Problem Function Year In Sql Mobile

Aug 29, 2007

Dear , all

I have a problem in fucntion year in sql mobile , Use select Date_in from Test Where Year(Date_in) = 8


Brg
Tingnong

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360-Day Calendar Year Function...

Jun 23, 2008

I'm looking for a function that will return an INTEGER that computes the number of days between two dates based on a 360-calendar year instead of using just the datediff function which is actual days.

If anybody knows where I could find something like this, I would be greatly appreciated.

Does this site have a library of user-defined sql functions? Or, does somebody have a site that you know of where there are a bunch?

Thanks,

South Side Rob

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Group By With Year Function

Jun 19, 2014

select empid,orderdate from [Sales].[Orders] WHERE custid = 71
group by empid,orderdate

sample data resultset:

empid orderdate
1 2006-12-25
1 2007-12-24
1 2007-12-23
1 2008-12-23
1 2008-04-24

select empid,year(orderdate) from [Sales].[Orders] WHERE custid = 71
group by empid,year(orderdate)

sample data resultset:

empid orderdate
1 2006
1 2007
1 2008

why is the year() gets only one year when worked with groupby. when empid =1 the year 2007 has 2 records and 2008 has 2 records in first select and when I used year(orderdate) in secong select only one year for each is selected.

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ISO Week Of Year Function

Jan 18, 2006

This function returns the ISO 8601 week of the year for the date passed. The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.

This code creates the function and demos it for the first day of each ISO week/year from 1990 to 2030.



drop function dbo.F_ISO_WEEK_OF_YEAR
go
create function dbo.F_ISO_WEEK_OF_YEAR
(
@Datedatetime
)
returnsint
as
/*
Function F_ISO_WEEK_OF_YEAR returns the
ISO 8601 week of the year for the date passed.
*/
begin

declare @WeekOfYearint

select
-- Compute week of year as (days since start of year/7)+1
-- Division by 7 gives whole weeks since start of year.
-- Adding 1 starts week number at 1, instead of zero.
@WeekOfYear =
(datediff(dd,
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end,@date)/7)+1
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aa
) a

return @WeekOfYear

end
go





-- Execute function on first day of first week of year from 1990 to 2030
select
DT,
ISO_WEEK_OF_YEAR =
dbo.F_ISO_WEEK_OF_YEAR(a.DT)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a








CODO ERGO SUM

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Feb 16, 2006

I have been spoiled by some report writing tools that have intrinsicfunctions like Last Year Month-to-date. I'm looking for a way to emulatethis in SQL Server now with my fields that are date/time.I'm thinking I need to develop a user defined function to accept a dateinput parameter, but I don't know where to start.Help/Examples appreciated.Thanks,Frank*** Sent via Developersdex http://www.developersdex.com ***

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Nov 17, 2005

I have a user defined function in datebase SQL 2000. function looks like
create function Getcurrentdate(@month int, @day int) returns smalldatetimebegin
declare date1 as smalldatetime--get current year --convert month, day and year into current date. then return
return date1end
my problem was , after using getDate(). I get error meassage which is "can'not use getDate() inside user function"How can I get current year in the user defined function. Thanks

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Jan 2, 2008

Hi ,
Year function in derived column gives error if the incoming date is less than 1/1/1753. Is this Issue or required behaviour

Thanks
Dharmbir

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May 27, 2015

UPDATE Report

SET MSYear= casewhen MSDate > '2011/06/30' and MSDate < '2012/07/01' THEN '2012'
when MSDate > '2012/06/30' and MSDate < '2013/07/01' THEN '2013'
when MSDate > '2013/06/30' and MSDate < '2014/07/01' THEN '2014'
when MSDate > '2014/06/30' and MSDate < '2015/07/01' THEN '2015'
when MSDate > '2015/06/30' and MSDate < '2016/07/01' THEN '2016'
when MSDate > '2016/06/30' and MSDate < '2017/07/01' THEN '2017'
End

Actually our business year starts from 1st july and for this code I need function which is dynamically updates the every year for example 2014-07-01 to 2015-06-30 this is called as a 2015 year like this I need function which will dynamically update a year.

