Query 8 Days Ago Based On System Date

Jan 16, 2008



Hi,

I'm trying to query an SQL table column with date values to show 8 Days ago results.

I've started with this query:

SELECT ficheiro, erro, descritivo_erro, contrato, DO, movimento, data, descritivo, tipo_movimento, desconto, montante, comissao, IVA
FROM status_day
WHERE (YEAR(data) = YEAR(GETDATE())) AND (MONTH(data) = MONTH(GETDATE())) AND (DAY(data) = DAY(GETDATE()) -8)
ORDER BY descritivo_erro, contrato

The problem is that the text in red will have some problems when the month changes - If I want the 8 days ago results from January and the system date is 1st of February the query will not return any values.

I read something about DATESERIAL but is wasn't conclusive on how to use it with system date.

Please help me out with this query.

View 6 Replies


ADVERTISEMENT

SQL Server 2012 :: Calculate Number Of Days Based On Computer System Date And Due Date Row

Mar 18, 2014

I have a query to run a report where the results has a column named “Due Date” which holds a date value based on the project submission date.Now, I need to add 4 columns named, “45 Days Expectant”, “30 Days Overdue”, “60 Days Overdue” and “90 Days Overdue”.I need to do a calculation based on the “Due Date” and “System (I mean default computer date) Date” that if “System Date” is 45 days+ to “Due Date” than put “Yes” in “45 Days Expectant” row.

Also, if “Due Date” is less than or equal to system date by 30 days, put “Yes” in “30 Days Overdue” and same for the 60 and 90 days.how to write this Case Statement? I have some answers how to do it in SSRS (Report Designer) but I want to get the results using T-SQl.

View 2 Replies View Related

Calculating Date Based On Business Days

Jul 21, 2001

Does anyone know of a way to calculate the date 'x' number of business days after another date?

View 2 Replies View Related

Case Statement - Calculate No Of Days Based On User Input Start And End Date

Jan 5, 2015

I have to produce a report to calculate no of days based on user input start date and end date. I have tried to explain below.

say for eg: in the tables I have emp name
user 'Phani' started work from - EStart 20/11/2014EEnd 10/01/2015 - total days --datediff
within his work period he did different roles:

PhaniMarketing (prSt Date) 20/11/2014prE date (28/11/2014) Total 9 days
PhaniAdmin (prSt Date) 29/11/2014prE date (20/12/2014) Total 22 days
PhaniCRM (prSt Date) 20/12/2014prE date (10/01/2015) Total 22 days
Total days 53 Days

For this :

I calculated datediff + 1 and got sub jobs days BUT

say financial director wants to see Title of 'Sub Jobs' with 'Days' from 1st Dec to 31st Dec

so on paper I calulated as :

1-31 Dec 2014
PhaniMarketing NULL (Do not fall in Req Dt)
PhaniAdmin 20 (Deduct 2 days of Nov & calculated 20 days of Dec)
PhaniCRM 11 (Deduct 20 days of Nov and deduct 11 days of Jan so for Dec , we got 11 days)
Total days 31

HOW CAN I USE Case statement to calculate days for given start date and end date. I have to include all three totals, 1 for Job dates, 2, subjobs dates, 3 cal of days for a requested period.

View 4 Replies View Related

T-SQL (SS2K8) :: Generate Working Schedule For Employees For X-days Ahead Based On Starting Date

May 6, 2014

I would like to generate a working schedule for employees for x-days ahead based on a starting date that the user can enter.

I have got 3 relevant tables:

1. Table X with (1) resourcenumber, (2) starting date working schedule and (3) the daynumber representing the starting date (this is ISO so 1 for Monday, 2 for Tuesday etc.)

2. Table Y has the schedule itself and can hold a 7-days schedule or a 14-days schedule. In case of 7 days schedule there a 14 (!) records with (1) resourcenumber, (2) daynumber, (3) starting hour a.m. (4) ending hour a.m (5) starting hour p.m and (6) ending hour p.m. In case of a 14-days schedule there are 28 records (a.m. and p.m. records)

3. Table Z with resource data.

An example to clarify (for fake employee 100):

Table X:
Resource: 100
Starting date: 2012-03-01 (from this date the schedule will be effective)
Daynumber: 4 (2012-03-01 was a Thursday)

Table Y (Resource has a 14 days schedule because per 2 weeks Monday is an off-day):

