Partition On Value
Feb 9, 2006
I can see lot of documentation on Range Partitioning. Is there any other type of partition supported in SQL Server 2005?
For example, I have a Fact table having Billion rows. It has a column called BATCH_ID. A BATCH_ID corresponds to 10-20 Million rows and it is a running sequence number like 1,2,3 etc. (not an identity column). Is there anyway I can specify a partition function with BATCH_ID column as an int value? Will the SQL Server automatically does the partition on each int value in that case? If not, what is the best way to do it?
Thanks in advance for all help in this
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Jul 6, 2006
i have a table named table1 sitting on a a partittion scheme px.
table1 is partitioned on u_id by tens,
first partion u_id=0 to 9
second partion u_id=10 to 19
third partion u_id=20 to 29
ans so on and so forth
i have a table named table2 with
records having u_id = 13 to 16
obviously belonging to the second partion.
i want to load table2 to table1 as fast as i could with
the following requirements:
all contents of partition 2 of table1 must be deleted before loading
table2 ceases to exist after the operation
how will i do that.
thanks.
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May 15, 2008
Hi All,
Can someone take a look at my code and tell me what i'm doing in wrong. The script runs fine but when i go to table property it says the table is not partitioned. Thanks for your help.
create database [mypartition]
go
--CREATE FILEGROUP
USE [mypartition]
GO
ALTER DATABASE mypartition ADD FILEGROUP Y2000_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2001_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2002_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2003_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2004_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2005_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2006_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2007_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2008_filegroup
ALTER DATABASE mypartition ADD FILEGROUP Y2009_filegroup
--CREATE FILES
USE mypartition
GO
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2000,
FILENAME = 'F:ss_datadatadetail_2000.ndf',
SIZE = 2MB)
TO FILEGROUP Y2000_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2001,
FILENAME = 'F:ss_datadatadetail_2001.ndf',
SIZE = 2MB)
TO FILEGROUP Y2001_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2002,
FILENAME = 'F:ss_datadatamdetail_2002.ndf',
SIZE = 2MB)
TO FILEGROUP Y2002_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2003,
FILENAME = 'F:ss_datadatadetail_2003.ndf',
SIZE = 2MB)
TO FILEGROUP Y2003_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2004,
FILENAME = 'F:ss_datadatadetail_2004.ndf',
SIZE = 2MB)
TO FILEGROUP Y2004_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2005,
FILENAME = 'F:ss_datadatadetail_2005.ndf',
SIZE = 2MB)
TO FILEGROUP Y2005_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2006,
FILENAME = 'F:ss_datadatadetail_2006.ndf',
SIZE = 2MB)
TO FILEGROUP Y2006_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2007,
FILENAME = 'F:ss_datadatadetail_2007.ndf',
SIZE = 2MB)
TO FILEGROUP Y2007_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2008,
FILENAME = 'F:ss_datadatadetail_2008.ndf',
SIZE = 2MB)
TO FILEGROUP Y2008_filegroup;
ALTER DATABASE mypartition
ADD FILE
(NAME = mypartition_detail_2009,
FILENAME = 'F:ss_datadatadetail_2009.ndf',
SIZE = 2MB)
TO FILEGROUP Y2009_filegroup;
--CREATE PARTITION FUNCTION
USE [mypartition]
GO
CREATE partition FUNCTION detail_part_function (varchar(10)) AS
RANGE LEFT FOR VALUES('2001','2002','2003','2004','2005','2006','2007','2008')
GO
--CREATE PARTITION SCHEME
USE [mypartition]
GO
CREATE PARTITION SCHEME detail_part_scheme AS
PARTITION detail_part_function TO
(Y2000_filegroup, Y2001_filegroup,Y2002_filegroup,Y2003_filegroup,Y2004_filegroup,Y2005_filegroup,Y2006_filegroup,Y2007_filegroup,Y2008_filegroup,Y2009_filegroup)
GO
-- Now just create a table that uses the particion scheme
USE [mypartition]
GO
/****** Object: Table [dbo].[partitioned_table] Script Date: 05/14/2008 09:44:21 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
SET ANSI_PADDING ON
GO
CREATE TABLE [dbo].[partitioned_table](
[id] [int] NOT NULL,
[fiscal_year] [varchar](10) COLLATE SQL_Latin1_General_CP1_CI_AS NULL,
CONSTRAINT [PK_partitioned_table] PRIMARY KEY CLUSTERED
(
[id] ASC
)WITH (IGNORE_DUP_KEY = OFF) ON [PRIMARY]
) ON detail_part_scheme(fiscal_year)
GO
SET ANSI_PADDING OFF
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Jul 3, 2004
Hi,
I recently installed MSSQL 2000 and sp3a onto a windows 2003 server in a test lab. I configured one big c: partion on this os and installed the db in the default location.