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May 21, 2008

 hay all, i'm trying to pass parameters to a stored procedure ..and i keep getting this error "Procedure or function 'selectFromView' expects parameter '@Year', which was not supplied." this is the procedure implementation : ALTER PROCEDURE dbo.selectFromView

@Year as varchar(10),
@Country as varchar(10),
@Family as varchar(10),
@Manu as varchar(10),
@Status as varchar(10),
@Type as varchar(10),
@Operator as varchar(10)


AS
SELECT * FROM ViewofAll
WHERE
ProductionYear = @Year and
CountryName = @Country and
Family = @Family and
Manufacturer = @Manu and
Status = @Status and
Type = @Type and
OperatorName = @Operator

RETURN and below how i call the procedure :   Dim connection As SqlConnection
connection = New SqlConnection()
connection.ConnectionString = "Data Source=BLACKIRIS3SQLEXPRESS;Initial Catalog=Aircrafts;Integrated Security=True"
connection.Open()
Dim command As SqlCommand
command = New SqlCommand("selectFromView", connection)
command.CommandType = CommandType.StoredProcedure
command.Parameters.Add(New SqlParameter("@Year", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input
command.Parameters.Add(New SqlParameter("@Country", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input
command.Parameters.Add(New SqlParameter("@Family", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input
command.Parameters.Add(New SqlParameter("@Manu", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input 'Stored prcedure parameters
command.Parameters.Add(New SqlParameter("@Status", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input
command.Parameters.Add(New SqlParameter("@Type", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input
command.Parameters.Add(New SqlParameter("@Operator", System.Data.SqlDbType.VarChar, 100)).Direction = ParameterDirection.Input
command.Parameters.Item("@Year").Value = myArray(0)
command.Parameters.Item("@Country").Value = myArray(1)
command.Parameters.Item("@Family").Value = myArray(2)
command.Parameters.Item("@Manu").Value = myArray(3)
command.Parameters.Item("@Status").Value = myArray(4)
command.Parameters.Item("@Type").Value = myArray(5)
command.Parameters.Item("@Operator").Value = myArray(5)
DSGrid.SelectCommand = command.CommandText With DSGrid
.DataBind()
End With  i'm not really familiar with stored procedures ...any one can help me plz ?  thanx in advance .  

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Apr 28, 2015

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Operand type clash: date is incompatible with int

Why is this error being returned?

Here is my function:

CREATE FUNCTION dbo.zEOM_LY_D(@Input Date)
       RETURNS date
AS
BEGIN;
  DECLARE @Result date;
  SET @Result =  convert(DATE, DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,dateadd(m, -11, @Input)+1),0)),101)
    RETURN @Result;
END;

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Sep 18, 2013

I have the following script that calculates Sales by month and current year.

We run a Fiscal year from April 1st thru March 31st.

So April 2012 sales are considered Fiscal Year 2013.

Is there a way I can alter this script to get Fiscal Year Totals?

select ClassificationId, YEAR(inv_dt) as Year, cus_no,
isnull(sum(case when month(inv_dt) = 4 then salesamt end),0) as 'Apr',
isnull(sum(case when month(inv_dt) = 5 then salesamt end),0) as 'May',
isnull(sum(case when month(inv_dt) = 6 then salesamt end),0) as 'Jun',
isnull(sum(case when month(inv_dt) = 7 then salesamt end),0) as 'Jul',

[Code] ....

Data returned looks like the following.

ClassificationID Year Cus_no Apr May June ....
100 2012 100 $23 $30 $400
100 2013 100 $40 $45 $600

What I would need is anything greater than or equal to April to show in the next years row.

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Mar 27, 2015

I'm trying to generate a report using matrix like this

                                                      Month
Product     PreviousYearSalesAmount    SelectedYearSalesAmount      %SalesDifference

I can populate year sales amount, but i cant calculate the percentage.

Note: Month and Year are passed as parameters.

