I posted a question yesterday about text field compare and I can't open the thread. Not sure why. Can you repost your reply to this thread regarding how to compare two text strings (i.e. two company names)? Much appreciated.
View 3 RepliesHey it's not often the blindman asks for advice on sql coding (never, I think), so here is an opportunity to solve a problem I've been knocking my head against for two days.
Here is sample code for setting up the problem:create table #blindman
(pkey smallint primary key,
fkey char(1),
updateddatetime)
insert into #blindman (pkey, fkey, updated)
select1, 'A', '1/1/2006'
UNION
select2, 'B', '1/1/2006'
UNION
select3, 'A', '1/2/2006'
UNION
select4, 'B', '1/2/2006'
UNION
select5, 'A', '1/4/2006'
UNION
select6, 'B', '1/2/2006'
UNION
select7, 'A', '1/3/2006'
UNION
select8, 'B', '1/3/2006'
UNION
select9, 'A', '1/5/2006'
UNION
select10, 'B', '1/5/2006'
drop table #blindman
Notice that for fkey 'B', there are two entries with '1/2/2006', and for fkey 'A' the updated values are not in synch with the order of the primary key.
The challenge: determine the next pkey for each pkey value, ordered by [updated], and using pkey as a tie-breaker when two records have the same [updated] value.
Here is the desired output for the sample data:pkey fkey updated nextpkey
------ ---- ---------- --------
1 A 2006-01-01 3
3 A 2006-01-02 7
7 A 2006-01-03 5
5 A 2006-01-04 9
2 B 2006-01-01 4
4 B 2006-01-02 6
6 B 2006-01-02 8
8 B 2006-01-03 10
Records 9 and 10 are missing because they have not succeeding records, though I'd be just has satisfied to include them with NULL as their nextpkey value.
Ideally, I want this as a VIEW.
Who's up for the challenge?
Just a few words to thanck some of the people
who connect each days to help others solve their problems.
I've finished migrating my programs to SQL Server
and it's been quite easier and quicker than I first tought
mainly because there are some
competent-intelligent-helpful-(funny) members on this forum.
So thank you all, thank you BK and BM
Caroline from France