I need to detach the db's on this server and re-attach them onto another MSSQL 2000/sp3a server running 2003 os with a partition scheme like this:
c: = 20 gigs for the os
e: = 600 gigs for the data
I could not re-attach the db's onto the e:default path odatabase
Is there a work-around for this? This makes sense to me as to why it is not working and was an install oversight on my part but there has to be a way to overcome this delima?
Thanks in advance,
damnit
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Nov 22, 2005
Hi
Please help me how to do the Horizontal table partition??
I have to split the table in to multiple sub tables with same columns and less rows and then I have to use each sub table.
Thanks you in advance....
Regards
LakshmiPK
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Oct 10, 2007
Hi everybody
Does anyone know where I can find code to PROCESS a Partition using DSO.
Thank a lot.
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Mar 31, 2008
I keep getting this error:
Msg 156, Level 15, State 1, Line 12
Incorrect syntax near the keyword 'over'.
What am I missing? The max() over statement looks just like the statement in the documentation.
select RegistrationId,
OrderId,
Sequence,
Title,
InformalFirstName,
FirstName,
MiddleName,
Lastname,
EntryDate,
max(Sequence) over(partition by RegistrationId) as 'maxsequence'
from registration
where OrderId = '68379449583' and
Year = '2008' and
Active = 'Yes'
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May 21, 2008
I have a situation where my SQL works everywhere else but my COBOL compiler complains wherever I use PARTITION BY. I can't find a workaround for that problem so I would like to remove all the PARTITION BYs. I'm not confident that I can do this accurately and would like some help getting started.
Here is my simplest example:
SELECT FESOR.REGION, FESOR.TYPE,
COUNT(*) OVER (PARTITION BY FESOR.REGION, FESOR.TYPE)
FROM FESOR, FR
where FESOR.phase = 'Ref'
and FESOR.assign is null
and FESOR.comp_date is null
and FESOR.region = FR.REGION
and FESOR.type = FR.TYPE
and FR.REP_ROW='A'
GROUP BY FESOR.REGION, FESOR.TYPE
What I'm looking for is a modified version of the SQL above which returns the same result set without using PARTITION BY.
Thanks in advance for your assistance.
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Aug 28, 2007
Hi,
I am using SQL Server 2000 SP3 Version 8.00.7.60. Can I create instances of SQL server 2000 even if it's already installed?
Thanks for your help in advance!
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Feb 25, 2008
Guys,
I have names in the database which I want partition by last name - for example last names starting with A, B, C, D should go to the file group 1. last names starting with E, F, G, H should go to file group 2.
I am trying to use the following function - but do I specify in the function that last names with with A, B, C, D should go to the file group 1
CREATE PARTITION FUNCTION myRangePF3 (char(20))
AS RANGE RIGHT FOR VALUES ('EX', 'RXE', 'XR');
Is there any way to modify partition function to accomplish this?
Any suggestions and inputs would help
Thanks
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Feb 27, 2008
All,
I have a partitioned table (1.7 billion rows) that is across 97 partions. The table is partitioned on datetime field.
When I query only this table with datetime field in where clause I see that cleary it outperforms the unpartitioned table.
When this table is joined to 3 tables it performs no better than
the non-partitioned table... it seems that the query does a partition scan.
The part. table has a 3 part composite clustered index and
a NC index on the partion field value.
Would appreciate any feedback.
thanks
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Mar 7, 2008
SUM(qtycolumn) OVER (PARTITION BY columnA, Column B)
is this function supported by Sql Ce?