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Aug 30, 2004

I have three web form controls, a ddl that contains the day, another ddl that contains the month and a textbox that contains the current year. To send the date chosen by the user to the database, I join the three web form control values so that the resultant string is ‘day/month/year’ thus:

CmdInsert.Parameters("@Date").Value = day.SelectedItem.Value + "/" + month.SelectedItem.Value + "/" + year.Text()

And the resultant string is: dd/mm/yyyy, for example 30/08/2004.
But the problem is if the user does not select any day or any day and month, then the resultant string is for example; 00/08/2004 or 00/00/2004, but the problem is the database does not accept this format as datetime. How can I do it?

I want the user has the possibility to chose as well only the month and year, and as well only the year. Is it possible to send to the database the datetime format with only the month and year, or only the year?

Thank you,
Cesar

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SELECT SUM([Sales (LCY)])
FROM [$Cust_ Ledger Entry] cle
LEFT OUTER JOIN dw.dim.FiscalDate fd
ON fd.CalendarDate = cle.[Posting Date]
WHERE [Customer No_] = '10135'
AND fd.CalendarYear = '2013'

[Code] ....

I would like to learn how to be able to make this a single query and end up with two columns and their summed up totals. Like it shows on the attached image.

This is my query without the columns I need:

SELECT
c.CustomerNumber
,c.Name
,c.ChainName
,c.PaymentTermsCode
,cle.CreditLimit AS 'CreditLimit'
,SUM(cle.Amount) AS 'Amount'

[Code] ....

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Feb 25, 2004

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The problem is that the episode date is stored in three integer fields (epiday, epimonth, epiyear) and I'm having a terrible time getting them into a format where I can use them in a between statement.

I've tried evaluating the parts of the episode date seperately like:


where
(epimonth>=10 and epiyear=2003)
or
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and that works, but what happens when someone wants to see from 10/2002 to 2/2004?

Any suggestions on the best way to do this?

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May 5, 2014

We have customers who are new to this year (2014) and there same customers in last year (2013). also there are customers we have not received business this year but only last year. so there are 4 conditions.

1) New customer (2014) - Customer(B)
2) Old Regular customer (2013 and 2014) - Customer(A)
3) Last Year (Lost) customer (2013) - Customer(C), no business received in year(2014)

For example we have a transaction table:

TransactionId, ReceivedDate, Customer
1, 2-Dec-2013, A
2, 3-Jan-2014, A
3, 2-Mar-2014, B
4, 25-Nov-2013, C

I want results like

Customer, Business (this year activity/last year activity)
A, 1/1
B, 1/0
C, 0/1

How can i show this for each year? I used to separate it month wise as below but it does not return applying year with each customer anyhow...

select t.customerId, YEAR(Receiveddate),
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sum(case month(ReceivedDate) when 2 then 1 else 0 end )as Feb,
sum(case month(ReceivedDate) when 3 then 1 else 0 end )as Mar,
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[Code] ....

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Mar 15, 2006

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Jul 14, 2015

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--------------------
1 | 1/1/2014
2 | 2/8/2014
3 | 10/1/2014
4 | 2/5/2014
5 | 4/1/2014
6 | 9/1/2014

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------------------------
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2/8/2014 | 2014 | 2
10/1/2014 | 2014 | 3
2/5/2015 | 2015 | 1
4/1/2015 | 2015 | 2
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or

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Dec 14, 2006

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Jan Feb Mar Apr May Jun Jul Aug Sep Oct Dec

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Oct 20, 2007

Guys,

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2005 100 10%
2006 200 20%
2007 300 30%

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Aug 8, 2006



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repl.AddSubscription(AddOption.CreateDatabase);
repl.Synchronize();

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Mar 23, 2006

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ISO Year Week Day Of Week Function

Jan 18, 2006

Function F_ISO_YEAR_WEEK_DAY_OF_WEEK returns the ISO 8601 Year Week Day of Week in format YYYY-W01-D for the date passed. W01 represents the week of the year from W01 through W53, and D represents the day of the week with 1 = Monday through 7 = Sunday.

The first week of each year starts on the first Monday on or before January 4 of that year, so that the year begins from December 28 of the prior year through January 4 of the current year.

