Remove Weekends And Non Working Days When Calculating Days Difference Between Two Dates
Jan 7, 2014
I have an SQL code below which removes weekends and non working days when calculating days difference between two dates:
ce.enquiry_time represents when the enquiry was logged
(DATEDIFF(dd, ce.enquiry_time, getdate()) + 1)
-(DATEDIFF(wk, ce.enquiry_time, getdate()) * 2)
-(CASE WHEN DATENAME(dw, ce.enquiry_time) = 'Sunday' THEN 1 ELSE 0 END)
-(CASE WHEN DATENAME(dw, getdate()) = 'Saturday' THEN 1 ELSE 0 END)
-(SELECT COUNT(*) FROM nonworking_day WHERE nonworking_day.nonworking_date >= ce.enquiry_time AND nonworking_day.nonworking_date < dateadd(dd,datediff(dd,0,getdate()),1))
It works but I don't understand how it works it out. I am having issues understanding each coloured piece of code and how it works together.
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Oct 14, 2015
Here I have 2 Dates. CreatedDttm & ModifiedDttm.
I want - DATEDIFF(Day,CreatedDttm,ModifiedDttm) and I have to exclude the Weekend days from that query result.
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Jul 12, 2000
Hello,
Can anyone out there tell me if there's a simple way to calculate the number of week days between two dates in TSQL? Need it to calc. average turnaround times, excluding weekends. Can do it v. easily in VB, but gets a little more tricky in TSQL as there's no way to return the number of Sundays and Saturdays between the two dates. Any help much appreciated !
Jon Reade
Sql Server DBA
NEC Technologies (UK) Ltd.
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Jul 12, 2000
Hello,
Can anyone out there tell me if there's a simple way to calculate the number of week days between two dates in TSQL? Need it to calc. average turnaround times, excluding weekends. Can do it v. easily in VB, but gets a little more tricky in TSQL as there's no way to return the number of Sundays and Saturdays between the two dates. Any help much appreciated !
Jon Reade
Sql Server DBA
NEC Technologies (UK) Ltd.
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Jun 7, 2015
Iam trying to calculate the number of working days between two dates. Iam getting the uouput as only 1 02 r working days??
select building_number as SchoolID,building_name as Campus, count( distinct( CASE WHEN(( DATEPART(dw, CurDate) + @@DATEFIRST)%7 NOT IN (0,1)) tHEN 1 ELSE 0 END)) as NumberofDaysServed from Sales sl join Buildings b on sl.Building_Num =b.Building_number join students2 s on s.Student_Number= sl.Student_Num join Sale_Items SI on si.UID = sl.UID where CONVERT(CHAR(10),CurDate,120) between '2015-05-01' and '2015-05-07' and VoidReview <> 'v' and SI.INum = '1' group by building_number,building_name order by building_number,Building_Name;
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Apr 16, 2015
I'm trying to calculate the time difference between a date field and today's date in days. The date field is not mandatory and can therefore be blank. I'm trying to execute the following query:
SELECT employee_code, Civil_ID, DATEDIFF(Day, Civil_ID, GETDATE())
FROM ODEV_VIEW_Credentials_Expiry_Dates
WHERE Civil_ID IS NOT NULL AND Civil_ID != ''
ORDER BY employee_code
I keep getting the following message:
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Warning: Null value is eliminated by an aggregate or other SET operation.
No matter what filter I use to process non-blank dates, it never works.
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Aug 14, 2007
I am trying to use the DateDiff function to calculate the difference between two dates in working days only... Is this possible in SSRS 2005, or can anyone suggest an alternate solution?
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Sep 4, 2007
Hi 2 all,
I need to calculate the number of working days in a month. In clear, i need to ignore saturday.sunday and holiday in a month.
can anyone say the solution?
thanks.
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Dec 16, 2013
I have the following simple SQL which counts the days difference between two date fields:
SELECT
DATEDIFF(dd,central_enquiry.enquiry_time, GETDATE()) as Days_Open
FROM
central_enquiry
---
How do I get it to exclude weekends?
I also have a table nonworkingdays which has a nonworking_date field where users can manually record national holidays and bank holidays etc.
