Password-Decryption

Aug 11, 2000

Hi,
Every one
Can i Encrypt & Decrypt Data store in SQL SERVER table. If field is alredy Encripted, then how I can decrypt in SQL SERVER.

Thanks
Nirmal

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Passing Key Decryption Password To Stored Procedure

Aug 7, 2006

I try to pass the key used to decrypt symmetric key to a stored procedure as a parameter like this:

OPEN SYMMETRIC KEY MyKey
DECRYPTION BY PASSWORD=@ keypassword;

I get an error message saying "Incorrect syntax near "@keypassword".
Is there something that I am missing?

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Dec 28, 2007

I would like to be able to store user network passwords in a database table and be able to encrypt and decrypt using stored procs. Could anyone give me a pointer on this.

Many thanks

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Aug 11, 2001

How to decrypt a Stored Procedure which has been encrypted in SQL Server 7.0

Thanks in Advance

Regards,

Karthik

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Oct 11, 2007

I am using the below function written by PESO to encrypt/Decrypt the data for my SSN Numbers stored as a Clear Text

First I am Encrypting all my SSN's using this function and storing it in the database in a seperate Column,

Some thing like this..

SELECT DBACentral.dbo.fnEncDecRc4( '145678908' , 'ty6578dmp1203' )
OUPPUT
--------
âUÙN_{��

How to Decrypt ( âUÙN_{�� ) using the below function.

CREATE FUNCTION dbo.fnEncDecRc4
(
@Pwd VARCHAR(256),
@Text VARCHAR(8000)
)
RETURNSVARCHAR(8000)
AS

BEGIN
DECLARE@Box TABLE (i TINYINT, v TINYINT)

INSERT@Box
(
i,
v
)
SELECTi,
v
FROMdbo.fnInitRc4(@Pwd)

DECLARE@Index SMALLINT,
@i SMALLINT,
@j SMALLINT,
@t TINYINT,
@k SMALLINT,
@CipherBy TINYINT,
@Cipher VARCHAR(8000)

SELECT@Index = 1,
@i = 0,
@j = 0,
@Cipher = ''

WHILE @Index <= DATALENGTH(@Text)
BEGIN
SELECT@i = (@i + 1) % 256

SELECT@j = (@j + b.v) % 256
FROM@Box b
WHEREb.i = @i

SELECT@t = v
FROM@Box
WHEREi = @i

UPDATEb
SETb.v = (SELECT w.v FROM @Box w WHERE w.i = @j)
FROM@Box b
WHEREb.i = @i

UPDATE@Box
SETv = @t
WHEREi = @j

SELECT@k = v
FROM@Box
WHEREi = @i

SELECT@k = (@k + v) % 256
FROM@Box
WHEREi = @j

SELECT@k = v
FROM@Box
WHEREi = @k

SELECT@CipherBy = ASCII(SUBSTRING(@Text, @Index, 1)) ^ @k,
@Cipher = @Cipher + CHAR(@CipherBy)

SELECT@Index = @Index +1
END

RETURN@Cipher
END

GO

Thanks for any help

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Feb 5, 2008

I have been testing two way symmetrical encryption. I have been able to encrypt rows of a spacific column using the following UPDATE statement, however, when I try and decrypt them, the query returns Null for the effected rows.
Can anyone see where I may have gone wrong in the decryption statement?UPDATE tblReceipts SET tblReceipts.CCNumber = EncryptByPassPhrase('Abracadabra!1234$',tblReceipts.CCNumber)
FROM tblReceipts
WHERE tblReceipts.CreditCardType > 0

Decrypt Does Not Work?????

SELECT CONVERT(varchar, DecryptByPassPhrase('Abracadabra!1234$',tblReceipts.CCNumber)) AS CCNumber
FROM tblReceipts
WHERE tblReceipts.CLIENTID = 15000My CCNumber field is nvarchar(20)My PassPhrase is just a test phraseThe data after it is encrypted in just a bunch of binary looking boxes  

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Apr 3, 2015

How do I tell SQL Server what key to use for DES3 decryption? I want to encrypt in Oracle and after ETL to SQL Server, be able to decrypt but keep a column's value encrypted in Oracle, SSIS and SQL side - only decrypting on the SQL Server side when needing to use the value.