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Nov 14, 2007
HI all,
I am in the progress of migrating my 2000 install over to SQL05 and onto a couple of new boxes. I have 2 Dell 1850's to set up mirroring on and wanted to know your opinion on the best partition setup. The 1850's are a 2 disk machine so it has to be a RAID 1 setup. I am just unsure of the benefit of partitioning the logical drive to seperate the log files from the data files.
Should I partition the drive, a 300G SCSI into 2 partitions and keep the logs on one partition and the data on another? Can anyone tell me if there is a benefit to doing this?
If there is a more pratical solution can you explain?
Thanks in advance!
Jason
Sydney Australia
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Mar 27, 2007
Most examples for SQL Server 2005 involve a sales table that you split based on date, i.e. sales records prior to 2000 go to this partition, and the ones after that go to another one. Nice and simple.
Say I have a sales table:
id Amount Date
1 10 1/1/1999
2 9.99 1/1/2007
Now then, I put all the records prior to 2000 in it's own partition.
So when I do something like this: SELECT * FROM Sales WHERE DATE = 1/1/1999
the SQL server will know which partition to look at. Very nice.
Now then, if I do this: SELECT * FROM Sales WHERE id = 1
How will the SQL server know which partition to look at?
Thank You!
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Oct 31, 2006
hi list
i have a table named stgBudgetFact, that is partitioned on DivisionID.
each DivisionID goes into its own partition, which is on its own file group.
the etl guru on the project wants to be able to truncate the partition, not do a delete from the table based on DivisionID.
Is it possible to truncate the partition somehow (remove rows where DivisionID = 3 for instance without ALTER DATABASE, where the medicine is worse than the disease) and then reestablish the partition so we can restart a failed load by division?
i really hope something like this is possible
thanks
drew
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Aug 30, 2007
hello,
I want to copy all or part data in one partition to another partition,how can I do?
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Nov 29, 2007
Dear all,
Sorry if my post misplaced. I have a table that contain huge data so I made a partition function and partition schema. Unfortunately there's only one column to be allowed as a partition column whereas my queries using a few columns. Can we make many partition function that apply to one partition schema ? I search no result in SQL BOL.
Thanks in advance.
Best regards,
Hery
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Dec 13, 2007
Hi Every body,
I am creating Table partition in tables but i am getting this error can you anybody plz help how can we do table partition in the database
CREATE TABLE PartitionTable (col1 int, col2 char(10))
ON myRangePS2 (col1) ;
GO
CREATE TABLE NonPartitionTable (col1 int, col2 char(10))
ON test2fg1 ;
GO
ALTER TABLE PartitionTable SWITCH PARTITION 2 TO NonPartitionTable ;
GO
Msg 1921, Level 16, State 1, Line 2
Invalid partition scheme 'myRangePS2' specified.
Msg 1921, Level 16, State 1, Line 1
Invalid filegroup 'test2fg1' specified.
Msg 4902, Level 16, State 1, Line 1
Cannot find the object "PartitionTable" because it does not exist or you do not have permissions.
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Aug 20, 2007
Does anyone know how much free space should be left available on a storage partition to allow for the optimum performance? In fact is there any performance benefit to allowing a certain amount of free space on a partition that is occupied by SQL data files?
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Nov 7, 2007
How complex can the over (partition by...) window functions be? All the examples I see in BoL, the partition clause is the same for each window function. Can it be different? How different?
Here are some snippets of where I'd like to take this. Right now I'm using successive views to bring the results to a single row.
SUM(building_function_table.e_and_g_square_foot + building_function_table.auxillary_square_foot)
OVER (PARTITION BY building_function_table.fice_code, building_function_table.building_number) AS sqft
SUM(building_function_table.e_and_g_square_foot * function_table.square_foot_value)
OVER (PARTITION BY building_function_table.fice_code, building_function_table.building_number,building_function_table.function_code) AS repl_value_e_g
SUM(building_needs_table.percentage * (building_needs_table.age / system_component_table.useful_life) * component_multiplier_table.multiplier)
OVER (PARTITION BY building_needs_table.fice_code, building_needs_table.building_number, building_needs_table.system_code, building_needs_table.system_component_code, building_needs_table.function_code) as maint_needs
And it gets even more complex, but these are all I've written because I don't know if it will work.