This code creates the function and demos it for the first day, first date+60, and first date+364 for each ISO week/year from 1990 to 2030.


drop function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
GO
create function dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK
(
@Datedatetime
)
returnsvarchar(10)
as
/*
Function F_ISO_YEAR_WEEK_DAY_OF_WEEK
returns the ISO 8601 Year Week Day of Week
in format YYYY-W01-D for the date passed.
*/
begin

declare @YearWeekDayOfWeekvarchar(10)

Select
--Format to form YYYY-W01-D
@YearWeekDayOfWeek =
convert(varchar(4),year(dateadd(dd,7,a.YearStart)))+'-W'+
right('00'+convert(varchar(2),(datediff(dd,a.YearStart,@Date)/7)+1),2) +
'-'+convert(varchar(1),(datediff(dd,a.YearStart,@Date)%7)+1)
from
(
select
YearStart =
-- Case finds start of year
case
whenNextYrStart <= @date
thenNextYrStart
whenCurrYrStart <= @date
thenCurrYrStart
elsePriorYrStart
end
from
(
select
-- First day of first week of prior year
PriorYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,-1,aaa.Jan4))/7)*7,-53690),
-- First day of first week of current year
CurrYrStart =
dateadd(dd,(datediff(dd,-53690,aaa.Jan4)/7)*7,-53690),
-- First day of first week of next year
NextYrStart =
dateadd(dd,(datediff(dd,-53690,dateadd(yy,1,aaa.Jan4))/7)*7,-53690)
from
(
select
--Find Jan 4 for the year of the input date
Jan4=
dateadd(dd,3,dateadd(yy,datediff(yy,0,@date),0))
) aaa
) aa
) a

return @YearWeekDayOfWeek

end
go


-- Execute function on first day, first day+60,
-- and first day+364 for years from 1990 to 2030.

select
DT= convert(varchar(10),DT,121),
YR_START_DT =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT),
YR_START_DT_60 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+60),
YR_START_DT_365 =
dbo.F_ISO_YEAR_WEEK_DAY_OF_WEEK(a.DT+364)
from
(
select DT = getdate()union all
select DT = convert(datetime,'1990/01/01') union all
select DT = convert(datetime,'1990/12/31') union all
select DT = convert(datetime,'1991/12/30') union all
select DT = convert(datetime,'1993/01/04') union all
select DT = convert(datetime,'1994/01/03') union all
select DT = convert(datetime,'1995/01/02') union all
select DT = convert(datetime,'1996/01/01') union all
select DT = convert(datetime,'1996/12/30') union all
select DT = convert(datetime,'1997/12/29') union all
select DT = convert(datetime,'1999/01/04') union all
select DT = convert(datetime,'2000/01/03') union all
select DT = convert(datetime,'2001/01/01') union all
select DT = convert(datetime,'2001/12/31') union all
select DT = convert(datetime,'2002/12/30') union all
select DT = convert(datetime,'2003/12/29') union all
select DT = convert(datetime,'2005/01/03') union all
select DT = convert(datetime,'2006/01/02') union all
select DT = convert(datetime,'2007/01/01') union all
select DT = convert(datetime,'2007/12/31') union all
select DT = convert(datetime,'2008/12/29') union all
select DT = convert(datetime,'2010/01/04') union all
select DT = convert(datetime,'2011/01/03') union all
select DT = convert(datetime,'2012/01/02') union all
select DT = convert(datetime,'2012/12/31') union all
select DT = convert(datetime,'2013/12/30') union all
select DT = convert(datetime,'2014/12/29') union all
select DT = convert(datetime,'2016/01/04') union all
select DT = convert(datetime,'2017/01/02') union all
select DT = convert(datetime,'2018/01/01') union all
select DT = convert(datetime,'2018/12/31') union all
select DT = convert(datetime,'2019/12/30') union all
select DT = convert(datetime,'2021/01/04') union all
select DT = convert(datetime,'2022/01/03') union all
select DT = convert(datetime,'2023/01/02') union all
select DT = convert(datetime,'2024/01/01') union all
select DT = convert(datetime,'2024/12/30') union all
select DT = convert(datetime,'2025/12/29') union all
select DT = convert(datetime,'2027/01/04') union all
select DT = convert(datetime,'2028/01/03') union all
select DT = convert(datetime,'2029/01/01') union all
select DT = convert(datetime,'2029/12/31') union all
select DT = convert(datetime,'2030/12/30')
) a