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Oct 16, 2006

What solutions are available?
Is there a way to read about from server's metadata?

Gus

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Dec 12, 2006

This function is used to initialize the seed for the RC4 algorithmCREATE FUNCTION dbo.fnInitRc4
(
@Pwd VARCHAR(256)
)
RETURNS @Box TABLE (i TINYINT, v TINYINT)
AS

BEGIN
DECLARE@Key TABLE (i TINYINT, v TINYINT)

DECLARE@Index SMALLINT,
@PwdLen TINYINT

SELECT@Index = 0,
@PwdLen = LEN(@Pwd)

WHILE @Index <= 255
BEGIN
INSERT@Key
(
i,
v
)
VALUES(
@Index,
ASCII(SUBSTRING(@Pwd, @Index % @PwdLen + 1, 1))
)

INSERT@Box
(
i,
v
)
VALUES(
@Index,
@Index
)

SELECT@Index = @Index + 1
END


DECLARE@t TINYINT,
@b SMALLINT

SELECT@Index = 0,
@b = 0

WHILE @Index <= 255
BEGIN
SELECT@b = (@b + b.v + k.v) % 256
FROM@Box AS b
INNER JOIN@Key AS k ON k.i = b.i
WHEREb.i = @Index

SELECT@t = v
FROM@Box
WHEREi = @Index

UPDATEb1
SETb1.v = (SELECT b2.v FROM @Box b2 WHERE b2.i = @b)
FROM@Box b1
WHEREb1.i = @Index

UPDATE@Box
SETv = @t
WHEREi = @b

SELECT@Index = @Index + 1
END

RETURN
ENDANd this function does the encrypt/decrypt partCREATE FUNCTION dbo.fnEncDecRc4
(
@Pwd VARCHAR(256),
@Text VARCHAR(8000)
)
RETURNSVARCHAR(8000)
AS

BEGIN
DECLARE@Box TABLE (i TINYINT, v TINYINT)

INSERT@Box
(
i,
v
)
SELECTi,
v
FROMdbo.fnInitRc4(@Pwd)

DECLARE@Index SMALLINT,
@i SMALLINT,
@j SMALLINT,
@t TINYINT,
@k SMALLINT,
@CipherBy TINYINT,
@Cipher VARCHAR(8000)

SELECT@Index = 1,
@i = 0,
@j = 0,
@Cipher = ''

WHILE @Index <= DATALENGTH(@Text)
BEGIN
SELECT@i = (@i + 1) % 256

SELECT@j = (@j + b.v) % 256
FROM@Box b
WHEREb.i = @i

SELECT@t = v
FROM@Box
WHEREi = @i

UPDATEb
SETb.v = (SELECT w.v FROM @Box w WHERE w.i = @j)
FROM@Box b
WHEREb.i = @i

UPDATE@Box
SETv = @t
WHEREi = @j

SELECT@k = v
FROM@Box
WHEREi = @i

SELECT@k = (@k + v) % 256
FROM@Box
WHEREi = @j

SELECT@k = v
FROM@Box
WHEREi = @k

SELECT@CipherBy = ASCII(SUBSTRING(@Text, @Index, 1)) ^ @k,
@Cipher = @Cipher + CHAR(@CipherBy)

SELECT@Index = @Index +1
END

RETURN@Cipher
END

Peter Larsson
Helsingborg, Sweden

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Jan 3, 2008

This is related to post :
http://www.sqlteam.com/forums/topic.asp?TOPIC_ID=78552

got a issue with this one..im not sure why..

My results are as follows:

Select dbo.fnEncDecRc4('Orange12345', 'Hello123')
Output : ,Mgl
Select dbo.fnEncDecRc4('Orange12345', ',Mgl')
Output : M

i am not able to decrypt it. Any idea why this is hapenning? Does it has to do something with regional settings?