Example date
nonworking_date
01/01/2014
18/04/2014
05/05/2014
How can I include this table in the calculation too?
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Jun 22, 2015
I have got this matrix and I am trying to calculate the average amount of working days in a month. At the moment, I have divided the total number of jobs by 21 for every month which is a hard coded value. However, I am not sure how to retrieve this value dynamically. Is there any formula that can find out the working days?
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Feb 2, 2014
I have already created a table name 'tblHolidays' and populated with 2014 Holidays. What I would like is be able to calculate (subtract or add) number of days from a date. For example subtract 2 days from 07/08/2014 and function should return 07/03/2014.
CREATE FUNCTION [dbo].[ElapsedBDays] (@Start smalldatetime, @End smalldatetime)
RETURNS int
AS
BEGIN
/*
Description:
Function designed to calculate the number of business days (In hours) between two dates.
[Code] ......
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May 19, 2014
I have a table with a list of jobs along with their start and end datetime values.
I am looking for a function which will return the time taken to process a job using a start date and an end date. If the date range covers a Saturday or Sunday I want the time to ignore the weekends.
Example
Start Date=2014-05-15 12:00:00.000
End Date=2014-05-19 13:00:00.000
Total Time should be: 2 Days, 1 Hour and 0 Minutes
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Aug 21, 2005
I have table with three columns: 1) TodaysDate,
2)
DueBackDate,
3) DaysOverdue
The problem I am having is creating a formula in MS SQL, so that when
the 'DueBackDate' column is more than todays date, I want the
'DaysOverdue' column to be incremented accordingly.
I have tried creating an SQL Query something like this:
UPDATE rental
SET DaysOverdue = DaysOverdue + 1
WHERE ({ fn NOW() } > DueBackDate)
But the problem with this that it only increments the 'DaysOverdue'
field by 1. When I want it to basically subtract todays date by
'DueBackDate'.
I have tried to also create a formula within MS SQL but I come up with
errors. I have done something like this in Access which worked. The
Formula looked like this:
IIF(Now()>[DueBackDate],int(Now()-[DueBackDate]),0)
Is there a way to convert this formula so that is would work in MS SQL?
Thanks.
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Jul 14, 2004
How can I calculate the no. of days in a month.I know it is a simple question but I am not able to find any code to calculate that.
Can someone help me?
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Nov 28, 2013
Aim – Calculate the number of days between CreatedDate and [Date_Docs_In_Complete__c],count how many Ids, Fall within a specific month by year, and then work out the avg number of days it took for each month
My query so far
select
ID,
left(CreatedDate,10) as CreatedDate,
left([Date_Docs_In_Complete__c],10) as [Date_Docs_In_Complete__c],
DATEDIFF(day,CreatedDate,[Date_Docs_In_Complete__c]) as Days
from #build
Produces following results
IDCreatedDateDate_Docs_In_Complete__cDays
0063000000ausKGAAY2010-03-262013-07-161208
0063000000mC359AAC2011-06-302013-07-03734
0063000000oyaSPAAY2011-11-292013-07-18597
Desired outcome results would be
Year Month Date_Docs_In_Complete__c Total Days Avg_Days
2013 07 3 2539846.3
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Jul 21, 2001
Does anyone know of a way to calculate the date 'x' number of business days after another date?
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Oct 7, 2015
I need the SQL to calculate the duration between a day and time, no specific date.
For example:
Sun 00:00 > Mon 08:00 = 5.67 days
So there is no date, it's just the general duration (in days), from a specific day and time to a specific day and time.
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Oct 25, 2006
Hello,I am writing a query to select records added to a table today, in the last 3 days, in the last 7 days, and so on.Here is what I have (which seems that its not working exactly). -- total listed today
SELECT COUNT (*) FROM mytable WHERE DATEDIFF(Day, mydatecolumn, getdate() ) <= 0-- total listed yesterday
SELECT COUNT (*) FROM mytable WHERE DATEDIFF(Day, mydatecolumn, getdate() ) <= 1-- total listed in the last 3 days
SELECT COUNT (*) FROM mytable WHERE DATEDIFF(Day, mydatecolumn, getdate() ) <= 3I'd like to be able to select the count for records added within the last X number of days. Can someone please help me out? Thanks so much in advance.
