Password Complexity Problem

Aug 23, 2007

I need to restore a v2000 database to a v2005 database including all users.

How can I disable password complexity so that I can achieve this ???? I'm sure others have run into this prblem.

Thanks in advance,
Nancy

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Need Help With Password Complexity

Sep 5, 2007

I need to restore a v2000 database to a v2005 database including all users. It's a brand new server and database. When I try to copy all of the new accounts, I get this error:

Msg 15118, Level 16, State 1, Line 1

Password validation failed. The password does not meet Windows policy requirements because it is not complex enough.

What do I do with the password complexity? Any ideas?

Regards,

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How To Enforce Password Complexity

Apr 13, 2004

Hi,
We testing our security.
For NT logins user password complexity and expiration enforced by NT


1.Any way to enforce password complexity and expiration for standard sql login ?

2.any way to check if existing sql login passwords less then N number of characters?

Thank you
Alex

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Password Complexity Problem

Aug 23, 2007

I need to restore a v2000 database to a v2005 database including all users.

How can I disable password complexity so that I can achieve this ???? I'm sure others have run into this prblem.

Thanks in advance,
Nancy

View 9 Replies View Related

Function To Test Password Complexity

Feb 11, 2008

My aim is to write a function that returns a bit determining if a varchar(30) argument is "complex enough" to serve as a password. I am open to suggestions of better heuristics, but the rules I was initially planning to use were:

1) Greater than 8 characters long.

2) Contains at least one upper case, lower case, number, and punctuation (loosely defined as anything not in the first three categories).

I can loop over the characters in the PW and use CHARINDEX to test against these three subsets, but I thought there just might be a more clever way to accomplish this.

I also mention the "meta" problem since I am all ears if anyone has a better idea of how to measure complexity.

Cheers,

Lyman Hurd

PS Only a hash gets stored in the DB. This is to be used in the stored proecdure where people set their passwords. Thanks in advance for any thoughts.

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Enforcing Password Complexity In Sql Server 2000

May 23, 2006

Hi all,

Are there any built-ins, utilities, ... within sql server 2000 that can be used to enforce password complexity in the database. i.e at least 8 characteres, upper and lowercase mix, includes at least on number and one punctuation (underscore,...).

I understand that this requirement can be achieved using windows authentication. Unfortunately we do not have that luxury (at the moment).

tx.

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Need To Take A Step Up In Complexity--please Help

Aug 5, 2005

Hi, I've been writing simple database queries for a long time, but I've come to a point where I need to do more work with fewer queries, and I've not been able to make a dent in it. Please excuse my ignorance.

I have a relational database of prices that holds the following info:

Currencies (yen, euro, dollar)
Industries (chemistry, biology, etc)
Company/Institute size (<500, 500-1000, +1000)
Main Products (lab equipment, classroom equipment, etc.)
Series (subproducts) (100ml beaker, chalk, etc)

I want to build a form where my customers can select their currency, their industry and their company size, and then display prices for a specific product (series).

My problem is on the way to the product select. I don't want to display a huge list of EVERYTHING--I want the customer to be able to first select a Main Product, and then populate a list with the relevant sub product for them to select.

However my database is set up with three tables for the individual products: a MainProducts table with main products and ids, a Series table with sub products (we call them series) and ids, and a third table Products that combines the mainproductid with the subproductid to create a unique Productid that is used throughout the rest of the database to get the prices.

(see the relationships here: http://magneticmirror.com/db.gif. The reason for this is that Series in two different MainProducts can have the same name, and so constitute different Products)

The only way I know how to display the name of the relevant series (sub products) is to get the user to:

*select a MainProduct from a list;
*then select all ProductIDs from the the Products table with that MainProductID;
*then for each row from the Products table, take the SeriesID (sub product) and run that against the Series table to get the name of the series corresponding to that ID

if there are 50 series in a product line, that would be 50 individual queries just to populate the list.

There must be a better way. Is this what joining tables is about?

Thanks for any help.

Luud

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DTS Package Complexity

Nov 9, 2006

Hi All,

Can anyone tellme how can we determine a DTS Package's complexity. I want to know the elements that determine the complexity of DTS Package.The very little knowledge I have is number of Connections, number of tasks, Number of Activex Script Tasks. Can anybody please give some more data on this.

Thanks in Advance

Regards,
Ravi Kiran

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Cyclomatic Complexity For Sprocs

May 8, 2015

there's a concept named cyclomatic complexity in software dev which measures the complexity of code by its number of decision points. This would be measured by # of if statements, nested if statements, etc in a method.

Do SQL queries have any type of equivalent? For example, # of joins, # of conditions, etc. Factors into a complexity metric which indicate how complex, risky or error-prone a sproc might be based on certain factors?

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Complexity Of Nested Self Left Joins?