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May 10, 2006

I wanted to configure Report Server and publish my reports. I configured report server 2005 on win 2003 os. I prepared few reports and deployed them. When I tried to view this report thru ReportServer (http://localhost/ReportServer) from my local machine, I got the following error message:-
The encrypted value for the "UnattendedExecutionAccountPassword" configuration setting cannot be decrypted.

The report server has encountered a configuration error. See the report server log files for more information.
Can anyone help me in solving this!
I will highly appreciate it.

Thanks in advance,

hemal

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Jan 24, 2008



Hi,
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Thanks

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Dec 2, 2007

I'm trying to put together a proof of concept utilizinf encryption with SQL Server and neded to get a little help. I've got the basics down but I'm not seeing the expected results. Here's the script that I'm running against a very simple table. I'm essentially just adding a coulmn to hose encrypted data, encrypting that data, and then selecting that data - in both encrypted and decrypted form:




Code Block
CREATE CERTIFICATE LAND_ENCRYPT_ACCOUNT3
WITH SUBJECT = 'ExternalAccountID';
GO
CREATE SYMMETRIC KEY AccountID3_01
WITH ALGORITHM = AES_128
ENCRYPTION BY CERTIFICATE LAND_ENCRYPT_ACCOUNT3;
GO
USE [LAND_ENCRYPT];
GO
-- Create a column in which to store the encrypted data.
ALTER TABLE Account
ADD EncryptedAccountID3 varbinary(128);
GO
-- Open the symmetric key with which to encrypt the data.
OPEN SYMMETRIC KEY AccountID3_01
DECRYPTION BY CERTIFICATE LAND_ENCRYPT_ACCOUNT3;
-- Encrypt the value in column NationalIDNumber with symmetric
-- key SSN_Key_01. Save the result in column EncryptedNationalIDNumber.
UPDATE Account
SET EncryptedAccountID3 = EncryptByKey(Key_GUID('AccountID3_01'), ExternalAccountID);
GO
-- Verify the encryption.
-- First, open the symmetric key with which to decrypt the data.
OPEN SYMMETRIC KEY AccountID3_01
DECRYPTION BY CERTIFICATE LAND_ENCRYPT_ACCOUNT3;
GO
-- Now list the original ID, the encrypted ID, and the
-- decrypted ciphertext. If the decryption worked, the original
-- and the decrypted ID will match.
SELECT ExternalAccountID, EncryptedAccountID3
AS 'Encrypted ID Number',
CONVERT(nvarchar, DecryptByKey(EncryptedAccountID3))
AS 'Decrypted ID Number'
FROM Account;
GO


But when I run the "decrypt" the data, the only character that appears unencrypted is the very last character of each account number:




ExternalAccountID Encrypted ID Number Decrypted ID Number

-------------------------------------------------- ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ ------------------------------

12345654444 0x007B9CA28582AC42B36EBD8DFF91434701000000E267255EC20E27E5B4AC03E68C508ADCFA2EB815C234116D54FEE639685D7ECF49BB200140952E45A246AFE83BF53444 ㈱�㘵��4

12312312312 0x007B9CA28582AC42B36EBD8DFF91434701000000DB3838A7C459A2F031B1FFECF2499647C7DE10B7A20171EFDEA68320F7996CCC1C6A45011E93361F9A93494F49311CB9 ㈱ㄳ㌲㈱ㄳ2

12345678901 0x007B9CA28582AC42B36EBD8DFF9143470100000057EEEC0B1E223819EBF8186F0CBFEF8FDF4BFF4C0DCE322FAB8735DC8EA144B5937FFCC745A7FC427282C493DFECD901 ㈱�㘵㠷〹1



The first value is the unencrypted account id, the second is the encrypted account id, the last is the decrypted account id. As you can see, the decrypted value isn't quite right.