Record 1 shows: Resource: 100, Daynumber: 1 (= Monday, working day), AM-Starting hour: 09:00, AM-Ending hour: 13:00, PM-starting hour: 13:30, PM-ending hour: 17:30
Record 2: same but daynumber is 2
Record 3: same but daynumber is 3 etc.
...
Record 8 shows: Resource: 100, Daynumber: 8 (= Monday, off-day), AM-Starting hour: 00:00, AM-Ending hour: 00:00, PM-starting hour: 00:00, PM-ending hour: 00:00
Record 9: same as record 2 but daynumber is 9.
etc.
...
Record 14: same as record 7 but day is 14 (= last day)

The weekend days show as 00:00 for the hours (same as day 8 in example)

I generated the working schedule with a CROSS APPLY function based on the starting date and the x-number of days ahead.

I then evaluate the actual daynumber corresponding with that date with the daynumber in table Y. That works fine with a 7-days schedule but I can't get it fixed with a 14-days schedule. Day 8 in that schedule represents an actual day 1 but how do I know what actual date day 8 is ... I think I have to start with the starting date in table X ...

I think ideally I would like to have the generated days as follows (as an example in case of a 14-days schedule starting 2014-05-01 for 30 days ahead):

2014-05-01 = day 4 (= actual daynumber)
2014-05-02 = day 5
2014-05-03 = day 6
...
2014-05-10 = day 13
2014-05-11 = day 14
2014-05-12 = day 1
2014-05-13 = day 2
2014-05-14 = day 3
...
2014-05-24 = day 13
2014-05-25 = day 14
2014-05-26 = day 1
2014-05-27 = day 2
...
2014-05-31 = day 6

With this done I can compare the actual daynumber with the daynumber in Table Y.

The rownumber that the CROSS APPLY function generates has to be reset to 1 after day 14. I tried PARTITION BY in THE ROW_NUMBER function but to no avail ... The only field I can partition by is the maximum value of the daynumber (14 is the example) but that is not allowed in the rownumber function.

View 0 Replies View Related

SQL 2012 :: Produce Report To Calculate No Of Days Based On User Input Start And End Date

Jan 5, 2015

I have to produce a report to calculate no of days based on user input start date and end date.

say for eg: in the tables I have emp name
user 'Phani' started work from - EStart 20/11/2014EEnd 10/01/2015 - total days --datediff
within his work period he did different roles:

PhaniMarketing (prSt Date) 20/11/2014prE date (28/11/2014) Total 9 days
PhaniAdmin (prSt Date) 29/11/2014prE date (20/12/2014) Total 22 days
PhaniCRM (prSt Date) 20/12/2014prE date (10/01/2015) Total 22 days
Total days 53 Days
for this :

[code]...

HOW CAN I USE Case statement to calculate days for given start date and end date. I have to include all three totals, 1 for Job dates, 2, subjobs dates, 3 cal of days for a requested period.

View 0 Replies View Related

Query Tables Where Date Between Now And 7 Days Ago

Jun 18, 2008

Hi Guys,

I currently have a large database, and I wish to query it.
It is running MSSQl 2000.

I wish to have a query that when ran, returns results between NOW() and 7 days ago (A weekly report from the current date).

The date/time field I am sorting by is stored as YY-MM-DD 00:00:00

Any help is appreciated :)

View 9 Replies View Related

How To Subtract Days From Date Variable In Sql Query?

Mar 12, 2007

Hi,
I've searched quite a bit for help with this syntax but have given up.
I need help with the where clause of a query using SQL SERVER that selects records a certain number of days before the current date.  I have tried this and it's incorrect syntax:
WHERE   (fldDate < ({ fn NOW() - 500 })
Can someone please help me out with correct syntax for this?  thanks much.
 

View 3 Replies View Related

Date Query Problem Last 8 Days, Different Year From Current

Feb 19, 2008

Hi,

I'm having problems creating a query that brings the results based on last 8 days on date column (column9) and diferrent year from the current one.

If I run the each filter,




Code SnippetYear(Column9) <> Year(GetDate())




and




Code Snippet
(Column9 >= DATEADD(Day, DATEDIFF(Day, 0, GETDATE() - 8), 0)) AND (Column9 < DATEADD(Day, DATEDIFF(Day, 0, GETDATE() - 7), 0))



it returns the right values.

