Query Table Without Data

Mar 13, 2006

I'm writting a stored proc that has to query 2 tables. One table is a table of "jobs" and the other table contains jobs that have been invoiced (2 tables are jobs and invoicedJobs). The invoiced table only contains records for jobs that have an invoice and not jobs that do not have an invoice.

My dilemma is that I need to write a query that can retrieve all un-invoiced jobs in my stored proc. You can't rightly join a table that does not have a relationship with another table (can you?). So in my query for jobs with an invoice, I simply join my jobs table and invoice table based on a job id that both tables contain. But how could I perform a query for jobs that do not exist in my invoice table inside my stored proc? Any help would be greatly appreciated.

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Thanks in advance,

Mark

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values are
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Test, All, gfd, rerwe
All, Newyork, fgsdf, dfgs
Demo, DC, erger, stgt
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production, Virgenia, dfgd, drtert

I want query that displays for the condition where environment = all or production and locationname =all or virgenia

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query on data in another table.
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01234Jackpot


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EventNameAmount
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EmptyCanister14.00

I would like to query Table2 based on the events in
the Table1. How do I do this ?
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Dec 12, 2007



Hi,

I have the following problem... For these two tables I have to query, all "nrtelefone" from PABX where tronco is not between tronco ini and tronco fim....and tronco is not in there clause "troncos_cliente", the the user will provide to us...
Let's suppose that the troncos_cliente has the value "NOT BETWEEN 32 and 55", and in tronco ini there is "10" and in tronco fim there is "20" so I need to query all nrtelefone that is not between 32 and 55 and not between 10 and 20, but the problem is with cursor this process will take to much time cause htere is too many clients..




Code Block
CREATE TABLE [LOGIN] (
[COD_CLIENTE] [varchar] (50),
[TRONCO_INI] [int] NULL ,
[TRONCO_FIM] [int] NULL ,
[TRONCOS_CLIENTE] [nvarchar] (4000)
)







Code Block
CREATE TABLE [PABX] (
[COD_CLIENTE] [varchar] (50) COLLATE Latin1_General_CI_AS NOT NULL ,
[NRTELEFONE] [varchar] (255) COLLATE Latin1_General_CI_AS NULL ,
[TRONCO] [int] NULL CONSTRAINT [DF_PABX_TRONCO] DEFAULT (9999),
)





So is there a way to make this query without using cursors ? (NOTE: I'm using cursor cause I need to build the T-SQL at runtime just because of the TRONCOS_CLIENTE that the user will provide the SQL clause)

Thanks

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<ROOT>
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<ADDRESS>
<ADDRESS1>
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<STATE>UP</STATE>

[code]....

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hi Experts,



I have a Issue table which stores the below data for many issue. some issue are duplicate to other and they are stored in a field Duplicate_of









ID
Duplicate_of
State

77637
65702
Duplicate

65702
42217
Duplicate

42217
-
Verified

i wanted to write a query or some stored procedure when passed 77637 should help me get 42217.



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/soni

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Query To Get Linked List Kind Of Data From The Table

Sep 18, 2006

hi Experts,



I have a Issue table which stores the below data for many issue. some issue are duplicate to other and they are stored in a field Duplicate_of









ID
Duplicate_of
State

77637
65702
Duplicate

65702
42217
Duplicate

42217
-
Verified

i wanted to write a query or some stored procedure when passed 77637 should help me get 42217.



Hint : 77637 when passed has field Duplicate_of which point to 65702 and his state will be Duplicate, 65702 will be duplicate to 42217 and state will be duplicate and 44217 is not duplicate to anything and state will be other then Duplicate

i appreciate if somebody can help me think in some line to give me some idea.



/soni

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Table Data:

CREATE TABLE Sales_Data
(
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[code]...

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May 1, 2008

Hello specialists.

Maybe this is the wrong formum but I've got a question for which you probably have the answer, i hope.


Situation
------------
John is member of Group_A and Group_B
Bill is member of Group_B and Group_C
Allison is member of Group_A and Group_E

How can I create a query to input Allisons username into table 1 and groupmembership into table 2. Also updating the relationship within table3 must be done automaticaly. I want to avoid duplicate records.
The final situation I want is given in red text.