Jul 23, 2005

Hi,I'm curious about the computational complexity of a query I have. Thequery contains multiple nested self left joins, starting with a simpleselect, then doing a self left join with the results, then doing a selfleft join with those results, etc. What puzzles me is that the timerequired for the query seems to grow exponentially as I add additionalleft joins, which I didn't expect. I expected the inner select toreturn about 25 rows (it does), then I expected the self join to resultin about 25 rows (it does), etc. Each join just adds another column; itdoesn't add more rows. So the left part of the join is staying the samesize, and so is the right part of the join, since I'm always joiningwith the same table.So I would think the time for this query should be (time to join 25rows against the source table) * (num joins), but it seems to besomething like (num rows) ^ (num joins). Any ideas? I'm just trying tounderstand the system a little better. (But if you have any ideas aboutimproving the query, I'm always open to those, too.)The execution plan is what you'd expect: an index seek loop-joined withanother index seek, the results of which are merge-joined with anotherindex seek, the results of which are merge-joined with another indexseek, ad nauseum, until a final "compute scalar cost (39%)" and "select(0%)"For the brave and curious, I've pasted the query below.Thanksselect right(x.cp_yyyymm, 2)+'-'+left(x.cp_yyyymm, 4) as [Month],table0.cp_num_loans/1 as [AFCM9704], table1.cp_num_loans/1 as[AFC9104], table2.cp_num_loans/1 as [BFAT01C], table3.cp_num_loans/1 as[BFAT02B], table4.cp_num_loans/1 as [BFAT03D], table5.cp_num_loans/1 as[BFAT03E], table6.cp_num_loans/1 as [BFAT03F], table7.cp_num_loans/1 as[BFAT04A], table8.cp_num_loans/1 as [BFAT04C], table9.cp_num_loans/1 as[BFAT04D], table10.cp_num_loans/1 as [BFAT99C] from (((((((((((selectdistinct cp_yyyymm from cp_deal_history where cp_deal_id in('AFCM9704', 'AFC9104', 'BFAT01C', 'BFAT02B', 'BFAT03D', 'BFAT03E','BFAT03F', 'BFAT04A', 'BFAT04C', 'BFAT04D', 'BFAT99C') and cp_yyyymmbetween 200304 and 200504) as x left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='AFCM9704') astable0 on x.cp_yyyymm=table0.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='AFC9104') as table1on x.cp_yyyymm=table1.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT01C') as table2on x.cp_yyyymm=table2.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT02B') as table3on x.cp_yyyymm=table3.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT03D') as table4on x.cp_yyyymm=table4.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT03E') as table5on x.cp_yyyymm=table5.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT03F') as table6on x.cp_yyyymm=table6.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT04A') as table7on x.cp_yyyymm=table7.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT04C') as table8on x.cp_yyyymm=table8.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT04D') as table9on x.cp_yyyymm=table9.cp_yyyymm) left join (select cp_yyyymm,cp_num_loans from cp_deal_history where cp_deal_id='BFAT99C') astable10 on x.cp_yyyymm=table10.cp_yyyymm order by x.cp_yyyymm

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Using Temporary Tables To Reduce Complexity

Dec 10, 2007

Right now I have some code, part SQL, mostly C#, to generate reports from a few tables.
I have the following tables:
UserGroups
-GroupId
-UserId

Users
-UserId
-Name

ItemLogs
-LogId
-ItemId
-UserId
* there will be multiple log entries for each item

I'm given a list of GroupIds.

I need to retrieve all the users within those groups
for each user I need to retrieve the UserId and the Name, along with the number of total rows in the ItemLogs with that user's UserId, and the number of distinct ItemIds in ItemLogs that belong to that User.

I'm able to easily do this using C# with minimal SQL, but that involves a lot of looping and small queries which is extremely slow.

I'm thinking that I could use some more advance SQL strategies to retrieve what I need a lot faster, but I don't know how.
My thought is to first create a temporary table with the group ids I'm given so I can quickly retrieve all of the users I need.
Once I have the UserIds, getting the Name is simple, but I don't know how to grab the data I need from ItemLogs without looping through for each User.

Any help would be greatly appreciated.

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Complexity Problem With Large Amount Of Records In A Link Table

Feb 1, 2008

A friend reminded me of a problem we tried to solve a few years ago and were unsuccessful.  Below is a copy of the email he sent me.  We would very much appreciate any ideas from the community.  Thanks!Lets start with a simple schema where you have 4
tables:

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Jul 24, 2015

I have connected to Database using my credentials by checking remember password option. After few days I forgot my password. How can I recover the password as SQL remember it. Is there any way to recover my password instead of resetting it.

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SQL Server Agent Job Will Not Retain Package Password (encrypt Sensitive With Password)

Apr 1, 2008

I have a package protected by a password - I am already unhappy that to get it to use the configuration file to change connection strings for the production servers I have had to hardcode the password into the config file - very insecure!
However, the package now deploys correctly to the production server and will run from there OK, but NOT if scheduled as a SQL Server Agent Job. Thus is because however often I edit the command line to include the password after the DECRYPT switch (which it has prompted me for when I click on the command line tab), the Job Step will not retain it.
If I open it up after I have edited it and closed it, the password has disappeared.