So far I've got (it returns no results):




Code Snippet
SELECT Column1, Column2, Column3, Column4, Column5, Column6, Column7, Column8, Column9, Column10, Column11, Column12, Column13, Column14,
Column15, Column16, Column17, Column18, Column19, Column20, Column21, Column22, Column23, Column24, Column25, Column26, Column27,
Column28, Column29, Column30, Column31, Column32, Column33, Column34, Column35, Column36, Column37, Column38, Column39, Column40,
Column41, Column42, Column43, Column44, Column45, Column46, Column47, Column48, Column49, data_anulacao, data_instalacao
FROM Contratos01
WHERE Year(Column9) <> Year(GetDate()) AND (Column9 >= DATEADD(Day, DATEDIFF(Day, 0, GETDATE() - 8), 0)) AND (Column9 < DATEADD(Day, DATEDIFF(Day, 0, GETDATE() - 7), 0))
ORDER BY Column1


Please give me your input.

THX.

View 10 Replies View Related

T-SQL (SS2K8) :: Query To Find Older Date That Is Less Than 90 Business Days

Feb 12, 2015

select DateAdd(dd,-90,getdate())

It gives the 90 days older date but i want to exclude the weekdays and holidays (saturday ,sunday,holiday)

As we dont have permission to call a function or Sp in high level environments looking for a simple query .

View 1 Replies View Related

Date Query (pulling System Date)

Nov 1, 2013

I'm currently using the SQL to find records older than todays date in the SSD_SED field. I'm having to update the date manually each day. Is there a way I can automate this?

AND (SSD_SED < '2013-11-01')order by SSD_SED DESC

View 3 Replies View Related

Query That Get Sets Of 3 Rows Based On Given Date?

Aug 16, 2014

I need to get 3 rows per set based on a date given (must be this date) but I want the rows to be based on this date as...

1 ( row where the date from the date column is the next date after given date )

0 ( row where the date is the closest date prior to the date given )

-1 ( prior to the date at 0 )

And add a column with the relative number.

** The dates for the same name and item will never repeat.

For example, a set of rows...

Row ID, Name, Item, Number, Date
1 Andy, Item1, 12030, 2014-06-30
2 Andy, Item1, 62030, 2014-03-31
3 Andy, Item1, 30300, 2013-12-31
4 Andy, Item1, 40030, 2013-10-31
5 Andy, Item1, 50030, 2013-08-30
6 John, Item2, 50240, 2014-04-30
7 John, Item2, 41400, 2014-03-31
8 John, Item2, 40509, 2014-01-31
9 Andy, Item2, 24004, 2014-03-31
10 Andy, Item2, 20144, 2013-12-31
11 Andy, Item2, 20450, 2013-09-30
12 Andy, Item2, 25515, 2013-06-30

If I have 2014-03-15 as the date and search for 'Andy', I expect...

Row ID, Item, Date, Relative Date
2, Item1, 2014-03-31, 1
3, Item1, 2013-12-31, 0
4, Item1, 2013-10-31, -1
9, Item2, 2014-03-31, 1
10, Item2, 2013-12-31, 0
11, Item2, 2013-09-30, -1

This is what I'm using which I have no issues switching if necessary...

DATEDIFF( quarter, 2014-03-31, date )
date BETWEEN DATEADD( quarter, -1, '20140315' ) AND
DATEADD( day, 1 ( DATEADD ( quarter, 2, '20140315' ) )

which returns...

Row ID, Item, Date, Relative Date
2, Item1, 2014-06-30, 1
3, Item1, 2014-03-31, 0
4, Item1, 2013-12-31, -1
9, Item2, 2014-03-31, 0
10, Item2, 2013-12-31, -1

Not sure if date math is the best option here. Perhaps using row_number() in some way?

I'm trying to avoid having to process the entire table programmatically given the size of the data set.

View 8 Replies View Related

Check System Date Format And Then Change It Thru SQL Query.

Nov 4, 2007



Hi All,

Is it possible to check the local system date format and then change the format to another format using SQL command in VB.

Eg.

-check current system format dd/MM/yyyy
-change current system format to MM/dd/yyyy format

Thanks
Jam.

View 12 Replies View Related

SQL Server 2008 :: Query To Select Every 2 Rows Based On A Date?