These would be all part of a giant overhead view of a building maintenance database. It's normalized and the respective tables above are all simple inner joins on the primary key of their parent.
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Jan 23, 2007
1 HIS_HTTP_LOG a partition table2 REL_HTTP_LOG not a partition table,the same structure of HIS_HTTP_LOGļ¼3 When HIS_HTTP_LOG doesn't exist any index the following executed succeed
ALTER PARTITION SCHEME PS_HIS_HTTP_LOG NEXT USED [FG_03] ALTER PARTITION FUNCTION PF_HIS_HTTP_LOG() SPLIT RANGE ('20070331 23:59:59.997') ALTER TABLE TMP_HTTP_LOG SWITCH TO HIS_HTTP_LOG PARTITION 3
4 However when I added the index in HIS_HTTP_LOG and execute the step 3,It made error: a) CREATE INDEX IDX_HIS_HTTP_LOG_001 ON HIS_HTTP_LOG(USERID)ON PS_HIS_HTTP_LOG (STARTIME) b) ALTER PARTITION SCHEME PS_HIS_HTTP_LOG NEXT USED [FG_03] ALTER PARTITION FUNCTION PF_HIS_HTTP_LOG() SPLIT RANGE ('20070331 23:59:59.997') ALTER TABLE TMP_HTTP_LOG SWITCH TO HIS_HTTP_LOG PARTITION 3
========================= Error messages================================================"ALTER TABLE SWITCH statement failed. There is no identical index in source table 'TMP_HTTP_LOG SWITCH ' for the index 'IDX_HIS_HTTP_LOG_001' in target table 'HIS_HTTP_LOG' ."
When I added index in REL_HTTP_LOG ,it gave me the same error message
Could you tell me how can I solve the problem !
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Jun 20, 2002
I have the pagefile.sys on the same partition (C:)as the database files. I been advised this is not a good idea. I'm getting paging. I'd like to move the swapfile to another partition on the same drive. Is that a good idea, or should I move it to another physical disk? And is it OK to leave the OS partition (C:) without any swapfile? Thanks!!
rob
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Dec 6, 1999
Does anyone know who can we do partition od table in sqlserve 7?
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Jan 21, 1999
Hi!
I'm installing a new SQL Server machine. During NT Server
installation our NT support guy converted the only 2GB FAT
C: partition to NTFS. So as of right now all my 4 8GB drives are
NTFS. I think it would be better to keep this C: partition in FAT
because, as of my knowledge, having FAT boot partition can help
to boot the machine in case of NT crash.
Is there anything that I'm really losing by this conversion to NTFS or I
should not be worried so much about it? Does it put my SQL Server
databases, database .dat files or NT Server in more danger situation
in case of any crash?
Or it's giving me some advantages?
Thanks
Ninel
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Jul 17, 2001
Hi folks,
Recently i've been working on a new project that would partition a large table 2 smaller tables. I then create a view to union the 2 smaller tables(table A, B). I've been getting a strange error when i try to update, insert, delete a record through the view. "View needs partitioning column"....i find this strange. Both of my table have a cluster primary key consisting of 3 columns, and one of the 3 columns(date field) consist of a check constraint. The constraint is used to determine what record goes into which table. Am i missing anything else? The really strange part is sometime it works, and sometimes i get the error message.
Any thoughts?
Joe R.
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Oct 26, 2006
If I have a table split up among partitions A, B, C, how do I select only from partition C?
~Le
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Jan 12, 2012
I need to create a new partition on a Cube using T-SQL and I am not much aware of either the Cubes or the ActiveX script. I am writing a T-SQL script for creating this partition on a cube.
Select Case iMonth
Case 1,2,3
sQuarter = "1"
Case 4,5,6
sQuarter = "2"
Case 7,8,9
sQuarter = "3"
Case 10,11,12
[Code] .....
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Dec 31, 2003
Hi ,
I have question regard data partition view .
Please see below sample from BOL + sample of execution plane .