I know that if I run dtexec plus the code in the Command Line tab (with the password), the package runs OK.

This is driving me insane!
I have read all the other posts and so I tried replacing the SSIS package step with a CmdExec step and pasting that code into there - then I get an OLEDB error..

The code I use is:
DTEXEC /SQL "ImportRateMonitoringTables" /SERVER servername /DECRYPT password /CONFIGFILE "D:Microsoft SQL ServerSSISDeploymentsRateMonitoringImportTasksDeploymentImportRateMonitoringTables_Production.dtsConfig" /MAXCONCURRENT " -1 " /CHECKPOINTING OFF /REPORTING E

and I get

SSIS Error Code DTS_E_OLEDBERROR. An OLE DB error has occurred. Error code: 0x8000FFFF

although the same code executes perfectly from a command prompt.

Please does anyone have any experience with a similar problem and if so, how did you get round it?

Thank you

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SQL 2005 SP2 - Windows 2003 Ent SP1 - Password Does Not Meet The Password Policy DLL

Jun 18, 2007

I am receiving the following error message when attempting to create a new SQL Authenticated login id.



Password validation failed. The password does not meet the requirements of the password filter DLL. (Microsoft SQL Server, Error: 15119)



I have four servers all running SQL Server 2005 SP2 on Windows 2003 Ent. SP1. Of the four servers, only one received the above error message using the same TSQL below.



CREATE LOGIN TEST_LOGIN WITH PASSWORD = 'pvif9dal' MUST_CHANGE, CHECK_EXPIRATION = ON



All four servers are in the same domain, which if I understand correctly, the password policies are therefore inherited at the OS level by the domain. The password being used is within the password policies of the domain.



Any ideas as to a root cause?

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Jun 30, 2007

I tried to install an ALLDATA database which run with SQL Server 2005 express edition. The data base fails to install becase of the following code that come up which is related to AS password requirement. The error that come up is:



TITLE: Microsoft SQL Server 2005 Setup
------------------------------

The sa password must meet SQL Server password policy requirements. For strong password guidelines, see Authentication Mode, in SQL Server Books Online.

For help, click: http://go.microsoft.com/fwlink?LinkID=20476&ProdName=Microsoft+SQL+Server&ProdVer=9.00.2047.00&EvtSrc=setup.rll&EvtID=28001&EvtType=sqlca%5csqlcax.cpp%40SAPasswordPolicyCheck%40SAPasswordPolicyCheck%40x6d61

------------------------------
BUTTONS:

&Retry
Cancel
------------------------------


I am trying to install this database in a network server operating under Windows Server 2003 R2 with SP2. If anyone knows how to solve this problem, please let me.



Thanks,



Amilcar

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Mar 11, 2008

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Thanks,

Brian

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Jun 2, 2014

I put this together to export the user name /password to a csv file to test my SP to output the user name/password.

DECLARE @user_name varchar(50)
DECLARE @psswrd varchar(10)
SELECT @user_name ,@psswrd
FROM ngweb_bulk_enrollments
EXEC master.dbo.xp_cmdshell 'bcp NGDevl.dbo.ngweb_bulk_enrollments out C: est.csv -Sserver1 -T -t, -r
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This works but I don't get the headers in the file. How can I include the headers?

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Mar 3, 2005

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PHP Code:




 $sql = "SELECT * FROM users WHERE username = "$username" AND user_password = password("$password")"; 






Apparently the password() function is not available when accessing SQL Server via ODBC. Is there an equivalent function I could use isntead so the passwords arent plaintext in the database? I only have 15 people using the system so a blank pwd reset wouldn't be too much trouble.

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Jun 28, 2007

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Microsoft OLE DB Provider for SQL Server error '80004005'
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Oct 25, 2007

Hi All.
 Have a nice day.
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Info=True;User ID=db1;Password=12345;" providerName="System.Data.SqlClient" />  </connectionStrings>
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Thanks.
Zahyea.

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Jul 22, 2002

Hello ,

Is is correct that the 'sa ' passoword is stored in one of the files of the SQL Server and is easily readable if the location of the file is known ?

If not , then is the password encrypted when i try to connect to the SQL server on the Internet ?

Thanks.

Sameer.

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Jul 18, 2000

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Feb 15, 2001

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Apr 2, 2001

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Apr 26, 1999

Recently my husband has taken the position of IS Manager for a major hotel Firm.
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Nov 5, 1998

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Jul 30, 2001

Hi!
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Thank you,
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Sep 14, 2001

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Feb 15, 2001

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Dec 29, 2004

All

I can not change the 'sa' password, it's give me the error attached.

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Dec 29, 2004

I can not change the 'sa' password. It's showing the error below:

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