I've tried the AES_256, DES, and AES_128 algorithms and they all yield the same result.

Am I missing something?

Also, if I'm going to be inserting into an encrypted column, do I need to do it via a view and a trigger, or can I just do a straight forward INSERT / UPDATE?

Thanks!!!!!

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Oct 30, 2006

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We got the code working for the seond case but for the first, WHEN:

CREATE SYMMETRIC KEY sym_Key WITH ALGORITHM =
AES_256 ENCRYPTION BY ASYMMETRIC KEY asym_Key
GO

THEN:

-- Msg 15314, Level 16, State 1, Line 1
-- Either no algorithm has been specified or the bitlength and the algorithm specified for the key are not available in this installation of Windows.

What can be the way out to be able to create the AES 256 Symmetric key.

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Apr 21, 2007

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if we uses master key the sysadmin can decrypt



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Jun 15, 2007

Hi

I get a strange error on my SQL Server 2005 database when I try to start replication.

Here is the manipulation leading to my problem:
1. Install new Windows server 2003 and SQL Server 2005 STD, service pack 2.
Server is part of a domain.
SQL2k5 is running under the LocalSystem account on each machine.
2. Get a copy of yesterday's full backup and transaction logs from running production SQL2k5 server.
3. Restore master, model, msdb and other user databases.
4. Try to start replication using the wizard.
I get the following error message

Msg 15466 sp_addlinkedsrvlogin
An error occurred during decryption.
Msg 15185 no remote user distributor_admin


I suspect this problem has to do with master service keys but need some advice. I am not sure it is related to the master restore since it also occurs on the production machine.


What should I do with this error message ?



TIA



Stephane

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Jan 17, 2008

Subject:RijndaelManaged decryption from SQL Server

Issue: I am trying to move the decryption code from C# to SQL Server 2005.


Web.config
...

<symmetricCryptoProviders>


<add algorithmType="System.Security.Cryptography.RijndaelManaged, mscorlib, Version=2.0.0.0, Culture=neutral, PublicKeyToken=xxxxxx" protectedKeyFilename="C:Keysfffff.key" protectedKeyProtectionScope="LocalMachine" type="Microsoft.Practices.EnterpriseLibrary.Security.Cryptography.SymmetricAlgorithmProvider, Microsoft.Practices.EnterpriseLibrary.Security.Cryptography, Version=2.0.0.0, Culture=neutral, PublicKeyToken=null" name="RijndaelManaged"/>

</symmetricCryptoProviders>
...

.cs file
....

decString = Cryptographer.DecryptSymmetric("RijndaelManaged", encString);
....

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Feb 19, 2008

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Oct 30, 2007



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i have get back the original source code

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Apr 1, 2008

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This is driving me insane!
I have read all the other posts and so I tried replacing the SSIS package step with a CmdExec step and pasting that code into there - then I get an OLEDB error..

The code I use is:
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and I get

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Please does anyone have any experience with a similar problem and if so, how did you get round it?

Thank you

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declare @thePassword as varbinary(128)

,@inTargetPassword as varchar(255)

,@pwd3 as varchar(255)

,@theUserId bigint

set @theUserId= 124564

set @inTargetPassword = 'test'

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DECRYPTION BY CERTIFICATE sqlSecurity;

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TITLE: Microsoft SQL Server 2005 Setup
------------------------------

The sa password must meet SQL Server password policy requirements. For strong password guidelines, see Authentication Mode, in SQL Server Books Online.

For help, click: http://go.microsoft.com/fwlink?LinkID=20476&ProdName=Microsoft+SQL+Server&ProdVer=9.00.2047.00&EvtSrc=setup.rll&EvtID=28001&EvtType=sqlca%5csqlcax.cpp%40SAPasswordPolicyCheck%40SAPasswordPolicyCheck%40x6d61

------------------------------
BUTTONS:

&Retry
Cancel
------------------------------


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Amilcar

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best way to encrypt and decrypt using user defined functions.Below is the query which is taking long time.

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