Sep 6, 2015

I have a table like the following (with much more data, but the concept is the same) with Dates and Actions for People and a column called Action with beginning Dates and end dates.

(I attached a picture because I could not figure out how to Format it)

begin Date end Date Name

begin 2014-10-15 end 2014-10-31 phil
begin 2014-09-18 end 2014-09-30 phil
begin 2014-08-21 end 2014-08-23 John

I need the query to be like this. The idea is to have the query grab the next 'END' not all Ends, which my attempts have done i.e. I get not just the closest end to the begin date, but ALL Ends with the same Person.

I Need it to look like this:

begin Date end Date Name

begin 2014-10-15 end 2014-10-31 phil
begin 2014-09-18 end 2014-09-30 phil
begin 2014-08-21 end 2014-08-23 John

There can be different People so the query Needs to return the beginning and end rows for the Person in sequential order.I can't figure out how to select only the 'next' end. My query always gets 'end' values that have a 'begin'. I

View 8 Replies View Related

Transact SQL :: Query To Show Most Recent Value Based On Date Field

Jun 18, 2015

I simply need to list the most recent value for each employee here... the value at each person's maximum date

Sample Detail Data:

EmpID                   Date                      Value
1                              1/1/14                  27
1                              2/12/15                333
2                              5/5/15                   255
3                              5/4/15                   110  
3                              1/1/13                   67                          
3                              3/2/14                   80

[Code] ....

What is the most efficient way to display the most recent value for each employee ID via MS SQL.?

View 4 Replies View Related

Transact SQL :: Query Distinct Results Based On Date Range

May 21, 2015

I have a data structure like this

UID , Name, amount, start date                               End Date
     1      A         10         2015-05-01 00:00:00             2015-05-01 23:59:59
     2      A         10         2015-05-02 00:00:00             2015-05-02 23:59:59
     3      A         10         2015-05-03 00:00:00             2015-05-03 23:59:59
     4      A         10         2015-05-04 00:00:00             2015-05-04 23:59:59
      5      B         10         2015-05-05 00:00:00             2015-05-05 23:59:59

[code]...

View 5 Replies View Related

Transact SQL :: Return Date Which Is 15 Working Days Prior To Given Future Date

Oct 28, 2015

i have written a sql function which returns only number of working days (excludes holidays and Weekends)  between given StartDate  and EndDate.
                 
USE [XXX]
GO
/****** Object:  UserDefinedFunction [dbo].[CalculateNumberOFWorkDays]    Script Date: 10/28/2015 10:20:25 AM ******/
SET ANSI_NULLS ON
GO

[code]...

I need  a function or stored procedure which will return the date which is 15 working days (should exclude holidays and Weekends) prior to the given future Date? the future date should be passed as a parameter to this function or stored procedure to return the date.  Example scenario:  If i give date as  12/01/2015, my function or stored procedure should return the date which is 15 working days (should exclude holidays and Weekends) prior to the given date i.e 12/01/2015...In my application i have a table  tblMasHolidayList where all the 2015 year holidays dates and info are stored.

View 18 Replies View Related

Need To CalcuThe Number Of Days Between The Current Date And A Stored Date

Sep 22, 2006

I need help with creating a query that compares the current date with a stored date field. If the difference between the two dates is greater or equal to 5 days for example, I need to be able to return these records. I am not sure if this can be done through a query alone but any help and suggestions would greatly be appreciated. Thanks in advance.

View 4 Replies View Related

Transact SQL :: Query Based On Date - Get Data From Table Above WHERE DateofBirth Is Tomorrow

Oct 30, 2015

Lets say I have a table, tblPersons

FirstName |  LastName   |  DateofBirth
----------------------------------------
  Thomas   | Alva Edison |   10-10-2015
  Benjamin | Franklin    |     10-10-2015
  Thomas   | More        |     11-10-2015
  Thomas   | Jefferson   |    12-10-2015

Suppose today's date is 09-10-2015 in (dd-MM-yyyy format), I want to perform a query in such a way that I should get the data from the table above WHERE DateofBirth is tomorrow, so I could get the following result.

FirstName |  LastName   |  DateofBirth
----------------------------------------
  Thomas   | Alva Edison |   10-10-2015
  Benjamin | Franklin    |     10-10-2015

View 15 Replies View Related

T-SQL (SS2K8) :: How To Split One Record Into Multiple Records In Query Based On Start And End Date

Aug 27, 2014

I would like to have records in my Absences table split up into multiple records in my query based on a start and end date.