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Aug 15, 2006
Hi! I am totally new to the forum and to the SQL.
Need your advice. My report will run on Friday automatically and I need to retrieve the data from previous Friday until Today’s Friday.
I have an example from another developer’s code, but this one gets the data on the previous day. Can you please help me to right the expression?
Here is an example ‘on the previous day’
CAST(CONVERT(CHAR(10), tbl1.closeddate,120) as datetime) = CAST(CONVERT(CHAR(10), dateadd(day, -1,getdate()), 120) as datetime)
This is what I did (assuming today is Friday)
(tbl1.closedDate BETWEEN CAST(CONVERT(CHAR(10), DATEADD(day, - 8, GETDATE()), 120) AS datetime) AND CAST(CONVERT(CHAR(10),
DATEADD(day, - 1, GETDATE()), 120) AS datetime))
I don't get any records back.
Please help.
Thanks a lot.
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Aug 6, 2007
Hi all,
I have a table in which I have two fields in my DB.
FromDate and ToDate.
Both are stored as Varchar(MAX).
I would like to have an SP which gives me the Days in Between them.
Regards,
Naveen.
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Apr 16, 2007
Hello,
I have a table with a field Expiration of smalldatetime. I want to only display the data that has 60 days or more between Expiration and todays date. Any help would be highly appreciated.
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Oct 10, 2013
i have a table
a1
-----
id t1
How can I calculate the difference between getdate() and t1 how many days.
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Apr 2, 2007
Suppose I have these two days fields
ddold 1/1/2005 12:00:00 AM
ddnew 2/1/2007 12:00:00 AM
How can i get the DateDifference of these two dates in days.
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Feb 27, 2005
select a.RelocateID,a.DateEntered,a.CompanyID,b.FileClose dDate from test1 a inner join test b on
(a.RelocateID = b.RelocateID) where
CompanyID ='5710' and DateEntered >= '01/01/2004' and convert(varchar,FileClosedDate,101) < '31/12/2004'
Hi I was wondering if somebody could help me alter this query so I an calulate the difference in days in between DateEntered and FileClosedDate having the above criteria.
I can't seem to be able to get the datediff function right in this particular example
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Jul 9, 2014
Have a table called Customers that has a datetime column called Submitted. I need a way to compare the Submitted field against the current date to tell if 5 days have pasted excluding weekends. In the sample data below, the record submitted on 7/2 is the record that should be returned in the query when compared to today's date 7/9.
FirstName........LastName.........Submitted
John................Miller...............7/01/2014
Mary................Smith..............7/02/2014
Bob.................Williams..........7/05/2014
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Jan 24, 2006
I have a table of sample data
Samples(sample_no, sample_date..)
I have no idea how to do the following in sql server or if its even possible:
1. Calculate the difference in days between all samples.
2. Select the median result
Any trick to get this done would be really helpful
thanks,
DB
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Jan 24, 2006
I have a table of sample data
Samples(sample_no, sample_date..)
I have no idea how to do the following in sql server or if its even possible:
1. Calculate the difference in days between all samples.
2. Select the median result
Any trick to get this done would be really helpful
thanks,
DB
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Apr 20, 2015
Log file rotation and cleanup script and how to remove the log file older then x days.
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Mar 26, 2014
The following query was used for retrieving dates for the last 7 days . Untill February this query was running fine and would return the last seven days date including today.
SELECT DISTINCT TOP 7 Convert(DateTime, DATEDIFF(DAY, 0, DateCreated)) AS DateCreated,
datepart(dw,DateCreated) AS WeekNum from [TechnologyRepository].[helpdsk].[WorkDetails]
WHERE DATEDIFF(DAY, Convert(DateTime, DATEDIFF(DAY, 0, DateCreated)),GETDATE()) <= 7
However from March (not sure of the exact date)..the query below would only give us 7 days until yesterday..i.e it would list dates from 3/19,3/20,3/21,3/22,3/23,3/24,3/25 and not 3/26 ..