The relationships between the tables are as follows
-------------------------------------------------------------
Table1 (PK)ID-Userinfo [ONE] <------------> [MANY] Table3 ID-Userinfo
Table3 (PK)ID-GroupInfo [MANY] <------------> [ONE] Table2 (PK)ID-GroupInfo

Table1: UserInfo
------------------------------
(PK)ID-Userinfo UserName
1 John
2 Bill
3 Allison

Table2: GroupInfo
------------------------------
(PK)ID-GroupInfo GroupName
1 Group_A
2 Group_B
3 Group_C

4 Group_E

Table3: MemberOf
------------------------------
(PK)ID-MemberOf ID-UserInfo ID-GroupInfo
1 1 1
2 1 2
3 2 2
4 2 3
5 3 1
6 3 4


I hope you can help me cracking this nut.

Thx in advance. Greetings Fred

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Source Tables :

OC
CREATE TABLE [dbo].[OC](
[OC] [nvarchar](255) NULL,
[DATE DEBUT] [date] NULL,
[DATE FIN] [date] NULL,
[Code Article] [nvarchar](255) NULL,
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[Code] ....

The update requirement is as follows:

DECLARE @Counter INT=0 --This causes the @@rowcount to be > 0
while @@rowcount>0
BEGIN
    SET rowcount 10000
    update r
    set Comp=t.Comp

[Code] ....

The update took more than 48h and didn't terminate , how to accelerate it ?

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May 1, 2008


Hello specialists.

Maybe this is the wrong formum but I've got a question for which you probably have the answer, i hope.


Situation
------------
John is member of Group_A and Group_B
Bill is member of Group_B and Group_C
Allison is member of Group_A and Group_E

How can I create a query to input Allisons username into table 1 and groupmembership into table 2. Also updating the relationship within junction-table3 must be done automaticaly. I want to avoid duplicate records.
The final situation I want is given in red text.

The relationships between the tables are as follows
-------------------------------------------------------------
Table1 (PK)ID-Userinfo [ONE] <------------> [MANY] Table3 ID-Userinfo
Table3 (PK)ID-GroupInfo [MANY] <------------> [ONE] Table2 (PK)ID-GroupInfo

Table1: UserInfo
------------------------------
(PK)ID-Userinfo UserName
1 John
2 Bill
3 Allison

Table2: GroupInfo
------------------------------
(PK)ID-GroupInfo GroupName
1 Group_A
2 Group_B
3 Group_C

4 Group_E

Table3: MemberOf
------------------------------
(PK)ID-MemberOf ID-UserInfo ID-GroupInfo
1 1 1
2 1 2
3 2 2
4 2 3
5 3 1
6 3 4


I hope you can help me cracking this nut.

Thx in advance. Greetings Fred

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----------------------------------------
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  Benjamin | Franklin    |     10-10-2015
  Thomas   | More        |     11-10-2015
  Thomas   | Jefferson   |    12-10-2015

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----------------------------------------
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  Benjamin | Franklin    |     10-10-2015

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Original Table:
================================================================
Id || Id1 || Id2 || MasterId || Obs ||Dec || Act || Status || InstanceId
================================================================
1 || 138 || 60 || 1 || Obs1 ||Dec1 || Act1 || 0|| 14
2 || 138 || 60 || 2 || Obs2 ||Dec2 || Act2 || 1|| 14
3 || 138 || 60 || 3 || Obs3 ||Dec3 || Act3 || 1|| 14
4 || 138 || 60 || 4 || Obs4 ||Dec4 || Act4 || 0|| 14
5 || 138 || 60 || 5 || Obs5 ||Dec5 || Act5 || 1|| 14

View For Reporting:

Row Header:
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Row Values:
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Any help would be greatly appreciated.

Current Table

Project | Task | Category | Fiscal Year | Fiscal Month | Total Hours
---------------------------------------------------------------------------------------------------------
Proj 1 | Task 1 | Cat 1 | 2007 | 01 | 40
Proj 1 | Task 1 | Cat 2 | 2007 | 02 | 20
Proj 1 | Task 1 | Cat 3 | 2007 | 03 | 35
Proj 1 | Task 1 | Cat 1 | 2008 | 01 | 40
Proj 1 | Task 1 | Cat 2 | 2008 | 02 | 40
Proj 1 | Task 1 | Cat 3 | 2008 | 03 | 40

Proposed Table

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---------------------------------------------------------------------------------------------------------------------------------------------------
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Proj 1 | Task 1 | Cat 2 | 0 | 20 | 0 | 2007Proj 1 | Task 1 | Cat 3 | 0 | 0 | 35 | 2007
Proj 1 | Task 1 | Cat 1 | 40 | 0 | 0 | 2008

Proj 1 | Task 1 | Cat 2 | 0 | 40 | 0 | 2008
Proj 1 | Task 1 | Cat 3 | 0 | 0 | 40 | 2008

Thanks,
Mike Misera

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