Function Test Results:

DT YR_START_DT YR_START_DT_60 YR_START_DT_364
---------- ----------- -------------- ---------------
2006-01-18 2006-W03-3 2006-W11-7 2007-W03-3
1990-01-01 1990-W01-1 1990-W09-5 1991-W01-1
1990-12-31 1991-W01-1 1991-W09-5 1992-W01-1
1991-12-30 1992-W01-1 1992-W09-5 1992-W53-1
1993-01-04 1993-W01-1 1993-W09-5 1994-W01-1
1994-01-03 1994-W01-1 1994-W09-5 1995-W01-1
1995-01-02 1995-W01-1 1995-W09-5 1996-W01-1
1996-01-01 1996-W01-1 1996-W09-5 1997-W01-1
1996-12-30 1997-W01-1 1997-W09-5 1998-W01-1
1997-12-29 1998-W01-1 1998-W09-5 1998-W53-1
1999-01-04 1999-W01-1 1999-W09-5 2000-W01-1
2000-01-03 2000-W01-1 2000-W09-5 2001-W01-1
2001-01-01 2001-W01-1 2001-W09-5 2002-W01-1
2001-12-31 2002-W01-1 2002-W09-5 2003-W01-1
2002-12-30 2003-W01-1 2003-W09-5 2004-W01-1
2003-12-29 2004-W01-1 2004-W09-5 2004-W53-1
2005-01-03 2005-W01-1 2005-W09-5 2006-W01-1
2006-01-02 2006-W01-1 2006-W09-5 2007-W01-1
2007-01-01 2007-W01-1 2007-W09-5 2008-W01-1
2007-12-31 2008-W01-1 2008-W09-5 2009-W01-1
2008-12-29 2009-W01-1 2009-W09-5 2009-W53-1
2010-01-04 2010-W01-1 2010-W09-5 2011-W01-1
2011-01-03 2011-W01-1 2011-W09-5 2012-W01-1
2012-01-02 2012-W01-1 2012-W09-5 2013-W01-1
2012-12-31 2013-W01-1 2013-W09-5 2014-W01-1
2013-12-30 2014-W01-1 2014-W09-5 2015-W01-1
2014-12-29 2015-W01-1 2015-W09-5 2015-W53-1
2016-01-04 2016-W01-1 2016-W09-5 2017-W01-1
2017-01-02 2017-W01-1 2017-W09-5 2018-W01-1
2018-01-01 2018-W01-1 2018-W09-5 2019-W01-1
2018-12-31 2019-W01-1 2019-W09-5 2020-W01-1
2019-12-30 2020-W01-1 2020-W09-5 2020-W53-1
2021-01-04 2021-W01-1 2021-W09-5 2022-W01-1
2022-01-03 2022-W01-1 2022-W09-5 2023-W01-1
2023-01-02 2023-W01-1 2023-W09-5 2024-W01-1
2024-01-01 2024-W01-1 2024-W09-5 2025-W01-1
2024-12-30 2025-W01-1 2025-W09-5 2026-W01-1
2025-12-29 2026-W01-1 2026-W09-5 2026-W53-1
2027-01-04 2027-W01-1 2027-W09-5 2028-W01-1
2028-01-03 2028-W01-1 2028-W09-5 2029-W01-1
2029-01-01 2029-W01-1 2029-W09-5 2030-W01-1
2029-12-31 2030-W01-1 2030-W09-5 2031-W01-1
2030-12-30 2031-W01-1 2031-W09-5 2032-W01-1

(43 row(s) affected)




CODO ERGO SUM

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Using MS VS 2005 (incl SQL Server Mobile)
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