A random record in my Absences table shows (as an example):

resource: 1
startdate: 2014-08-20 09:00:00.000
enddate: 2014-08-23 13:00:00.000
hours: 28 (= 8 + 8 + 8 + 4)

I would like to have 4 lines in my query:

resource date hours
1 2014-08-20 8
1 2014-08-21 8
1 2014-08-22 8
1 2014-08-23 4

Generating the 4 lines is not the issue; I call 3 functions to do that together with cross apply.One function to get all dates between the start and end date (dbo.AllDays returning a table with only a datevalue column); one function to have these dates evaluated against a work schedule (dbo.HRCapacityHours) and one function to get the absence records (dbo.HRAbsenceHours) What I can't get fixed is having the correct hours per line.

What I now get is:

resource date hours
...
1 2014-08-19 NULL
1 2014-08-20 28
1 2014-08-21 28
1 2014-08-22 28
1 2014-08-23 28
1 2014-08-24 NULL
...

... instead of the correct hours per date (8, 8, 8, 4).

A very simplified extract of my code is:

DECLARE @startdate DATETIME
DECLARE @enddate DATETIME
SET @startdate = '2014-01-01'
SET @enddate = '2014-08-31'
SELECTh.res_id AS Resource,
t.datevalue,
(SELECT ROUND([dbo].[HRCapacityHours] (h.res_id, t.datevalue, t.datevalue), 2)) AS Capacity,
(SELECT [dbo].[HRAbsenceHours] (9538, h.res_id, t.datevalue, t.datevalue + 1) AS AbsenceHours
FROMResources h (NOLOCK)
CROSS APPLY (SELECT * FROM [dbo].[AllDays] (@startdate, @enddate)) t

p.s.The 9538 value in the HRAbsenceHours function refers to the absences-workflowID.I can't get this solved.

View 1 Replies View Related

Transact SQL :: Finding Unique Counts Based On Consecutive Days?

Jul 9, 2015

I have a scenario here where the data looks like -

ID        Date
100      07/01
100     07/02
100    07/03
100   08/01
100   08/02
100   08/15

Now I need to find out unique occurrences of ID - 100 ( where count = unique only if the occurrences are in consecutive days, gap of even 1 day causes it to be a different instance ) - SO with the above data I should have unique occurrences as 3.efficient way to calculate this ?

View 5 Replies View Related

How To Add 3 Days To The Existing Date

Oct 23, 2007

Bottom is my table structure. please some one can give me the sql code to add 3 days to the existing date.  
SemesterID intSemesterLongID varcharSemesterIdentifier charSemesterIdentifierName varcharSemesterName varcharSemesterStart datetimeSemesterEnd datetimeSemesterNameAlt varcharEnrollmentDeadline datetimeRegistrationStart datetimeRegistrationEnd datetimeLengthInWeeks varcharBulletinStartDate datetimeBulletinEndDate datetimeClassroomStartDate datetimeClassroomEndDate datetimeFacClassStartDate datetimeFacClassEndDate datetimePlanningStart datetimePlanningEnd datetimeGoToTeach datetimeTOButAppears datetimeTOButDisappears datetimeSignature datetimeTOButDue datetimeBookListDue datetimeProfAccess datetimeExamDue datetimeSCGDue datetimeGradesDue datetimeExtGradesDue datetimeTOExt datetimeSessionPlanning datetimeTODue datetimeSCGStart datetimeTOExpire datetimeSRPTOCDue datetimeSRPCopyDue datetimeSRPCCCFormDue datetimeTOID intSemesterIdentifierID intCode varcharTitleIVDescription varcharCreatedBy varcharModifiedBy varcharDateCreated datetimeDateModified datetime

View 1 Replies View Related

Add N Numbers Of Days To A Date

Nov 11, 2007

Hi,
I have a textbox with date selected from calendar... Now i put in another textbox to enters number of day(30 or 120 or other), this number may vary...
so my qns is how to add the n numbers of days entered to the date selected? i stored date as smalldatetime
Help is appreciated

View 4 Replies View Related

Todays Date Plus 42 Days

Apr 7, 2008

 i have a customer and his output date must be 6 weeks or 42 days after his input date in my sql queryhow do i do this i've don't it in access and tried a similar code to no avail '[inputDate]' + '42' alias ext1 can anyone help me out thanks chris 

View 4 Replies View Related

SELECT * WHERE [date] &> 100 Days

Nov 29, 2006

Hi !
for MS SQL 2000/2000, I need :

SELECT * FROM table1 WHERE table1.[date] > 100 days

how can i do that ?

thank you for helping

View 2 Replies View Related

Display Last 30 Days From Given Date

Aug 1, 2013

I need to display the last 30 days from given period.

