PROBLEM WITH NULL WHEN CONCATENATE

May 22, 2008

I m Creating One table
Create table Empname
( NAME1 Char(10) NULL,
NAME2 Char(10) NULL,
NAME3 Char(10) NULL
)
AFTER That Inserting The data in Empname table With Some Null Values
After that I m Fetch the records
SELECT (NAME1 + NAME2 + NAME3) AS NAME FROM Empname)
GET ME RECORDS LIKE THIS
'yaman NULL GUPTA'
'RAJ KUMAR NULL'
Why NULL IS COMING




Yaman

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Concatenate When One Column Is NULL

Jul 26, 2006

I am trying to concatenate three columns and when one column might be NULL, the result set is NULL. I have set "concat null yields null" to false and the result is the same. Here is my code:


Code:


SELECT lname + ',' + space(1) + fname + SPACE(1) + mname as FullName



TIA

Mike

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Problem With Isnull. Need To Substitute Null If A Var Is Null And Compare It To Null And Return True

Sep 20, 2006

Hey. I need to substitute a value from a table if the input var is null. This is fine if the value coming from table is not null. But, it the table value is also null, it doesn't work. The problem I'm getting is in the isnull line which is in Dark green color because @inFileVersion is set to null explicitly and when the isnull function evaluates, value returned from DR.FileVersion is also null which is correct. I want the null=null to return true which is why i set ansi_nulls off. But it doesn't return anything. And the select statement should return something but in my case it returns null. If I comment the isnull statements in the where clause, everything works fine. Please tell me what am I doing wrong. Is it possible to do this without setting the ansi_nulls to off??? Thank you

set ansi_nulls off


go

declare

@inFileName VARCHAR (100),

@inFileSize INT,

@Id int,

@inlanguageid INT,

@inFileVersion VARCHAR (100),

@ExeState int

set @inFileName = 'A0006337.EXE'

set @inFileSize = 28796

set @Id= 1

set @inlanguageid =null

set @inFileVersion =NULL

set @ExeState =0

select Dr.StateID from table1 dR

where

DR.[FileName] = @inFileName

AND DR.FileSize =@inFileSize

AND DR.FileVersion = isnull(@inFileVersion,DR.FileVersion)

AND DR.languageid = isnull(@inlanguageid,null)

AND DR.[ID]= @ID

)

go

set ansi_nulls on

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Feb 1, 2007

Need help. How to concat into 1 row from the example below:

Table Address
Block Flr Road
2 1 Green
3 - Maine
4 3 Bell
5 2 Prade

Result :
Block 2 Flr 1 Green Road
Block 3 Maine Road
Block 4 Flr 3 Bell Road
Block 5 Flr 2 Prade Road

Cheers!

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Aug 31, 2007

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Oct 1, 2007

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Feb 23, 2001

I'm trying to use a variable (@sqlfields1) for building a select statement.
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If @showo1 = 1
select @sqlfields1 = 'o1,'

If @showo5 = 1
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I want @sqlfields1 to be = 'o1, o5'.

Regards,

Abrazame

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Oct 25, 2004

Please help me with this if you can.
I have one table with CustomerID and some other data.
In other table i have CustomerID(the link with the first table) and Agent
The relation of the first with the second one is ONE TO MANY.
I want something like this:
Customer,'Agent1,Agent2,Agent3'

Is it possible.
Please help :)

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Jul 27, 2007

Hey all

Just like the title asks...Is it possible...I have a table that stores memos but breaks the memo text field up and assigns a key to associate it all as one big text field in the application. What I am needing to do is to create a custom table for a customization to have the memo txt in one row per customer, per memo number. So, is there any way to concatenate memotext into one row per memo?

Thanks
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Aug 31, 2007

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i have 2 selects and i want to display all results from the first
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with paging.

if i use union, all the results will be mixed.

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Sep 29, 2012

Is there a way to concatenate the values of a particular field together into one field for all the records in each group of a GROUP BY without using XML?

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For example, if my data was:
1 "A"
1 "B"
1 "C"
2 "D"
2 "E"

I want to group by the first value and concatenate the second value:
1 "A,B,C"
2 "D,E"

Very easy using code - I simply add a function to the query in Access (not very efficient, but effective), or using recordsets in the app (which is actually very efficient) except my front end is Crystal in this case .

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Mar 30, 2014

I have a table like so

code remarks
1234 abcd
4567 efgh

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Jan 25, 2007

I have a table like below.

certid name
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1 yyy
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Mar 5, 2007

I hope this is the correct place to ask this...

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But unfortunately I am getting the error:
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Any idea how to get around this at all just using an SQL query statement?

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Mar 27, 2007

-- Prepare sample data
DECLARE@Sample TABLE (ID INT, Code VARCHAR(3))

INSERT@Sample
SELECT290780, 'LT' UNION ALL
SELECT290780, 'AY' UNION ALL
SELECT290781, 'ILS' UNION ALL
SELECT290780, 'AY'

-- Show the expected output
SELECT DISTINCTs1.ID,
STUFF((SELECT DISTINCT TOP 100 PERCENT ',' + s2.CODE FROM @Sample AS s2 WHERE s2.ID = s1.ID ORDER BY ',' + s2.CODE FOR XML PATH('')), 1, 1, '') AS CODES
FROM@Sample AS s1
ORDER BYs1.ID

SELECT DISTINCTs1.ID,
STUFF((SELECT TOP 100 PERCENT ',' + s2.CODE FROM @Sample AS s2 WHERE s2.ID = s1.ID ORDER BY ',' + s2.CODE FOR XML PATH('')), 1, 1, '') AS CODES
FROM@Sample AS s1
ORDER BYs1.ID

SELECT DISTINCTs1.ID,
STUFF((SELECT ',' + s2.CODE FROM @Sample AS s2 WHERE s2.ID = s1.ID FOR XML PATH('')), 1, 1, '') AS CODES
FROM@Sample AS s1
ORDER BYs1.ID

Peter Larsson
Helsingborg, Sweden

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Jul 23, 2005

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Jul 20, 2005

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Oct 9, 2007

Hi there,


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May 2, 2008

Hi,
Whats wrong with the following T-SQL?

DECLARE @SQL NCHAR(4000)

SELECT @SQL = 'xxxx'
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PRINT @SQL

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Jan 16, 2008

Hi,

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Sep 20, 2007

Hi

I have a table similar to the following:

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12/12/2007 123456 Fred Smith 111111 Full Day
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12/12/2007 654321 Bob Blue 333333 Half Day PM

I need the following output:
Date ID Name Job Number JobType
12/12/2007 123456 Fred Smith 111111 Full Day
12/12/2007 654321 Bob Blue 222222 Half Day AM
12/12/2007 654321 Bob Blue 333333 Half Day PM



Now before you say the output is the same . It isn't! There are only 2 records in the output. The italic lines are one record, with a carriage return linefeed between each piece of data. So for job number the field is equal to 111111 + CHAR(10) + CHAR(13) + 222222

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Cheers

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Code Snippet

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However attempting the same command in T-SQL I get the following error:

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[Code] ....

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4       Raven
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