I changed the query to <= 6 and it works as expected. But still not sure why it would not return todays date with <= 7.
SELECT DISTINCT TOP 7 Convert(DateTime, DATEDIFF(DAY, 0, DateCreated)) AS DateCreated,
datepart(dw,DateCreated) AS WeekNum from [TechnologyRepository].[helpdsk].[WorkDetails]
WHERE DATEDIFF(DAY, Convert(DateTime, DATEDIFF(DAY, 0, DateCreated)),GETDATE()) <= 6
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Apr 17, 2007
I have a table like this (a small section of the table)
Cu_id |Tr_id |Date
1234 |1 |12/3/2006
1234 |2 |12/18/2006
1234 |3 |1/5/2007
1234 |4 |1/9/2007
1234 |5 |2/21/2007
9999 |91 | 1/3/2006
9999 |81 |1/10/2006
9999 |71 |1/18/2007
9999 |61 |2/1/2007
I have to find the number of days between the dates for the same cu_id and add the number as a new column. The new table should look like this.
Cu_id |Tr_id |Date| Days_between
1234 |1 |12/3/2006 |0
1234 |2 |12/18/2006 |15
1234 |3 |1/5/2007 |18
1234 |4 |1/9/2007 |4
1234 |5 |2/21/2007 | 43
9999 |91 |1/3/2006 |0
9999 |81 |1/10/2006 |7
9999 |71 |1/18/2007 |8
9999 |61 |2/1/2007 |14
Please let me know how I can find the number of days between two dates in the same column for the same cu_id (customer_id).
Thanks
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Dec 9, 2011
I have data in which i need to calculate employees working hours for a day...
name time in_out
manisha 2011-01-01 9:30:00.000am 1
manisha 2011-01-01 10:30:00.000 0
manisha 2011-01-01 10:45:00.000 1
manisha 2011-01-02 1:00:00.000am 0
How can i calculate time in that two dates as 1 is for entry an 0 is for exit..
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Sep 16, 2005
I have written a function that returns the number of Days, Hours and minutes from a given number of minutes. On testinf the results are close but not quite there. Can anyone see where I have gone wrong or is there an easier way of doing this? Code is as follows:
CREATE FUNCTION dbo.GetTimeBetweenLong
(@StartTime DateTime, @EndTime DateTime, @CurrentDate DateTime)
RETURNS VarChar(50) AS
BEGIN
DECLARE @TotalTime Numeric
DECLARE @Minutes Numeric
DECLARE @Hours Numeric
DECLARE @Days Numeric
DECLARE @MinutesInDays Numeric
IF @EndTime IS NULL
BEGIN
SET @Days = DATEDIFF(Day, @StartTime, @CurrentDate)
SET @Hours = DATEDIFF(Hour, @StartTime, @CurrentDate) - (@Days * 24)
SET @Minutes = DATEDIFF(Minute, @StartTime, @CurrentDate) - ((@Days * 24)*60) - (@Hours * 60)
END
ELSE
BEGIN
SET @Days = DATEDIFF(Day, @StartTime, @EndTime)
SET @Hours = DATEDIFF(Hour, @StartTime, @EndTime) - (@Days * 24)
SET @Minutes = DATEDIFF(Minute, @StartTime, @EndTime) - ((@Days * 24)*60) - (@Hours * 60)
END
IF(@Days <0)
BEGIN
SET @Days = @Days - @Days - @Days
END
IF (@Hours < 0)
BEGIN
SET @Hours = @Hours - @Hours - @Hours
END
IF (@Minutes <0)
BEGIN
SET @Minutes = @Minutes - @Minutes - @Minutes
END
RETURN CONVERT(nVarChar(10),@Days) + ' Days, ' + CONVERT(nVarChar(5), @Hours) + ' Hours, ' + CONVERT(nVarCHar(5), @Minutes) + ' Mins'
END
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May 21, 2015
declare @siva1 datetime;
declare @siva2 datetime;
set @siva1='2014-03-10 05:02:11'
set @siva2='2014-03-12 23:52:11'
i want output like this 2.18 means 2day 18hours difference how using query
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