1
2
3
4
..
..
..
30

View 1 Replies View Related

Adding Days To Date

Sep 4, 2014

DATEADD function as i'm running into an error...Below is my SQL to derive start date of a month based on deliververydate feild.I'm running into error when i try to add 25 days to the start date of the month.

DATEADD(m,DATEDIFF(m,0,convert(varchar(30),DATEADD (month , @count*3 ,SR.DeliveryDate))),0)

When i want to add 25 days to the start date of a month getting an error...Error SQL

DateAdd(day,(DATEADD(m,DATEDIFF(m,0,convert(varchar(30),DATEADD (month , @count*3 ,SR.DeliveryDate))),0)),25)

Argument data type datetime is invalid for argument 2 of dateadd function.What do i need to change to make it work

View 2 Replies View Related

Working Days Only Date

Jan 29, 2015

I need to calculate a date.example it needs to be 20 working days ago compared to today so that means it needs to not include any Saturday or Sunday in between

declare @start_date datetime
declare @end_date datetime
declare @working_days int
set @working_days = 20

[code]...

So I need to calculate @start_date but it needs to exclude any weekend days.@working_days is the number of working day I'm interested in.

View 1 Replies View Related

Date Lying Between 2 Days

Apr 3, 2006

In the following query i want to get the orders for previous day and not the current day.
I am unable to frame the date range for this, so i am leaving it blank.I tried so many ways but what i need is date starting from zero hrs yesterday till zero hrs today.I need report lying for the day before today.
Thanks

I have the following query


SELECT O.work_order_id,O.LOAN_NUMBER,WEB_SUBMIT_DT
FROM OA_EST_HDR A (NOLOCK)
JOIN grasscutordercompletion B (NOLOCK) ON A.ORDER_ID = B.grasscutorderID
WHERE b.SUBMIT_STATUS = 0 AND O.ORDER_STATUS = 13
and day(WEB_SUBMIT_DT) =

I have the date in the following format "2004-01-28 08:49:00"

View 4 Replies View Related

How To Add 35 Days To Every Date Field In A Table?

Nov 29, 2004

Hello!

Your advice might helps me a lot! I'm looking for the answer for days.
I would like to add 35 days to every date field in a table. I The table structure, and content is dynamically changing.
Is it possible?

Thanks,
norbi

View 1 Replies View Related

Date Between Two Days Gives Wrong Output?

Aug 28, 2013

I have a table with a date column of datatype varchar(15) and the format is dd/mm/yyyy

When I write the following query, it displays complete data of the table and it cannot understand I want only between '01/08/2013' and '31/08/2013'

select date,column1,column2 from table1

where date between '01/08/2013' and '31/08/2013'

How to fix this?

View 4 Replies View Related

Adding 60 Days To Date Column

Dec 2, 2013

Aim – To add 60days to [Date_Approved_By_Risk__c] column

Query so far is

select
[Date_Approved_By_Risk__c]
--left([Date_Approved_By_Risk__c],10)+60 as correct_date
from #build
where [Date_Approved_By_Risk__c] is not null

[Date_Approved_By_Risk__c] is in the following format “2010-04-30T23:00:00.000Z”

When i add the following “left([Date_Approved_By_Risk__c],10)+60 as correct_date” into the query i get the following error Msg 245, Level 16, State 1, Line 1
Conversion failed when converting the varchar value '2010-07-13' to data type int.

View 9 Replies View Related

How To Calculate A Date Difference In Days

Apr 2, 2007

Suppose I have these two days fields
ddold 1/1/2005 12:00:00 AM
ddnew 2/1/2007 12:00:00 AM

How can i get the DateDifference of these two dates in days.

View 4 Replies View Related







Copyrights 2005-15 www.BigResource.com, All rights reserved