I would like to ask what is the way to avoid the optimizer scan tables out of the scope (I would expect that the only table for this query will be SUPPLY1)
Thanks,
Eyal
--This example uses tables named SUPPLY1, SUPPLY2, SUPPLY3, and SUPPLY4, which correspond to the supplier tables from four offices, located in different countries/regions.
USE tempdb
GO
--create the tables and insert the values
CREATE TABLE SUPPLY1 (
supplyID INT PRIMARY KEY CHECK (supplyID BETWEEN 1 and 150),
supplier CHAR(50)
)
CREATE TABLE SUPPLY2 (
supplyID INT PRIMARY KEY CHECK (supplyID BETWEEN 151 and 300),
supplier CHAR(50)
)
CREATE TABLE SUPPLY3 (
supplyID INT PRIMARY KEY CHECK (supplyID BETWEEN 301 and 450),
supplier CHAR(50)
)
CREATE TABLE SUPPLY4 (
supplyID INT PRIMARY KEY CHECK (supplyID BETWEEN 451 and 600),
supplier CHAR(50)
)
GO
--create the view that combines all supplier tables
CREATE VIEW all_supplier_view
AS
SELECT *
FROM SUPPLY1
UNION ALL
SELECT *
FROM SUPPLY2
UNION ALL
SELECT *
FROM SUPPLY3
UNION ALL
SELECT *
FROM SUPPLY4
GO
INSERT all_supplier_view VALUES ('1', 'CaliforniaCorp')
INSERT all_supplier_view VALUES ('5', 'BraziliaLtd')
INSERT all_supplier_view VALUES ('231', 'FarEast')
INSERT all_supplier_view VALUES ('280', 'NZ')
INSERT all_supplier_view VALUES ('321', 'EuroGroup')
INSERT all_supplier_view VALUES ('442', 'UKArchip')
INSERT all_supplier_view VALUES ('475', 'India')
INSERT all_supplier_view VALUES ('521', 'Afrique')
GO
/* */
SELECT * FROM all_supplier_view WHERE supplyID BETWEEN 1 and 150
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Jan 28, 2004
I have created a horizontal partition view from 4 physical tables.
just wondering how the index works in the partition view:
1) If I need to build an index on a column, do I need to build
it on all 4 physical tables? or I just build it on the view? or build
it on view and 4 physical tables?
2) If I build it on view, and if I add a table into view, do I need to
recreate all indices on the view?
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Jan 22, 2014
I'm moving set of data from one partition to another what is the best way.
what all the things need to be considered
Note: The set of data will be all from one partition to another one partition
My current query:
UPDATEtable1
SET table1.partitioncolumn = @newpartitioncolumn
FROMtable1
INNER JOIN table2
ON table1.id = table1.id
AND table1.partitioncolumn = @oldpartitioncolumn
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Feb 27, 2008
Can you join a partitioned table to other tables that either
are/are not partitioned??
When you join partitioned tables ... Do they have to be partition key 'aligned'??
thanks
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Aug 8, 2006
Hello,I have a SQL 2000 installation on a small partion that I would like tomove to a second larger partion on the same disk array array with theconfig as follows:d: full installation of prod and test instances with data and log files100 GBe: empty partion with 204 GB which I want to move the "whole thing"I did an Xcopy of all files,permissions and attributes, checked forerrors, then I changed driveletters and restarted. Only one instance came up (the other threw anerror of: MSSQL,,the system cannot find the file specified.I realize that I could detatch the DB's and move them leaving the baseinstall on the old partition however I would like to simulate the lossof the disk array and the restore to said array from a backup.(ultimately I want to delete the 2 partitions and restore from tape toa single 300GB d: partition)I am trying to buy time and avoid a re-install of SQL untill I can geta whole new platform.I can work it out on my own if someone can point me in the rightdirection. I suspect a registry entry to a disk id (partition)
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Feb 20, 2007
I can't seem to find a way to do the following:create table part_table (col1 int,col2 datetime) on psX (datename(week,col2))I want to partition based on the week number of a date field.So if I enter in data like the following in my part_table:(1, 1/1/2007) should go into partition 1 for week #1(52, 12/21/2007) should go into partition 52 for week #52 of the yearI tried adding in a computed column, but it says its nondeterministic.
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