not get to any databases, but I am connected to the SQL server. Does anyone have a solution for this problem?????
I have tried re-inatalling and all of the service packs.
Thanks !!
Family Tree Branches
Jul 26, 2004Okie, this one has me a little stumped so bear with me an I will explain as best I can....
I have a family tree database...
The two key tables (for this problem) are Person and Child. The person table is your generic person details table and contains, PersonId, PersonFirstName, PersonLastName, PersonDOB etc. The Child table is a linking table that links a PersonId to a ChildPersonId (so both Id's are valid Id's in the person table).
Now what I want to try and achieve is a breakdown of the different branchs of the family tree. A branch is an independant, unattached section of the tree (if that makes sense). It's a grouping of people we know are related but we can't determine how they are related to another group of people in the tree.
If you look at this http://gw.geneanet.org/index.php3?b=bengos&lang=en;m=N;v=van+halewyn you will get an idea of what I mean.
I'm not sure if this is something that can be don't with a query at all the be honest... I suspect that I will have to wrap some other code around it, but I'm really not sure on what approach I should be using. Any help people could offer would be great.
Hiearchical List Of Tree
Jul 8, 2007Hi,
table(id,parent,level, name)
parent ...fk referenced table(id))
level ... depth of tree (root has 0)
How SQL for hiearchical list:
name 1
name 1.1
name 1.2
name 2.
name 2.1.
name 2.1.1
name 2.1.2
etc.
???
thanks for your help
Example Code For User Tree
Sep 17, 2007One of the users on another web site posted a question about how to associate users in a tree-like organization. That web site isn't well suited to posting code or ongoing discussions about code, so I'm going to post the example here. Feel free to discuss as you see fit.DROP TABLE LI_UserLinks
GO
DROP TABLE LI_Users
GO
DECLARE @d1DATETIME
, @d2DATETIME
, @d3DATETIME
, @d4DATETIME
, @d5DATETIME
, @d6DATETIME
, @d7DATETIME
, @d8DATETIME
SELECT @d1 = GetDate()
CREATE TABLE LI_Users (
uidINT
PRIMARY KEY (uid)
)
SELECT @d2 = GetDate()
CREATE TABLE LI_UserLinks (
uid_fromINT
CONSTRAINT XFK01LI_UserLinks FOREIGN KEY (uid_from)
REFERENCES LI_Users (uid)
, uid_toINT
CONSTRAINT SFK01LI_UserLinks FOREIGN KEY (uid_to)
REFERENCES LI_Users (uid)
CONSTRAINT XPKLI_UserLinks PRIMARY KEY (uid_from, uid_to)
)
ALTER TABLE LI_Userlinks
ADD CONSTRAINT XCK01LI_UserLinks CHECK (uid_from != uid_to)
SELECT @d3 = GetDate()
INSERT INTO LI_Users (
uid) SELECT n0 + 10 * n1 + 100 * n2 + 1000 * n3 + 10000 * n4 + 100000 * n5
FROM (SELECT 0 AS n0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z0
CROSS JOIN (SELECT 0 AS n1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z1
CROSS JOIN (SELECT 0 AS n2 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z2
CROSS JOIN (SELECT 0 AS n3 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z3
CROSS JOIN (SELECT 0 AS n4 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z4
CROSS JOIN (SELECT 0 AS n5 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z5
SELECT @d4 = GetDate()
INSERT INTO LI_UserLinks (
uid_from, uid_to) SELECT
uid, 100 * uid + n0 + 10 * n1
FROM LI_Users
CROSS JOIN (SELECT 0 AS n0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z0
CROSS JOIN (SELECT 0 AS n1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z1
WHERE LI_Users.uid BETWEEN 0 AND 99
AND uid != 100 * uid + n0 + 10 * n1
SELECT @d5 = GetDate()
INSERT INTO LI_UserLinks (
uid_from, uid_to) SELECT
uid, 100 * uid + n0 + 10 * n1
FROM LI_Users
CROSS JOIN (SELECT 0 AS n0 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z0
CROSS JOIN (SELECT 0 AS n1 UNION SELECT 1 UNION SELECT 2 UNION SELECT 3
UNION SELECT 4 UNION SELECT 5 UNION SELECT 6 UNION SELECT 7
UNION SELECT 8 UNION SELECT 9) AS z1
WHERE LI_Users.uid BETWEEN 100 AND 9999
SELECT @d6 = GetDate()
SELECT u.uid, r1.uid_to, r2.uid_to
FROM LI_Users AS u
INNER JOIN LI_UserLinks AS r1
ON (r1.uid_from = u.uid)
INNER JOIN LI_UserLinks AS r2
ON (r2.uid_from = r1.uid_to)
WHERE 1 = u.uid
SELECT @d7 = GetDate()
SELECT Count(DISTINCT u.uid), Count(DISTINCT r1.uid_to), Count(distinct r2.uid_to)
FROM LI_Users AS u
INNER JOIN LI_UserLinks AS r1
ON (r1.uid_from = u.uid)
INNER JOIN LI_UserLinks AS r2
ON (r2.uid_from = r1.uid_to)
SELECT @d8 = GetDate()
SELECT
DateDiff(ms, @d1, @d2)
, DateDiff(ms, @d2, @d3)
, DateDiff(ms, @d3, @d4)
, DateDiff(ms, @d4, @d5)
, DateDiff(ms, @d5, @d6)
, DateDiff(ms, @d6, @d7)
, DateDiff(ms, @d7, @d8)
, DateDiff(ms, @d1, @d8)-PatP
Getting A Tree Using Parent-child
Sep 27, 2013Here is the table - Company with fields:
CompanyID, ParentCompanyID (both integers)
Given a CompanyID - I want to get all the children for the Company.
I did similar procedures but somehow, could not get this to work.
Creating A Tree From Set Of Rows
Feb 9, 2015I have following 4 rows in a table with field name as ID
ID
--
AA
BB
CC
DD
I require output as
ID NewColumn
-- ----------
AA AA
BB AA~BB
CC AA~BB~CC
DD AA~BB~CC~DD